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  • Example 11.21 Analyzing Classical Form third movement, 9–23 · Adagio molto G [Main Theme] 55 5 5555 55555 5 = f 5k$ 55 5!5 55 5!55M 3: p 55 $ 5555 = f. Title: example11-21 Author:
13
Allegro 1 2 G f 5 : 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 : 5 5 fz 5 5 5 5 5 B 5 = 5 : 5 5 5 5 5 5 5 5 B ! : f B 4 B 5 fz 5 5 5 5 5 ! B 4 B 4 B : G f 5 5 : 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 : 5 5 fz 5 5 5 5 5 5 5 5 5 5 B 5 B 5 = 5 5 5 : 5 5 5 5 fz 5 5 5 5 5 ! 5 5 5 5 5 5 5 5 5 5 5 5 B B B B 4 G B 5 5 5 5 5 5 5 5 5 5 5 ! B B 5 5 = B B B B 4 G B B B : : : 15 1 2 G 5 fz 5 : 5 5 ! 4 5 : 5 5 4 5 : 5 5 ! 4 5 : 5 5 fz B ! 5 4 5 ! 5 4 5 5 4 5 ! G 5 fz 5 : 5 5 ! 5 5 ! 5 5 $ 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 ! 5 5 ! 5 f 5 5 5 5 5 5 5 5 G 5 5 5 5 5 ! 5 5 5 5 5 5 5 5 4 5 5 ! 5 5 4 5 5 ! 5 5 4 5 5 ! Copyright © 2013 Oxford University Press Example 11.21 Haydn, Piano Trio in E-flat, H. 22 third movement, 9–23 1 Analyzing Classical Form

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Page 1: Example 11.21 Analyzing Classical Form third movement, 9–23 · Adagio molto G [Main Theme] 55 5 5555 55555 5 = f 5k$ 55 5!5 55 5!55M 3: p 55 $ 5555 = f. Title: example11-21 Author:

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Allegro12G���

f

5 :55� 555555 555555555 :55fz

5� 5 5 5 5 B 5� = 5 :55� 555555 B! :����

f

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55 :55� 55fz

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BBBB 4 G BBB :::

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fz

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fz

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fz

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5� 5 5 5 5� 5� 5 5G��� 5 5 5 5 5! 5 5 5 5 5 5 5 5 4 �

55! 55 455�! 55 4 55!

Copyright © 2013 Oxford University Press

Example 11.21Haydn, Piano Trio in E-flat, H. 22third movement, 9–23

1

Analyzing Classical Form

Page 2: Example 11.21 Analyzing Classical Form third movement, 9–23 · Adagio molto G [Main Theme] 55 5 5555 55555 5 = f 5k$ 55 5!5 55 5!55M 3: p 55 $ 5555 = f. Title: example11-21 Author:

1912G��� 5� 4 5 : 5 5!

4 4[Subordinate Theme]

555! 4 5 : 55 5! 4 5 : 5 5 5 4 5 : 55���� 5 4 5� 5 4 4 5 4 5 5 5 4 5 5! 5 4 5 5

G��� 5� 5555555�

55555! 55555555555 5! 55555555555 5! 5555555

G5555

555555555555���� 55 4 55!� 55 4 4 5 5 5 5 5 5 5 5 5! 5 5 5 5 5 5 5 5 5

Example 11.21, Haydn, Piano Trio in E-flat, H. 22, third movement, 9–23 (continued)

Copyright © 2013 Oxford University Press 2

Page 3: Example 11.21 Analyzing Classical Form third movement, 9–23 · Adagio molto G [Main Theme] 55 5 5555 55555 5 = f 5k$ 55 5!5 55 5!55M 3: p 55 $ 5555 = f. Title: example11-21 Author:

