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4.1 Exponential Functions
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Objectives
► Exponential Functions
► Graphs of Exponential Functions
► Compound Interest
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Exponential FunctionsHere, we study a new class of functions called exponential functions. For example,
f(x) = 2x
is an exponential function (with base 2).
Notice how quickly the values of this function increase:
f(3) = 23 = 8
f(10) = 210 = 1024
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Exponential Functionsf(30) = 230 = 1,073,741,824
Compare this with the function g(x) = x2, where
g(30) = 302 = 900.
The point is that when the variable is in the exponent, even a small change in the variable can cause a dramatic change in the value of the function.
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Exponential FunctionsTo study exponential functions, we must first define what we mean by the exponential expression ax when x is any real number.
We defined ax for a > 0 and x a rational number, but we have not yet defined irrational powers.
So what is meant by or 2 ?
To define ax when x is irrational, we approximate x by rational numbers.
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Exponential FunctionsFor example, since
1.73205. . .
is an irrational number, we successively approximate by the following rational powers:
a1.7, a1.73, a1.732, a1.7320, a1.73205, . . .
Intuitively, we can see that these rational powers of a are getting closer and closer to .
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Exponential FunctionsIt can be shown by using advanced mathematics that there is exactly one number that these powers approach. We define to be this number.
For example, using a calculator, we find
51.732
16.2411. . .
The more decimal places of we use in our calculation, the better our approximation of .
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Exponential FunctionsIt can be proved that the Laws of Exponents are still true when the exponents are real numbers.
We assume that a 1 because the function f(x) = 1x = 1is just a constant function.
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Exponential FunctionsHere are some examples of exponential functions:
f(x) = 2x g(x) = 3x h(x) = 10x
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Example 1 – Evaluating Exponential Functions
Let f(x) = 3x, and evaluate the following:
(a) f(2) (b) f
(c) f() (d) f( )
Solution:We use a calculator to obtain the values of f.
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Example 1 – Solution cont’d
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Graphs of Exponential Functions
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Graphs of Exponential FunctionsWe first graph exponential functions by plotting points.
We will see that the graphs of such functions have an easily recognizable shape.
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Example 2 – Graphing Exponential Functions by Plotting Points
Draw the graph of each function.
(a) f(x) = 3x
(b) g(x) =
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Example 2 – SolutionWe calculate values of f(x) and g(x) and plot points to sketch the graphs in Figure 1.
Figure 1
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Example 2 – SolutionNotice that
so we could have obtained the graph of g from the graph of f by reflecting in the y-axis.
cont’d
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Graphs of Exponential FunctionsFigure 2 shows the graphs of the family of exponential functions f(x) = ax for various values of the base a.
Figure 2A family of exponential functions
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Graphs of Exponential FunctionsAll of these graphs pass through the point (0, 1) because a0 = 1 for a 0.
You can see from Figure 2 that there are two kinds of exponential functions:
If 0 < a < 1, the exponential function decreases rapidly.
If a > 1, the function increases rapidly.
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Graphs of Exponential FunctionsThe x-axis is a horizontal asymptote for the exponential function f(x) = ax.
This is because when a > 1, we have ax 0 as x , and when 0 < a < 1, we have ax 0 as x (see Figure 2).
Figure 2A family of exponential functions
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Graphs of Exponential FunctionsAlso, ax > 0 for all x , so the function f(x) = ax has domain and range (0, ).
These observations are summarized in the following box.
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Example 3 – Identifying Graphs of Exponential Functions
Find the exponential function f(x) = ax whose graph is given.
(a) (b)
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Example 3 – Solution(a) Since f(2) = a2 = 25, we see that the base is a = 5.
So f(x) = 5x.
(b) Since f(3) = a3 = , we see that the base is a = . So f(x) = .
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Example 5 – Comparing Exponential and Power Functions
Compare the rates of growth of the exponential function f(x) = 2x and the power function g(x) = x2 by drawing thegraphs of both functions in the following viewing rectangles.
(a) [0, 3] by [0, 8]
(b) [0, 6] by [0, 25]
(c) [0, 20] by [0, 1000]
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Example 5 – Solution(a) Figure 4(a) shows that the graph of g(x) = x2 catches up
with, and becomes higher than, the graph of f(x) = 2x atx = 2.
Figure 4(a)
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Example 5 – Solution(b) The larger viewing rectangle in Figure 4(b) shows that
the graph of f(x) = 2x overtakes that of g(x) = x2 when x = 4.
cont’d
Figure 4(b)
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Example 5 – Solution(c) Figure 4(c) gives a more global view and shows that
when x is large, f(x) = 2x is much larger than g(x) = x2.
cont’d
Figure 4(c)
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Compound Interest
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Compound InterestExponential functions occur in calculating compound interest. If an amount of money P, called the principal, is invested at an interest rate i per time period (called effective rate of interest), then after one time period the interest is Pi, and the amount A of money is
A = P + Pi = P(1 + i)
If the interest is reinvested, then the new principal isP(1 + i), and the amount after another time period is
A = P(1 + i)(1 + i) = P(1 + i)2.
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Compound InterestSimilarly, after a third time period the amount is
A = P(1 + i)3
In general, after k periods the amount is
A = P(1 + i)k
Notice that this is an exponential function with base 1 + i.
If the annual interest rate is r and if interest is compounded n times per year (r is called nominal interest rate), then in each time period the interest rate is i = r/n, and there are nt time periods in t years.
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Compound InterestThis leads to the following formula for the amount after t years.
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Example 6 – Calculating Compound Interest
A sum of $1000 is invested at an interest rate of 12% per year. Find the amounts in the account after 3 years if interest is compounded annually, semiannually, quarterly, monthly, and daily.
Solution:We use the compound interest formula withP = $1000, r = 0.12, and t = 3.
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Compound InterestIf an investment earns compound interest, then the annual percentage yield (APY) is the simple interest rate that yields the same amount at the end of one year.
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Example 7 – Calculating the Annual Percentage Yield
Find the annual percentage yield for an investment that earns interest at a rate of 6% per year, compounded daily.
Solution:After one year, a principal P will grow to the amount
A = P
= P(1.06183)
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Example 7 – SolutionThe formula for simple interest is
A = P(1 + r)
Comparing, we see that 1 + r = 1.06183, so r = 0.06183.
Thus, the annual percentage yield is 6.183%.
cont’d