Download - FIR Project
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MC LC
Phn Trang
Li m u ...................................................................................................................... 2
Li cm n ........................................................................................................................ 3
I. Yu cu b lc v l thuyt tng qut ........................................................................ 4
1. Yu cu v b lc FIR ......................................................................................... 4
2. L thuyt b lc FIR ............................................................................................ 4
II. M phng MATLAB v vit chng trnh CCS ..................................................... 10
1. M phng Matlab bi ton b lc FIR ............................................................... 10
2. Yu cu phn mm v phn cng ...................................................................... 14
3. Vit chng trnh trn CCS 6.1 ......................................................................... 16
III. Kt qu ....................................................................................................................... 23
IV. Ti liu tham kho .................................................................................................... 24
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LI M U
X l tn hiu s (Digital Signal Processing DSP) tr thnh mn hc c s cho nhiu
ngnh khoa hc, k thut: in- in t, Vin thng,Trong , php x l c bn nht
ca DSP l lc, v cc h thng c cp n nhiu nht trong x l tn hiu s l cc
b lc s (Digital Filter). Nu xt v p ng xung c th chia cc b lc s thnh 2 loi
chnh l b lc c p ng xung hu hn FIR (Finite Impulse Response) cn gi l lc
khng quy, v b lc c p ng cung v hn IIR (Infinite Impulse Response) cn gi
l lc quy. Xt v p ng tn s bin c th chia cc b lc, FIR hay IIR, thnh 4
loi c bn: thng thp, thng cao, thng di v chn di. Cc b lc ny c th c thit
k bng nhng phng php sau y: phng php ca s ( Window Design Techniques),
phng php ly mu tn s (Frequency Sampling Design Techniques) v phng php
xp x ti u cn bng gn sng (Optimal Equiripple Design Techniques).
Trong bo co bi tp ln ny, nhm xin php c trnh by vic thit k b lc thng
thp FIR bc 3 thc hin trn phn cng TMS320C5515 ca Texas Instrument (TI)
nm vng l thuyt v b lc FIR cng nh lm quen vi KIT TMS320C5515 v cc phn
mm h tr Code Composer Studio (CCS), MATLAB
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LI CM N
Trn thc t khng c s thnh cng no m khng gn lin vi nhng s h tr, gip
t hay nhiu, d trc tip hay gin tip ca ngi khc. Trong sut thi gian thc hin bo
co ny, nhm em nhn c s quan tm, gip ca qu Thy c v bn b.
Vi lng bit n su sc nht, nhm xin chn thnh cm n PGS.TS L Tin Thng
hng dn nhm trong vic tip cn n cc vn X l s tn hiu hon thnh bo
co ny.
Project c thc hin trong gn sut hc k 2, bc u gip nhm tm hiu thm v
mt s kin thc cn hn ch v cn nhiu b ng. Do vy, khng trnh khi nhng thiu
st l iu chc chn, nhm rt mong nhn c nhng kin ng gp qu bu ca qu
Thy c v cc bn hc cng lp nhng kin thc ca nhm trong lnh vc ny c
hon thin hn.
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I. Yu cu b lc v l thuyt tng qut
1. Yu cu v b lc FIR
Trong project ny, yu cu thit k b lc thng thp FIR bc 3, c tn s ct =3000.
Thit k trn KIT TMS 320C5515.
2. L thuyt b lc FIR
Cc h thng LTI ri rc c th phn loi thnh h thng FIR ( Finite Impulse Response)
v IRR ( Infinite Impulse Response), l n c p ng xung h(n) hu hn hay v hn.
Trong bi bo co ny, ta ch cp n b lc FIR.
y l dng b lc c p ng xung h(n) c gi tr trn khong thi gian hu hn 0 v bng 0 cc gi tr khc:
= {0, 1, 2, , , 0,0,0, . }
trong M c xem nh l bc ca b lc. Tng ng vi n, chiu di ca vector p
ng xung ca b lc FIR = {0, 1, 2, , } l = + 1.
Cc h s ca p ng xung {0, 1, 2, , } c gi theo nhiu cch khc nhau h s lc ( filter coeficients, filter weights, hay filter taps).
