hindi paper code kota (rajasthan) form number …(4) cycas, pisum, euglena 2. read the following...
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Your Target is to secure Good Rank in Pre-Medical 2015
Path to Success
CAREER INSTITUTEKOTA (RAJASTHAN)
T M
FORM NUMBER
(ACADEMIC SESSION 2014-2015)
PAPER CODE
ALLEN AIPMT TEST DATE : 25 - 04 - 2015
0 1 C M 3 1 4 2 4 5
TARGET : PRE-MEDICAL 2015
Corporate Office
CAREER INSTITUTE
“SANKALP”, CP-6, Indra Vihar, Kota (Rajasthan)-324005
+91-744-5156100, 2436001 [email protected]
CLASSROOM CONTACT PROGRAMME
1. A seat marked with Reg. No. will be allotted to each student. The student should ensure that he/she occupies the correct seat only.If any student is found to have occupied the seat of another student, both the students shall be removed from the examination andshall have to accept any other penalty imposed upon them.
2. Duration of Test is 3 Hours and Questions Paper Contains 180 Questions. The Max. Marks are 720.
31807203. Student can not use log tables and calculators or any other material in the examination hall.
4. Student must abide by the instructions issued during the examination, by the invigilators or the centre incharge.
5. Before attempting the question paper ensure that it contains all the pages and that no question is missing.
6. Each correct answer carries 4 marks, while 1 mark will be deducted for every wrong answer. Guessing of answer is harmful.
17. A candidate has to write his / her answers in the OMR sheet by darkening the appropriate bubble with the help of Blue / Black Ball
Point Pen only as the correct answer(s) of the question attempted.
OMR
8. Use of Pencil is strictly prohibited.
INSTRUCTIONS ()
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ENTHUSIAST, LEADER & ACHIEVER COURSE
Test Type : MAJOR Test Pattern : AIPMT
Hindi
Do not open this Test Booklet until you are asked to do so /
TEST SYLLABUS : FULL SYLLABUS
Note : In case of any Correction in the test paper, please mail to [email protected] within 2 days along with Your FormNo. & Complete Test Details.
Correction Form No. Test Details [email protected] mail
1 4
(ALL PHASE)
Phase/ENTHUSIAST, LEADER & ACHIEVER/25-04-2015
H-1/37Kota/01CM314245
1. Which of the following set of examples exemplify
'Cryptogamia' ?
(1) Pinus, Pisum, Riccia
(2) Salvinia, Sphagnum, Eucalyptus
(3) Funaria, Dryopteris, Ulothrix
(4) Cycas, Pisum, Euglena
2. Read the following statements (A-D) regarding
Platyhelminthes.
A. They have dorso-ventrally flat body.
B. Bilaterally symmetrical, Diploblastic and
acoelomate animals.
C. Specialised cell called renette cell helps in
Osmoregulation and exertion.
D. Fertilization is internal.
How many of the above statements are correct ?
(1) Four (2) One
(3) Three (4) Two
3. How many of the following are concerned with
monocarpellary gynoecium with unilocular and
superior ovary ?
Gram, Arhar, Sem, Moong, Soyabean, Lupin,
Tobacco, Tomato, Potato, Tulip, Ahwagandha
(1) 7 (2) 6 (3) 3 (4) 5
4. In the given diagram, which of the following is
correct match of structure with its function :-
A
B
C
(1) A-Gall bladder - secretion of bile and enzymes
(2) C-Pancreas - secretion of pepsin and insulin
(3) B-Duodenum - secretion of trypsin
(4) B-Pancreas - secretion of insulin and glucagon
1. (1)
(2)
(3) (4)
2. (A-D) A. B.
C.
D. ?(1) (2) (3) (4)
3.
:
(1) 7 (2) 6 (3) 3 (4) 5
4. :-
A
B
C
(1) A- -
(2) C--
(3) B- -
(4) B- -
BEWARE OF NEGATIVE MARKING
HAVE CONTROL HAVE PATIENCE HAVE CONFIDENCE 100% SUCCESS
Kota/01CM314245H-2/37
Major Test For Target : Pre-Medical 2015/25-04-2015
5. Which of the following is the correct match of
supply of blood to organ and its blood :-
Blood Organ Blood vessel
1 DeoxygenatedHeartmuscles
Coronaryartery
2 Oxygenated Lungspulmonaryartery
3 DeoxygenatedSmallintertine
Hepatic portalvein
4 Oxygenated Liver Hepatic artery
6. Following are the events that occur duringmeiosis.
(A) Compaction of chromosomes start(B) DNA replication
(C) Meiotic spindle assembled(D) Dissolution of synaptonemal complex
(E) Action of recombinase enzyme(F) Seperation of sister chromatids
(G) Segregation of homologous chromosomes(H) Formation of tetrad of cells
Which of the following is the correct sequence ofevents ?
