economic load dispatch

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ECONOMIC LOAD DISPATCH DEEPAK JOHN S1 M. Tech POWER SYSTEM PRESENTED BY

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Page 1: Economic load  dispatch

ECONOMIC LOAD DISPATCH

DEEPAK JOHN S1 M. TechPOWER SYSTEM

PRESENTED BY

Page 2: Economic load  dispatch

CONTENTSINTRODUCTIONDIFFERENT CONSTRAINTS IN ECONOMIC

LOAD DISPATCHOPERATING COST OF THERMAL PLANTECONOMIC DISPATCH NEGLECTING

LOSSES ECONOMIC DISPATCH INCLUDING

LOSSES REFERENCES

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INTRODUCTIONIn power generation our main aim is to

generate the required amount of power with minimum cost.

Economic load dispatch means that the generator’s real and reactive power are allowed to vary within certain limits so as to meet a particular load demand with minimum fuel cost

This allocation of loads are based on some constraints.

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DIFFERENT CONSTRAINTS IN ECONOMIC LOAD DISPATCH

INEQUALITY CONSTRAINTS Voltage constraints Vmin ≤ V ≤ Vmax , δmin ≤ δ ≤ δmax Generator constraints KVA loading of generator should not exceed

prescribed value Pmin ≤ P ≤ Pmax Qmin ≤ Q ≤ Qmax

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Running spare capacity constraints This constraints are needed to meet forced

outage of one or more alternators in the system and also unexpected load on the system

Transmission line constraints flow of power through transmission line

should less than its thermal capacity Transformer tap set

for autotransformer tap t should between 0 & 1 For two winding transformer – between 0& k

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Equality constraints Real power Pp= Vp Σ Ypq Vq cos(θpq-(δp+δq)) Reactive power Qp= Vp Σ Ypq Vq sin(θpq-(δp+δq))

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OPERATING COST OF THERMAL PLANT

The factors influencing power generation at minimum cost are operating efficiencies of generators, fuel cost, and transmission losses.

The most efficient generator in the system does not guarantee minimum cost as it may be located in an area where fuel cost is high.

If the plant is located far from the load center, transmission losses may be considerably higher and hence the plant may be overly uneconomical.

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The input to the thermal plant is generally measured in Btu/h, and the output is measured in MW

In all practical cases, the fuel cost of generator can be represented as a quadratic function of real power generation

a) Heat rate curve b) Fuel cost curve

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• By plotting the derivative of the fuel-cost curve versus the real power we get the incremental fuel-cost curve

Incremental fuel-cost curve

The incremental fuel-cost curve is a measure of how costly it will be to produce the next increment of power.

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ECONOMIC DISPATCH NEGLECTING LOSSES

It is the simplest economic dispatch problem Assume that the system is only one bus with

all generation and loads connected to itA cost function Ci is assumed to be known for

each plant

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The problem is to find the real power generation for each plant such that the objective function (i.e., total production cost) as defined by the equation

Is minimum ,subjected to the constraints

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when losses are neglected with no generator limits, for most economic operation. all plants must operate at equal incremental production cost

Production from each plant can be found by

This equation is known as the coordination equationFor analytic solution we can find λ by

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In an iterative technique, starting with a value of λ and the process is continued until ∆Pi is within a specified accuracy

Corresponding to this λ ,

is calculated, and the power mismatch is calculated by

Update value of λ by

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EXAMPLE

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Above three eqn represent the eqn for straight line on plotting this line we will get

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ECONOMIC DISPATCH INCLUDINGLOSSES

When power is transmitted over long distances transmission losses are a major factor that affect the optimum dispatch of generation

One common practice for including the effect of transmission losses is to express the total transmission loss as a quadratic function of the generator power outputs. The simplest quadratic form is

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Using the langrange multiplier

Minimum of this function is fount at the points where the partials of the function to it’s variables are zero

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Itration method

Initially assume a λ value. Then find out the generation from each plant using the equation

Calculate the power mismatch

calculate

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Update value of λ

Repeat the procedure with new value of λ until the power mismatch is within the limit

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EXAMPLE

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SOLUTION

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REFERENCESPower System Analysis - Hadi Saadatpower system analysis by nagrath and

kothari

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THANKS