feynman integrals - lecture 1
TRANSCRIPT
Feynman Integrals
Lecture 1
Stefan Weinzierl
Institut für Physik, Universität Mainz
Higgs Centre School for Theoretical Physics 2021
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Section 1
Organisation
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Organisation
Online course on Feynman integrals via zoom.
Daily schedule for this course:
9:00-11:00 Lecture followed by a
discussion session in the plenum
11:30-12:30 Tutorial
Slides and exercise sheets on the indico page.
Afternoon: Lectures by Matthew McCullough
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Tutorials
For each lecture there will be an exercise sheet.
Tutorials: Small groups (5-7 people) in breakout rooms
Tutor: Yao Ma
Close-out at 12:20 in the plenum.
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Advice
A summer school has a scientific part and a social part.
Talk to your fellow students in the tutorials.
Ask questions in the discussion session.
It’s your summer school!
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Section 2
Motivation
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Scattering amplitudes
We would like to make precise predictions for observables in scattering
experiments from quantum field theory.
Any such calculation will involve a scattering amplitude.
Unfortunately we cannot calculate scattering amplitudes exactly.
If we have a small parameter like a small coupling, we may use
perturbation theory.
We may organise the perturbative expansion of a scattering amplitude in
terms of Feynman diagrams.
Scattering amplitude = sum of all Feynman diagrams
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Scattering amplitudes
Example: Scattering amplitude for a 2 → 2-process:
p1
p2 p3
p4
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Scattering amplitudes
We may compute the scattering amplitude within perturbation theory:
p1
p2 p3
p4
= + + ...
O(
g2)
+ + + ...
O(
g4)
+ + + ...
O(
g6)
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Feynman diagrams
At leading order we (usually) have only tree diagrams. These do not pose
any conceptual problem.
But precise predictions require more terms in the perturbative expansion.
Beyond leading order we have loop diagrams and we have to compute
loop integrals.
Content of this course: How do we compute loop integrals?
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Section 3
Basics
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Introducing Feynman integrals
We may define Feynman integrals without knowledge of quantum field theory.
We just need:
Special relativity
Graphs
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Special relativity
Denote by D the number of space-time dimensions.
In our real world D equals 4 (one time dimension and three spatial dimensions), but it is
extremely helpful to keep this number arbitrary. We will always assume that space-time
consists of one time dimension and (D−1) spatial dimensions.
The momentum of a particle is a D-dimensional vector, whose first
component gives the energy E (divided by the speed of light c) and the
remaining (D−1) components give the components of the spatial
momentum, which we label with superscripts:
p =
(
E
c,p1, . . . ,pD−1
)
.
It is common practice to work in natural units, where
c = ~ = 1.
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Special relativity
In natural units we write p0 = E and
p =(
p0,p1, . . . ,pD−1)
.
A component of p is denoted by
pµ with 0 ≤ µ ≤ D−1
The index µ is called a Lorentz index.
Minkowski metric: gµν = diag(1,−1, . . . ,−1).
Minkowski scalar product of two momentum vectors pa and pb:
pa ·pb =D−1
∑µ=0
D−1
∑ν=0
pµ
a gµν pνb = p
µ
a gµν pνb .
In the last expression we used Einstein’s summation convention.
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Special relativity
We represent a particle propagating in space-time by a line:
If we would like to indicate the direction of the momentum flow, we optionally
put an arrow:
p
The line is our first building block for a Feynman graph. A line for a particle
with momentum p and mass m stands for
p,m=
1
−p2 +m2.
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Special relativity
Remark: If one follows standard conventions in quantum field theory the
propagator of a scalar particle with momentum p and mass m is given by
i
p2 −m2.
This differs by a factor (−i) from
1
−p2 +m2.
This is just a prefactor and easily adjusted.
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Graphs
An unoriented graph consists of edges
and vertices, where an edge connects
two vertices.
A graph may be connected or
disconnected. We will mainly consider
connected graphs.
