force inclined
TRANSCRIPT
8/19/2019 Force Inclined
http://slidepdf.com/reader/full/force-inclined 1/7
FNFF
w
8/19/2019 Force Inclined
http://slidepdf.com/reader/full/force-inclined 2/7
FNFF
w
8/19/2019 Force Inclined
http://slidepdf.com/reader/full/force-inclined 3/7
FN
FF
w
w x
w y
= sin θ
= sin θ
= s i n ( θ ) = cos θ
= cos θ
= c o s ( θ )
8/19/2019 Force Inclined
http://slidepdf.com/reader/full/force-inclined 4/7
= + =
= + =
= s i n ( θ )
= c o s ( θ )
+ = 0
+ () cos(θ) = 0
= c o s ( θ )
=
=cos(θ)
= + =
cos(θ)
+ s i n ( θ ) =
sin θ cos(θ) = sin θ cos(θ) =
0
8/19/2019 Force Inclined
http://slidepdf.com/reader/full/force-inclined 5/7
= sin θ cos(θ)
= 0
0= sin θ cos(θ)
0
= sin θ cos(θ)
cos θ = sin θ
= sin θ
cos θ
= θ
If a =0
= θ
8/19/2019 Force Inclined
http://slidepdf.com/reader/full/force-inclined 6/7
Examples
• Find the acceleration of a crate sliding down a 400 inclined plane
if the coefficient of friction between the surfaces is 0.55
• = sin θ cos(θ) = 9.8 2 sin 40 0.55cos(40)
• = ? ? ? =
8/19/2019 Force Inclined
http://slidepdf.com/reader/full/force-inclined 7/7