(1) B A C D F E G H(2) B A E D C G F H
(3) A B E D C F G H(4) B A E D C F G H
7. Monosaccharide is :-(a) Pentose sugar (b) Hexose sugar
(c) Triose sugar(1) a and b only (2) a and c only
(3) b and c only (4) All of the above8.
Chlorophyll b
Carotenoids
Abs
orba
nce
of
ligh
t by
ch
loro
pla
st p
igm
ents
Chlorophyll a
400 500 600 700
Wavelength of light in nanometres
Which of the following statement is not correct
with reference to above given diagram ?
(1) Chl b absorb more Red light than Chl a
(2) Chl b absorb more Blue light than Chl a
(3) This figure represent the absorption spectrum.
(4) Carotenoids absorbs the light of intermediate
wavelengths .
5. :-
1
2
3
4
6. (A) (B) DNA (C) (D) (E) (F) (G) (H) (tetrad) ?(1) B A C D F E G H
(2) B A E D C G F H
(3) A B E D C F G H
(4) B A E D C F G H
7. :-(a) (b) (c) Triose (1) a b (2) a c(3) b c (4)
8.
Chlorophyll b
Carotenoids
Ab
sorb
ance
of
lig
ht
by
chlo
ropla
st p
igm
ents
Chlorophyll a
400 500 600 700
Wavelength of light in nanometres
:-(1) Chl b, Chl a
(2) Chl b, Chl a
(3) (4)
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9. RBC :-(1) (2) ANF
(3) (4) 10. ""
(1) (2)(3) (4)
11. :-A.
B.
C.
D. (1) A C (2) C D(3) B D (4) C
12. :-(i) (a) (ii) (b) (iii) (c) (iv) (d)
(i) (ii) (iii) (iv)
(1) (c) (a) (d) (b)(2) (a) (c) (d) (b)
(3) (c) (a) (b) (d)(4) (a) (b) (c) (d)
13. :-(1) (2) (3) (4)
14. (1) (thecodont) (Diphyodont )
(2)
(3) crypts)
(4)
9. A peptide hormone produced by juxtaglomerular
cells of kidney which stimulate RBC production
is :-
(1) Erythropoietin (2) ANF
(3) Secretin (4) Cholecystokinin
10. Which of the following cell is responsible for cell
mediated immunity ?
(1) T-lymphocytes (2) Monocytes
(3) B-lymphocytes (4) Neutrophils
11. Choose the incorrect statement from followings.A. The most advanced gametophyte is found in
mosses among bryophytesB. Highly reduced gametophyte, which is having
limited numbers of cells is found in floweringplants.
C. In both bryophtes and pteridophytessporophyte is free living.
D. Gametophyte is always non-vascular.(1) A and C (2) C and D
(3) B and D (4) Only C12. Match the following :-
(i) Aplysia (a) Pearl oyster(ii) Pinctada (b) Hook worm
(iii) Limulus (c) Sea hare(iv) Ancylostoma (d) King crab
(i) (ii) (iii) (iv)(1) (c) (a) (d) (b)
(2) (a) (c) (d) (b)(3) (c) (a) (b) (d)
(4) (a) (b) (c) (d)13. Which of the following characterise the habitat of
an organism ?(1) Physiochemical or abiotic components only(2) Living members only(3) Only place, where organism lives(4) The place where organism lives along with
abiotic components and biotic componentslike pathogens, parasites, predators andcompetitors.
14. Which of the following option is incorrect for the
human digestive system :-
(1) Teeth are thecodont and diphyodont
(2) Serosa is the outer most layer of alimentary
canal and it is madeup of a thin mesothelium
(3) Submucosa forms glands in the stomach
(gastric glands) and crypts in between the
bases of villi in the intestine.
(4) The opening of the stomach into the duodenum
is guarded by the pyloric sphincter
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Major Test For Target : Pre-Medical 2015/25-04-2015
15. A,B,C D
:-
]]
GrindingregionIncisingregion
B
C
D
A
EB
C
D C B A
1
2
3
4
16. :-(1) 9 : 3 : 4, 9 : 7 (2) 9 : 7, 12 : 3 : 1
(3) 9 : 3 : 3 : 1, 9 : 7 (4) 12 : 3 : 1, 9 : 7
17.