An oriented graph is a graph, where for
every edge an orientation is chosen. An
orientated edge is usually drawn with an
arrow line:
source sink
v1v2
v3
v4v5
e1
e2
e3 e4
e5
v6
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Valency of a vertex
The valency of a vertex is the number of
edges attached to it.
A vertex of valency 0 is necessarily
disconnected from the rest of graph.
A vertex of valency 1 has exactly one
edge attached to it. This edge is called
an external edge. All other edges are
called internal edges.
A vertex of valency 2 is also called a dot.
v1v2
v3
v4v5
e1
e2
e3 e4
e5
v6
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Momentum conservation
Choose an orientation for every edge.
E source(va) : set of edges, which have vertex va as source,
E sink(va) : set of edges, which have vertex va as sink.
At each vertex va of valency > 1 we impose momentum conservation:
∑ej∈E source(va)
qj = ∑ej∈E sink(va)
qj .
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Dots
Consider a vertex of valency 2 inside a Feynman graph:
q,m q,m=
1
(−q2 +m2)2.
We get the same effect if we associate to each edge in addition to p and m a
number ν, corresponding to the power of the propagator:
q,m,ν=
1
(−q2 +m2)ν
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The loop number
Consider a graph G with n edges, r vertices and k connected components.
The loop number l is defined by
l = n− r + k .
If the graph is connected we have
l = n− r +1.
The loop number l is also called the first Betti number of the graph or the
cyclomatic number.
Physics interpretation: If we fix all momenta of the external lines and if we
impose momentum conservation at each vertex, then the loop number is equal
to the number of independent momentum vectors not constrained by
momentum conservation.
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Trees and forests
A connected graph of loop number 0 is called a tree.
A graph of loop number 0, connected or not, is called a forest.
If the forest has k connected components, it is called a k-forest.
A tree is a 1-forest.
Feynman graphs which are trees pose no conceptual problem.
Our focus in this lecture is on connected Feynman graphs, which are not trees,
e.g. Feynman graphs with loop number l > 0.
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Notation
Consider a connected graph G with next external edges, nint internal edges
and loop number l :
External momenta: p1, . . . ,pnext
Internal momenta: q1, . . . ,qnint
Independent loop momenta: k1, . . . ,kl
qj =l
∑r=1
λjr kr +next−1
∑r=1
σjr pr , λjr ,σjr ∈ −1,0,1.
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Example
p1
p2 p3
p4
q1 =
k1 + p2
q4 =
k1 + k2
q7 =
k2 + p3
q2 = k1 q5 = k2
q3 =
k1 + p1 + p2
q6 =
k2 − p1 − p2
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Quiz
How many loops does this graph have?
(A) 5
(B) 6
(C) 11
(D) 16
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Integration
We may consider the external momenta as input data, but what shall we
do with the l independent loop momenta?
Quantum field theory instructs us to integrate over the independent
loop momenta. Thus we include for every independent loop momentum
kr a D-dimensional integration
∫dDkr
iπD2
.
If one follows standard conventions in quantum field theory, the measure
is given by
∫dDkr
(2π)D.
The difference is a simple prefactor and one easily converts from one
convention to the other convention.
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Integration domain
Naive expectation: We integrate each of the D components of kr along
the real axis from −∞ to +∞.
However, there will be poles on the real axis:
kr ,m=
1
−k2r +m2
Quantum field theory dictates us that the correct integration contour is:
Re(k0r)
Im(k0r)
−E~kr
E~kr
Feynman’s iδ-prescription:
q,m=
1
−q2 +m2 − iδ
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Notation
For the space-time dimension D we write
D = 4−2ε.
Euler’s constant γE:
γE = limn→∞
(
− lnn+n
∑j=1
1
j
)
= 0.57721566490153286 . . .
In order to enforce that our Feynman integral is dimensionless, we
introduce an arbitrary parameter µ with mass dimension dim(µ) = 1 and
multiply by an appropriate power of µ.
