calculocpuente rev4 subir scribb
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CalculocPuente Rev4 Subir ScribbTRANSCRIPT
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Area de Puente Vista de Planta
0.32 m0.015 m 0.02 m
0.035 m 0.035 m
0.070 m
0.35 m
Hallando la Presion Total "P" en la Placa en funcion a la Fuerza "Ft" en (N) Newton
Presiones por Areas: A1, A2.
0.035 m
A1 A2 A2 A3A3
L M N
T
T
A
FP
)10.0)(32.0(TFP
11 FPA
1125.31 FAFT
)10.0()055.0(25.311 TFF
TFF 171875.01
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0.115 m
0.0859375 Ft
NUDO B
BLAB = BC
AB BC BC = 0.17590758
0.0859375 Ft
NUDO C
BC = CD
BC CD CD = 0.17590758
A
D
CA B D
L M N
∑▒ 〖� =0_�〗
∑▒ 〖� =0_�〗
4TF TF0859375.0
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0.0546875 Ft
NUDO D
CD = DE
CD DE DE = 0.17590758
0.0546875 Ft
NUDO E
DE = EF
DE EF EF = 0.17590758
0.0546875 Ft
∑▒ 〖� =0_�〗
∑▒ 〖� =0_�〗
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0.07 m
0.10 m
0.0300.1100.0350.350
Hallando la Presion Total "P" en la Placa en funcion a la Fuerza "Ft" en (N) Newton
P=
P A1 =31.25F1 =
NO HAY NUDO, ESTAN SUPERPUESTOS PERO NO HAY CONTACTO0.070 m 0.035 m NO CALCULAR PORQUE NO HAY NUDOS ALGUNOS
A1A3 A2 A2
O P Q R S
)10.0)(32.0(TFP
TFP 25.31
)10.0()055.0(25.311 TFF
22 FPA
2225.31 FAFT
)10.0)(035.0(25.312 TFF
TFF 109375.02
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0.0546875 Ft
NUDO O
AO Cos 39°BL = 0.0859375 Ft
0.17590758 Ft
NUDO N
AN Cos 48°CM = 0.0546875 Ft
0.17590758 Ft
D
F G I JE H
O P Q R S
∑▒ 〖� =0_�〗 ∑▒ 〖� =0_�〗
∑▒ 〖� =0_�〗 ∑▒ 〖� =0_�〗
4TF
TF0546875.0
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NUDO M
AM Cos 59°DN = 0.0546875 Ft
0.17590758 Ft
NUDO L
AL Cos 73°EO = 0.0546875 Ft
0.17590758 Ft
NUDO AAL
∑▒ 〖� =0_�〗 ∑▒ 〖� =0_�〗
∑▒ 〖� =0_�〗 ∑▒ 〖� =0_�〗
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Ft4
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Sale de la diferencia entre 6 diferente a tu valor
31.25 Ft A1 = 0.0055 A3 =A2 = 0.0035
F1 P A2 = F2 P A3 =Ft A1 = F1 31.25 Ft A2 = F2 0.0070
0.171875 Ft F2 = 0.109375 Ft F2 =
NO HAY NUDO, ESTAN SUPERPUESTOS PERO NO HAY CONTACTONO CALCULAR PORQUE NO HAY NUDOS ALGUNOS
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NO OP
39° EO = AO Sen 39°AO = EO .
EO Sen 39°AO AO = 0.054688
0.62932AO Sen 39° AO = 0.086899
MN NO
48° DN = AN Sen 48°AN = DN .
DN Sen 48°AN AN = 0.054688
∑▒ 〖� =0_�〗 ∑▒ 〖� =0_�〗
∑▒ 〖� =0_�〗 ∑▒ 〖� =0_�〗
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0.743145AN Sen 48° AN = 0.073589
LM MN
59° CM = AM Sen 59°AM = CM .
CM Sen 59°AM AM = 0.054688
0.857167AM Sen 59° AM = 0.0638
LM
73° BL = AL Sen 73°AL = BL .