:-
(1)
(2)
(3)
(4) 18. 10
(1) 10
(2) 10
(3) 10
(4) 10
15. In the given diagram of mouth parts of cockroach
Identify A,B,C and D and choose correct option :-
]]
GrindingregionIncisingregion
B
C
D
A
EB
C
D C B A
1 Labrum Labium Mandible Maxilla
2 Labrum Maxilla Mandible Labium
3 Labium Maxilla Mandible Labrum
4 Maxilla Labium Mandible Labrum
16. Complementary and epistasis gene interaction
ratio is respectivily :-
(1) 9 : 3 : 4, 9 : 7 (2) 9 : 7, 12 : 3 : 1
(3) 9 : 3 : 3 : 1, 9 : 7 (4) 12 : 3 : 1, 9 : 7
17. If both strands of DNA in a given segment of DNA
are transcribed then the two RNA molecules
formed will be :-
(1) Parallel and complementary
(2) parallel and identical
(3) Antiparallel and complementary
(4) Antiparallel and identical
18. A plant has critical photoperiod of 10 hours and
it is being considered as long day plant because
it flowers when :-
(1) Photoperiod of less than 10 hours is given
(2) Seed is exposed to 10 hours of light before
sowing
(3) Photoperiod of more than 10 hours is given
to shoot apex
(4) Photoperiod of more than 10 hours is given
to mature leaves
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19.
:-
(1)
(2)
(3)
(4)
20. :-(1) CT (2) PET
(3) MRI (4) 21. A, B, C, D
A, B, C
D :-
D
A B C
A B C D
1.
2.
3.
4.
22. :-(A) – (B) – (C) – (D) – (1) A C (2) B D(3) C D (4) D C
19. Read all statement's carefully and find out wrong
statement :-
(1) Cerebellum has very convoluted surface in
order to provide the additional space for many
neuron.
(2) Hypothalamus control's body temperature,
urge of eating and drinking.
(3) Transmission of impulse across electrical
synapse is very similar to impulse conduction
along a single axon.
(4) in resting state, axonal membrane is
comparatively more permeable for sodium
ions and nearly impermeable for potassium
ions.
20. Which of the following is based on use of
magnetic field ?
(1) CT-Scan (2) PET
(3) MRI (4) Sonography
21. In given flow chart A, B, C, and D represent
different classes of Kingdom Fungi. Identify the
A, B, C and D for given information :-
Fungi
Sexual Reproduction
Known Not Known / Absent
Aseptate
Mycelium
Septate
D
A B C
A B C D
1. Phycomycetes Deuteromycetes Ascomycetes Basidiomycetes
2. Ascomycetes Phycomycetes Basidiomycetes Deuteromycetes
3. Deuteromycetes Basidiomycetes Ascomycetes Phycomycetes
4. Phycomycetes Ascomycetes Basidiomycetes Deuteromycetes
22. Choose correct option from the following table :-
(A) Aptenodytes – Pigeon
(B) Canis – Cat
(C) Delphinus – Common dolphin
(D) Neophron – Vulture
(1) A and C (2) B and D
(3) C and D (4) D and C
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Major Test For Target : Pre-Medical 2015/25-04-2015
23. A –
B–
(1) A B B, 'A'
(2) A B B, A
(3) A B (4) A B
24. :-(1)
(2)
(3) (4)
25. WBCs :-(1) (2) (3) (4)
26. (1) 25% (2) 50% (3) 75% (4) 100%
27. :-(1) p2 (2) q2
(3) p2 + 2pq (4) p2 + q2
28. ?(i) (ii) (iii) (iv)
:-(1) I, II (2) I, III
(3) I, II, IV (4) I, II, III, IV
29. :-(1) (2) (3) (4)
23. A– The temperature on land is closely linked with
availability of light.
B–Sun light is the source of both light and
temperature on earth.
(1) Both 'A' and 'B' are correct and 'B' is the correct
explaination of 'A'
(2) Both 'A' and 'B' are correct but 'B' is incorrect
explanation of 'A'
(3) A is correct but B is incorrect
(4) A and B both are incorrect
24. Which of the following is incorrect statement :-
(1) Earthworm use their moist cuticle for
respiration of gases.
(2) Special vascularised structures called gills are
used by most of the aquatic arthropods and
molluscs for respiration
(3) Frogs can respire through their moist skin also
(4) Human pharynx is a cartilagenous box which
helps in sound production and hence called the
sound box.
25. Which WBCs resist infections and are also
associated with allergic reactions :-
(1) Lymphocytes (2) Neutrophils
(3) Eosinophils (4) Monocytes
26. A woman carrier for albinism and also carrier for
colourblindness marries with albinic and
colourblind male. Then find out percentage of
progeny with both colourblindness and albinism.
