ce 230-engineering fluid mechanics lecture # 29-30 turbulent flow in circular pipes

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CE 230- Engineering Fluid Mechanics Lecture # 29-30 Turbulent flow in circular pipes

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Page 1: CE 230-Engineering Fluid Mechanics Lecture # 29-30 Turbulent flow in circular pipes

CE 230-Engineering Fluid Mechanics

Lecture # 29-30

Turbulent flow in circular pipes

Page 2: CE 230-Engineering Fluid Mechanics Lecture # 29-30 Turbulent flow in circular pipes

Head loss for turbulent flow

Difficult to develop velocity distribution

Newton’s viscosity law does not apply, instead:

turbulantarlavudy

ud

min''

Page 3: CE 230-Engineering Fluid Mechanics Lecture # 29-30 Turbulent flow in circular pipes

Head loss formula, Turbulent flow

Avoiding detail a formula that is widely used is Darcy-Weisbach equation:

Where: f friction factor function of Re and material type and sizeOther variables are well known by now

g

V

D

Lfh f 2

2

Page 4: CE 230-Engineering Fluid Mechanics Lecture # 29-30 Turbulent flow in circular pipes

Factors affecting f

Smooth pipes only Re is important

Rough pipes Re as well as ks/D

Fully turbulent Re is not important

See Moody chart or equations

Page 5: CE 230-Engineering Fluid Mechanics Lecture # 29-30 Turbulent flow in circular pipes

Rough pipes

We can idealize the roughness in pipes using mean values which are reported for different materials as ks shown below

Page 6: CE 230-Engineering Fluid Mechanics Lecture # 29-30 Turbulent flow in circular pipes
Page 7: CE 230-Engineering Fluid Mechanics Lecture # 29-30 Turbulent flow in circular pipes
Page 8: CE 230-Engineering Fluid Mechanics Lecture # 29-30 Turbulent flow in circular pipes
Page 9: CE 230-Engineering Fluid Mechanics Lecture # 29-30 Turbulent flow in circular pipes

Classes of problems handled

Given size and type of pipe and Q find head loss.

Given size and type of pipe and head loss find Q.

Given type of pipe, Q and head loss find size.

Page 10: CE 230-Engineering Fluid Mechanics Lecture # 29-30 Turbulent flow in circular pipes

Type one problem

Page 11: CE 230-Engineering Fluid Mechanics Lecture # 29-30 Turbulent flow in circular pipes

=0.12/200

V= Q/A=1.6 m/sRe=1000(1.6)(.2)/0.001=320000

From Moody Chart f=0.019

Page 12: CE 230-Engineering Fluid Mechanics Lecture # 29-30 Turbulent flow in circular pipes

Example 10.5:If the head loss per kilometer for a 30-cm diameter asphalt cast iron pipe is 12.2 m, estimate Q.

Example 10.6Estimate Q through the 50 cm diameter steel pipe..

Type one problems

Page 13: CE 230-Engineering Fluid Mechanics Lecture # 29-30 Turbulent flow in circular pipes

Example 10.6:What size of asphalt cast iron pipe is required to carry Q=3cfs with a head loss of 4 ft per 1000 ft of pipe?

Type three problem