frequency response this is an extremely important topic in ee. up until this point we have analyzed...
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Frequency Response
This is an extremely important topic in EE. Up until this point we have analyzed circuits without considering the effect on the answer over a wide range of frequencies. Many circuits have frequency limitations that are very important.
Example: Discuss the frequency limitations on the following items.
1) An audio amplifier
2) An op amp circuit
Read: Ch. 14, Sect. 1-5 in Electric Circuits, 9th Edition by Nilsson
1Chapter 14 EGR 272 – Circuit Theory II
Example: Discuss the frequency limitations on the following items (continued)
3) A voltmeter (% error vs frequency)
4) The tuner on a radio (band-pass filter)
2Chapter 14 EGR 272 – Circuit Theory II
Filters
A filter is a circuit designed to have a particular frequency response, perhaps to alter the frequency characteristics of some signal. It is often used to filter out, or block, frequencies in certain ranges, much like a mechanical filter might be used to filter out sediment in a water line.
Basic Filter Types
• Low-pass filter (LPF) - passes frequencies below some cutoff frequency, wC
• High-pass filter (HPF) - passes frequencies above some cutoff frequency, wC
• Band-pass filter (BPF) - passes frequencies between two cutoff frequency, wC1 and wC2
• Band-stop filter (BSF) or band-reject filter (BRF) - blocks frequencies between two cutoff frequency, wC1 and wC2
3Chapter 14 EGR 272 – Circuit Theory II
Ideal filters
An ideal filter will completely block signals with certain frequencies and pass (with no attenuation) other frequencies. (To attenuate a signal means to decrease the signal strength. Attenuation is the opposite of amplification.)
LM
wwC
Ideal LPF
LM
w
wC
Ideal HPF
LM
wwC1
Ideal BPF
wC2
LM
wwC1
Ideal BSF
wC2
4Chapter 14 EGR 272 – Circuit Theory II
Filter order
Unfortunately, we can’t build ideal filters. However, the higher the order of a filter, the more closely it will approximate an ideal filter.
The order of a filter is equal to the degree of the denominator of H(s).
(Of course, H(s) must also have the correct form.)
LM
wwC
Ideal LPF
3rd-order LPF
2nd-order LPF
1st-order LPF
4th-order LPF
C
KH(s) =
(s + w )
2C
KH(s) =
(s + w )
3C
KH(s) =
(s + w )
4C
KH(s) =
(s + w )
C
KH(s) =
(s + w )
5Chapter 14 EGR 272 – Circuit Theory II
Defining frequency response
Recall that a transfer function H(s) is defined as:Y(s)
H(s) X(s)
Where Y(s) = some specified output and X(s) = some specified input
In general, s = + jw. For frequency applications we use s = jw (so = 0).
So now we define:s jw
H(jw) H(s)
Since H(jw) can be thought of as a complex number that is a function of frequency, it can be placed into polar form as follows:
H(jw) H(jw) ( )w
6Chapter 14 EGR 272 – Circuit Theory II
When we use the term "frequency response", we are generally referring to information that is conveyed using the following graphs:
H(jw) vs w - referred to as the or the
20log( H(jw) ) vs w - referred to as the
(w) vs w - referred to as the
magnitude response amplitude response
log - magnitude (LM) response
phase re sponse
7Chapter 14 EGR 272 – Circuit Theory II
Example: Find H(jw) for H(s) below. Also write H(jw) in polar form.
4sH(s)
(s + 10)(s + 20)
Example:
A) Find H(s) = Vo(s)/Vi(s)
B) Find H(jw)Vo(s)
+
_ Vi(s)
+
_
R 1
sC
8Chapter 14 EGR 272 – Circuit Theory II
Example: (continued)
C) Sketch the magnitude response, |H(jw)| versus w
D) Sketch the phase response, (w) versus w
E) The circuit represents what type of filter?
9Chapter 14 EGR 272 – Circuit Theory II
Example:
A) Find H(s) = V(s)/I(s)
B) Find H(jw) V(s)
+
_
1 sC
I(s) R sL
10Chapter 14 EGR 272 – Circuit Theory II
Example: (continued)
C) Sketch the magnitude response, |H(jw)| versus w
D) Sketch the phase response, (w) versus w
E) The circuit represents what type of filter?
