filter loading and backwash rates well yields and chlorine dosage in waterworks operation math for...

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Filter Loading and Backwash Rates Well Yields and Chlorine Dosage in Waterworks Operation Math for Water Technology MTH 082 Lecture Chapter 4 & 8- Applied Math for Water Plant Operators Loading Rate Calculations (pg 62-66); Well yield (163-177) Mathematics Chapter 19-20 &23- Basic science Concepts and Applications (pg 183-190; 197-203)

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Filter Loading and Backwash Rates Well Yields and Chlorine Dosage in

Waterworks Operation

Filter Loading and Backwash Rates Well Yields and Chlorine Dosage in

Waterworks Operation

Math for Water TechnologyMTH 082

Lecture Chapter 4 & 8- Applied Math for Water Plant Operators

Loading Rate Calculations (pg 62-66); Well yield (163-177)Mathematics Chapter 19-20 &23- Basic science Concepts and

Applications (pg 183-190; 197-203)

Math for Water TechnologyMTH 082

Lecture Chapter 4 & 8- Applied Math for Water Plant Operators

Loading Rate Calculations (pg 62-66); Well yield (163-177)Mathematics Chapter 19-20 &23- Basic science Concepts and

Applications (pg 183-190; 197-203)

ObjectivesObjectives

1. Filter overviews

2. Filter loading and backwash rates

3. Well yield

4. Chlorine dosage for a new well

1. Filter overviews

2. Filter loading and backwash rates

3. Well yield

4. Chlorine dosage for a new well

Reading assignment: Chapter 4 & 8- Applied Math for Water Plant Operators Loading Rate Calculations (pg 62-66); Well yield (163-177)Mathematics Chapter 19-20 &23- Basic science Concepts and Applications (pg 183-190; 197-203)

Reading assignment: Chapter 4 & 8- Applied Math for Water Plant Operators Loading Rate Calculations (pg 62-66); Well yield (163-177)Mathematics Chapter 19-20 &23- Basic science Concepts and Applications (pg 183-190; 197-203)

Conventional Treatment Conventional Treatment • Conventional Treatment – common treatment steps used to remove turbidity from the initial source water.

• Conventional Treatment – common treatment steps used to remove turbidity from the initial source water.

2. Flocculation2. Flocculation 3. Sedimentation3. Sedimentation 4. Filtration4. Filtration1. Coagulation1. Coagulation

PretreatmentPretreatment

Raw WaterRaw Water

Rapid or flash Mixing

Alum, polymer

Rapid or flash Mixing

Alum, polymer

SlowSlowFastFast

SludgeSludgeWashwaterWashwater

5. Clear Well Disinfection5. Clear Well Disinfection

Distri

bution

Distri

bution

ClearwellBackwash

pumps

ClearwellBackwash

pumps

ChlorinationOzone

UV

ChlorinationOzone

UV

High Rate FilterHigh Rate FilterDual or Multi Media Filter

-4 times faster then rapid sand -granular activated carbon-anthracite coal-garnet sand and gravel-backwash ready (70 hr longevity)-excellent water quality

Dual or Multi Media Filter-4 times faster then rapid sand -granular activated carbon-anthracite coal-garnet sand and gravel-backwash ready (70 hr longevity)-excellent water quality

High Rate Filters High Rate Filters

Anthracite CoalAnthracite Coal

Fine sandFine sand

Garnet sandGarnet sand

High Rate FilterHigh Rate Filter

Dualmedia FilterDualmedia Filter

Anthracite CoalAnthracite Coal

Fine sandFine sand

Garnet sandGarnet sand

Monomedia Coarse sand

Monomedia Coarse sand

Monomedia FilterMonomedia Filter

Dual-media and multimedia filters

Dual-media and multimedia filters

Req

uire

an e

xt...

Can

oper

ate

at...

Can

not r

educe

...

Do n

ot req

uire...

