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3 Conics The definition of a circle is the collection of all points (x, y) that are equidistant from a fixed point (h, k) leads to the standard equation of a circle (x – h) 2 + (y – k) 2 = r 2. Equation of circleTRANSCRIPT
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Copyright © Cengage Learning. All rights reserved.
Pre-Calculus Honors9.1: Circles and Parabolas
HW: p.643 (8-24 even, 28, 30, 36, 42)
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Conics
A conic section (or simply conic)is the intersection of a plane anda double-napped cone.
Notice in Figure 9.1 that in theformation of the four basic conics,the intersecting plane does notpass through the vertex of the cone.
Figure 9.1
Basic Conics
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ConicsThe definition of a circle is the collection of all points (x, y) that are equidistant from a fixed point (h, k) leads to the standard equation of a circle
(x – h)2 + (y – k)2 = r2. Equation of circle
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Example 1 – Finding the Standard Equation of a Circle
The point (1, 4) is on a circle whose center is at (–2, –3), as shown in Figure 9.4. Write the standard form of the equation of the circle.
Figure 9.4
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Example 2 – Sketching a CircleSketch the circle given by the equation
x2 – 6x + y2 – 2y + 6 = 0and identify its center and radius.Solution:Begin by writing the equation in standard form.
x2 – 6x + y2 – 2y + 6 = 0
(x2 – 6x + __) + (y2 – 2y + __) = –6 + __ + __ Complete the squares
In this form, you can identify the center and radius of the circle and then sketch the graph.
Write in standard form
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Example 2 – SolutionNow graph the function.
cont’d
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Practice with circles.1. Write the equation of a circle in standard form with
center = (3, 7) and point on the circle = (1, 0).2. Write the equation of a circle in standard form with
center = (-3, -1) and diameter = Identify the center and radius of the circle, then graph. 3. (x – 3)2 + y2 = 84. x2 – 14x + y2 + 8y + 40 = 0
cont’d
72
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Do NowGraph 9x2 + 9y2 + 54x – 36y + 17 = 0
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9Copyright © Cengage Learning. All rights reserved.
Pre-Calculus Honors9.1: Circles and Parabolas
HW: p.644 (70 and 76: write in standard form), (62, 66, 68, 78: graph labeling the vertex and 2
additional points, determine domain and range).
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Parabolas
Vertex: (h, k); there are other characteristics of a parabola we are not going to find and sketch in the graph (directrix and focus).
opens up or down b/c x is squared
opens right or left b/c y is squared
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ParabolasRewrite the parabola in standard form:
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ParabolasSolution: Convert to standard form by completing the square.
–2y = x2 + 2x – 1
1 – 2y = x2 + 2x
Create a coefficient of 1 for x2
Isolate the x2 and bx term
__ + 1 – 2y = x2 + 2x + __
2 – 2y = x2 + 2x + 1
–2(y – 1) = (x + 1)2
Complete the square
Combine like terms
Factor to write in standard form
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Graph the parabola.Graph the parabola. Label the vertex and 2 additional points on the parabola. Determine the domain and range.1. y2 = 3x
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Graph the parabola.Graph the parabola. Label the vertex and 2 additional points on the parabola. Determine the domain and range.2. (x + ½)2 = 4(y – 1)
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Graph the parabola.Graph the parabola. Label the vertex and 2 additional points on the parabola. Determine the domain and range.3. y2 + x + y = 0
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Graph the parabola.Graph the parabola. Label the vertex and 2 additional points on the parabola. Determine the domain and range.4. 3x2 + 6x + y = 4