chapter 5.3. give an algebraic expression that represents the sequence of numbers. let n be the...

19
Chapter 5.3

Upload: austen-bates

Post on 19-Jan-2016

216 views

Category:

Documents


2 download

TRANSCRIPT

Page 1: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

Chapter 5.3

Page 2: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …).

2, 4, 6, …

1, 3, 5, …

7, 10, 13, 16, …

9, 14, 19, 24, …

…45,135,225,315,…

…60,120,240,300,…

Page 3: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

5.3 Solving Trigonometric Equations

In this chapter you will be learning how to solve trigonometric equations

To solve a trigonometric equation, your goal is to isolate the trigonometric function involved in the equation.

In other words, get the trigonometric function to one side by itself. Use standard algebra such as collecting like terms and factoring to do this.

Page 4: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

5.3 Solving Trigonometric Equations01sin2 xFor Example:1sin2 x

2

1sin x

To solve for x, note that the equation has the solutions and

in the interval . Remember that since has a period of , there are infinitely many other solutions that can be written as:

and

2

1sin x

6

x

6

5x )2,0[ xsin

2nx

26

nx 2

6

5 General solution

Original equation

Add 1 to each side

Divide each side by 2

Page 5: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

5.3 Solving Trigonometric Equations

The equation has infinitely many solutions. Any

angles that are coterminal with are also solutions

to the equation.

2

1sin x

6

5

6

or

sin 1

2

Page 6: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

5.3 Solving Trigonometric EquationsCollecting like terms

Find all of the solutions of in the intervalxx sin2sin

)2,0[

xx sin2sin

2sinsin xx

2sin2 x

2

2sin x

The solutions in the interval are

and

)2,0[

4

5x

4

7x

Page 7: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

5.3 Solving Trigonometric EquationsTry #17 pg.3641

Find all of the solutions of the equation in the interval

algebraically.

)2,0[

03tan x

Page 8: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

5.3 Solving Trigonometric EquationsExtracting Square Roots

Solve:

1tan3 2 x

3

1tan2 x

3

1tan x

01tan3 2 x Add 1 to each side

Divide each side by 3

Take the square root of both sides

Tan x has a period of so first find all of the solution in the

interval [0, ). These are and .Add multiples of

to get the general form and

6

x

6

5x

nx

6

5nx

6

Page 9: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

5.3 Solving Trigonometric EquationsTry #19 pg.3642

Find all of the solutions of the equation in the interval

algebraically.

)2,0[

02csc2 x

Page 10: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

5.3 Solving Trigonometric EquationsFactoring

Solve: xxx cot2coscot 2 0cot2coscot 2 xxx0)2(coscot 2 xx

0cot x 02cos2 x2cos2 x2cos x

Set each factor equal to 0

The equation cot x=0 has the solution in the interval (0, ). No solution is obtained for because are outside the range of the cosine function. Because cot x has a period of the general form of the solution is obtained by adding multiples of to

get where n is an integer.

2

x

2cos x 2

nx

2

Page 11: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

5.3 Solving Trigonometric EquationsTry #21 pg.3643

Find all of the solutions of the equation in the interval

algebraically.

)2,0[ xx tantan3 3

Page 12: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

Find all solutions of in the interval 2 1 02sin sin [ , )0 2

Page 13: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

Now attempt #28 on p.364

Page 14: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

Find all solutions of in the interval cos sin 1 [ , )0 2

Page 15: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

Now attempt #26 on p. 364

Page 16: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

Solve 2 3 1 0cos x

Page 17: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

Now attempt #39 on p.365

Page 18: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

Solve 323 0tan

x

Page 19: Chapter 5.3. Give an algebraic expression that represents the sequence of numbers. Let n be the natural numbers (1, 2, 3, …). 2, 4, 6, … 1, 3, 5, … 7,

Now attempt #45 on p.365