Ta bit y(n) l tch chp (convolution) ca chui u vo x(n) vi chui b lc h(n),
c vit di dng:
() = (0)() + (1)( 1) + (2)( 2)
Hay vit rt gn li l:
() = ()( ) ()
V vy vi b lc FIR, c phng trnh n gin nh sau:
() = ()( )
=0
Hay khai trin ra l:
() = 0() + 1( 1) + + ( )
Nh vy, phng trnh I/O nhn c t tng c trng s ca cc mu u vo hin to v
M mu trc ( 1), ( 2), , ( )
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V mt l thuyt, da trn c im ca p ng tn s, x l tn hiu s quan tm n 4
loi b lc l tng sau y:
a. B lc thng thp l tng
p ng bin - tn s : |()| = {
1, || 0,
Khi p ng xung ca b lc thng thp l tng vi tr nhm l:
() =
sin( )
b. B lc thng cao l tng
p ng bin - tn s : |()| = {
1, || 0,
Khi p ng xung ca b lc thng thp l tng vi tr nhm l:
() = ( )
sin( )
c. B lc thng di l tng
p ng bin - tn s : |()| = {
1, 1 || 20 ,
Khi p ng xung ca b lc thng thp l tng vi tr nhm l:
() = 2
sin2( ) 1
sin1( )
d. B lc chn di l tng
p ng bin - tn s : |()| = {
0, 1 || 21 ,
Khi p ng xung ca b lc thng thp l tng vi tr nhm l:
() = ( ) 2
sin2( ) +1
sin1( )
Chng ta c nhn xt l p ng cung ca cc b lc l tng ni trn c chiu di v hn,
xut pht t ch s n +, v khng nhn qu, dn n khng th thc hin c v mt vt l. Khi tng hp b lc thc t, ta phi chp nhn p ng xung phi xut pt t
ch s 0 p ng iu kin nhn qu. Khi , p ng tn s ca b lc thc t c phn
qu t di thng n di chn, hoc ngc li, v c gi l di chuyn tip (transition
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band). ng thi phi c s gn sng (ripple) c di thng v di chn hoc t nht ti
mt trong hai, di thng hoc di chn.
Vic thit k b lc l qu trnh tm ra cc tham s, hay dy p ng xung ca b lc, tha
mn cc yu cu ch tiu k thut cho trc, c th l mt s hoc tt c cc tham s tuyt
i (absolute specification) sau:
Tn s ct di thng
Tn s ct di chn
gn sng di thng 1
gn sng di chn 2
Trn thc t, cc tham s thng c cho di dng tng i(relative specification) tnh
theo n v decibels di dng sau y:
gn sng di thng theo dB c tnh bng cng thc:
= 20 log1 11 + 1
[]
suy gm di chn theo dB c tnh bng cng thc:
= 20 log2
1 + 1[]
B lc FIR c mt s u im v mt thc hin nh sau:
- p ng pha l tuyn tnh
- Tng i d thit k v lun lun l h thng n nh
- Thc hin c vi hiu qu cao
- C th thc hin c trn c s p dng bin i Fourier ri rc
Hm p ng pha - tn s ca b lc FIR c dng sau:
() = , ,
V hm p ng tn s ca b lc FIR c cho di dng ln v pha nh sau:
() = () , ()
Da trn tnh cht i xng hay phn i xng ca dy p ng xung v chiu di N ca
dy p ng xung, ngi ta phn loi b lc FIR lm 4 loi sau y:
a. B lc FIR loi 1:
h(n) i xng, N l, = 0, = 1
2
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() =
[ ()
12
=0]
12
vi (0) = (1
2) , (
1
2)
() = 2 ( 1
2 ) , 1
1
2
dn n: () = ()1
2=0 , () =
1
2
b. B lc FIR loi 2:
h(n) i xng, N chn, = 0, =
2
() =
[ ()cos (
1
2)
2
=0]
12
vi () = 2 (
2 ) , 1
2
dn n: () = ()cos ( 1
2)
2=0 , () =
1
2
c. B lc FIR loi 3:
h(n) i xng, N l, =
2, =
1
2
() =
[ ()
12
=0] (
2
12 )
vi () = 2 (1
2 ) , 1
1
2
dn n: () = ()1
2=0 , () =
2
1
2
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d. B lc FIR loi 4:
h(n) i xng, N chn, =
2, =
2
() =
[ ()sin(
1
2)
2
=0] (
2
12 )
vi () = 2 (
2 ) , 1
2
dn n: () = ()sin( 1
2)
2=0 , () =
2
1
2
C 3 phng php tng hp b lc FIR pha tuyn tnh, l: Phng php ca s. Phng php ly mu tn s Phng php lp
Trong phn ny ta xt phng php thit k da trn phng php ca s.