BL Sen 73°AL AL = 0.085938
0.956305AL Sen 73° AL = 0.089864
AMAN AL Cos 73°+AM Cos 59°+AN Cos 48°+AO Cos 39° =
AOAB = 0.17590758 Ft
AB
∑▒ 〖� =0_�〗 ∑▒ 〖� =0_�〗
∑▒ 〖� =0_�〗 ∑▒ 〖� =0_�〗
∑▒ 〖� =0_�〗 ∑▒ 〖� =0_�〗
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0.0070
F3Ft A2 = F2
0.21875 Ft
NO HAY NUDO, ESTAN SUPERPUESTOS PERO NO HAY CONTACTO
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AO Sen 39° AO Cos 39° + NO = OP
OP = 0.17590758 FtFt
Ft
AN Sen 48° AN Cos 48° + MN = NO
NO = 0.108374142 FtFt
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Ft
AM Sen 59° AM Cos 59° + LM = MN
MN = 0.059133296 FtFt
Ft
AL Sen 73° AL Cos 73° = LM
LM = 0.02627373 FtFt
Ft
AB AL Sen 73°+AM Sen 59°+AN Sen 48°+AO Sen 39° =
Ft = 1
∑▒ 〖� =0_�〗
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Ft4
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Area de Puente Vista de Planta
0.32 m0.015 m 0.02 m
0.035 m 0.035 m
0.070 m
0.35 m
0.070 m
0.035 mB D F H
0.11 m
C E G I
51.5 51.5 77.2555.181
A1 A2 A2
A
A3A3
4TF
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Hallando la Presion Total "P" en la Placa en funcion a la Fuerza "Ft" en (N) Newton
LT = Largo Total de la Planacha de Fierro = 0.32AT = Ancho Total de la Plancha de Fierro = 0.08
W = Carga que soporta el Puente enen Kg= 48
FT = Carga que soporta el Punte en Newton 471
Hallando Carga o Fuerza 1 (en el Area 1)
A1 = Ancho del Area 1= 0.0375 Ingresar DatoL1 = Logitud del Area 1= 0.08 Ingresar Dato
F1 = FT * A1*L1 = 55.181 NewtonLT*AT
Hallando Carga o Fuerza 2 (en el Area 2)
A2 = Ancho del Area 2= 0.035 Ingresar DatoL2 = Logitud del Area = 0.08 Ingresar Dato
F2 = FT * A2*L1 = 51.503 NewtonLT*AT
Hallando Carga o Fuerza 3 (en el Area 3)
A3 = Ancho del Area 3= 0.0525 Ingresar DatoL3 = Logitud del Area 3 = 0.08 Ingresar Dato
F3 = FT * A3*L1 = 77.254 NewtonLT*AT
NUDO I
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HI
GI II
38.63
NUDO H
AH Sen 51.843 HH
FHArcotan 0.14 = 51.843
51.84 0.11
AH38.63
AH cos 51.843
NUDO F
AF Sen 43.668 FH
DFArcotan 0.11 = 43.7
43.67 0.11
AF25.75
AF cos 43.668
NUDO D
AD Sen 32.471 DF
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BDArcotan 0.07 = 32.5
32.47 0.11
AD25.75
AD cos 32.471
NUDO B
AB Sen 17.650 BD
Arcotan 0.04 = 17.717.65 0.11
AB25.75
AB cos 17.650
NUDO A
AC
AF sen
AD sen 32.47
AB sen 17.65
Ft4
AC = AH sen 51.84 + AF sen 43.67 + AD sen
∑▒ 〖� =0_�〗
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AC= 49.161 + 24.58 + 16.39 + 8.19
AC= 98.32 Newton
NUDO CAC CE
NUDO ECE EG
NUDO GEG GI
NUDO IGI II
MIEMBRO DE LA ARMADURA NewtonMiembro AB 27.02Miembro AD 30.52Miembro AF 35.60Miembro AH 62.52Miembro BC 25.75Miembro DE 25.75Miembro FG 25.75Miembro HI 38.63
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Miembro AC 98.32Miembro CE 98.32Miembro EG 98.32Miembro GI 98.32Miembro HH 98.32Miembro II 98.32
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0.07 m
0.8 m
0.070 m 0.035 m NO HAY NUDO, ESTAN SUPERPUESTOS PERO NO HAY CONTACTO
H F D B NO CALCULAR PORQUE NO HAY NUDOS ALGUNOS
I G E C A
A1A2 A2A3
4TF
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Hallando la Presion Total "P" en la Placa en funcion a la Fuerza "Ft" en (N) Newton
Ingresar DatoIngresar Dato
∑▒ 〖� =0_�〗 ∑▒ 〖� =0_�〗
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HI = 38.63 Newton
AH Cos 51.8 = 38.63 AH Sen 51.84
AH = 62.52 Newton 49.16 +
AF Cos 43.7 = 25.75 AF Sen 43.67
AF = 35.60 Newton 24.58 +
∑▒ 〖� =0_�〗 ∑▒ 〖� =0_�〗
∑▒ 〖� =0_�〗∑▒ 〖� =0_�〗
∑▒ 〖� =0_�〗∑▒ 〖� =0_�〗
∑▒ 〖� =0_�〗∑▒ 〖� =0_�〗
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AD Cos 32.5 = 25.75 AD Sen 32.47
AD = 30.52 Newton 16.39 +
AB Cos 17.7 = 25.75 AB Sen 17.7
AB = 27.02 Newton BD
AH sen 51.8
AF sen 43.7
AD sen 32.47 + AB sen 17.65
∑▒ 〖� =0_�〗∑▒ 〖� =0_�〗
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AC = CECE = 98.323 Newton
CE = EGEG = 98.323 Newton
EG = GIGI = 98.323 Newton
GI = IIII = 98.323 Newton
27.0230.5235.6062.5225.75
∑▒ 〖� =0_�〗
∑▒ 〖� =0_�〗
∑▒ 〖� =0_�〗
∑▒ 〖� =0_�〗
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NO HAY NUDO, ESTAN SUPERPUESTOS PERO NO HAY CONTACTO
NO CALCULAR PORQUE NO HAY NUDOS ALGUNOS
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+ FH = HH
49.16 = 98.32
HH = 98.32 Newton
+ DF = FH
24.58 = 49.16 Newton
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+ BD = DF
8.19 = 24.58 Newton
= BD
= 8.19 Newton
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