graph each function. label the vertex and axis of symmetry
DESCRIPTION
4.2. WARM-UP. Graph each function. Label the vertex and axis of symmetry. Vertex is (0,0). Axis of symmetry is x = 0. y = 5 x 2 y = 4 x 2 + 1 y = - 2 x 2 – 6 x + 3. Vertex is (0,1). Axis of symmetry is x = 0. Vertex is (-1.5,7.5). Axis of symmetry is x = -1.5. 4.2. - PowerPoint PPT PresentationTRANSCRIPT
Graph each function. Label the vertex and axis of symmetry.
1. y = 5x2
2. y = 4x2 + 1
3. y = -2x2 – 6x + 3
4.2
Vertex is (0,0).
Axis of symmetry is x = 0.
Vertex is (0,1).
Axis of symmetry is x = 0.
Vertex is (-1.5,7.5).
Axis of symmetry is x = -1.5.
In the previous lesson we graphed quadratic functions in Standard
Form: y = ax2 + bx + c, a ≠ 0
Today we will learn how to graph quadratic functions in two more forms:
Vertex Form
Intercept Form
4.2
Vertex Form
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This is another text box to take up room!1. The graph is a parabola
with vertex (h, k).
Graph Vertex Form: y = a (x – h)2 + k
Characteristics of the graph of:
y = a (x – h)2 + k
2. The axis of symmetry is x = h
3. The graph opens up if a > 0 and opens down if a < 0.
(h, k)y = x2 (h, k)
y = a (x – h)2 + k
x = h Axis of symmetry
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GUIDED PRACTICEGraph the function. Label the vertex and axis of symmetry.
2. y = (x + 2)2 – 3
Vertex (h, k) = (– 2, – 3).
Axis of symmetry is x = – 2.
3. y = – (x + 1)2 + 5
Vertex (h, k) = (– 1, 5).
Axis of symmetry is x = – 1.
Opens down a < 0. (-1 < 0)
GUIDED PRACTICE4. f (x) = (x – 3)2 – 412
Vertex (h, k) = ( 3, – 4).
Axis of symmetry is x = 3.
Opens up a > 0. (1/2 < 0)
Intercept FormGraph Intercept Form: y = a (x – p) (x – q)
Characteristics of the graph of y = a (x – p) (x – q):
1. The x – intercepts are p and q, so the points (p, 0) and (q, 0) are on the graph.
2. The axis of symmetry is halfway between (p, 0) and (q, 0) and has equation: x = (p + q) / 2
3. The graph opens up if a > 0 and opens down if a < 0.
(p, 0)
(q, 0)
x = (p + q) / 2
y = a (x – p) (x – q)
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Graph the function.
6. y = (x – 3) (x – 7)
x - intercepts occur at the points (3, 0) and (7, 0).
Axis of symmetry is x = 5
Vertex is (5, – 4).
7. f (x) = 2(x – 4) (x + 1)
x - intercepts occur at the points (4, 0) and (– 1, 0).
Axis of symmetry is x = 3/2.
Vertex is (3/2, 25/2).
GUIDED PRACTICE8. y = – (x + 1) (x – 5)
x - intercepts occur at the points (– 1, 0) and (5, 0).
Vertex is (2, 9).
Axis of symmetry is x = 2.
Changing quadratic functions from intercept form or vertex form to
standard form.
FOIL Method:To multiply two expressions that each contain two terms, add the
products of the First terms, the Outer terms, the Inner terms, and the Last terms.
Example:
F O I L
(x + 4)(x + 7) = x2 + 7x + 4x + 28
= x2 + 11x + 28
EXAMPLE 5Change from intercept form to standard form.
Write y = – 2 (x + 5) (x – 8) in standard form.
y = – 2 (x + 5) (x – 8)
= – 2 (x2 – 8x + 5x – 40)
= – 2 (x2 – 3x – 40)= – 2x2 + 6x + 80
EXAMPLE 6Change from vertex form to standard form.
Write f (x) = 4 (x – 1)2 + 9 in standard form.
f (x) = 4(x – 1)2 + 9
= 4(x – 1) (x – 1) + 9= 4(x2 – x – x + 1) + 9
= 4(x2 – 2x + 1) + 9= 4x2 – 8x + 4 + 9= 4x2 – 8x + 13
GUIDED PRACTICEWrite the quadratic function in standard form.
7. y = – (x – 2) (x – 7)
y = – (x – 2) (x – 7)
= – (x2 – 7x – 2x + 14)
= – (x2 – 9x + 14)
= – x2 + 9x – 14
8. f(x) = – 4(x – 1) (x + 3)
= – 4(x2 + 3x – x – 3)
= – 4(x2 + 2x – 3)
= – 4x2 – 8x + 12
GUIDED PRACTICE
9. y = – 3(x + 5)2 – 1
y = – 3(x + 5)2 – 1
= – 3(x + 5) (x + 5) – 1= – 3(x2 + 5x + 5x + 25) – 1
= – 3(x2 + 10x + 25) – 1= – 3x2 – 30x – 75 – 1= – 3x2 – 30x – 76
Homework: p. 249: 3-52 (EOP)