Download - Online Massive
Question 10.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
692, 440
Correct Answer:
Top Left Coordinates
(623, 370)
Bottom Right Coordinates
(818, 521)
Instructor selection and student response
Question 20.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
702, 440
Correct Answer:
Top Left Coordinates
(638, 363)
Bottom Right Coordinates
(843, 569)
Instructor selection and student response
Question 30.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
726, 477
Correct Answer:
Top Left Coordinates
(659, 369)
Bottom Right Coordinates
(869, 578)
Instructor selection and student response
Question 40.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
354, 306
Correct Answer:
Top Left Coordinates
(51, 165)
Bottom Right Coordinates
(429, 441)
Instructor selection and student response
Question 50.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
727, 302
Correct Answer:
Top Left Coordinates
(522, 178)
Bottom Right Coordinates
(930, 456)
Instructor selection and student response
Question 60.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
767, 289
Correct Answer:
Top Left Coordinates
(523, 177)
Bottom Right Coordinates
(901, 441)
Instructor selection and student response
Question 70.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
338, 525
Correct Answer:
Top Left Coordinates
(85, 479)
Bottom Right Coordinates
(471, 662)
Instructor selection and student response
Question 80.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
501, 315
Correct Answer:
Top Left Coordinates
(402, 253)
Bottom Right Coordinates
(564, 414)
Instructor selection and student response
Question 90.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
667, 299
Correct Answer:
Top Left Coordinates
(539, Bottom Right Coordinates
(747, 398)
154)
Instructor selection and student response
Question 100.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
782, 346
Correct Answer:
Top Left Coordinates
(597, 211)
Bottom Right Coordinates
(838, 492)
Instructor selection and student response
Question 110.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
387, 289
Correct Answer:
Top Left Coordinates
(203, 135)
Bottom Right Coordinates
(437, 400)
Instructor selection and student response
Question 120 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
551, 350
Correct Answer:
Top Left Coordinates
(701, 248)
Bottom Right Coordinates
(907, 463)
Instructor selection and student response
Question 130.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
367, 321
Correct Answer:
Top Left Coordinates
(162, 205)
Bottom Right Coordinates
(414, 490)
Instructor selection and student response
Question 140.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
334, 544
Correct Answer:
Top Left Coordinates
(78, 473)
Bottom Right Coordinates
(466, 659)
Instructor selection and student response
Question 150.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
688, 458
Correct Answer:
Top Left Coordinates
(602, 240)
Bottom Right Coordinates
(853, 534)
Instructor selection and student response
Question 160.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
339, 413
Correct Answer:
Top Left Coordinates
(111, 229)
Bottom Right Coordinates
(403, 542)
Instructor selection and student response
Question 170.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
367, 278
Correct Answer:
Top Left Coordinates
(158, 142)
Bottom Right Coordinates
(391, 400)
Instructor selection and student response
Question 180.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
701, 308
Correct Answer:
Top Left Coordinates
(605, 148)
Bottom Right Coordinates
(820, 403)
Instructor selection and student response
Question 190.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
660, 356
Correct Answer:
Top Left Coordinates
(547, 258)
Bottom Right Coordinates
(758, 502)
Instructor selection and student response
Question 200.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
391, 344
Correct Answer:
Top Left Coordinates
(182, 256)
Bottom Right Coordinates
(444, 521)
Instructor selection and student response
Question 21
0.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
574, 413
Correct Answer:
Top Left Coordinates
(501, 270)
Bottom Right Coordinates
(711, 494)
Instructor selection and student response
Question 220.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
316, 342
Correct Answer:
Top Left Coordinates
(168, 254)
Bottom Right Coordinates
(396, 498)
Instructor selection and student response
Question 230.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
348, 392
Correct Answer:
Top Left Coordinates
(218, 233)
Bottom Right Coordinates
(445, 473)
Instructor selection and student response
Question 240.75 out of 0.75 points
Follow the directions in the image below.Answer
Selected Answer:
764, 331
Correct Answer:
Top Left Coordinates
(672, 241)
Bottom Right Coordinates
(876, 453)
Instructor selection and student response
Question 250.75 out of 0.75 points
Which of the following statements is true?Answer
Selected Answers: The Wittig reaction is essentially an anti-ozonlysis
reaction.
the by-product of the Wittig reaction is triphenyl phosphine oxide.
