derivation of kinematic equations

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Derivation of Kinematic Equations View this after Motion on an Incline Lab

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Derivation of Kinematic Equations. View this after Motion on an Incline Lab. Constant velocity. Average velocity equals the slope of a position vs time graph when an object travels at constant velocity. Displacement when object moves with constant velocity. - PowerPoint PPT Presentation

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Page 1: Derivation of Kinematic Equations

Derivation of Kinematic Equations

View this after Motion on an Incline Lab

Page 2: Derivation of Kinematic Equations

Constant velocity

Average velocity equals the slope of a position vs time graph when an object travels at constant velocity.

v xt

Page 3: Derivation of Kinematic Equations

Displacement when object moves with constant velocity

The displacement is the area under a velocity vs time graph

v

t

x

x v t

Page 4: Derivation of Kinematic Equations

Uniform accelerationThis is the equation of the line of the velocity vs time graph when an object is undergoing uniform acceleration.

The slope is the acceleration

The intercept is the initial velocity

v f at v 0v

t

v0

v

t

Page 5: Derivation of Kinematic Equations

Displacement when object accelerates from rest

Displacement is still the area under the velocity vs time graph. However, velocity is constantly changing.

v

t

Page 6: Derivation of Kinematic Equations

Displacement when object accelerates from rest

Displacement is still the area under the velocity vs time graph. Use the formula for the area of a triangle.

x 12vt

v

t

v

Page 7: Derivation of Kinematic Equations

Displacement when object accelerates from rest

From slope of v-t graphRearrange to get

Now, substitute for ∆v

a vt

v a t

x 12a t t

v

t

v

Page 8: Derivation of Kinematic Equations

Displacement when object accelerates from rest

Simplify

Assuming uniform acceleration and a starting time = 0, the equation can be written:

v

t

v

x 12a (t)2

x 12

at 2

Page 9: Derivation of Kinematic Equations

Displacement when object accelerates with initial velocityBreak the area up into two parts:

the rectangle representingdisplacement due to initial velocity

v

t

v0

x v 0t

Page 10: Derivation of Kinematic Equations

Displacement when object accelerates with initial velocityBreak the area up into two parts:

and the triangle representingdisplacement due to acceleration

x 12a(t)2

v

t

v0

v

Page 11: Derivation of Kinematic Equations

Displacement when object accelerates with initial velocitySum the two areas:

Or, if starting time = 0, the equation can be written:

x v 0t 12

a(t )2

x v0t 12at 2

v

t

v0

v

Page 12: Derivation of Kinematic Equations

Time-independent relationship between ∆x, v and a

Sometimes you are asked to find the final velocity or displacement when the length of time is not given.To derive this equation, we must start with the definition of average velocity:

v xt

Page 13: Derivation of Kinematic Equations

Time-independent relationship between ∆x, v and a

Another way to express average velocity is:

v xt

v v f v 0

2

Page 14: Derivation of Kinematic Equations

Time-independent relationship between ∆x, v and a

We have defined acceleration as:

This can be rearranged to:

and then expanded to yield :

a vt

t va

t vf v0

a

Page 15: Derivation of Kinematic Equations

Time-independent relationship between ∆x, v and a

Now, take the equation for displacement

and make substitutions for average velocity and ∆t

x v t

Page 16: Derivation of Kinematic Equations

Time-independent relationship between ∆x, v and a

x v t

v v f v 0

2

t vf v0

a

Page 17: Derivation of Kinematic Equations

Time-independent relationship between ∆x, v and a

x v t

x vf v0

2vf v0

a

Page 18: Derivation of Kinematic Equations

Time-independent relationship between ∆x, v and a

Simplify

x vf v0

2vf v0

a

x vf

2 v02

2a

Page 19: Derivation of Kinematic Equations

Time-independent relationship between ∆x, v and a

Rearrange

x vf

2 v02

2a

2a x v f2 v 0

2

Page 20: Derivation of Kinematic Equations

Time-independent relationship between ∆x, v and a

Rearrange again to obtain the more common form:

2a x v f2 v 0

2

vf2 v0

2 2a x

Page 21: Derivation of Kinematic Equations

Which equation do I use?• First, decide what model is appropriate

– Is the object moving at constant velocity? – Or, is it accelerating uniformly?

• Next, decide whether it’s easier to use an algebraic or a graphical representation.

Page 22: Derivation of Kinematic Equations

Constant velocity

If you are looking for the velocity,– use the algebraic form

– or find the slope of the graph (actually the same thing)

v xt

Page 23: Derivation of Kinematic Equations

Constant velocity• If you are looking for the displacement,

– use the algebraic form

– or find the area under the curve

x v t

v

t

x

Page 24: Derivation of Kinematic Equations

Uniform acceleration• If you want to find the final velocity,

– use the algebraic form

• If you are looking for the acceleration– rearrange the equation above

– which is the same as finding the slope of a velocity-time graph

vf at v0

a vt

Page 25: Derivation of Kinematic Equations

Uniform acceleration

If you want to find the displacement,– use the algebraic form– eliminate initial velocity if the object

starts from rest

– Or, find the area under the curve

x v0t 12at 2

v

t

v0

v

Page 26: Derivation of Kinematic Equations

If you don’t know the time…

You can solve for ∆t using one of the earlier equations, and then solve for the desired quantity, orYou can use the equation

– rearranging it to suit your needs

vf2 v0

2 2a x

Page 27: Derivation of Kinematic Equations

All the equations in one place

constant velocity uniform acceleration

vf2 v0

2 2ax

x v0t 12at 2

a vt

v f at v 0

v xt

x v t