T tng c bn ca phng php ca s l tm ra p ng xung ca b lc l tng
risau ct xn hai u ( hay nhn vi mt hm ca s) dy p ng xung sao cho
ta thu c mt b lc FIR pha tuyn tnh, ng thi l nhn qu. im nhn mnh
phng php ny l tm ra p ng xung thch hp ca b lc l tng v la chn hm
ca s thch hp. V mt l tng, b lc thng thp l tng pha tuyn tnh c li di
thng bng 1 v p ng tn s bng 0 trn ton di chn, tc l:
() = {
, || 0 ,
, vi
Th ta s thu c dy p ng xung
() =
sin( )
C tnh cht i xng ti
Vi cc b lc s l tng khc, bao gm thng cao, thng di, v chn di, dy ca p
ng xung cng c dng tng t nh vy v c th suy ra t dng p ng xung ca b lc
thng thp l tng ni trn.
thu c p ng xung ca b loc FIR v mt thc t, phng php ca s dng k
thut nhn hm p ng xung ca b lc l tng () vi mt hm ca s w(n), vi
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w(n) l mt hm i xng vi trong khong t 0 n N-1 v bng 0 trong khong cn
li. Kt qu l hm p ng xung ca b lc thc t h(n) l i xng hoc phn i xng
vi = 1
2 trong khong [0,N-1].
Cc ca s thng dng:
Ca s ch nht Ca s tam gic Ca s Hamming Ca s Hanning Ca s Blackman Ca s Kaiser
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II. M phng MATLAB v lp trnh trn CCS
1. M phng Matlab bi ton b lc FIR
Trc khi thit k b lc FIR da trn yu cu t ra, nhm thc hin thit k b lc FIR
trn Matlab bng cng c fdatool ca n. Sau tin hnh m phng trn Simulink da
vo b lc FIR c thit k vi mt s mu tn hiu.
Tng quan v cng c thit k b lc s FDATool
Cng c thit k b lc s (FDATool) cung cp cho ta nhng k thut in tin thit k,
phn tch, m phng cc b lc s. N cho php nng cao kh nng x l h thng trong
thi gian thc nh vi b lc thch nghi, b lc a nhim v s chuyn i gia chng.
hp cng c h tr thit k b lc FIR gm:
+ Tramg b cho thit k b lc FIR bao gm cc chc nng gim thiu v th t, v gn
song, v pha, v bang k bn, v im n bang, li xp x, song hi v gn song ln
nht ca thit k.
+ Thit k vi b lc FIR gn nh, ti u vi nhng thit k pha phi tuyn v gim thiu
c li.
+ Thit k b lc FIR na bng tn c trang b bao gm: phng php ca s, phng
php hnh vung
Tin hnh thit k b lc FIR vi fdatool
+ G lnh >>fdatool trn command window, hin ra ca s lm vic Filter Design &
Analysis Tool.
+ Trong ca s lm vic, thit k b lc FIR theo yu cu, s dng phng php ca s
(Design/Window)
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Hnh 1. B lc thng thp FIR dng phng php ca s trong Design v Response
Hnh 2. Chn bc b lc trong Filter v s dng ca s hnh ch nht bng cch chn
Rectangular Window trong Options
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Hnh 3. Trong Frequency chn Fc- tn s ct ca b lc FIR v tn s ly mu- Fs
Cui cng, nhn Design Filter hon thnh vic thit k b lc.