Correct Answers: The Wittig reaction is essentially an anti-ozonlysis
reaction.
the by-product of the Wittig reaction is triphenyl phosphine oxide.
Question 260.75 out of 0.75 points
Which of the following statements is true?Answer
Selected Answer: The carbonyl is a polar
bond.
Correct Answer: The carbonyl is a polar
bond.
Question 270.75 out of 0.75 points
Select all of the true statements.Answer
Selected Answers: Hemiacetals have an OH and an OR (R=carbon
group) attached to the same carbon.
Correct Answers: Hemiacetals have an OH and an OR (R=carbon
group) attached to the same carbon.
Question 280.75 out of 0.75 points
Ketones are not water soluble because they are not polar enough.Answer
Selected Answer:
False
Correct Answer:
False
Question 290.75 out of 0.75 points
Which of the following results whenever an organolithium reagent is added to an aldehyde?Answer
Selected Answer: a secondary
alcohol.
Correct Answer: a secondary
alcohol.
Question 300.75 out of 0.75 points
Ketones have high boiling points because of the dipole-dipole interactions arising from the carbonylAnswer
Selected Answer:
True
Correct Answer:
True
Question 310.75 out of 0.75 points
It is not possible to deprotonate the alpha position of an acid.Answer
Selected Answer:
False
Correct Answer:
False
Question 320.75 out of 0.75 points
Select all of the true statements.Answer
Selected Answers: When tertiary amines react with aldehydes or
ketones, the resulting product is unstable and the system reverts back to starting materials.
When primary amines react with aldehydes or ketones, an imine is formed.
When secondary amines react with aldehydes or ketones, an enamine is formed.
Correct Answers: When tertiary amines react with aldehydes or
ketones, the resulting product is unstable and the system reverts back to starting materials.
When primary amines react with aldehydes or ketones, an imine is formed.
When secondary amines react with aldehydes or ketones, an enamine is formed.
Question 330.75 out of 0.75 points
Which of the following statements is/are true?Answer
Selected Answers: ketones can be deprotonated at the alpha position
The michael addition allows a nucleophile to be added to the carbon beta do a carbonyl of an alpha beta unsaturated ketone.
Correct Answers: ketones can be deprotonated at the alpha position
The michael addition allows a nucleophile to be added to the carbon beta do a carbonyl of an alpha beta unsaturated ketone.
Question 340.75 out of 0.75 points
Select all of the true statements.Answer
Selected Answers: Regarding the atoms of the carbonyl, the oxygen will
always be the Lewis base and the carbon will always be the Lewis Acid when the carbonyl reacts.
The alpha carbon of esters can be deprotonated.
Correct
Answers: Regarding the atoms of the carbonyl, the oxygen will always be the Lewis base and the carbon will always be the Lewis Acid when the carbonyl reacts.
The alpha carbon of esters can be deprotonated.
Question 350.75 out of 0.75 points
HBr does not add in a radical sense to an alkene because the C-Br bond is too weak it to be thermodynamically favorable for this bond to form while the pi bond breaks.Answer
Selected Answer:
False
Correct Answer:
False
Question 360.75 out of 0.75 points
Radicals are formed via the homolytic cleavage of bonds.Answer
Selected Answer:
True
Correct Answer:
True
Question 370.75 out of 0.75 points
Radicals have two unpaired electrons in different orbitals.Answer
Selected Answer:
False
Correct Answer:
False
Question 380.75 out of 0.75 points
One of the ways in which the formation of radicals can be accomplished more easily is to make the radical less stable and thus, more reactive.Answer
Selected Fals
Answer: e
Correct Answer:
False
Question 390.75 out of 0.75 points
Reacting HCl with an alkane results in radical halogenation at both the more substituted and the less substituted carbons.Answer
Selected Answer:
False
Correct Answer:
False
Question 400.75 out of 0.75 points
Lactones can be formed from acids.Answer
Selected Answer:
True
Correct Answer:
True
Question 410.75 out of 0.75 points
Which of the following statements are true?Answer
Selected Answers: Hydrogen bonding greatly influences intermolecular
interactions such as boiling point.
The acidity of carboxylic acids is dependent on the inductive effect.
Correct Answers: Hydrogen bonding greatly influences intermolecular
interactions such as boiling point.
The acidity of carboxylic acids is dependent on the inductive effect.
Question 42
0.75 out of 0.75 points
Which of the following reactions will give an ester from an acid?Answer
Selected Answers: Carboxylate
nucleophile.
