fisika matematika iii (fis-208)

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  • z = x + iy x yi i =

    1

    i2 = 1

    f(z) = u(x, y) + iv(x, y)

    u(x, y) v(x, y)x y

    f(z) = z2 f(z) = z2 = (x+ iy)2 = x2y2 + i2xyu(x, y) = x2 y2 v(x, y) = 2xy

    f(z)f(z)

    f (z) = limz0

    f(z + z) f(z)z

    z = x + iy z

    f(z)

  • f(z) z = a f(z) z =a f(z)

    f(z)

    f(z) = u(x, y) + iv(x, y)

    u

    x=

    v

    yu

    y= v

    x

    u(x, y) v(x, y) x yf(x)

    f(z) = z3

    f(z) = z3 = (x + iy)3 = x3 + 3x2iy + 3x(iy)2 + (iy)3 = x3 3xy2 + i(3x2y y3)

    u(x, y) = x3 3xy2 v(x, y) = 3x2y y3

    u

    x= 3x2 3y2 ; u

    y= 6xy ; v

    x= 6xy ;

    v

    y= 3x2 3y2

    u

    x=

    v

    y

    u

    y= v

    x

    f(z) = z3

    u v x y

  • 2u

    x2+

    2u

    y2= 0

    2v

    x2+

    2v

    y2= 0

    2u = 0

    f(z) = u + iv u vu

    v

    f(z)

    z

    f(z)

    u(x, y) = x2 y2

    2u = 2u

    x2+

    2u

    y2= 2 2 = 0

    v(x, y) u + iv z

    v

    y=

    u

    x= 2x

    y

    v(x, y) = 2xy + g(x)

    g(x) x x

    v

    x= 2y +

    dg

    dx= u

    y= 2y

    dg

    dx= 0, g =

    f(z) = u + iv = x2 y2 + i(2xy + )

  • f(z)

    Cf(z)dz = 0

    z2z1

    f(z)dz z2z1

    f(z)dz = F (z2) F (z1) F (z) = f(z) f(z)

    f(z) = 2z

    C2z dz = 0

    1+i

    2i2z dz = z2|1+i2i = (1 + i)

    2 (2i)2 = 2i + 4

    f(z) a

    C

    f(z)z a dz = 2i f(a)

    a

    a

    C

    f(z)(z a)n+1 dz =

    2in!

    f (n)(a)

    f (n)(z) n f(z)

    C

    sin z2z dz

    |z| = 1 |z| = 2

  • C

    sin z2z dz =

    C

    sin z2(z 2 )

    dz =12

    C

    sin zz 2

    dz

    a = 2 = 1, 57 a

    a

    12

    C

    sin zz 2

    dz =122i sin

    2= i

    f(z) z = a

    a

    f(z) = f(a) + f (a)(z a) + f(a)2!

    (z a)2 + f(a)3!

    (z a)3 +

    f(z) f(z)f(z) f(z)

    f(z) z = a

    C1 C2 z0 f(z)R f(z)

    f(z) = a0 + a1(z z0) + a2(z z0)2 + +b1

    z z0+

    b2(z z0)2

    +

    an =1

    2i

    C

    f(z) dz(z z0)n+1

    ; bn =1

    2i

    C

    f(z) dz(z z0)n+1

    z0

    R

  • R.

    b

    b f(z) z = z0 z0

    b = 0 b bn f(z)z = z0 n = 1 f(z)

    b f(z)z = z0

    b1 1zz0 f(z) z = z0

    z0 f(z)C f(z)dz

    C z0 z0

    Cf(z)dz = 2i f(z) C

    C z0, z1,z2, . . . C0, C1C2 . . . f(z) C

    Cf(z)dz = 2i f(z) C

    C

    f(z)

    f(z) z = z0R(z0) b1 1(zz0)

    f(z) = ez

    z1 z = 1

    ez

    z 1 =e ez1

    z 1 =e

    z 1

    1 + (z 1) + (z 1)2

    2!+ . . .

    =e

    z 1 + e +e

    2(z 1) + . . .

    1z1 R(1) = e

  • f(z) z = z0f(z) (z z0) z = z0

    f(z) = z(2z+1)(5z) R(12) R(5)

    R(12) f(z) (z +12) (2z + 1)

    z = 12

    (z +12)f(z) = (z +

    12)

    z

    (2z + 1)(5 z) =z

    2(5 z)

    R(12) =

    122(5 + 12)

    = 122

    R(5)

    (z 5)f(z) = (z 5) z(2z + 1)(5 z) =

    z

    2z + 1

    R(5) = 511

    f(z) g(z)h(z) g(z) z = z0h(z0) = 0 h(z0) = 0

    R(z0) =g(z0)h(z0)

    h(z0) h(z) z = z0.

    f(z) = z(2z+1)(5z) g(z) = z h(z) = (2z + 1)(5 z)h(z) = 2(5 z) + (2z + 1)(1) = 4z + 9

    R(z0) =z0

    4z0 + 9

    R(12) =

    122 + 9

    = 122

    R(5) =5

    20 + 9 = 511

  • f(z) nf(z) (z z0)m m

    n (m 1)(m 1)! z = z0

    R(z0) =1

    (m 1)!dm1

    dzm1(z z0)mf(z)

    z=z0

    f(z) = z sin z(z)2 z =

    m = 3 (m 1) = 2

    R() =12!

    d2

    dz2z sin z

    z=

    =12(z sin z + 2 cos z)

    z=

    = 1

    2

    0

    d

    5 + 4 cos

    z = ei 0 2z |z| = 1

    z = ei dz = ieid = izd d = 1izdzcos = 12(e

    i + ei) = 12(z +1z )

    I = 2

    0

    d

    5 + 4 cos =

    C

    1izdz

    5 + 2(z + 1z )=

    1i

    C

    dz

    5z + 2z2 + 2=

    1i

    C

    dz

    (2z + 1)(z + 2)

    C f(z) z = 12z = 2 z = 12 C f(z)

    z = 12

    R(12) =

    1(2z + 1) + 2(z + 2)

    z= 12

    =1

    4z + 5

    z= 12

    =13

    I = 1i 2iR(12) =

    23

    0 13