general view on the duality between statics and kinematics m.sc student: portnoy svetlana advisor:...
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General view on the duality between statics and kinematics
M.Sc student: Portnoy Svetlana
Advisor: Dr. Offer Shai
The outline of the talk
1 .The two reported types of graph theory duality.
2 .Duality between trusses and linkages and the theoretical results derived from it .
3 .The relation between Maxwell reciprocal diagram and graph theory duality.
4 .Introducing polyhedral interpretation for the theoretical results obtained from this duality .
5 .The second type of duality – duality between Stewart Platforms and serial robots and its
projective geometry interpretation .
6 .Example of a practical application based on the theoretical results
obtained in this research .
7 .Further research .
The graph theory duality
Stewart Platform and Serial robotTruss and Mechanism
1’
2’
3’
4’
5’
6’
7’
8’
9’
10’
11’
12’
13’
1
2
3
4
5
6
7
8
9
10
11
12 1
3
The two reported types of graph theory duality .
2’
3’
We obtain the dual systems.
1O/AV
3O/BV
The relative linear velocity of the driving link is equal to the corresponding external force.
The absolute linear velocity corresponds to the new variable in statics – face force.
1
2A
B
O1 O3
3
B/AV
1’
P
'3F
'2F
AFF
BFF
PV10/A
'330/B FV
'2B/A FV
B30/B FFV
A
10/A FFV
What kind of a variable corresponds to the absolute linear velocity ?
Duality between trusses and linkages and the theoretical
results derived from it .
The relative linear velocity of each link is equivalent to the force acting in the corresponding rod.
The relation between Maxwell reciprocal diagram
and graph theory duality .
C
A B
D
F1
B
C
D
V1’
A B
C
D
12
3
45
6
7
8
9
O
1F
1F
BFFAFF
CFFDFF
The truss underlying the reciprocal diagram has infinitesimal motion.
Removing link 1 and turning its internal force (the blue arrow), into an external force acting upon a linkage in a locked position
The original and the dual graphs
The unstable truss dual to the linkage in a locked position.
A
Applying rotation to the reciprocal diagram.
The Relation between Static Systems, Mobile Systems and Reciprocity
AV
BV
CV
DV
CD
B
A
AV
BV
CV
DV
B
A
O D
C
Maxwell’s theorem 1864: The isostatic framework that satisfies E=2*V-3 has a self stress iff it has a reciprocal diagram.
B
1’
2’
3’ 4’
6’
9’5’
A
O
7’
8’
D
CThe reciprocal diagram
The isostatic framework
O
V1’
The isostatic framework has a self-stress.
B
A
O D
C
For every link there exists a point where its linear velocity is equal to zero.
For every force there exists a line where the moment it exerts is equal to zero.
joI0V
joI
j
jF jom
0Mjoj mF
For every two links there exists a point where their linear velocities are equal. .
For every two forces there exists a line, such that the moments exerted by the two forces on each point on the line are equal.
k
jkjk IkIj VV
jkkjkj mFmF MM
jF
kFjkm
j
Kinematics in 2DStatics in 2D
Theoretical results obtained from the duality between trusses
and linkages .
jkI
l
k
j
jlI
jkI
jlm
klI
klm
jkm
kF
jF
lF
The Kennedy Theorem. For any three links, the corresponding three relative instant centers
must lie on the same line .
The Dual Kennedy Theorem. For any three forces, the corresponding three relative equimomental lines
must intersect at the same point .
The isostatic framework that has a self-stress.
Maxwell’s theorem (1864): Isostatic framework that satisfies E=2*V-3 has a self stress IFF it is a projection of a polyhedron.The sufficient part was proved only in 1982 by Walter Whitely .
A B
C
D
1
2
3
45
6
78
9
O
A
B
D
C
O
12
3
4
5
67
89
The isostatic framework The corresponding polyhedron
a
b
c
d
e
f
a
b
c
d
e
f
Introducing a polyhedral interpretation for the theoretical results obtained from this duality .
An EQML mBD == An edge between vertices B and D in the dual Kennedy circle == An intersection line between
planes B and D in the polyhedron .
Triangle in the dual Kennedy circle == An intersection point of the corresponding three EQML.
An equimomental line between two adjacent faces== A known edge in the dual Kennedy circle between two corresponding vertices== An intersection line between two adjacent planes in the polyhedron.
An EQML between two nonadjacent faces == An unknown edge in the dual Kennedy circle between two corresponding vertices == An intersection line between two nonadjacent planes.
Two triangles that include the EQML in the circle == Points that this line passes through them.
mDO corresponds to the intersection line between plane D and the projection plane - O .
An EQML mCO == An edge between vertices C and O in the dual Kennedy circle == An intersection line
between planes C and O in the polyhedron .
An EQML mCD == An edge between vertices C and D in the dual Kennedy circle== An intersection line between
planes C and D in the polyhedron .
A face in the framework == A vertex in the Dual Kennedy circle == A plane in the polyhedron.
A reference face O== A reference vertex in the dual Kennedy circle==A projection plane in the
polyhedron .
An EQML mBO == An edge between vertices B and O in the dual Kennedy circle== An intersection line between
planes B and O in the polyhedron .