Acid catalysis with an alcohol.
DCC an alcohol
Correct Answers: Carboxylate
nucleophile.
Acid catalysis with an alcohol.
DCC an alcohol
Question 430.75 out of 0.75 points
Which of the following are valid conditions for making an amide from an acid.Answer
Selected Answer: DCC and an
amine.
Correct Answer: DCC and an
amine.
Question 440.75 out of 0.75 points
Carboxylic acids canAnswer
Selected Answers: be converted into
anhydrides
be converted into acid chlorides
be deprotonated by even weak bases
Correct Answers: be converted into
anhydrides
be converted into acid chlorides
be deprotonated by even weak bases
Question 450.75 out of 0.75 points
LAH reduces acids to secondary alcohols.Answer
Selected Answer:
False
Correct Answer:
False
Question 460.75 out of 0.75 points
Which of the following transformations are not possible for acids in one step?Answer
Selected Answers: The conversion of acids to secondary
alcohols.
Correct Answers: The conversion of acids to secondary
alcohols.
Question 470.75 out of 0.75 points
Which of the following statements are false?Answer
Selected Answers: Hydrogen bonding greatly influences intramolecular
interactions such as crystal size.
High pKa values indicate a very strong acid.
Correct Answers: Hydrogen bonding greatly influences intramolecular
interactions such as crystal size.
High pKa values indicate a very strong acid.
Question 480.75 out of 0.75 points
Circle all of the true statements.Answer
Selected Answers: If an acid is deprotonated first, it can accept an
organolithium or Grignard reagent nucleophile to make a ketone.
Correct Answers: If an acid is deprotonated first, it can accept an
organolithium or Grignard reagent nucleophile to make a ketone.
Question 49
0.75 out of 0.75 points
Which of the following are true regarding pyridine and pyrrole? You should choose 2 answers.Answer
Selected Answers: Pyrrole is not basic because the lone pair of electrons
on the pyrrole nitrogen are part of the aromatic ring. This means that donation of these electrons to an H+ will destroy the aromaticity of the ring.
Pyridine is basic because the lone pair of electrons on the nitrogen of pyridine are not part of the aromatic ring. This means that the electrons can be donated to an H+ and not result in the destruction of aromaticity.
Correct Answers: Pyrrole is not basic because the lone pair of electrons
on the pyrrole nitrogen are part of the aromatic ring. This means that donation of these electrons to an H+ will destroy the aromaticity of the ring.
Pyridine is basic because the lone pair of electrons on the nitrogen of pyridine are not part of the aromatic ring. This means that the electrons can be donated to an H+ and not result in the destruction of aromaticity.
Question 500.75 out of 0.75 points
Which of the following statements is/are true? There may be more than one answer.Answer
Selected Answers: Pyridine is
aromatic.
Correct Answers: Pyridine is
aromatic.
Question 510.75 out of 0.75 points
Which of the following is/are requirements for aromaticity? There may be multiple answers.Answer
Selected Answers: Fully
conjugated.
4n + 2"pi" electrons.
Correct Answers: Fully
conjugated.
4n + 2"pi" electrons.
Question 520.75 out of 0.75 points
All aromatic rings are nonpolar.Answer
Selected Answer:
False
Correct Answer:
False
Question 530.75 out of 0.75 points
Choose all of the substituents that the diazonium ion can be converted into.Answer
Selected Answers: OH
CN
Correct Answers: OH
CN
Question 540.75 out of 0.75 points
Which of the following statements is/are false? There may be multiple answers.Answer
Selected Answers: Aromatic compounds must be
neutral.
Correct Answers: Aromatic compounds must be
neutral.
Question 550.75 out of 0.75 points
Which of the following statements is/are true. There may be multiple answers.Answer
Selected Answers: Although halogens are ortho/para directors, they
are deactivators.
the NO2 group is both an deactivator and a meta director
Aromatic rings can have heteroatoms.
Correct Answers: Although halogens are ortho/para directors, they
are deactivators.
the NO2 group is both an deactivator and a meta director
Aromatic rings can have heteroatoms.
Question 560.75 out of 0.75 points
Which of the following choices account for the increased reactivity of anisole, compared to benzene? There may be more than one answer.Answer
Selected Answers: The lone pair of electrons on the oxygen of anisole
allows for a resonance stabilized intermediate. This makes the intermediate lower in energy, making it easier to access.