5% 5%0%

91%1. Require an extremely deep bed

2. Can operate at three or four times the rate of sand filters

3. Cannot reduce turbidity

4. Do not require backwashing

1. Require an extremely deep bed

2. Can operate at three or four times the rate of sand filters

3. Cannot reduce turbidity

4. Do not require backwashing

When mixed media filters composed of garnet, sand, and

crushed anthracite coal are used, which of the following

describes their placement in the filter bed?

When mixed media filters composed of garnet, sand, and

crushed anthracite coal are used, which of the following

describes their placement in the filter bed?

Anth

raci

te c

oa...

Gar

net o

n top,..

.

San

d on

top, a

...

Anth

raci

te c

oa...

8%

92%

0%0%

1. Anthracite coal on top, garnet in the middle, and sand on the bottom

2. Garnet on top, anthracite coal in the middle, and sand on the bottom

3. Sand on top, anthracite coal in the middle, and garnet on the bottom

4. Anthracite coal on top, sand in the middle, and garnet on the bottom

1. Anthracite coal on top, garnet in the middle, and sand on the bottom

2. Garnet on top, anthracite coal in the middle, and sand on the bottom

3. Sand on top, anthracite coal in the middle, and garnet on the bottom

4. Anthracite coal on top, sand in the middle, and garnet on the bottom

In a filter using gravel, anthracite, and sand, the

anthracite should be?

In a filter using gravel, anthracite, and sand, the

anthracite should be?

The

top la

yer .

..

Ben

eath

the

gr...

Bet

wee

n the

sa...

Mix

ed w

ith th

e...

88%

0%

12%

0%

1. The top layer of media

2. Beneath the gravel

3. Between the sand and the gravel

4. Mixed with the sand

1. The top layer of media

2. Beneath the gravel

3. Between the sand and the gravel

4. Mixed with the sand

Pilot Filters Pilot Filters

Anthracite CoalAnthracite Coal

Fine sandFine sand

Garnet sandGarnet sand

The main action of a mixed media filter is:

The main action of a mixed media filter is:

Stra

inin

g

Dis

infe

ctin

g

Coag

ulatin

g

None

of the

ab.

..

87%

9%4%0%

1. Straining

2. Disinfecting

3. Coagulating

4. None of the above

1. Straining

2. Disinfecting

3. Coagulating

4. None of the above

BackwashBackwash• Suspended particles entrapped by filter media. • Accumulation occurs:

– head loss within the filter to reach excessively high levels (6 to 8 feet of hydraulic head).

- Particles pass through the filter, water turbidities reach unacceptable levels

- Rule Backwash at 0.1 NTU- SWTR Allows 0.3 NTU.

• Suspended particles entrapped by filter media. • Accumulation occurs:

– head loss within the filter to reach excessively high levels (6 to 8 feet of hydraulic head).

- Particles pass through the filter, water turbidities reach unacceptable levels

- Rule Backwash at 0.1 NTU- SWTR Allows 0.3 NTU.

Head LossHead Loss• Clean filter =0 psi= one foot of head loss on

a new filter

• As filter clogs more negative pressure

• Pressure builds in a linear fashion

-2.5 to -4.0 psi = 6 to 10 ft of head loss

• More clogged greater the head loss

• Remember 1 ft of water column = 0.433 psi

• 2.31 ft of water for 1 psi change

• Clean filter =0 psi= one foot of head loss on a new filter

• As filter clogs more negative pressure

• Pressure builds in a linear fashion

-2.5 to -4.0 psi = 6 to 10 ft of head loss

• More clogged greater the head loss

• Remember 1 ft of water column = 0.433 psi

• 2.31 ft of water for 1 psi change

Filter BackwashFilter Backwash

• Some plants use head loss, some use time

• Some plants use operator knowledge and turbidity

• Each operator has their own scheme!!

• Parents and diapers--

• Some plants use head loss, some use time

• Some plants use operator knowledge and turbidity

• Each operator has their own scheme!!

