chapter 30 lect. 15: faraday’s law and induction hw 5 (problems): 28.5, 28.10, 28.15, 28.27,...

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Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14, 30.34, 30.42, 30.48 Due Thursday, July 17.

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Page 1: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Chapter 30

Lect. 15:

Faraday’s Law and Induction

HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14, 30.34, 30.42, 30.48

Due Thursday, July 17.

Page 2: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Induction

An induced current is produced by a changing magnetic field

There is an induced emf associated with the induced current

A current can be produced without a battery present in the circuit

Faraday’s law of induction describes the induced emf

Page 3: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

EMF Produced by a Changing Magnetic Field, 1

A loop of wire is connected to a sensitive ammeter

When a magnet is moved toward the loop, the ammeter deflects The direction was

arbitrarily chosen to be negative

Page 4: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

EMF Produced by a Changing Magnetic Field, 2

When the magnet is held stationary, there is no deflection of the ammeter

Therefore, there is no induced current Even though the magnet

is in the loop

Page 5: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

EMF Produced by a Changing Magnetic Field, 3

The magnet is moved away from the loop

The ammeter deflects in the opposite direction

Use the active figure to move the wires and observe the deflection on the meter

Page 6: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Faraday’s Experiment – Conclusions

An electric current can be induced in a loop by a changing magnetic field This would be the current in the secondary circuit of this

experimental set-up The induced current exists only while the magnetic

field through the loop is changing This is generally expressed as: an induced emf is

produced in the loop by the changing magnetic field The actual existence of the magnetic flux is not sufficient to

produce the induced emf, the flux must be changing

Page 7: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Faraday’s Law – Statements

Faraday’s law of induction states that “the emf induced in a circuit is directly proportional to the time rate of change of the magnetic flux through the circuit”

Mathematically,

Bdε

dt

Page 8: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Faraday’s Law – Statements, cont

Remember B is the magnetic flux through the circuit and is found by

If the circuit consists of N loops, all of the same area, and if B is the flux through one loop, an emf is induced in every loop and Faraday’s law becomes

B d B A

Bdε N

dt

Page 9: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Faraday’s Law – Example

Assume a loop enclosing an area A lies in a uniform magnetic field

The magnetic flux through the loop is B = BA cos

The induced emf is = - d/dt (BA cos )

B

Page 10: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Ways of Inducing an emf

The magnitude of can change with time The area enclosed by the loop can change

with time The angle between and the normal to the

loop can change with time Any combination of the above can occur

B

B

Page 11: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Applications of Faraday’s Law – Pickup Coil The pickup coil of an

electric guitar uses Faraday’s law

The coil is placed near the vibrating string and causes a portion of the string to become magnetized

When the string vibrates at some frequency, the magnetized segment produces a changing flux through the coil

The induced emf is fed to an amplifier

Page 12: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Motional emf

A motional emf is the emf induced in a conductor moving through a constant magnetic field

The electrons in the conductor experience a force, that is directed along ℓ

q F v B

Page 13: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Motional emf, final

For equilibrium, qE = qvB or E = vB The electric field is related to the potential difference

across the ends of the conductor: V = E ℓ =B ℓ v A potential difference is maintained between the

ends of the conductor as long as the conductor continues to move through the uniform magnetic field

If the direction of the motion is reversed, the polarity of the potential difference is also reversed

Page 14: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Sliding Conducting Bar

A bar moving through a uniform field and the equivalent circuit diagram

Assume the bar has zero resistance The stationary part of the circuit has a resistance R

Page 15: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Sliding Conducting Bar, cont. The induced emf is

Since the resistance in the circuit is R, the current is

Bd dxε B B v

dt dt

Iε B v

R R

Page 16: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Sliding Conducting Bar, Energy Considerations

The applied force does work on the conducting bar

This moves the charges through a magnetic field and establishes a current

The change in energy of the system during some time interval must be equal to the transfer of energy into the system by work

The power input is equal to the rate at which energy is delivered to the resistor

2

app Iε

F v B vR

Page 17: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Lenz’s Law

Faraday’s law indicates that the induced emf and the change in flux have opposite algebraic signs

This has a physical interpretation that has come to be known as Lenz’s law

Developed by German physicist Heinrich Lenz

Page 18: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Lenz’s Law, cont.