Ta thy p ng tn s ca b lc hin th trn ca s Filter
Hnh 4. p ng tn s ca b lc hin th trn ca s Filter
V p ng xung ca FIR c xut ra bng cch chn File/ Export
Trong Command Window s hin ra bng Num cha cc gi tr ca h(n)
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Hnh 5. Cc gi tr ca h(n)
Do vy, ta c () = {0.2406, 0.2594, 0.2594, 0.2406}
Da vo thit k b lc FIR trn, m phng bng code Matlab nh sau
Tn hiu u vo ( ) 5sin(1000 ) 3 os(4000 ) 6sin(20000 ) 8cos(32000 )x t t c t t t
f1=500; f2=2000; f3=10000; f4=16000; fs=40000; T=1/fs; L=1000; t=(0:L-1)*T;
NFFT = 2^nextpow2(L); x=5*sin(2*pi*f1*t)+3*cos(2*pi*f2*t)+6*sin(2*pi*f3*t)+8*cos(2*pi*f4*t); X=fft(x,NFFT)/L; f=fs/2*linspace(0,1,NFFT/2+1); subplot(2,2,1); plot(f,2*abs(X(1:NFFT/2+1))); title('Input signal X(t)'); xlabel('f[Hz]'); ylabel('Magnitude of X(t)');
h4=[0.2406 0.2694 0.2594 0.2406]; y=conv(x,h4); Ly=L+length(h4)-1; NFFTy=2^nextpow2(Ly); Y=fft(y,NFFTy)/Ly; fy=fs/2*linspace(0,1,NFFTy/2+1); subplot(2,2,2); plot(fy,2*abs(Y(1:NFFTy/2+1))); title('Output signal Y(t) after X(t) pass throw Lowpass FIlter 3kHz');
xlabel('f[Hz]'); ylabel('Magnitude of Y(t)');
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Ph bin ca tn hiu u ra v u vo nh sau
Hnh 6. Ph bin ca tn hiu vo v ra
Cho thy vi b lc thng thp FIR tn s ct 3kHz, ti cc tn s cao 10kHz v 16kHz
u b trit tiu gn nh hon ton. V vy c th s dng b lc FIR h = {0.2406, 0.2694,
0.2594, 0.2406}.
2. Yu cu phn mm v phn cng
Phn mm v phn cng
Cc phn mm v phn cng cn thit cho bi tp ln bao gm
B TMS320C5515 eZdsp USB Stick Development Tool do TI sn xut
Phn mm giao tip gia PC vi b KIT Code Composer StudioTM (CCS)
Phn mm tnh ton MATLAB ( thc hin vic m phng)
My tnh Laptop, USB, phn mm h tr pht song.
Gii thiu v KIT TMS320C5515 eZdsp USB Stick Development Tool
Hnh 7. KIT TMS320C5515 eZdsp USB Stick Development Tool
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Cc thnh phn chnh ca b KIT
C55x CPU v cc b nh lin quan
Phn cng tng tc FFT
Bn b iu khin DMA v giao din b nh bn ngoi
Module qun l in
Cc thit b ngoi vi I/O bao gm I2S, I2C, SPI, UART, Timers, EMIF, 10 bit SAR
ADC, iu khin LCD, USB 2.0.
Hnh 8. S khi chc nng b KIT
Phn mm giao tip gia PC vi b KIT Code Composer StudioTM (CCS)
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Hnh 9. Phn mm giao tip gia PC vi b KIT Code Composer StudioTM (CCS)
Code Composer Studio l mi trng pht trin tch hp c TI xy dng nhm h tr
khch hng trong vic tip cn v pht trin ng dng vi cc sn phm ca TI. IDE ny
c mi trng lm vic kh thn thin, c kt hp vi Programer v Debugger.