• Parents and diapers--

The most critical criterion for determining when a mixed media filter should be backwashed is:

The most critical criterion for determining when a mixed media filter should be backwashed is:

Filt

er e

ffluen

...

Flo

w ra

te

Hea

d loss

Vis

ual in

spec

t...

52%

4%

39%

4%

1. Filter effluent quality

2. Flow rate

3. Head loss

4. Visual inspection of the filter surface

1. Filter effluent quality

2. Flow rate

3. Head loss

4. Visual inspection of the filter surface

Filtration Rate CalculationFiltration Rate CalculationUnit Filter Run= (Total gal filtered gal)

Filter Area (sq ft)

Filtration Rate= (flow gpm)

Area (sq ft)

Units will be gpm

ft2!

Backwash Rate = (flow gpm)

Area (sq ft)

Units will be gpm

ft2!

Downward

Upward

The total water filtered during a filter run (between backwashes) is 2,950,000 gal. If the filter is 15 ft by 20 ft, What is the

unit filter run volume (UFRV)?

The total water filtered during a filter run (between backwashes) is 2,950,000 gal. If the filter is 15 ft by 20 ft, What is the

unit filter run volume (UFRV)?

9.8

33 g

/ft2

101

.7 g

/ft2

983

3 g/ft

2

0.9

833

g/ft2

25%

0%

75%

0%

L= 15 ft, W=20 ft; Rate 2,950,000 galA=L X WUFVR= (Total gallons filtered g) Area (sq ft)

A= 20 ft X 15 ft = 300 ft2

UFVR= (2,950,000 gal) 300 (sq ft) UFVR = 9833 g/ft2

L= 15 ft, W=20 ft; Rate 2,950,000 galA=L X WUFVR= (Total gallons filtered g) Area (sq ft)

A= 20 ft X 15 ft = 300 ft2

UFVR= (2,950,000 gal) 300 (sq ft) UFVR = 9833 g/ft2

Given

Formula

Solve:

Given

Formula

Solve:

1. 9.833 g/ft2

2. 101.7 g/ft2

3. 9833 g/ft2

4. 0.9833 g/ft2

1. 9.833 g/ft2

2. 101.7 g/ft2

3. 9833 g/ft2

4. 0.9833 g/ft2

The total water filtered during a filter run (between backwashes) is 4.8 MG. If the

filter is 20 ft by 30 ft, What is the unit filter run volume (UFRV)?

The total water filtered during a filter run (between backwashes) is 4.8 MG. If the

filter is 20 ft by 30 ft, What is the unit filter run volume (UFRV)?

960

00 g

/ft2

800

0 g

/ft2

800

g/ft

2

0.0

08 g

/ft2

0% 0%0%

100%

L= 20 ft, W=30 ft; Rate 4.8 MGA=L X WUFVR= (Total gallons filtered g) Area (sq ft)

A= 20 ft X 30 ft = 600 ft2

UFVR= (4,800,000 gal) 600 (sq ft) UFVR = 8000 g/ft2

L= 20 ft, W=30 ft; Rate 4.8 MGA=L X WUFVR= (Total gallons filtered g) Area (sq ft)

A= 20 ft X 30 ft = 600 ft2

UFVR= (4,800,000 gal) 600 (sq ft) UFVR = 8000 g/ft2

Given

Formula

Solve:

Given

Formula

Solve:

1. 96000 g/ft2

2. 8000 g/ft2

3. 800 g/ft2

4. 0.008 g/ft2

1. 96000 g/ft2

2. 8000 g/ft2

3. 800 g/ft2

4. 0.008 g/ft2

A filter 20 ft by 25 ft receives a flow of 1940 gpm. What is the filtration rate in

gpm/ft2?

A filter 20 ft by 25 ft receives a flow of 1940 gpm. What is the filtration rate in

gpm/ft2?