The lone pair of electrons on the oxygen of anisole can be donated into the ring, making the ring more electron rich, and therefore, more likely to donate electrons to an electrophile, which is electron-poor.
Correct Answers: The lone pair of electrons on the oxygen of anisole
allows for a resonance stabilized intermediate. This makes the intermediate lower in energy, making it easier to access.
The lone pair of electrons on the oxygen of anisole can be donated into the ring, making the ring more electron rich, and therefore, more likely to donate electrons to an electrophile, which is electron-poor.
Question 570.75 out of 0.75 points
Aromatic compounds such as benzene are prone to substitution reactions and not addition reactions because permanent destruction of the aromatic ring , which would occur during an addition reaction, is unfavorable.Answer
Selected Answer:
True
Correct Answer:
True
Question 580.75 out of 0.75 points
Which of the following statements is/are true about the basicity of aromatic compounds? There may be more than one answer.Answer
Selected Answers: Aniline is basic because the NH2 group is attached to
the aromatic ring, meaning that the N can donate its lone pair of electrons to an H+ without any repercussions on the aromatic ring.
Whether or not a N in an aromatic ring is basic depends on whether or not the lone pair of electrons is part of the aromatic system.
Pyridine is basic because the nitrogen of the ring has a lone pair of electrons that are not part of the aromatic system. As a result, they are available for donation to an H+.
Correct Answers: Aniline is basic because the NH2 group is attached to
the aromatic ring, meaning that the N can donate its lone pair of electrons to an H+ without any repercussions on the aromatic ring.
Whether or not a N in an aromatic ring is basic depends on whether or not the lone pair of electrons is part of the aromatic system.
Pyridine is basic because the nitrogen of the ring has a lone pair of electrons that are not part of the aromatic system. As a result, they are available for donation to an H+.
Question 590.75 out of 0.75 points
An alkyne is a suitable dienophile for the Diels-Alder reaction.Answer
Selected Answer:
True
Correct Answer:
True
Question 600.75 out of 0.75 points
Paracyclophanes are highly reactive.Answer
Selected Answer:
True
Correct Answer:
True
Question 610.75 out of 0.75 points
The Diels-Alder reaction is extremely specific with regards to both stereochemsitry and regiochemistry.Answer
Selected Answer:
True
Correct Answer:
True
Question 620.75 out of 0.75 points
Some Diels-Alder reactions do not result in the formation of a 6 member ring.Answer
Selected Answer:
False
Correct Answer:
False
Question 63
0.75 out of 0.75 points
The Diels-Alder reaction can be used to generate as many as 4 stereocenters but as few as 2, depending on the substrates. In fact, in some cases, it will generate 0 stereocenters.Answer
Selected Answer:
True
Correct Answer:
True
Question 640.75 out of 0.75 points
Which of the following can be used to furnish an acid?Answer
Selected Answers: Hydrolysis of an ester.
Hydrolysis of a nitrile.
oxidation of primary alcohols with Jones reagent.
addition of an organolithium or a Grignard to CO2
Correct Answers: Hydrolysis of an ester.
Hydrolysis of a nitrile.
oxidation of primary alcohols with Jones reagent.
addition of an organolithium or a Grignard to CO2
Question 650.75 out of 0.75 points
all of the acid derivatives can be easily converted into one another.Answer
Selected Answer:
False
Correct Answer:
False
Question 660.75 out of 0.75 points
Esters are less reactive than acids.Answer
Selected Answer:
True
Correct Answer:
True
Question 670.75 out of 0.75 points
Amides are the least reactive of the acid derivatives.Answer
Selected Answer:
True
Correct Answer:
True
Question 680.75 out of 0.75 points
Which of the following statements about acid derivatives are/is false?Answer
Selected Answers: Acid chlorides are more reactive
than acids.
Correct Answers: Acid chlorides are more reactive
than acids.
Question 690.75 out of 0.75 points
Acids can be a protecting group for an ester.Answer
Selected Answer:
False
Correct Answer:
False
Question 700.75 out of 0.75 points
A good protecting group is:(Choose all that apply)Answer
Selected Answers: Very stable, but easy to to take off under very
specific conditions.
A group that will keeps other reactive groups from transforming under the reaction conditions you are using in your synthesis.
A group that you can introduce into your compound in a very high-yielding reaction.