Geometric interpretation for the new variable – the equimomental line.
A
B
D
C
O
12
3
4
5
67
89
B
C
D
12
3
45
6
78
9
O
DOm
BOm
COm
The projection plane .
The isostatic framework
The corresponding
polyhedron BO
CO
O
A
BC
D
The dual Kennedy circle
BDm
CDm
Constructing the dual Kennedy circle for finding all the equimomental lines.
A
DOBD
CD
8
5
9
3
83 95
9583mDO
For every link there exists a point where its linear velocity is equal to zero.
For every force there exists a line where the moment it exerts is equal to zero.
0VjoI
j
jF jom
0Mjoj mF
For every two links there exists a point where their linear velocities are equal.
For every two forces there exists a line, such that the moments exerted by the two forces on each point on the line are equal.
jkjk IkIj VV
jkkjkj mFmF MM
kF
jkm
j
joI
k
jlI
jkI klI
The Kennedy Theorem. For any three links, the corresponding three relative instant centers must lie on the same line.
l
k
j
jF
jlm
klm
jkm
kF
jF
lF
The Dual Kennedy Theorem. For any three forces, the corresponding three relative equimomental lines must intersect at the same point.
For every plane there exists a line where it intersects the
projection plane .
J
O
For every two planes there exists a line where they intersect.
J
K
JO
JK
Every three planes must intersect at a point .
Kinematics in 2DStatics in 2DGeometry in 3D
jkI
Consider a Stewart platform system.
The projective geometry interpretation (4D) of the second type of graph theory
duality yielding the duality between Stewart platforms and serial robots
1
24
56
3
O
I
P
Stewart platform
1
24
56
3
O
I
P
Stewart platform
61 2 3 4 5
I
Every platform element corresponds to a vertex and every leg to an edge .
The original graph
P
O
1
24
56
3
O
I
P
Stewart platform
61 2 3 4 5
I
The original graph
P
O
The dual graph
1’ 2’ 3’
4’ 5’ 6’
A
B C D E F
1
24
56
3
O
I
P
Stewart platform
61 2 3 4 5
I
The original graph
P
O
The dual graph
1’ 2’ 3’
4’ 5’ 6’
A
B C D E F
Serial robot
Every joint corresponds to a link and an edge to a joint.
A
BC
E
D
F
1’
2’3’
4’
5’6’
1
24
56
3
O
I
P
Stewart platform
61 2 3 4 5
I
The original graph
P
O
The dual graph
1’ 2’ 3’
4’ 5’ 6’
A
B C D E F
Serial robot
Every joint corresponds to a link and edge to a joint.
A
BC
E
D
F
1’
2’3’
4’
5’6’
The force in the leg of Stewart platform is identical to the relative angular velocity of the corresponding joint in the
dual serial robot . P
4F
5/4
4’
5’
4
The duality relation between Stewart platforms and serial robots.
5/44F
The magnitude and the unit direction of the force correspond to the second projective
point that is located at infinity .
"Force" applied at point ‘p’ F(p) is defined by: the force and the point .
Motion in the projective plane is a line that joints between two projective points .
The angular velocity and the instant center correspond to the first projective point.
The point p corresponds to the second projective point.
Adding a dimension and defining a projective plane on Z=1.
The point p corresponds to the first projective point.
Y
X
p
c
c
Z
p
Z=1 pc
Y
X
p
Z
p
Z=1pq
qf
q
pcM pqF
The relation between kinematics and statics through projective geometry.
Kinematics Statics
Motion of a point ‘p’ on a link - M(p) is defined by: the instant center, angular velocity and the
point on the link .
Adding a dimension and defining a projective plane on Z=1 .
Introducing the motion in the projective plane.
Introducing the “force” in the projective plane.
It follows that the magnitude of the angular velocity is equivalent to the magnitude of the force vector. The "force" in the projective plane is a line that
joints between two projective points, one is at the infinity .
10
29
3
6
711
4
A
B
C
D
E
O
8
DO
Testing whether a line drawing is a correct projection of a polyhedron.
A
B
C
E
O
D
10
8
7
9
2
64
3
11
Which of the drawings is a projection of a polyhedron?
O
A
B
C
D
E
Dual Kennedy circle
11
55 For example, checking the existence of the EQML mDO
The EQML mDO should pass through three points The EQML mDO cannot pass through the three points , thus
this drawing is not a projection of a polyhedron .
Finding all the EQML there exists a self stress in the configuration (Maxwell+Whiteley) it is a
projection of a polyhedron
The EQML mDO passes through the three points. Since all the EQML can be found, the drawing is a projection of a
polyhedron .
1
311
7
10
8
117
108 108
117
31 31
31108117mDO
Marking all known EQML.EQMLs needed for finding mDO.
Example of a practical application based on the theoretical results
obtained in this research .
Further research:
-Employing the theoretical results for additional practical applications, such as:
combinatorial rigidity – found to be important in biology, material science, CAD and more.
-Developing new synthesis methods.
-Applying the methods for static-kinematic systems, such as: deployable structures,
Tensegrity Systems and more .
Thank you!