(1) 25% (2) 50% (3) 75% (4) 100%
27. According to Hardy Weinbergh law the frequency
of organism having homozygous character will be:-
(1) p2 (2) q2
(3) p2 + 2pq (4) p2 + q2
28. Which of the following statements are true about
vernalization ?
(i) Helpful to convert biennial plant in to annual
(ii) It hastens flowering by a cold treatment
(iii) It does not occur in dry seed
(iv) It helps in shortning of vegetative period of
plants
Options :-
(1) I, II (2) I, III
(3) I, II, IV (4) I, II, III, IV
29. Inflammation of joint's due to accumulation of uric
acid crystals is called :-
(1) Rheumatoid Arthritis
(2) Gouty Arthritis
(3) Muscular dystrophy
(4) Tetany
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30. :-
(1)
(2)
(3)
(4) B ELISA
31. :-
(1) –
(2) –
(3) –
(4) –
32.
?
(1)
(2)
(3)
(4)
33.
C
B
A
:-
(1) C (2) B
(3) A (4) A B
30. Which of the following pair is not matched
correctly :-
(1) Diptheria Schick test
(2) Leprosy Multi drug therapy
(3) Typhoid Torniquet test
(4) Hepatitis-B ELISA test
31. Find the incorrect match :-
(1) Heterocysts – Nitrogen fixation
(2) Lichen – Indicator of air
pollution
(3) Selaginella – Prothallus
(4) Marchantia – Antheridiophore
32.
Given figure does not explain :-
(1) Terminal position of shoot apical meristem
(2) Acropetalous arrangement of leaves on stem
(3) Origin of axillary buds
(4) Origin of root cap
33. Carefully observe the diagram given below.
External level
Inte
rnal
lev
el
C
B
A
Birds and mammals are :-
(1) C (2) B
(3) A (4) A or B
Kota/01CM314245H-8/37
Major Test For Target : Pre-Medical 2015/25-04-2015
34. A-D :-A. 6000 8000
B. O2 CO2 20–25
C. (pneumotaxic)
D. 100 CO2 4
(1) (2) (3) (4)
35. (A-D) A. B. C.
(stresses)
D.
:-(1) (2) (3) (4)
36. 4 (1) 15 (2) 10 (3) 20 (4) 12
37.
(i) (A)
(B)
(C)
(D)
(ii)
(iii)
(iv)
(1) (i) – A, (ii) – B, (iii) – C, (iv) – D
(2) (i) – D, (ii) – C, (iii) – A, (iv) – B
(3) (i) – C, (ii) – D, (iii) – B, (iv) – A
(4) (i) – B, (ii) – C, (iii) – D, (iv) – A
38. :-(1) (2) (3) (4)
34. Read the following A-D statements :-
A. A healthy man can inspire or expire
approximately 6000 to 8000 mL of air per
minute
B. The solubility of O2 is 20–25 times higher than
that of CO2
C. The pneumotaxic centre can moderate the
functions of the respiratory rhythum centre.
D. Every 100 ml of deoxygenated blood delivers
approximately 4mL of CO2 to the alveoli
How many of the above statements are correct :-
(1) Four (2) Three (3) Two (4) One
35. Read the following (A-D) statements
A. It is made of more than one layer (multi
layered) of cells
B. If has a limited role in secretion and absorption
C. Their main function is to provide protection
against chemical and mechanical stress
D. It covers the dry surface of the skin and the
moist surface of buccal cavity.
Howmany of the above statements are correct for
compound epithelium :-
(1) Four (2) Three (3) Two (4) One
36. Coat colour of rabbit is controlled by 4 alleles then
find out types of genotype.
(1) 15 (2) 10 (3) 20 (4) 12
37. Match the following.
(i) (A) Monozygotictwins
(B) Carrier for srecessive
disease
exlinked
(C) Carrier forautosomalrecessive disease
(D) Normal female
(ii)
(iii)
(iv)
(1) (i) – A, (ii) – B, (iii) – C, (iv) – D
(2) (i) – D, (ii) – C, (iii) – A, (iv) – B
(3) (i) – C, (ii) – D, (iii) – B, (iv) – A
(4) (i) – B, (ii) – C, (iii) – D, (iv) – A
38. During photorespiration, oxidation, deamination
and decarboxylation takes place in :-
(1) chloroplast
(2) mitochondria
(3) peroxisome
(4) Both mitochondria and peroxisome
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39. :-
(1) (2)
(3) (4) 40.
:- (1) 5 (2) 3 (3) 4 (4) 2
41.
(1) (2) (3) (4) 1 3
42.
:-(1) (2) (3) (4)
43. ?(1) (2) (3) (4)
44.