3.9

gpd/ft

3

3.9

gpm

/ft2

0.2

5 gpm

/ft2

0.2

5 gpd/ft

3

11%

0%6%

83%

L= 20 ft, W=25 ft; Rate 1940 gpmA=L X WFiltration Rate= (flow gpm) Area (sq ft)

A= 20 ft X 25 ft = 500 ft2

Filtration Rate= (1940 gpm) 500 (sq ft) Filtration Rate = 3.9 gpm/ft2

L= 20 ft, W=25 ft; Rate 1940 gpmA=L X WFiltration Rate= (flow gpm) Area (sq ft)

A= 20 ft X 25 ft = 500 ft2

Filtration Rate= (1940 gpm) 500 (sq ft) Filtration Rate = 3.9 gpm/ft2

1. 3.9 gpd/ft3

2. 3.9 gpm/ft2

3. 0.25 gpm/ft2

4. 0.25 gpd/ft3

1. 3.9 gpd/ft3

2. 3.9 gpm/ft2

3. 0.25 gpm/ft2

4. 0.25 gpd/ft3

Given

Formula

Solve:

Given

Formula

Solve:

A filter 20 ft by 35 ft receives a flow of 1530 gpm. What is the filtration rate in

gpm/ft2?

A filter 20 ft by 35 ft receives a flow of 1530 gpm. What is the filtration rate in

gpm/ft2?

2.2

gpm

/ft2

2.2

gpm

/ft3

0.4

5 gpm

/ft2

0.4

5 gpd/ft

3

89%

0%0%11%

L= 20 ft, W=35 ft; Rate 1530 gpmA=L X WFiltration Rate= (flow gpm) Area (sq ft)

A= 20 ft X 35 ft = 700 ft2

Filtration Rate= (1530 gpm) 700 (sq ft) Filtration Rate = 2.2 gpm/ft2

L= 20 ft, W=35 ft; Rate 1530 gpmA=L X WFiltration Rate= (flow gpm) Area (sq ft)

A= 20 ft X 35 ft = 700 ft2

Filtration Rate= (1530 gpm) 700 (sq ft) Filtration Rate = 2.2 gpm/ft2

1. 2.2 gpm/ft2

2. 2.2 gpm/ft3

3. 0.45 gpm/ft2

4. 0.45 gpd/ft3

1. 2.2 gpm/ft2

2. 2.2 gpm/ft3

3. 0.45 gpm/ft2

4. 0.45 gpd/ft3

Given

Formula

Solve:

Given

Formula

Solve:

A filter 25 ft by 30 ft receives a flow of 3.3 MGD. What is the filtration rate in

gpm/ft2?

A filter 25 ft by 30 ft receives a flow of 3.3 MGD. What is the filtration rate in

gpm/ft2?

3.1

gpm

/ft3

0.3

2 gpm

/ft2

3.1

gpm

/ft2

0.3

2 gpd

/ft3

0% 0%

100%

0%

L= 25 ft, W=30 ft;Rate 3.3 MG 1,000,000 gal 1 Day D 1MG 1440 minA=L X WFiltration Rate= (flow gpm) Area (sq ft)

A= 25 ft X 30 ft = 750 ft2

Filtration Rate= (2292 gpm) 750 (sq ft) Filtration Rate = 3.1 gpm/ft2

L= 25 ft, W=30 ft;Rate 3.3 MG 1,000,000 gal 1 Day D 1MG 1440 minA=L X WFiltration Rate= (flow gpm) Area (sq ft)

A= 25 ft X 30 ft = 750 ft2

Filtration Rate= (2292 gpm) 750 (sq ft) Filtration Rate = 3.1 gpm/ft2

1. 3.1 gpm/ft3

2. 0.32 gpm/ft2

3. 3.1 gpm/ft2

4. 0.32 gpd/ft3

1. 3.1 gpm/ft3

2. 0.32 gpm/ft2

3. 3.1 gpm/ft2

4. 0.32 gpd/ft3

Given

Formula

Solve:

Given

Formula

Solve:

Given

Formula

Solve:

Given

Formula

Solve:

A filter 25 ft by 10 ft has a backwash rate of 3400 gpm. What is the filter backwash

rate in gpm/ft2?