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Andante ed innocentemente1

2

G� 0 =p

05M 5M 5M =[Subordinate Theme]

fz

5M 5M 5M 5 5 5 555M 5M 5 5 5 5 5M 5M

G� 4 = 5E 5 5� = 4fz5 : 5! 5 5 5 5 5 4 0

fz

5 55555M 5M��

fz

5 : 5 5 5 5 5 5� = 4fz

5 : 5 5 5 5 4fz5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5

��fz

5 5 5 5 5 4fz

B 5 4fzB 5 4

Copyright © 2013 Oxford University Press

Example 11.22Haydn, String Quartet in D minor, Op. 42first movement, 9–14

1

Analyzing Classical Form

Page 4: Example 11.21 Analyzing Classical Form third movement, 9–23 · Adagio molto G [Main Theme] 55 5 5555 55555 5 = f 5k$ 55 5!5 55 5!55M 3: p 55 $ 5555 = f. Title: example11-21 Author:

����

Allegro

G�[Main Theme]

5 5 55 55 45 5 4 5 5 4

f

5E 5 : 555 55 5 55 5E 5 55M 5 5 5 5 : 55555 5E

G� 55 4 55 5 4 555 55 4 �555 55 455EE 55

� 5 5 5 5 5 5 5 5 5 5 555

5555E 4

26G� 5 : 5 5 5 5 5 5E 5 : 5 5 5 5 5 5 5 5 5M 5 5 5 5555!� :::: 5 5 5� 5 5 5 5� : 5 5 5� 5 5 5!�� 55

5555E 4 5 5 5 5 5 5 5 5 5 5 5 555

5555!� 4 555555!� 4

31G� 5 5555 5� 555 5 5� 555 4 5 5 5� 55 5� 555 5� 5� 555 4 5 5 5E 55 5� 555�� 5� 5 5 5 5 5 5� 5 5 5 5 5 5 5� 5� 5 5 5 5 5� 5� 5 5 5 5� 5 5� 5 5 5

Copyright © 2013 Oxford University Press

Example 11.23Mozart, Piano Sonata in F, K. 332first movement, 19–40

1

Analyzing Classical Form

Page 5: Example 11.21 Analyzing Classical Form third movement, 9–23 · Adagio molto G [Main Theme] 55 5 5555 55555 5 = f 5k$ 55 5!5 55 5!55M 3: p 55 $ 5555 = f. Title: example11-21 Author:

36G� 5E 5� 5 5 5 55 5! 5 B 5 5� 5 5 B 5 5� 5 5 5 : 5� 5 5 5� 5 5 5M 5M 4

�� 5� 5 5� 5 5 5 5 5! 5 5 5 5� 5 5! 5 5 5 5� 55 :: 5� 5 5 5� 5 5 5M 5M 4

Example 11.23, Mozart, Piano Sonata in F, K. 332, first movement, 19–40 (continued)

Copyright © 2013 Oxford University Press 2

Page 6: Example 11.21 Analyzing Classical Form third movement, 9–23 · Adagio molto G [Main Theme] 55 5 5555 55555 5 = f 5k$ 55 5!5 55 5!55M 3: p 55 $ 5555 = f. Title: example11-21 Author:

��������

Andante

G���[Main Theme]

5 555555 5 5 5 = 4 5� 5� = 5� 5 55 5 = 4 5� 5� = 5� 5 55���� 355555 355555 5 = 4 5� 5� = 5� 5 5� 5 = 4 5� 5� = 5� 5 5�

G��� 5 555555 5 5 5 = 4 55� 55� = 55� 55 : 5� 55 = 4 55� 55� = 55� 55 55�

����55 :: 55

:: 55 555555 5 5! 5� = 5� 5� : 55 555555 5 5! 5� = 5� 5� :