Correct Answers: Very stable, but easy to to take off under very
specific conditions.
A group that will keeps other reactive groups from transforming under the reaction conditions you are using in your synthesis.
A group that you can introduce into your compound in a very high-yielding reaction.
Question 710.75 out of 0.75 points
Esters can serve as protecting groups for alcohols or for acids, depending on which you care more about.Answer
Selected Answer:
True
Correct Answer:
True
Question 720.75 out of 0.75 points
Which of the following can be a protecting group for a ketone?Answer
Selected Answers: acet
al
Correct Answers: acet
al
Question 730.75 out of 0.75 points
Which of the following can be a protecting group for an alcoholAnswer
Selected Answers: acetal
silyl ether
ester
methyl ether
Correct Answers: acetal
silyl ether
ester
methyl ether
Question 740.75 out of 0.75 points
Amino acids require protecting group schemes when used in synthesis.Answer
Selected Answer:
True
Correct Answer:
True
Question 750.75 out of 0.75 points
Reactions of sugars include:Answer
Selected Answer: selective oxidation of the aldehyde
to an acid.
Correct Answer: selective oxidation of the aldehyde
to an acid.
Question 760.75 out of 0.75 points
Mutarotation of sugars is...Answer
Selected Answer: the epimerization of one of the
stereocenters.
Correct Answer: the epimerization of one of the
stereocenters.
Question 770.75 out of 0.75 points
The anomeric position of an unfunctionalized furanose is an acetal.Answer
Selected Answer:
False
Correct Answer:
False
Question 780.75 out of 0.75 points
The anomeric position of furanoses and pyranoses reacts under very selective conditions.Answer
Selected Answer:
True
Correct Answer:
True
Question 790.75 out of 0.75 points
Which of the following statements about sugars is/are trueAnswer
Selected Answers: Sugars have the general formula
Cn(H2O)n
They can exist in an open chain or ring form.
Correct Answers: Sugars have the general formula
Cn(H2O)n
They can exist in an open chain or ring form.
Question 800.75 out of 0.75 points
Select all of the true statements.Answer
Selected Answers: The synthesis of peptides is made relatively easy by
clever use of protecting groups.
Pyranoses and furanoses can be reduced with NaBH4 because there is an equilibrium that allows an aldehyde or ketone to be produced.
There are multiple selective reactions of carbohydrates.
Correct Answers: The synthesis of peptides is made relatively easy by
clever use of protecting groups.
Pyranoses and furanoses can be reduced with NaBH4 because there is an equilibrium that allows an aldehyde or ketone to be produced.
There are multiple selective reactions of carbohydrates.
Question 810.75 out of 0.75 points
the anomeric position of an unfunctionalized furanose is a hemiacetalAnswer
Selected Answer:
True
Correct Answer:
True
Question 820.75 out of 0.75 points
Because sugars have so many aldehyde groups they are very polar.Answer
Selected Answer:
False
Correct Answer:
False
Question 830.75 out of 0.75 points
Which of the following statements about amino acids is true?Answer
Selected Answer: The acid is often protected as
an ester.
Correct Answer: The acid is often protected as
an ester.
Question 840.75 out of 0.75 points
Which of the following statements is/are true about amino acids.Answer
Selected Answers: They can be formed by simple SN2 reactions where
an amine displaces a leaving group.
They can exist as zwitterions at the right pH.
Correct Answers: They can be formed by simple SN2 reactions where
an amine displaces a leaving group.
They can exist as zwitterions at the right pH.
Question 850.75 out of 0.75 points
Which of the following statements about Fischer projections is true?Answer
Selected Answer: The horizontal bonds are coming out of the page
and the veriical bonds are going into the page.
Correct Answer: The horizontal bonds are coming out of the page
and the veriical bonds are going into the page.
Question 860.75 out of 0.75 points
Epimers are a very specific type of diasereomer.Answer
Selected Answer:
True
Correct Answer:
True
Question 870.75 out of 0.75 points
Select all of the true statements.Answer
Selected Answers: Peptides are comprised of
amino acids.
Correct Answers: Peptides are comprised of
amino acids.
Question 880.75 out of 0.75 points
Select all of the false statements.Answer
Selected Answers: carbohydrates readily react with amino acids to
make peptides.
Correct Answers: carbohydrates readily react with amino acids to
make peptides.
Tuesday, May 1, 2012 12:18:39 PM EDTOK