:-
(1) -
(2) -
(3) -
(4) -
39. Fluid of seminal vesicles and prostate fluids get
mixed in :-
(1) Seminal ducts (2) Ejaculatory ducts
(3) Prostatic urethra (4) Vas deferens
40. In the given list how many factors are not included
in physiological barriers :-
Acid in stomach, Saliva in mouth, Skin,
PMNL-neutrophils, Monocytes.
(1) 5 (2) 3 (3) 4 (4) 2
41. In which of the following plant(s) prokaryotic
autotrophic nitrogen fixing symbiont is present. ?
(1) Cycas (2) Pisum
(3) Azolla (4) Both 1 and 3
42.
Which of the following is incorrect with respect
to figure given above :-
(1) Undifferentiated cortex
(2) Eustele and open vascular bundles
(3) Presence of parenchymatous starch sheath
(4) Absence of sclerenchymatous bundle sheath
43. Which of the following aspect of evil quartet is
related to the obligate interaction between both the
interacting species ?
(1) Habitat loss and fragmentation
(2) Over-exploitation
(3) Alien species invasions
(4) Co-extinctions
44. Which of the following is incorrect match of
disorder :-
(1) Occupational respiratory disorders - Asthma
(2) Angina - insufficient oxygen is reaching the
heart muscles
(3) Cardiac arrest - The heart stops beating
(4) Renal calculi - stone or insoluble mass of
crystallised salts (oxalates) formed with in the
kidney
Kota/01CM314245H-10/37
Major Test For Target : Pre-Medical 2015/25-04-2015
45. :-
(1) 15 mya (2) 3-4 mya
(3) 2 mya (4) 1.5 mya
46.
(RR)
200
(1) 150 (2) 200 (3) 50 (4) 100
47.
(1)
(2)
(3)
(4)
48.
(1) CoA
(2) CoA
(3)
(4)
49.
:-
(1) (2)
(3) (4)
50. :-
(1)
(2)
(3)
(4) HIV
45. Ramapithecus existed about :-
(1) 15 mya (2) 3-4 mya
(3) 2 mya (4) 1.5 mya
46. In a certain plant red flower is dominant over white
colour flower. When homozygous (RR) Plant is
cross with white flower plant 200 offsprings are
obtained. Then find out number of red flower
offsprings.
(1) 150 (2) 200 (3) 50 (4) 100
47. Cutting of gel for removal of DNA is called.
(1) Elution
(2) Upstream processing
(3) Down stream processing
(4) Transformation
48. Which of the following does not require
decarboxylation in respiratory process ?
(1) Pyruvate Acetyl CoA
(2) Acetyl CoA Malic acid
(3) Pyruvate Lactic acid
(4) Pyruvate Ethyl alcohol
49. Which of the following not included in female
external genitalia ?
(1) Mons pubis (2) Labia majora
(3) Clitoris (4) Vagina
50. Which of the following statement is false :-
(1) Treatment of AIDS with anti-retroviral drugs
is only partially effective.
(2) Normal cells show a property called contact
inhibition.
(3) Treatment of AIDS can only prolong the life
of the patient but cannot prevent death, which
is inevitable.
(4) T-helper cell continue to produce HIV and in
this way acts as HIV factory.
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51. :-
A B C D
(1) B –
(2) A –
(3) D – TMV ds DNA (4) C –
52. :-(1) (2) (3) (4)
53. .................... :-
(1) GPP-R = N.P.P.
(2) Nt+1 = Nt + [B + I]–[D + E]
(3) S = CAz
(4) dN
dT = rN
K N
K
54. (1)
(2) (3)
(4)
55. :-(1) (2) (3) (4)
56. (genic balance theory) XX+2A XY+3A ?(1) Normal female Super male
(2) Super male normal female
(3) Intersex super female
(4) Metafemale super male
51. Identify the following figures and choose the option
which gives correct description about them :-
A B C D
(1) B – Chara Sexual organs are multicellular
and jacketed.
(2) A – Cycas Male and female cones are borne
on same tree
(3) D – TMV Genetic material is ds DNA.
(4) C – Euglena Shows mixotrophic nutrition.
52. In a dicot root pericycle forms :-
(1) Complete ring of cork cambium
(2) A part of vascular cambium
(3) Lateral roots
(4) All of these
53. ....................is the contribution of German
naturalist and Geographer Alexander von
Humboldt :-
(1) GPP-R = N.P.P.
(2) Nt+1 = Nt + [B + I]–[D + E]
(3) S = CAz
(4) dN
dT = rN
K N
K
54. Which of the following is correct :-
(1) Plasma without the clotting factors is called
lymph.
(2) Bone marrow is the graveyard of RBCs
(3) Monocytes are the most abundant cells of the
WBCs
(4) A reduction in the number of platelets can leads
to excessive loss of blood from the body.