11Chapter 14 EGR 272 – Circuit Theory II
Example:
A) Find H(s) = Vo(s)/Vi(s)
B) Find H(jw)Vo(s)
+
_ Vi(s)
+
_
2k
10mH 3k
12Chapter 14 EGR 272 – Circuit Theory II
Example: (continued)
C) Sketch the magnitude response, |H(jw)| versus w
D) Sketch the phase response, (w) versus w
E) The circuit represents what type of filter?
13Chapter 14 EGR 272 – Circuit Theory II
General 2nd Order Transfer Function
For 2nd order circuits, the denominator of any transfer function will take on the
following form: s2 + 2s + wo2
Various types of 2nd order filters can be formed using a second order circuit, including:
122
o
KH(s) (2nd-order low-pass filter (LPF))
s 2 s w
222
o
K sH(s) (2nd-order band-pass filter (BPF))
s 2 s w
2
322
o
K sH(s) (2nd-order high-pass filter (HPF))
s 2 s w
14Chapter 14 EGR 272 – Circuit Theory II
Series RLC Circuit (2nd Order Circuit)
Draw a series RLC circuit and find transfer functions for LPF, BPF, and HPF.
Note that the denominator is the same in each case (s2 + 2s + wo2). Also show
that:o
R 1 and w for a series RLC circuit
2L LC
15Chapter 14 EGR 272 – Circuit Theory II
Parallel RLC Circuit (2nd Order Circuit)
Draw a parallel RLC circuit and find transfer functions for LPF, BPF, and HPF.
Note that the denominator is the same in each case (s2 + 2s + wo2). Also show
that:o
1 1 and w for a parallel RLC circuit
2RC LC
16Chapter 14 EGR 272 – Circuit Theory II
2nd Order Bandpass Filter
A 2nd order BPF will now be examined in more detail. The transfer function,
H(s), will have the following form:
22o
KsH(s) (2nd-order band-pass filter (BPF))
s 2 s w
Magnitude response• Show a general sketch of the magnitude response for H(s) above• Define wo , wc1 , wc2 , Hmax , BW, and Q
• Sketch the magnitude response for various values of Q (in general)
17Chapter 14 EGR 272 – Circuit Theory II
Determining Hmax
Find H(jw) and then H(jw).
Show that o
max ow = w
KH H(jw) H(jw )
2
18Chapter 14 EGR 272 – Circuit Theory II
Determining wc1 and wc2 :
maxc
H KH(jw )
2 2 2 leads to
22c1 o
22c2 o
w - w
w w
Show that
19Chapter 14 EGR 272 – Circuit Theory II
Determining wo, BW, and Q:
Show that wo is the geometric mean of the cutoff
frequencies, not the arithmetic mean. Also find
BW and Q. Specifically, show that:
o c1 c2
c2 c1
o o
w w w
BW w - w 2
w wQ
BW 2
o
Define (zeta) damping ratio
1
w 2Q
Damping ratio is simply defined here. Its significance will be seen later in this course and in other courses (such as Control Theory). Circuits with similar values of z have similar types of responses.
20Chapter 14 EGR 272 – Circuit Theory II
Example: A parallel RLC circuit has L = 100 mH, and C = 0.1 uF
1) Find wo , , Hmax , wc1 , wc2 , Hmax , BW, Q, and z
2) Show that wo is the geometric mean of the wc1 and wc2 , not the arithmetic
mean.
A) Use R = 1 kW
21Chapter 14 EGR 272 – Circuit Theory II
Example: A parallel RLC circuit has L = 100 mH, and C = 0.1 uF
1) Find wo , , Hmax , wc1 , wc2 , Hmax , BW, Q, and z
2) Show that wo is the geometric mean of the wc1 and wc2 , not the arithmetic
mean.
B) Use R = 20 kW
22Chapter 14 EGR 272 – Circuit Theory II
Example: Plot the magnitude response, |H(jw)|, for parts A and B in the last
example. (Note that a curve with a geometric mean will appear symmetrical on
a log scale and a curve with an arithmetic mean will appear symmetrical on a
linear scale.)
0
2
4
6
8
10
1000 10000 100000
5k 6k 7k 8k 9k 10k 20kw (log scale)
|H(jw)|
23Chapter 14 EGR 272 – Circuit Theory II