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The Feynman integral
Definition
The Feynman integral for a Feynman graph G with next external edges, nint
internal edges and l loops is given in D space-time dimensions by
I = elεγE(
µ2)ν− lD
2
∫ l
∏r=1
dDkr
iπD2
nint
∏j=1
1(
−q2j +m2
j
)νj,
where each internal edge ej of the graph is associated with a triple (qj ,mj ,νj),
qj =l
∑r=1
λjr kr +next−1
∑r=1
σjr pr , ν =nint
∑j=1
νj .
The coefficients λjr and σjr can be obtained from momentum conservation at
each vertex of valency > 1.
The integration contour is given by Feynman’s iδ-prescription.
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Wick rotation
Minkowski scalar product:
k2 = k20 −k2
1 −k22 −k2
3 − ...
If the quarter-circles at infinity give no contribution:
∮dk0f (k0) = 0 ⇒
∞∫
−∞
dk0f(k0) =−
−i∞∫
i∞
dk0f(k0)
Change variables:
k0 = iK0,
kj = Kj , for 1 ≤ j ≤ D−1.
Final result:
∫dDk
iπD/2f (−k2) =
∫dDK
πD/2f (K 2),
with Euclidean scalar product K 2 = K 20 +K 2
1 +K 22 +K 2
3 + ....
Re k0
Im k0
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The need for regularisation
Loop integrals in four space-time dimensions can be divergent!
∫d4k
(2π)4
1
(k2)2=
1
(4π)2
∞∫
0
dk2 1
k2=
1
(4π)2
∞∫
0
dx
x
This integral diverges at
k2 → ∞ (UV-divergence) and at
k2 → 0 (IR-divergence).
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Dimensional regularisation
Replace the four-dimensional integral by an D-dimensional integral,
where D is now an additional parameter, which can be a non-integer or
even a complex number.
We consider the result of the integration as a function of D and we are
interested in the behaviour of this function as D approaches 4.
Concept closely related to: Consider a function f (z), which is defined for
any positive integer n ∈ N by
f (n) = n! = 1 ·2 ·3 · · · · ·n.
We would like to define f (z) for any value z ∈ C (except for a countable
set of isolated points, where f (z) is allowed to have poles).
Answer is well known and given by Euler’s gamma function
f (z) = Γ(z +1) .
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Dimensional regularisation
A Feynman integral I has a Laurent expansion in ε:
I =∞
∑j=jmin
εj I(j),
where I(j) denotes the coefficient of εj .
For precision calculations we are interested in the first few terms I(jmin),
I(jmin+1), . . . of this Laurent series.
The exact number of required terms depends on the order of perturbation
theory we are calculating.
Let us stress that we would like to get the I(j) ’s, not necessarily I itself.
There are situations where a closed form expression for I is readily
obtained, but the Laurent expansion in ε is not immediate.
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The tadpole integral
Let’s get our hands dirty: We start with a one-loop integral, which only
depends on the loop momentum squared (and no scalar product k ·p with
some external momentum).
The one-loop tadpole integral:
Tν = eεγE(
µ2)ν− D
2
∫dDk
iπD2
1
(−k2 +m2)ν .
After Wick rotation we have
Tν = eεγE(
µ2)ν− D
2
∫dDK
πD2
1
(K 2 +m2)ν .
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Spherical coordinates
One radial variable K , D− 2 polar angles θ1, ..., θD−2 and one azimuthal angle θD−1:
K0 = K cosθ1
K1 = K sinθ1 cosθ2
...
KD−2 = K sinθ1...sinθD−2 cosθD−1
KD−1 = K sinθ1...sinθD−2 sinθD−1
The measure becomes
dDK = K D−1dKdΩD
Integration over the angles yields
∫dΩD =
π∫
0
dθ1 sinD−2 θ1...
π∫
0
dθD−2 sinθD−2
2π∫
0
dθD−1 =2πD/2
Γ(
D2
)
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Euler’s gamma function
The gamma function is defined for Re(z) > 0 by
Γ(z) =
∞∫
0
e−t tz−1dt .
It fulfils the functional equation
Γ(z + 1) = z Γ(z).
For positive integers n it takes the values
Γ(n+ 1) = n! = 1 ·2 ·3 · ... ·n.