55. According to Hugo de Vries, root cause of
speciation is :-
(1) Natural selection
(2) Mutation
(3) Branching descent
(4) Use and disuse of organs.
56. According to genic balance theory, what would
be the sex of Drosophila having XX + 2A and
XY+3A karyotype resepectively ?
(1) Normal female and Super male
(2) Super male and normal female
(3) Intersex and super female
(4) Metafemale and super male
Time Management is Life Management
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Major Test For Target : Pre-Medical 2015/25-04-2015
57. :-
(1) (2)
(3) (4)
58. (a)PS-I (b) CO2 C4 C3
(c) Cu (d) :-(1) (2) (3) (4)
59. :-(1) (2) (3) (4)
60. :-(1) RBC
(2) (3) (4)
61. (1) (2) (3) (4)
62. :-
(1) (2)
(3) (4)
57. The first letter of the name of restriction
endonuclease comes from the :-
(1) Genus of organism (2) Species of organism
(3) Family of organism (4) Class of organism
58. How many statement(s) is/are correct ?
(a) In stroma lamella only PS-I is present
(b) C4 plants loose nearly half amount of water
for fixing same amount of CO2 than C3 plants
(c) Cu is essential for overall metabolism in plant
(d) Ethylene Increase male flowers in cucumber
Options :-
(1) One (2) Two (3) Three (4) Four
59. Which is not included in the layers of
testis :-
(1) Tunica vaginalis (2) Tunica vasculosa
(3) Tunica albuginea (4) Tunica propria
60. Gametes of plasmodium are formed in :-
(1) RBC of human
(2) Liver of human
(3) Mosquito
(4) Salivary gland of human
61. Which of the following bacteria have a significant
impact on human affairs such as making curd from
milk and production of antibiotics ?
(1) Photosynthetic autotrophic bacteria.
(2) Chemosynthetic autotrophic bacteria.
(3) Archaebacteria
(4) Heterotrophic bacteria.
62. Which of the following diagram exhibit direct
elongation of radicle bearing lateral roots in
several orders :-
(1) (2)
(3) (4)
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63. (1) 6°C (2) 0.6°C (3) 10°C (4) 15°C
64. (1) - (2) - (3) -
(4) - CO2 (~200 /)
65. (1) (2) (3) (4)
66. :-(1) (2) (3) (4)
67. (a)
(b) (c)
(d) Fe Mn
:-(1) (2) (3) (4)
68. (blind spot) :-(1)
(2)
(3) (4)
69. (1) (2)
(3) (4)
63. Increase in the level of green house gases has led
to considerable heating of earth leading to global
warming. During the past century, the temperature
of earth has increased by :-
(1) 6°C (2) 0.6°C (3) 10°C (4) 15°C
64. Which fo the following is not correctly matched
with its function :-
(1) Lacteals - absorption of fat
(2) Calcium ions - Blood clotting
(3) Purkinje fibres - initiating and maintaining the
rhythmic contractile activity
of the heart
(4) Lungs - Remove large amounts of CO2
(~200 mL/minute)
65. In addition to malpighian tubules, which structures
also help in exceretion in cockroach ?
(1) Nephrocytes (2) Urecose gland
(3) Urate cells (4) All
66. The distillation process is not required in the
formation of :-
(1) Rum and Beer (2) Brandy and Whisky
(3) Brandy and Wine (4) Wine and Beer
67. How many statements is/are correct ?
(a) Hydroponics is helpful to determine the
function of different elements in plant
(b) Guttation takes place when atmosphere is arid.
(c) When the rate of transpiration increase, the
rate of guttation also increase
(d) Absorption of Fe is affected by Mn toxicity
Options :-
(1) one (2) two (3) three (4) four
68. Which of the following statement is true about
"blind spot" :-
(1) optic nerve enters and retinal blood vessels
leave the eye.
(2) it is a point medial to and slightly above the
posterior pole of the eye ball.
(3) Photoreceptor cells are present is this region.
(4) At posterior pole, above to blind spot there is
yellowish pigmented spot called macula lutea
69. Type of reproduction in which the female gamete
undergoes development to form new organism,
without fertilization, is called ?
(1) Vegetative reproduction
(2) Parthenocarpy
(3) Parthenogenesis
(4) Regeneration
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70. :-(1) (2) (3) (4)
71 (1) (2) (3) (4)
72. A –
B –
C – D –
:-(1) 5 (2) 4 (3) 3 (4) 2
73. A –
B – 1981
1987
C –
D – BOD,
:-(1) A (2) A B (3) A,B C (4) D
74.