3. Lp trnh trn CCS 6.1
Trong project ny, nhm s dng tn hiu u vo nh trn
( ) 5sin(1000 ) 3 os(4000 ) 6sin(20000 ) 8cos(32000 )x t t c t t t
V c to ra t matlab nh sau
f1=500; f2=2000; f3=10000; f4=16000; fs=40000; T=1/fs; L=1000; t=(0:L-1)*T;
% Tao tin hieu x(n) cac tan so f1, f2, f3, f4 x=5*sin(2*pi*f1*t)+3*cos(2*pi*f2*t)+6*sin(2*pi*f3*t)+8*cos(2*pi*f4*t);
% Tao file du lieu vao dang binary id = fopen('F:\Project\x.bin','wb'); fwrite( id, x, 'float') ; fclose(id) ;
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Sau khi chy trong matlab, nhm c file x.bin lm ng vo ca KIT TMS320C5515.
Trong CCS 6.1, to Project mi lp trnh cho KIT vi cc thng s b FIR tn s ct
3kHZ nh trn:
h = {0.2406, 0.2694, 0.2594, 0.2406}
Trong main.c
#include
#include
#include "usbstk5515.h"
#include "convolution.h"
#include "overlap.h"
#define M 3
#define Lx 1000
int main( void )
{
float h[M+1] = { 0.2406, 0.2694, 0.2694, 0.2406 } ;
float *x , *y, *ytemp ;
x = ( float* ) malloc( Lx * sizeof ( float* ) ) ;
y = ( float* ) malloc( ( M + Lx )* sizeof ( float* ) ) ;
ytemp = ( float*) malloc( M * sizeof ( float* ) ) ;
if( ( x == NULL ) || ( y == NULL ) || ( ytemp == NULL ) )
{
printf(" Error : Memory full \n") ;
exit ( 1 ) ;
}
overlap( M, h, Lx, x, y, ytemp ) ;
printf(" OK \n " ) ;
return 0 ;
}
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Trong overlap.c
#include
#include
#include "overlap.h"
#include "usbstk5515.h"
#include "convolution.h"
void overlap( unsigned short M, float *h ,
unsigned short Lx, float *x ,
float *y , float *ytemp )
{
FILE *pfile_in, *pfile_out ; // open files input
and output
Uint8 *pdata_in, *pdata_out ; // buffer_data
Uint32 i, k ; // count var
Uint32 *p_y_Uint32 = ( Uint32* )y ,tempt ; // tranmitter
Uint32 *p_x_Uint32 = ( Uint32* )x, data[4] ; // receiver
float sizefile ;//Int32 sizefile ; // sizefile of input
(byte)
Uint32 number_block ; // How many blocks have input file got ?
//--------------------------------------------------------------------
-------------//
// Open file input and output
//--------------------------------------------------------------------
-------------//
pfile_in = fopen("D:\\CCS\\workspace\\LowpassFilter\\x.bin","rb");
pfile_out = fopen("D:\\CCS\\workspace\\LowpassFilter\\y.bin","wb");
if ( ( pfile_in == NULL ) || ( pfile_out == NULL ) )
{
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printf(" Error : can't open files \n");
exit(1) ;
}
//--------------------------------------------------------------------
-------------//
// Buffer Data
//--------------------------------------------------------------------
-------------//
pdata_in = ( Uint8* ) malloc( 4 * Lx * sizeof( Uint8 ) ) ;
pdata_out = ( Uint8* ) malloc( 4 * Lx * sizeof( Uint8 ) );
if ( ( pdata_in == NULL )|| ( pdata_out == NULL ) )
{
printf(" Error : memory are full \n") ;
exit(1);
}
//--------------------------------------------------------------------
-------------//
// xem file x.bin co bao nhieu byte
//--------------------------------------------------------------------
-------------//
fseek( pfile_in, 0L , SEEK_END ) ;
sizefile = (float)ftell ( pfile_in ) ; // sizefile dang byte
fseek( pfile_in, 0L, SEEK_SET ) ;
//--------------------------------------------------------------------------
-------//