A filter 25 ft by 10 ft has a backwash rate of 3400 gpm. What is the filter backwash

rate in gpm/ft2?

13.

1 gpm

/ft3

0.0

74 g

pm/ft

2

13.

6 gpm

/ft2

136

gpd/ft

3

0% 0%

100%

0%

L= 25 ft, W=10 ft; Rate 3400 gpmA=L X WBackwash Rate = (flow gpm) Area (sq ft)

A= 25 ft X 10 ft = 250 ft2

Filter Backwash Rate= (3400 gpm) 250 (sq ft) Filter Backwash Rate = 13.6 gpm/ft2

L= 25 ft, W=10 ft; Rate 3400 gpmA=L X WBackwash Rate = (flow gpm) Area (sq ft)

A= 25 ft X 10 ft = 250 ft2

Filter Backwash Rate= (3400 gpm) 250 (sq ft) Filter Backwash Rate = 13.6 gpm/ft2

1. 13.1 gpm/ft3

2. 0.074 gpm/ft2

3. 13.6 gpm/ft2

4. 136 gpd/ft3

1. 13.1 gpm/ft3

2. 0.074 gpm/ft2

3. 13.6 gpm/ft2

4. 136 gpd/ft3

Given

Formula

Solve:

Given

Formula

Solve:

A filter 20 ft by 15 ft has a backwash rate of 4.5 MGD. What is the filter backwash

rate in gpm/ft2?

A filter 20 ft by 15 ft has a backwash rate of 4.5 MGD. What is the filter backwash

rate in gpm/ft2?

10.

4 gpm

/ft3

0.0

1 gpm

/ft2

10.

4 gpm

/ft2

0.0

1 gpd

/ft3

6%0%

94%

0%

L= 20 ft, W=15 ft; ft;Rate 4.5 MG 1,000,000 gal 1 Day D 1MG 1440min A=L X WBackwash Rate = (flow gpm) Area (sq ft)

A= 20 ft X 15 ft = 300 ft2

Filter Backwash Rate= (3125 gpm) 300 (sq ft) Filter Backwash Rate = 10.4 gpm/ft2

L= 20 ft, W=15 ft; ft;Rate 4.5 MG 1,000,000 gal 1 Day D 1MG 1440min A=L X WBackwash Rate = (flow gpm) Area (sq ft)

A= 20 ft X 15 ft = 300 ft2

Filter Backwash Rate= (3125 gpm) 300 (sq ft) Filter Backwash Rate = 10.4 gpm/ft21. 10.4 gpm/ft3

2. 0.01 gpm/ft2

3. 10.4 gpm/ft2

4. 0.01 gpd/ft3

1. 10.4 gpm/ft3

2. 0.01 gpm/ft2

3. 10.4 gpm/ft2

4. 0.01 gpd/ft3

Well ProblemsWell Problems• Drawdown ft = pumping water level – static water level ft

• Well yield = Flow gallons

duration of Test, min

• Specific yield, gpm/ft = (Well yield gpm) (Drawdown ft)

• Well casing disinfection

lbs= (dose mg/L Cl2)(water in well casing MG)(8.34 lb/gal)

Chlorine lbs = chlorine lbs

% available chlorine

100

• Drawdown ft = pumping water level – static water level ft

• Well yield = Flow gallons

duration of Test, min

• Specific yield, gpm/ft = (Well yield gpm) (Drawdown ft)

• Well casing disinfection

lbs= (dose mg/L Cl2)(water in well casing MG)(8.34 lb/gal)

Chlorine lbs = chlorine lbs

% available chlorine

100

Given

Formula

Solve:

Given

Formula

Solve:

Before the pump is started the water level is measured at 140 ft. The pump is then started. If the pumping water level is determined to be 167 ft, what is the

drawdown in ft?