(1) 1100-1200
(2)
(3) GFR 125
(4) II
70. House flies act as mechanical carrier in which of
the following disease :-
(1) Filariasis (2) Amoebiasis
(3) Malaria (4) Pneumonia
71. According to two kingdom system of classification
Chlamydomonas and Chlorella are placed under:-
(1) Kingdom – Protista
(2) Kingdom – Monera
(3) Kingdom – Fungi
(4) Kingdom – Plantae
72. A – Stamens are epiphyllous, when they are
attached to the perianth as in the flowers of
brinjal.
B – Generally, sepals are green, leaf like and
protect the flower in the bud stage.
C – Parietal placentation is found in Argemone.
D – In coconut, which is a drupe, mesocarp is
fibrous.
How many of the given above are correct ?
(1) 1 (2) 4 (3) 3 (4) 2
73. A – Rich biodiversity is not only essential for
ecosystem health but imperative for the very
survival of the human race on this planet.
B – In India, the air (prevention and control of
pollution) Act came into force in 1981, but
was amended in 1987 to include noise as an
air pollutant.
C – In in-situ conservation, the endangered species
are protected in their natural habitat so that
the entire ecosystem is protected.
D – BOD, micro-organisms and amount of
biodegradable matter are not inter related.
Correct statements are :-
(1) A only (2) A and B only
(3) A,B and C (4) D only
74. Which of the following is incorrect statement :-
(1) On an average, 1100-1200ml of blood is
filtered by the kidneys per minute
(2) Vasa-recta is absent or highly reduced in the
cortical nephrons
(3) GFR in a healthy individual is approximately
125 ml/minute
(4) Angiotensin II decreases the glomerular blood
pressure
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75. (A-D)
(1)
(2)
(3)
(4)
76. :-
(1)
(2)
(3)
(4)
77.
(1)
(2)
(3) Si
(4) N2 .
78. "" :-
(1) VIIth
(2) VIth
(3) IVth
(4) VIIIth
79. -I -II
-I -II
A (i)
B (ii)
C (iii)
D (iv)
(1) A – i, B–iv,C–ii, D–iii
(2) A – iii, B–iv,C–ii, D–i
(3) A – iii, B–iv,C–i, D–ii
(4) A – ii, B–iv,C–i, D–iii
75. Read the following four statements (A-D).
(1) Lysosome is a double membrane bound
structure.
(2) Centrioles are made up of nine unevenly
spaced peripheral fibrils of tubulin protein.
(3) Prokaryotic flagella are structurally different
from that of the eukaryotic flagella.
(4) Transport through membrane protein is
always acitve
76. Plant breeding may be used to create varities
which :-
(1) are resistant to pathogen
(2) have increased yield of food
(3) Also has increased protein content of plant
food and enhance the quality of food.
(4) All of these.
77. Which of the following statements is correct ?
(1) Calcium inhibits the translocation of
manganese in shoot apex.
(2) Calcium deficiency is first reported in old
leaf.
(3) In grasses, Si provides the mechanical strength.
(4) Nitrogenase catalyse the conversion of NH3
to atm N2 .
78. "Organ of Corti" sends the sound impulses to
cerebrum through :-
(1) VIIth cranial nerve
(2) VIth cranial nerve
(3) IVth cranial nerve
(4) VIIIth cranial nerve
79. Match the column-I with the column-II and find
correct answer.
Column-I Column-II
A Radicle (i) Shoot
B Ovary (ii) Endosperm
C Plumule (iii) Root
D P.E.N (iv) Fruit
(1) A – i, B–iv,C–ii, D–iii
(2) A – iii, B–iv,C–ii, D–i
(3) A – iii, B–iv,C–i, D–ii
(4) A – ii, B–iv,C–i, D–iii
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80.
(1)
(2)
(3)
(4)
81. I, II III :-
-I -II -III
A. a. i.
B. b. ii.
C. c. iii.
D. d. iv.
(1) A-a-i, B-b-iii, C-d-iv, D-c-ii
(2) A-a-i, B-b-iii, C-c-iv, D-d-ii
(3) C-d-iv, D-c-ii, A-a-iii, B-b-i
(4) A-d-iv, B-c-iii, C-b-ii, D-a-i
82.
?
(A)
(B)
(C)
(D)
(E)
(1) 2 (2) 3 (3) 4 (4) 5
80. Which one of the following intercellular plasma
membrane modification stop substances from
leaking across the tissue ?
