d inteles
TRANSCRIPT
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ANALISIS DE DINTEL
SIN TENSORAUTOR: JAVIER RAMOS
oyecto:
BD - ES fecha: May-13
B
s
A C
a. Kleinlogel caso 15/3
flecha = 200.00 cm
claro = 900.00 cm
E dintel = 2100000 kg/cm^2
Inercia dintel = 130 cm^
carga !niforme = "2.#0 kg/cm$Area de tensor = 0 cm^2
s = 92. cm s i%& = s der
'a = 'c = "11(0.00 kg )eacciones *ert en los a+o,os
-a =-c = "1#.31 kg ) hori%ontales
= #12.0 kg"cm omento en el +arteag!as
+/mto. a. = 1#.( cm
= "3(019.31 kg"cm
claro/2 = 0 cm
segmentos20 long. 4egmento = 22. cm
nodo 5 /l &$/2 63/"/l7 Mx(kg-cm)1 0.00 22.0 0 0 0.3( 0.00
2 22.0 2(.0 0.02 "2#32 0.30 "9213.(
3 .00 0.00 0.0 "2#0 0.32 "1(111.2
#(.0 32.0 0.0( "(9( 0.300 "23#92.0
90.00 3#0.00 0.1 "10300 0.2( "29(.0
# 112.0 33(.0 0.12 "131#2 0.20 "3290#.2
( 13.00 31.00 0.1 "1(90 0.22 "33.(
1(.0 292.0 0.1( "12( 0.200 "3#.00
9 10.00 2(0.00 0.2 "210#00 0.1( "3#.00
10 202.0 2(.0 0.22 "23#92 0.10 "33.(
11 22.00 22.00 0.2 "2#320 0.12 "3290#.2 M max.
12 2(.0 202.0 0.2( "29( 0.100 "29(.0 kg"cm13 2(0.00 10.00 0.3 "31900 0.0( "23#92.0 #13
1 292.0 1(.0 0.32 "3222 0.00 "1(111.2
1 31.00 13.00 0.3 "3#0 0.02 "9213.(
1# 33(.0 112.0 0.3( "39( 0.000 0.00
1( 3#0.00 90.00 0. "21200 "0.02 1030.00
1 32.0 #(.0 0.2 "(2 "0.00 223(#.2
19 0.00 .00 0. "(30 "0.0( 33.(
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20 2(.0 22.0 0.( "001( "0.100 001(.0
21 0.00 0.00 0. "2#00 "0.12 #12.0
-60000.00
-40000.00
-20000.00
0.00
20000.00
40000.00
60000.00
80000.00Diagrama de mtos.
dist X
Momen
tos
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ANALISIS DE DINTELCON TENSOR
oyecto:
BD - ES fecha: Feb-12
AUTOR: JAVIER RA
B
s
8%
A C
flecha = 200.00 cm Constantes:
claro = 900.00 cm $ = 0.03#22031
E dintel = 2100000 kg/cm^2 % = 2.03#22031
Etensor = 2100000 kg/cm^2 ) = "1(#2
Inercia dintel = 130 cm^ 4igma = "3120carga !niforme = "2.#0 kg/cm$ 4 = "120.3
Area de tensor = .0( cm^2
s = 92. cm
claro /2 = 0 cm
: = "193.2# kg 8%a en el tensor
'a = 'c = "120.3 kg )eacciones en los a+o,os
= (101 kg"cm omento en el +arteag!as
= 3(9 kg"cm
claro/2 = 0 cm
segmentos = 20 long. 4egmento = 22. cm
noo ! !" !/l #!$ #!%&g-'(1 0 0 0 0 0.00
2 22. 2(. 0.02 "120.3( "91.30
3 0 0.0 "23#92. "1#12.3#
#(. 32. 0.0( "33#.3( "22(9.1#
90 3#0 0.1 "2120 "2((9.(1
# 112. 33(. 0.12 "939.3( "3109.01
( 13 31 0.1 "22. "33(2.0(
1(. 292. 0.1( "99.3( "3(.(
9 10 2(0 0.2 "#310 "39.2 M max.
10 202. 2(. 0.22 "#1.3( "323.(3 kg"cm
11 22 22 0.2 "#12. "29911.( (101
12 2(. 202. 0.2( "#1.3( "2##3.
13 2(0 10 0.3 "#310 "20099.13
1 292. 1(. 0.32 "99.3( "1321.
1 31 13 0.3 "22. "021.9
1# 33(. 112. 0.3( "939.3( 91.(1
1( 3#0 90 0. "2120 1321.1#
1 32. #(. 0.2 "33#.3( 2(##.
19 0 0. "23#92. 092.0
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20 2(. 22. 0.( "120.3( (0(.00
21 0 0 0. 0 (101.
0 2
2.
5
4
5
6
7.
5
9
0
1
1
2.
5
1
3
5
1
5
7.
5
1
8
0
2
0
2.
5
2
2
5
2
4
7.
5
2
7
0
2
9
2.
5
3
1
5
3
3
7.
5
3
6
0
3
8
2.
5
4
0
5
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2
7.
5
4
5
0
-60000.00
-40000.00
-20000.00
0.00
20000.00
40000.00
60000.00
80000.00Diagrama de mtos.
dist X
mo
mentos
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ANALISIS DE DINTELCON TENSOR ) CO#*RESOR
AUTOR: JAVIER RAMOS
oyecto:
BD - ES Fecha: Feb-12+ni,o'e aitacional
Caga:
C
s2
s1 ; E
a
A B
ref. )igid frame form!las< caso 1(/ 1
or> A. ?leinlogel
factores de carga
flecha = 10.00 cm 33(00.00claro = 100.00 cm 9#9.
E dintel = 2100000 kg/cm^2 33(00.00
Etensor = 2100000 kg/cm^2 9#9.
Inercia dintel = 3#9 cm^ #(000.0
carga !niforme = .0 kg/cm$ 1939(.10
Area de tensor = .0( cm^2 istancias %c'(
s1 = 00 cm 0oi. ) et. e s1 2 s
s2 = 2#. cm 4o. s1 67$.7
long *iga = s1s2 = (#. cm 4o. s 57.81
0.19(399 radianes et. s1 79.$11.31 grados et. s 51.76
@ en s1 = 2(00.00 kg
@ en s2 = 130.21 kg s i%& = s der
Constantes:
k = 1.9
8 = 10.
= 129(
Resultados:
c = 1(23.3 kg"cm en +arteag!as
d = e = "129(.1 kg"cm
-a = - = 13(. kg 8%a en tensor 6o en a+o,os sin desli%am. -r%.7
-c = 11.0# kg
'a = 'c = 130.21 kg ) *ert en a+o,os
- en d"e = 1#.(9 kg f%a en com+resor
8 aial en 41 = 1#9.#2 kg
8 aial en 42 = (9.31 kg
)1=)=
$1 =
$=
sL1=
sL=
a=
a=