Before the pump is started the water level is measured at 140 ft. The pump is then started. If the pumping water level is determined to be 167 ft, what is the

drawdown in ft?

307

ft

-27

ft 2

7 ft

0 ft

0% 0%

100%

0%

Static WL= 140 ft, Pumped WL=167 ft

Drawdown ft = pumping water level – static water level ft

Drawdown = 167 ft- 140 ftDrawdown = 27 ft

Static WL= 140 ft, Pumped WL=167 ft

Drawdown ft = pumping water level – static water level ft

Drawdown = 167 ft- 140 ftDrawdown = 27 ft

1. 307 ft

2. -27 ft

3. 27 ft

4. 0 ft

1. 307 ft

2. -27 ft

3. 27 ft

4. 0 ft

Given

Formula

Solve:

Given

Formula

Solve:

During a five minute test for well yield, a total of 740 gallons are removed from the

well. What is the well yield in gpm?

During a five minute test for well yield, a total of 740 gallons are removed from the

well. What is the well yield in gpm?

67

gpm

148

gpm

370

0 gpm

0 g

pm

0% 4%0%

96%

total = 740 gal, time = 5 minutes

Well yield = Flow gallons Duration of Test, min

Well yield = 740 gallons = 148 gpm 5 min

total = 740 gal, time = 5 minutes

Well yield = Flow gallons Duration of Test, min

Well yield = 740 gallons = 148 gpm 5 min 1. 67 gpm

2. 148 gpm

3. 3700 gpm

4. 0 gpm

1. 67 gpm

2. 148 gpm

3. 3700 gpm

4. 0 gpm

Given

Formula

Solve:

Given

Formula

Solve:

How many lbs of calcium hypochlorite (65% available chlorine) is required to disinfect a well if the casing is 18 inches in diameter and 220 ft long, with water level at 100 ft from the top of the well? The desired dose is

50 mg/L?

How many lbs of calcium hypochlorite (65% available chlorine) is required to disinfect a well if the casing is 18 inches in diameter and 220 ft long, with water level at 100 ft from the top of the well? The desired dose is

50 mg/L?

2 lb

s

1 lb

s

.02

lbs

0.6

5 lb

s

24%

6%0%

71%

Cl= 65/100 D=18 in=1.5 ft Well 220-100 =120 ft220 ft - 100 ft = 120 ft water in well(0.785)(D2)(H) = ft3

(0.785)(1.5 ft)(1.5 ft) (120 ft)(7.48 gal/ft3)= 1585 gal(50 mg/L)(.001585 MG)(8.34 lb/gal) = 1.01lbs 65/100

Cl= 65/100 D=18 in=1.5 ft Well 220-100 =120 ft220 ft - 100 ft = 120 ft water in well(0.785)(D2)(H) = ft3

(0.785)(1.5 ft)(1.5 ft) (120 ft)(7.48 gal/ft3)= 1585 gal(50 mg/L)(.001585 MG)(8.34 lb/gal) = 1.01lbs 65/100

1. 2 lbs

2. 1 lbs

3. .02 lbs

4. 0.65 lbs

1. 2 lbs

2. 1 lbs

3. .02 lbs

4. 0.65 lbs

Today’s objective: Filter Loading Rates, Filter Backwash Rates, Well yield and

chlorine dosage of new wells been met?

Today’s objective: Filter Loading Rates, Filter Backwash Rates, Well yield and

chlorine dosage of new wells been met?

Stro

ngly A

gree

Agre

e

Neu

tral

Dis

agre

e

Stro

ngly D

isag

ree

0% 0% 0%0%0%

1. Strongly Agree

2. Agree

3. Neutral

4. Disagree

5. Strongly Disagree

1. Strongly Agree

2. Agree

3. Neutral

4. Disagree

5. Strongly Disagree