equilibrium & newton’s laws of motion tensional forces
TRANSCRIPT
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Equilibrium & Newton’s Laws of Motion
Tensional Forces
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Equilibrium
Newton’s 1st Law of Motion When the forces on an object are balance, it is
said to be in equilibrium. When an object is in equilibrium, it is not
accelerating. An object that is not accelerating is stationary or
moving at constant speed in a straight line.
You balanced forces during the force table lab.
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Equilibrium in 2-Dimensions
When objects are in equilibrium: ax and ay = 0
It then follows that: ΣFx and ΣFy = 0
Because Fnet = ma and a = 0.
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Ex. 1: Equilibrium
A 100 N sign is hung by two wires as seen below. What is the tension in the wires?
Physics is Fun
Fg = 100 N
FA FB
= 15°
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Diagram the Problem
Physics is Fun
Fg = 100 N
FA FB
y
x
System
= 15°
y
x
FBx
FByFAy
FAx
Fg = 100 N
FA FB
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State the Known & Unknown
What is known? Fg = 100N θ = 15°
What is not known? FA
FB
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Perform Calculations
Isolate the x and y components separately. Since the sign is not moving, Fnet = ma = 0 in both the x and y
directions. x – direction:
-FAx + FBx = 0
-FA cosθ + FB cosθ = 0 FA cosθ = FB cosθ
= 15°
y
x
FBx
FByFAy
FAx
Fg = 100 N
FA FB
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Perform Calculations
y – direction: FAy + FBy – Fg = 0 FA sinθ + FB sinθ – Fg = 0 2FA sinθ = Fg (due to symmetry, FAy = FBy) FA = (100N)/((sin15°)(2)) FA = 193 N
= 15°
y
x
FBx
FByFAy
FAx
Fg = 100 N
FA FB
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Ex. 2: Equilibrium
An engine has a weight of 3150 N. The engine is positioned above the engine compartment using rope, a pulley and a ring as shown. Find the tension in each of the sections of rope
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State the Known & Unknown
What is known? W = 3150 N θ1 = 10° θ2 = 80°
What is not known? T1
T2
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Perform Calculations
Isolate the x and y components separately. Since the engine is not moving, Fnet = ma = 0 in both the x
and y directions. x – direction:
-T1sin θ1 + T2sin θ2 = 0
-T1sin 10° + T2sin 80° = 0 (1)
y – direction: T1cos θ1 - T2cos θ2 – W = 0
T1cos 10° - T2cos 80° - W = 0 (2)
Solve (1) for T1 and substitute into (2).
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Perform Calculations (cont.)1 2
sin80.0
sin10.0T T
2 2
2
2
2
1
sin80.0cos10.0 cos80.0 0
sin10.0
:
sin80.0cos10.0 cos80.0
sin10.0
3150582
sin80.0cos10.0 cos80.0
sin10.0
sin80.0(582 ) 3300
sin10.0
T T W
Solve forT
WT
NT N
T N N