20G��� 5 = 4 5� 5 = 4 5� 5 = 4 5� 5 = 4 =���� 5 = 4 5� 5 = 4 5� 5 = 4 5� 5 = 4 =

G���55

= 4 5� 5 5 55 5E 5 5 5 5M 5 5 5 5 5E 5 5 5 5M 5 5 55 5E 5 5 5 5���� 55 5 555 55 5 5! 5 = 4 5!� 5 = 4 5!� 5 = 4 =

Copyright © 2013 Oxford University Press

Example 11.24Mozart, Clarinet Trio in E-flat, K. 498first movement, 15–26

1

Analyzing Classical Form

Page 7: Example 11.21 Analyzing Classical Form third movement, 9–23 · Adagio molto G [Main Theme] 55 5 5555 55555 5 = f 5k$ 55 5!5 55 5!55M 3: p 55 $ 5555 = f. Title: example11-21 Author:

24G��� 0[Subordinate Theme]

5 : 5 5 5 5 5 5 5! 5 5 5

���� 0 0 0

G���f555 :::

p555!� = = 3 5 55 5 55 5 3 5! 55 5 55 5

3 5 55 5 55 5 3 5 555 555���� 55�� :: 55

� = = 5� = = 5� = = 5� = = 5! � = =

Example 11.24, Mozart, Clarinet Trio in E-flat, K. 498, first movement, 15–26 (continued)

Copyright © 2013 Oxford University Press 2

Page 8: Example 11.21 Analyzing Classical Form third movement, 9–23 · Adagio molto G [Main Theme] 55 5 5555 55555 5 = f 5k$ 55 5!5 55 5!55M 3: p 55 $ 5555 = f. Title: example11-21 Author:

����

Allegro

GE[Main Theme]

5 5 5 55 5 55 =

cresc.

5�8

sf

5E 55M 5M 5M 5 5 5� = =:cresc.

5�sf

5M 5M 5M 5M 5 5� =�E 3 5 5 5 3 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5

13GE =p

5� 5555M 5Mcresc.

5� 5 5 5 55� 5� 5 5� 5� 5E 5 5 5E5� 5� 5 5� 5� 5 5��E 555555 55 5555 5E 555 55555555 555555 5E 5 55 5E 55555 5555 G5E 555

19GEp

5� 5E 5� 5 5 3 5 5 5 5 5 5 5E 3 5 5 5 5 5 5 5 3 5 5 5 5 53 3 3 3

GE5 5 5 5 5 5 5E 5 5 5E 5 5 5 5 5E 5 5 5 5 5 5 5 5E 5 5 5E 5 5 5 5 5E 5

Copyright © 2013 Oxford University Press

Example 11.25Beethoven, Piano Sonata in G, Op. 14, No. 2first movement, 7–27

1

Analyzing Classical Form

Page 9: Example 11.21 Analyzing Classical Form third movement, 9–23 · Adagio molto G [Main Theme] 55 5 5555 55555 5 = f 5k$ 55 5!5 55 5!55M 3: p 55 $ 5555 = f. Title: example11-21 Author:

23GE 5 5E 555555 5555 55 5E 55 5E 5 5E 5 5! 5E 5! 5E[Subordinate Theme]

p

5 5 5 5 55 :: 55EE 55 :: 55 55 :: 55!! 55 55 55 55E3

GE5 5 5 5 5 5 5E 5 555E

� = 4 0 � 3 5 5 3 3 55 3 G 3 5 5 3 4

Example 11.25, Beethoven, Piano Sonata in G, Op. 14, No. 2, first movement, 7–27 (continued)

Copyright © 2013 Oxford University Press 2

Page 10: Example 11.21 Analyzing Classical Form third movement, 9–23 · Adagio molto G [Main Theme] 55 5 5555 55555 5 = f 5k$ 55 5!5 55 5!55M 3: p 55 $ 5555 = f. Title: example11-21 Author:

�

��

Allegro

G�[Main Theme]

5E 5 5M 5M 5! 5 5M 5M 5! 4 ?p5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5

G� 5 5 5 5 5 5 5 5 cresc.5 5 5 5 5 555555

5 5

p

55555 B 55555555 B 55 5! 555 5� 5�� 5 5 5 5 5 4 ?

'' ''

13G�5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5

G� 5 : 5� 5 55 5 B 5 4 5 5 5 5 5 5 5

65555 5 5 5 5 5 5 B 5 4�� '' '' '' ''