Lenz’s law: the induced current in a loop is in the direction that creates a magnetic field that opposes the change in magnetic flux through the area enclosed by the loop

The induced current tends to keep the original magnetic flux through the circuit from changing

Page 19: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Lenz’ Law, Example The conducting bar slides on

the two fixed conducting rails The magnetic flux due to the

external magnetic field through the enclosed area increases with time

The induced current must produce a magnetic field out of the page The induced current must be

counterclockwise If the bar moves in the

opposite direction, the direction of the induced current will also be reversed

Page 20: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Induced emf and Electric Fields

An electric field is created in the conductor as a result of the changing magnetic flux

Even in the absence of a conducting loop, a changing magnetic field will generate an electric field in empty space

This induced electric field is nonconservative Unlike the electric field produced by stationary

charges

Page 21: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Induced emf and Electric Fields, cont.

The emf for any closed path can be expressed as the line integral of over the path

Faraday’s law can be written in a general form:

Bdd

dt

E s

dE s

Page 22: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Induced emf and Electric Fields, final

The induced electric field is a nonconservative field that is generated by a changing magnetic field

The field cannot be an electrostatic field because if the field were electrostatic, and hence conservative, the line integral of would be zero and it isn’t

dE s

Page 23: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Generators

Electric generators take in energy by work and transfer it out by electrical transmission

The AC generator consists of a loop of wire rotated by some external means in a magnetic field

Use the active figure to adjust the speed of rotation and observe the effect on the emf generated

Page 24: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Rotating Loop

Assume a loop with N turns, all of the same area rotating in a magnetic field

The flux through the loop at any time t is B = BA cos =

BA cos t

Page 25: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Induced emf in a Rotating Loop

The induced emf in the loop is

This is sinusoidal, with max = NAB

sin

Bdε N

dtNABω ωt

Page 26: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Induced emf in a Rotating Loop, cont.

max occurs when t = 90o or 270o

This occurs when the magnetic field is in the plane of the coil and the time rate of change of flux is a maximum

= 0 when t = 0o or 180o

This occurs when the magnetic field is perpendicular to the plane of the coil and the time rate of change of flux is zero

Page 27: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Motors

Motors are devices into which energy is transferred by electrical transmission while energy is transferred out by work

A motor is a generator operating in reverse A current is supplied to the coil by a battery

and the torque acting on the current-carrying coil causes it to rotate

Page 28: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Motors, final

The current in the rotating coil is limited by the back emf The term back emf is commonly used to indicate

an emf that tends to reduce the supplied current The induced emf explains why the power

requirements for starting a motor and for running it are greater for heavy loads than for light ones

Page 29: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Some Terminology

Use emf and current when they are caused by batteries or other sources

Use induced emf and induced current when they are caused by changing magnetic fields

When dealing with problems in electromagnetism, it is important to distinguish between the two situations

Page 30: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Self-Inductance

When the switch is closed, the current does not immediately reach its maximum value

Faraday’s law can be used to describe the effect

Page 31: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Self-Inductance, 2

As the current increases with time, the magnetic flux through the circuit loop due to this current also increases with time

This increasing flux creates an induced emf in the circuit

The direction of the induced emf is opposite the direction of the emf of the battery

Page 32: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Self-Inductance, 3

This effect is called self-inductance Because the changing flux through the circuit and

the resultant induced emf arise from the circuit itself

The emf εL is called a self-induced emf

Page 33: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Self-Inductance, Equations

An induced emf is always proportional to the time rate of change of the current The emf is proportional to the flux, which is proportional to

the field and the field is proportional to the current

L is a constant of proportionality called the inductance of the coil and it depends on the geometry of the coil and other physical characteristics

L

d Iε L

dt

Page 34: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Inductance of a Coil A closely spaced coil of N turns carrying

current I has an inductance of

The inductance is a measure of the opposition to a change in current; The SI unit of inductance is the henry (H)

B LN εL

I d I dt

AsV

1H1

Page 35: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Inductance of a Solenoid

Assume a uniformly wound solenoid having N turns and length ℓ Assume ℓ is much greater than the radius of the

solenoid The flux through each turn of area A is

B o o

NBA μ nI A μ I A

2

oB μ N ANL

I

Page 36: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

RL Circuit, Introduction

A circuit element that has a large self-inductance is called an inductor

The circuit symbol is We assume the self-inductance of the rest of

the circuit is negligible compared to the inductor However, even without a coil, a circuit will have

some self-inductance

Page 37: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Effect of an Inductor in a Circuit

The inductance results in a back emf Therefore, the inductor in a circuit opposes

changes in current in that circuit The inductor attempts to keep the current the

same way it was before the change occurred The inductor can cause the circuit to be “sluggish”

as it reacts to changes in the voltage

Page 38: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

RL Circuit, Analysis

An RL circuit contains an inductor and a resistor

Assume S2 is connected to a

When switch S1 is closed (at time t = 0), the current begins to increase

At the same time, a back emf is induced in the inductor that opposes the original increasing current

Page 39: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

RL Circuit, Analysis, cont.