// Processing
//--------------------------------------------------------------------
-------------//
for ( i = 0 ; i < M ; i++ )
ytemp[i] = 0 ;
for ( number_block = 0 ; number_block < sizefile /( 4*Lx ) ;
number_block++ )
{
fread( pdata_in, sizeof(Uint8), 4 * Lx, pfile_in ) ;
for ( i = 0 ; i < Lx ; i++ )
{
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if ( number_block % 50 == 0 ) printf(" %ld \n ", number_block ) ;
//--------------------------------------------------------------
-------------------//
fread( pdata_in, sizeof(Uint8), 4 * Lx, pfile_in ) ;
for ( i = 0 ; i < Lx ; i++ )
{
data[0] = (Uint32)( *( pdata_in + 4*i ) ) ;
data[1] = (Uint32)( *( pdata_in + 4*i + 1 ) ) > 16 ) ;
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*( pdata_out + 4*i + 3 ) = (Uint8) ( ( tempt & 0xFF000000 ) >> 24 ) ;
}
fwrite( pdata_out, sizeof(Uint8), 4 * Lx, pfile_out) ;
}
//--------------------------------------------------------------------
-------------//
//--------------------------------------------------------------------
-------------//
fread( pdata_in, sizeof(Uint8), (sizefile - number_block * Lx * 4 ) ,
pfile_in ) ;
for ( i = 0 ; i < Lx ; i++ )
{
if ( i < (sizefile/4 - number_block * Lx ) )
{
data[0] = (Uint32)( *( pdata_in + 4*i ) ) ;
data[1] = (Uint32)( *( pdata_in + 4*i + 1 ) )
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for ( k = 0 ; k < M ; k++ )
{
y[ k ] += ytemp[ k ] ;
ytemp[ k ] = y[ k + Lx ] ;
}
//--------------------------------------------------------------------
-------------//
for (i = 0; i < Lx ; i++ )
{
tempt = *( p_y_Uint32 + i ) ;
*( pdata_out + 4*i ) = (Uint8) ( tempt & 0x000000FF
) ;
*( pdata_out + 4*i + 1 ) = (Uint8) ( ( tempt & 0x0000FF00 ) >>
8 ) ;
*( pdata_out + 4*i + 2 ) = (Uint8) ( ( tempt & 0x00FF0000 ) >>
16 ) ;
*( pdata_out + 4*i + 3 ) = (Uint8) ( ( tempt & 0xFF000000 ) >>
24 ) ;
}
fwrite( pdata_out, sizeof(Uint8), 4 * Lx, pfile_out) ;
//--------------------------------------------------------------------
-------------//
for (i = 0; i < M ; i++ )
{
tempt = *( ytemp + i ) ;
*( pdata_out + 4*i ) = (Uint8) ( tempt & 0x000000FF
) ;
*( pdata_out + 4*i + 1 ) = (Uint8) ( ( tempt & 0x0000FF00 ) >>
8 ) ;
*( pdata_out + 4*i + 2 ) = (Uint8) ( ( tempt & 0x00FF0000 ) >>
16 ) ;
*( pdata_out + 4*i + 3 ) = (Uint8) ( ( tempt & 0xFF000000 ) >>
24 ) ;
}
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III. Kt qu
Kt qu thc hin c
Nhm tm hiu l thuyt b FIR v mt s l thuyt lin quan trong bi tp ln
ny.
Tm c b lc c p ng ph hp vi yu cu ca project
Thc hin code trong CCS v build thnh cng
M phng MATLAB c kt qu ph hp vi yu cu
fwrite( pdata_out, sizeof(Uint8), 4 * M , pfile_out) ;
//--------------------------------------------------------------------
-------------//
// Close
//--------------------------------------------------------------------
-------------//
free(pdata_in);
free(pdata_out) ;
fclose(pfile_in) ;
fclose(pfile_out) ;
-
Bo co bi tp ln X l tn hiu tng t v s GVHD: PGS.TS L Tin Thng Nhm 1
24
IV. Ti liu tham kho
Gio trnh X l s tn hiu v wavelet L Tin Thng.
Gio trnh: Digital Design of Signal Processing Systems - Shoab Ahmed Khan.
Gio trnh: Digital Signal Processing Using MATLAB, 3rd Edition
Vinay K.Ingle v John G.Proakis
Cc ti liu, ebook c thu thp trn mng Internet.