gauss jordan
DESCRIPTION
gauss jordanTRANSCRIPT
berikut contoh soal persamaan linear 3 variabel:
2x + 3y – z = 53x + y + 2z = 113x – 2y +3z = 8
bikin model matrik nya dari 3 persamaan di atas
| 2 3 -1 || 3 1 2 || 3 -2 3 |
buat matrik utama tersebut kedalam bentuk matriks identitas
| 2 3 -1 | 5 | 1 0 0 | x| 3 1 2 | 11 => | 0 1 0 | y| 3 -2 3 | 8 | 0 0 1 | z
1. baris 1 dibagi dengan 2
| 1 3/2 -1/2 | 5/2 | 1 0 0 | x| 3 1 2 | 11 => | 0 1 0 | y| 3 -2 3 | 8 | 0 0 1 | z
2. baris 2 dikurangi dengan baris 3
| 1 3/2 -1/2 | 5/2 | 1 0 0 | x| 0 3 -1 | 3 => | 0 1 0 | y| 3 -2 3 | 8 | 0 0 1 | z
3. baris 3 dikurangi (baris 1 * 3)
| 1 3/2 -1/2 | 5/2 | 1 0 0 | x| 0 3 -1 | 3 => | 0 1 0 | y| 0 -13/2 9/2 | 1/2 | 0 0 1 | z
4. baris 3 dikali 2
| 1 3/2 -1/2 | 5/2 | 1 0 0 | x| 0 3 -1 | 3 => | 0 1 0 | y| 0 -13 9 | 1 | 0 0 1 | z
5. baris 2 dibagi 3
| 1 3/2 -1/2 | 5/2 | 1 0 0 | x| 0 1 -1/3 | 1 => | 0 1 0 | y| 0 -13 9 | 1 | 0 0 1 | z
6. baris 3 ditambah (baris 2 * 13)
| 1 3/2 -1/2 | 5/2 | 1 0 0 | x| 0 1 -1/3 | 1 => | 0 1 0 | y| 0 0 14/3 | 14 | 0 0 1 | z
7. baris 3 dibagi 14/3
| 1 3/2 -1/2 | 5/2 | 1 0 0 | x| 0 1 -1/3 | 1 => | 0 1 0 | y| 0 0 1 | 3 | 0 0 1 | z
8. baris 1 dikurangi (baris 2 * 3/2)
| 1 0 0 | 1 | 1 0 0 | x| 0 1 -1/3 | 1 => | 0 1 0 | y| 0 0 1 | 3 | 0 0 1 | z
9. baris 2 dikurangi (baris 3 * -1/3)
| 1 0 0 | 1 | 1 0 0 | x| 0 1 0 | 2 => | 0 1 0 | y| 0 0 1 | 3 | 0 0 1 | z