Copyright © 2013 Oxford University Press

Example 11.26Beethoven, Violin Sonata in F, Op. 24first movement, 9–40

1

Analyzing Classical Form

Page 11: Example 11.21 Analyzing Classical Form third movement, 9–23 · Adagio molto G [Main Theme] 55 5 5555 55555 5 = f 5k$ 55 5!5 55 5!55M 3: p 55 $ 5555 = f. Title: example11-21 Author:

17G�5 5 5 5

cresc.5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 p

5 5! 5 5 5 5 5 5 5� 5 5 5

G� 555 5E 55 5E 5 65E 5 5 5! 5 5Ecresc.

5! 5! B 5 5 5 5 B p

5 5 5 5! 5 5 : 55 5! 555

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BB BB BB 5 5 5 5

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cresc.5 5! 5 5 55M

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=55M�

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555 5! 5555555 5! 55555555�� 5 5 5 5 5 5 5 5 5 5 5 5 5M

= 5M� 5M= 5M�

25G�f55M

sf555M? 0 0 0

p

B 5 5E 5 5

G�f

5Msf

5555M? B� 5� 5 5 5 5 5 5� 5 5� 55 5� 555555 5� 5�

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p5ME4 ?

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B� 5� 5 5 5 5 5 5� 5 5� 55 5� 555555 5� 5� 5555 5M 5M 5M� 5M 5ME 4 555M!E 4

Example 11.26, Beethoven, Violin Sonata in F, Op. 24, first movement, 9–40 (continued)

Copyright © 2013 Oxford University Press 2

Page 12: Example 11.21 Analyzing Classical Form third movement, 9–23 · Adagio molto G [Main Theme] 55 5 5555 55555 5 = f 5k$ 55 5!5 55 5!55M 3: p 55 $ 5555 = f. Title: example11-21 Author:

30G� 5M! 4 ? B 5 5E 5 5 5M� 4 ? =cresc.5 5� 5E 5 5 5� 5

G� = 5! 5 5E 5 5! 5 5E 5M 4 ? = 5� 5 5!cresc.

5 5� 5 5! B 5 5! 5 5E

��555! 4 ? 555M! 4

555M! 4555� 4 ?

55��4 55� 4

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sf

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5 555 555 555 555 555sfp

555 555 555 555555M� 555 555 555 555 555 555 555

�� 5 5E 5 5 5! 5 5� 5 5M� 555! 555 555 555 555

555 555 G555 555 555 555 555 555 5

5 55 555M!� 5555! 555555555555555555555555

Example 11.26, Beethoven, Violin Sonata in F, Op. 24, first movement, 9–40 (continued)

Copyright © 2013 Oxford University Press 3

Page 13: Example 11.21 Analyzing Classical Form third movement, 9–23 · Adagio molto G [Main Theme] 55 5 5555 55555 5 = f 5k$ 55 5!5 55 5!55M 3: p 55 $ 5555 = f. Title: example11-21 Author:

��

��

Adagio molto

G����[Main Theme]

�5 55 5 5 5 55 5 5 5 5 5� =

f

k5$5 5 5 5! 5 5 5 5! 5M� 3 :

p55�$ 55 55� =

f

k5$5 5 5 5 5 5 5 5 5M� 3 :

p55�$5�

����� 55 5! 5� 5 55 5 5 5 55 : 5� =5555! = 3 : 55! �$ 55 :: =

5555 = 3 +55�$

20G���� 55 55�= 4 = 3 :

fp555�$ 5 5! 5! 5 5! 5 5E 5! 5! 5 5 5� 5

����� 55 :: =f

k5� $5� 5 5 5 5 5 5 5� �

3 :55���$ 55 ::55 :: = 0

Copyright © 2013 Oxford University Press

Example 11.27Beethoven, Piano Sonata in C minor, Op. 10, No. 1second movement, 15–23

1

Analyzing Classical Form


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