chapter 8 conservation of linear momentum linear momentum; momentum conservation impulse total...
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Chapter 8Conservation of Linear Momentum
Linear momentum;Momentum conservation
ImpulseTotal kinetic energy of a system
March 9, 2010
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Conservation of Linear Momentum• Definition of linear momentum,
€
rp
€
rp = mr v Linear momentum is a vector (decompose to x,y,z directions).Units of linear momentum are kg-m/s.
Can write Newton’s second law in terms of momentum:
€
dr p dt
=d(mr v )
dt= m
dr v dt
= mr a
€
⇒ dr p dt
=r F net
Momentum force, as if Kinetic energy work
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Momentum of a system of particles
• The total momentum of a system of particles is the vector sum of the momenta of the individual particles:
From Newton’s second law, we obtain
Psys
u ruu= mi
rvi
i∑ =
rpi
i∑
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Conservation of Momentum
• Law of conservation of momentum:– If the sum of the external forces on a system is
zero, the total momentum of the system does not change.
If then
Momentum is always conserved when no net “external” force.(even if “internal” forces are non-conservative).
rFext
i∑ =0
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Collisions
“before”m1 m2
“after”m1
m2
momentum before collision = momentum after collision
Always -
But only if
€
rF external = 0
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Explosion - I“before”M
“after”m1
m2v1
v2
Example: m1 = M/3 m2 = 2M/3
After explosion, which block has larger momentum? (left, right, same)
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“before”M
“after”m1
m2v1
v2
Example: m1 = M/3 m2 = 2M/3
After explosion, which block has larger momentum? (left, right, same)
Each has the same momentum
Explosion - I
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“before”M
“after”m1
m2v1
v2
Example: m1 = M/3 m2 = 2M/3
After explosion, which block has larger momentum? (left, right, same)
Each has the same momentum
Which block has larger speed?
Explosion - I
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“before”M
“after”m1
m2v1
v2
Example: m1 = M/3 m2 = 2M/3
After explosion, which block has larger momentum? (left, right, same)
Each has the same momentum
Which block has larger speed?
mv is the same for each block, so smaller mass has larger speed.
Explosion - I
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“before”M
“after”m1
m2v1
v2
Example: m1 = M/3 m2 = 2M/3
After explosion, which block has larger momentum? (left, right, same)
Each has the same momentum
Which block has larger speed?
mv is the same for each block, so smaller mass has larger speed.
Is kinetic energy conserved?
Explosion - I
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Explosion - I“before”M
“after”m1
m2v1
v2
Example: m1 = M/3 m2 = 2M/3
After explosion, which block has larger momentum? (left, right, same)
Each has the same momentum
Which block has larger speed?
mv is the same for each block, so smaller mass has larger speed.
Is kinetic energy conserved? NO! K was 0 before, it is greater after the explosion.
(internal non-conservative force does some work.)
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Momentum and Impulse Momentum
rFaveΔt≡I definition of impulserF =m
ra =m
drv
dt=
drp
dt⇒ Δ
rp=
rFΔt
rp ≡m
rv
For single object…. If F = 0, then momentum conserved (p = 0)
rpsys =
rpi
i∑
Internal forces ≡ forces between objects in system
External forces ≡ any other forces
Δrpsys =
rFextΔt
Thus, if rFext =0, then Δ
rpsys =0
i.e. total momentum is conserved!
• For “system” of objects …
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Elastic Collision in 1-Dimension
m1v1i + m2v2i =m1v1 f + m2v2 f
12
m1v1i2 +
12
m2v2i2 =
12
m1v1 f2 +
12
m2v2 f2
Linear momentum is conserved
Energy conserved (for elastic collision only)
Initial Final
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Elastic CollisionConservation of Momentum
m1v1i + m2v2i =m1v1 f + m2v2 f
m1(v1i −v1 f ) =m2 (v2 f −v2i )
Conservation of Kinetic Energy
12
m1v1i2 +
12
m2v2i2 =
12
m1v1 f2 +
12
m2v2 f2
m1(v1i2 −v1 f
2 ) =m2 (v2 f2 −v2i
2 )
m1(v1i −v1 f )(v1i + v1 f ) =m2 (v2 f −v2i )(v2 f + v2i )
Combining the above two equations
v1i + v1 f =v2i + v2 f
v1i −v2i =−(v1 f −v2 f )
Magnitude of relative velocity is conserved.
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Is this an elastic collision?
v1i −v2i =−(v1 f −v2 f )For elastic collision only:
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Is this an elastic collision?
v1i −v2i =−(v1 f −v2 f )Yes, the relative speeds are approximately the samebefore and after collision
For elastic collision only:
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What is the speed of the golf ball, in case of an elastic collision Club speed: 50 m/sMass of clubhead: 0.5kgMass of golfball: 0.05kgTwo unknowns: after the impact,
speed of club and speed of golfball
Problem solving strategy: - Momentum conservation- Energy conservation (oruse the derived equationfor relative velocities)
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v1 f =m1 −m2
m1 + m2
v1i
v2 f =2m1
m1 + m2
v1i
Result:
Special cases:1) Golf shot: m1>>m2
Club speed almost unchangedBall speed almost 2 x club speed
2) Neutron scatters on heavy nucleus: m1<<m2neutron scatters back with almost same speedspeed of nucleus almost unchanged
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Some Terminology
• Elastic Collisions:
collisions that conserve kinetic energy
• Inelastic Collisions:
collisions that do not conserve kinetic energy
* Completely Inelastic Collisons:
objects stick together
n.b. ALL CONSERVE MOMENTUM!!
If external forces = 0
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Kinetic energy of a system of particles:
Where
in terms of the CM velocity and relative velocity to the CM.