Applying Kirchhoff’s loop rule to the previous circuit in the clockwise direction gives

Looking at the current, we find

0d I

ε I R Ldt

1 Rt LεI e

R

Page 40: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

RL Circuit, Analysis, Final

The inductor affects the current exponentially The current does not instantly increase to its

final equilibrium value If there is no inductor, the exponential term

goes to zero and the current would instantaneously reach its maximum value as expected

1 Rt LεI e

R

Page 41: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

RL Circuit, Time Constant The expression for the current can also be

expressed in terms of the time constant, , of the circuit

where = L / R

Physically, is the time required for the current to reach 63.2% of its maximum value

1 t τεI e

R

Page 42: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

RL Circuit Without A Battery

Now set S2 to position b The circuit now

contains just the right hand loop

The battery has been eliminated

The expression for the current becomes

t tτ τ

i

εI e I e

R

Page 43: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Energy in a Magnetic Field

In a circuit with an inductor, the battery must supply more energy than in a circuit without an inductor

Part of the energy supplied by the battery appears as internal energy in the resistor

The remaining energy is stored in the magnetic field of the inductor

Page 44: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Energy in a Magnetic Field, cont.

Looking at this energy (in terms of rate)

I is the rate at which energy is being supplied by the battery

I2R is the rate at which the energy is being delivered to the resistor

Therefore, LI (dI/dt) must be the rate at which the energy is being stored in the magnetic field

2 d II ε I R LI

dt

Page 45: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Energy in a Magnetic Field, final

Let U denote the energy stored in the inductor at any time

The rate at which the energy is stored is

To find the total energy, integrate and

dU d ILI

dt dt

2

0

1

2

IU L I d I LI

Page 46: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Energy Density of a Magnetic Field Given U = ½ L I2 and assume (for simplicity) a

solenoid with L = o n2 V

Since V is the volume of the solenoid, the magnetic energy density, uB is

This applies to any region in which a magnetic field exists (not just the solenoid)

2 221

2 2oo o

B BU μ n V V

μ n μ

2

2Bo

U Bu

V μ

2oB μ N AN

LI

Page 47: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Energy Storage Summary

A resistor, inductor and capacitor all store energy through different mechanisms Charged capacitor

Stores energy as electric potential energy Inductor

When it carries a current, stores energy as magnetic potential energy

Resistor Energy delivered is transformed into internal energy

Page 48: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Mutual Inductance

The magnetic flux through the area enclosed by a circuit often varies with time because of time-varying currents in nearby circuits

This process is known as mutual induction because it depends on the interaction of two circuits

Page 49: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Mutual Inductance, 2

The current in coil 1 sets up a magnetic field

Some of the magnetic field lines pass through coil 2

Coil 1 has a current I1

and N1 turns Coil 2 has N2 turns

Page 50: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Mutual Inductance, 3

The mutual inductance M12 of coil 2 with respect to coil 1 is

Mutual inductance depends on the geometry of both circuits and on their orientation with respect to each other

2 1212

1

NM

I

Page 51: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Induced emf in Mutual Inductance

If current I1 varies with time, the emf induced by coil 1 in coil 2 is

If the current is in coil 2, there is a mutual inductance M21

If current 2 varies with time, the emf induced by coil 2 in coil 1 is

12 12 2 12

d d Iε N M

dt dt

21 21

d Iε M

dt

Page 52: Chapter 30 Lect. 15: Faraday’s Law and Induction HW 5 (problems): 28.5, 28.10, 28.15, 28.27, 28.36, 28.45, 28.50, 28.63, 29.15, 29.36, 29.48, 29.54, 30.14,

Mutual Inductance, Final

In mutual induction, the emf induced in one coil is always proportional to the rate at which the current in the other coil is changing

The mutual inductance in one coil is equal to the mutual inductance in the other coil M12 = M21 = M

The induced emf’s can be expressed as2 1

1 2andd I d I

ε M ε Mdt dt