chapter 5 linkage, recombination, and the mapping of genes on chromosomes
TRANSCRIPT
Chapter 5
Linkage, recombination, and the
mapping of genes on chromosomes
Fig. 5.1
linkage
recombination
wY+
W+y
wY+
W+y
wY+
wY+
wY+
W+y
W+Y+wy
When genes are linked, parental
combinations outnumber
recombination types.
W+Y+
wy
W+Y+
W+Y+
wy
W+Y+
Two parental types
Two recombination types
W+Y+
wy
W+Y+
W+Y+
wy
W+Y+
Fig. 5.5
Autosomal genes can also exhibit linkage
bb: black cc: curved
bc+
bc+
b+c
bc+
b+c
b+c
The Chi square test pinpoints the probability that experimental results are
evident for linkage
Chi test measures the “goodness of fit”:
How often an experimentally observed deviation from the prediction of a particular hypothesis will occur solely by chance.
Fig. 5.6
Assume A and B genes are not linked.
F1
Chi Square – Experiment 1 & 2
2 = (observed – expected)2
number expected
2 = (31 – 25)2 + (19 – 25)2 25 25
= 2.88
2 = (62 – 50)2 + (38 – 50)2 50 50
= 5.76
Experiment 1
Experiment 2
Table 5.1
A and B are not linked A and B are linked
difference is significantdifference is non-significant
Recombination results when crossing-over during meiosisseparates linked genes
Fig. 5.7
Evidence that recombination results from reciprocal exchangebetween homologous chromosomes
X chromosome
Fig. 5.8
Recombination through the light microscope
(synaptonemal complex)
anaphase
Fig. 5.9
Recombination frequencies are the basis of genetic map
RF: recombination frequency;
1% RF= 1 Centimorgan (cM)=1 map unit (m.u.)
Fig. 5.10
Unlinked genes show a recombination frequency of 50%
ry ry+
tkv tkv+
ry
tkv
ry
tkv+
ry+
tkv
ry+
tkv+
Fig. 5.10
Unlinked genes show a recombination frequency of 50%
Locus: chromosomal position of a gene
Mapping: the process of determining that locus
Fig. 5.11
Mapping genes by comparison of two-point crosses
The limitation of two-point cross
1. Gene order is difficult to determine if they are very close.
2. Actually distance do not always add up.
Fig. 5.12
Vestigial wingsBlack bodyPurple eye color
Vg to b: (252+ 241+131+118)/4197=0.177, 17.7%Vg to pr:(252+241+13+9)/4197=0.123, 12.3%B to pr:(131+118+13+9)/4197=0.064, 6.4%
Fig. 5.13
Three point-crosses allow correction for double cross-over
Vg to b (three-point cross):(252+241+131+118+13+13+9+9)/4197=0.187, 18.7%
Vg to b (two-point cross): (252+ 241+131+118)/4197=0.177, 17.7%
For greatest accuracy, it is always best to constructa map using many genes separated by relative short
distance.
Mapping genes at X chromosome by two-point cross
Fig. 5.14
RF between Y and W: 49+41+1+2/6823 X100=1.3 m.u.
RF between m and W: 1203+1092+2+1/6823 X100=33.7 m.u
RF between m and y: 1203+1029+49+41+2+2+1+1/6823 X100=35 m.u.
y w m
The actual physical distance between genes does notalways show a direct correspondence to genetic map
distance
1. Recombination is not uniform over the length of a single chromosome,
Hot spot.
• The existence of double, triple, or even more cross-overs.
Rates of recombination differ from species to species
In human, 1 m.u. is = 1 million baseIn yeast, 1 m.u. is 1500 base pairs
In Drosophila, meiotic recombination only occurs in female.
Fig. 5.15
Linkage groups:
Fig. 5.16a
The life cycle of the yeast Saccharomyces cerevisiae
stress
Fig. 5.16b
The life cycle of the bread mold Neurospora crassa
Bread mold
Fig. 5.17ab
How meiosis can generate three kinds of tetrads
Fig. 5.17cde
When PD=NPD, two genes are unlinked
Four types of gametes when genes on different chromosome
H
HHtt hhTT
Ht hT
H
h
h
T
T
t
t
(h)
(H)
Fig. 5.18
When genes are linked, PDs exceed NPDs
Fig. 5.19abc
How crossovers between linked genesgenerate different tetrads
Fig. 5.19def
Rare!
How to calculate the recombination frequency between
two linked genes in the tetrad analyses?
RF=(NPD+1/2 T)/total tetrads x100
RF= 3+(1/2)(70)/200 x100=19 m.u. (tetrads) = (4X3)+ (2X70)/800 x100=19 m.u. (spores)
Fig. 5.20
Tetrad analyses confirms that recombination occurs at the four-strand stage
(A mistake model!) (a lot)
Fig. 5.22
How ordered tetrads form
Arrangement of the four chromatids of each homologous chromosome pair
Fig. 5.23
(Cross-over between gene and centromere)
Ordered Tetrads help locate genes in relation to the centromere
Fig. 5.24
Genetic mapping by ordered-tetrad analysis
Thr-centromere: (1/2) (16+2+2+1)/105 x100=10 m.u.
Arg-centromere:(1/2) (11+2+2+1)/105 x100=7.6 m.u.
Thr-Arg linkage: 3+(1/2)(16+11+2)/105 X100=16.7
PD PDT T T NPD NPDDouble
cross-over
NPD Tetrad
Double cross-over
Double cross-over
Double cross-over
Fig. 5.25
Mitotic recombinationWild-type tissue: y sn+/Y+ sn: wild-type color and bristle
y sn+/y sn+ Y+ sn /Y+ sny sn+/y sn+
Y+ sn /Y+ sn
Fig. 5.26
Fig. 5.27
Mitotic recombination during growth of diploid yeastcolonies can create sectors
ADE2/ade2
ade2/ade2
Recombinatioinbetweem ade2and centromere
AA
aa
A
Aa
aMitotic recombination
Fig. 5.28
Fig. 5a.p131
Fig. 5a.p143
Fig. 5.21
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