The expansion around z = 1 reads
Γ(1+ ε) = exp
(
−γEε+∞
∑n=2
(−1)n
nζnεn
)
, ζn =∞
∑j=1
1
jn.
ζn is called a zeta value. Laurent expansion around z = 0:
Γ(ε) =1
ε− γE +O(ε).
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Euler’s beta function
Euler’s beta function is defined for Re(z1)> 0 and Re(z2)> 0 by
B (z1,z2) =
1∫
0
tz1−1(1− t)z2−1dt,
or equivalently by
B (z1,z2) =
∞∫
0
tz1−1
(1+ t)z1+z2dt.
The beta function can be expressed in terms of Gamma functions:
B (z1,z2) =Γ(z1)Γ(z2)
Γ(z1 + z2).
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The tadpole integral
Performing the angular integrations for our tadpole integral we obtain
Tν =eεγE
(
µ2)ν− D
2
Γ(
D2
)
∞∫
0
dK 2
(
K 2)
D2−1
(K 2 +m2)ν .
We substitute t = K 2/m2 and obtain
Tν =eεγE
Γ(
D2
)
(
m2
µ2
)D2−ν ∞∫
0
dtt
D2−1
(t +1)ν .
The remaining integral is just Euler’s beta function
∞∫
0
dtt
D2−1
(1+ t)ν =Γ(
D2
)
Γ(
ν− D2
)
Γ(ν).
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The tadpole integral
Tadpole integral:
Tν
(
D,m2
µ2
)
=eεγEΓ
(
ν− D2
)
Γ(ν)
(
m2
µ2
)D2−ν
.
We are interested in the Laurent expansion of Feynman integrals. With
D = 4−2ε, ν = 1 and L = ln(m2/µ2) we obtain
T1 (4−2ε) =m2
µ2eεγEΓ(−1+ ε)e−εL
=m2
µ2
[
−1
ε+(L−1)+
(
−1
2L2 −
1
2ζ2 +L−1
)
ε
]
+O(
ε2)
.
The pole at ε = 0 originates from the ultraviolet divergence of tadpole integral
with ν = 1 in four-space time dimensions.
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The tadpole integral
Tadpole integral:
Tν
(
D,m2
µ2
)
=eεγEΓ
(
ν− D2
)
Γ(ν)
(
m2
µ2
)D2−ν
.
The result is valid for any D, so we may as well expand it around two
space-time dimensions. Just for fun, let’s do it:
ε T1 (2−2ε) = eεγEΓ(1+ ε)e−εL
= 1−Lε+
(
1
2L2 +
1
2ζ2
)
ε2 +O(
ε3)
.
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Weights
Define a weight as follows:
Any algebraic expression in the kinematic variables has weight 0.
The dimensional regularisation parameter has weight (−1).
L = ln(m2/µ2) has weigth 1, ζn has weight n.
The weight of a product is the sum of the weights of its factors.
We observe
T1(4−2ε) contains terms of mixed weight.
ε T1(2−2ε) only involves terms of weight zero.
We call ε T1(2−2ε) to be of uniform weight.
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Dimensional shift relations
We may show
Tν (D) = νTν+1 (D+2) .
This is an example of a dimensional shift relation, relating integrals in D and
D+2 space-time dimensions.
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Master integrals
Write D = [D]− 2ε and set
J1 = ε T1 (2− 2ε) = eεγEΓ(1+ ε)e−εL.
It is not too difficult to show that
Tν (D) =Γ(
ν− [D]2+ ε)
Γ(ν)Γ(1+ ε)
(
m2
µ2
)
(
[D]2 −ν
)
J1.
For ν ∈ N and [D] even, the prefactor is always a rational function in ε and m2. Thus
we may express Tν(D) as a rational coefficient times J1.
Later on we will see, that this generalises as follows: We may express any member of
a family of Feynman integrals as a linear combination of Feynman integrals from a
finite set. The Feynman integrals from this finite set are called master integrals. A
master integrals, which is of uniform weight, is called a canonical master integral.
Thus J1 is a canonical master integral.
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