(1) Tight junction
(2) Gap junction
(3) Adhering junction
(4) Plasmodesmata
81. Identify correct match from the columns I, II
and III :-
Column-I Column-II Column-III
A. Flame cells a. Platyhelminthes i. Osmoregulation
B. Renette cells b. Aschelminthes ii. Capture food
C. Radula c. Coelenterata iii. Excretion
D. Stinging cells d. Mollusca iv. Rasping organ
(1) A-a-i, B-b-iii, C-d-iv, D-c-ii
(2) A-a-i, B-b-iii, C-c-iv, D-d-ii
(3) C-d-iv, D-c-ii, A-a-iii, B-b-i
(4) A-d-iv, B-c-iii, C-b-ii, D-a-i
82.
How many of the following are correct with
respect to the figure given above ?
(A) Endospermic seed
(B) It is cypsella fruit
(C) Plant belongs to poaceae
(D) Plumule and radicle are enclosed in sheaths
which are called coleoptile and coleorrhiza
respectively
(E) The outer covering of triploid tissue is a
proteinaceous layer called Aleurone layer
(1) 2 (2) 3 (3) 4 (4) 5
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83. The most effective instrument for removing
gaseous pollutants is :-
(1) Scrubber
(2) Electrostatic precipitator
(3) Incinirator
(4) Green mufler
84. The catalysts used in catalytic converter
are :-
(1) Tungsten and Platinum
(2) Platinum-palladium and rhodium
(3) Iron and Copper
(4) Copper and Tungsten
85. How many of the statements below are true for
both mitochondria and chloroplast ?
(A) Presence of porins
(B) Presence of cristae
(C) Presence of ribosomes
(D) Presence of enzymes for protein synthesis
(E) Site for oxidative phosphorylation
(F) Occurence of chain of oxidation-reduction
reactions
(G) Presence of DNA
(1) Six (2) Five (3) Four (4) Three
86. How many of the following are the varieties of
wheat ?
Sonalika, Atlas-66, Pusa swarnim, Himgiri, Pusa komal, Pusa sadabahar
(1) One (2) Two (3) Three (4) Four
87.
Km [s]=substratex
12
12
vmax
vmax
1
[v]vmax
vmax
1
y
a
b
Which of the following is true for above given
diagram regarding enzymes ?
(1) Due to competitive inhibition b change into a
(2) Due to competitive inhibition a change into b
(3) Due to noncompetitive inhibition b is change
into a
(4) Due to noncompetitive inhibition a change
into b
83. (1) (2) (3) (4)
84. () (1) (2) - (3) (4)
85. ?(A) (B) (C) (D) (E) (F) (G) DNA (1) (2) (3) (4)
86. :-
-66,
(1) (2)
(3) (4)
87.
Km [s]=x
12
12
vmax
vmax
1
[v]vmax
vmax
1
y
a
b
(1) b,a
(2) a, b
(3) b, a
(4) a, b
Kota/01CM314245H-18/37
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88. Read the statement A-D carefully and choose the
option which contain all correct statements :-
(A) Pituitary gland is located in a membranous
cavity called sella tursica and is attached to
hypothalamus by a stalk.
(B) Due to cancer of thyroid gland or due to
development of nodule of thyroid gland, the
rate of synthesis and secretion of thyroid
hormone is decreased leading to
hypothyroidism.
(C) The secretion of PTH is regulated by the
circulating level of calcium ions.
(D) Prolonged hyperglycemia leads to a complex
disorder called "diabetes mellitus".
Options :-
(1) A and B (2) A, B and C
(3) C and D (4) B, C and D
89. Which of the following statement in not correct?
(1) Pollen tube is made up of sporopollenin
(2) Female gametophyte of Angiosperm is
embryosac
(3) Black pepper is perispermic seed
(4) Apomixis is a form of asexual reproduction that
mimics sexual reproduction
90. Consider the following four statements (a-d) and
select the option which includes all the incorrect
ones only.
(a) Amount of glucose is maximum in honey.
(b) Honey is the food of high nutritive value and
is used in the preparation of cosmetics and
polishes of various kinds.
(c) Pisciculture is an industry devoted to the
catching processing or selling of fish, shellfish
or other aquatic animals.
(d) Honey bee are the pollinaters of many of our
crops.
Options :
(1) Statement (b), (c) and (d)
(2) Statement (a) and (d)
(3) Statement (c) and (d)
(4) Statement (a), (b) and (c)
88. A-D
:-
(A)
(B)
(C) PTH
(D)
""
:-
(1) A B (2) A, B C
(3) C D (4) B, C D
89.
(A)
(B)
(C)
(D)
90. (a-d)
(a)
(b)
(c)
(d)
(1) (b), (c) (d)
(2) (a) (d)
(3) (c) (d)
(4) (a), (b) (c)
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91. Which of the following is not correct
representation of vander walls gas equation ?
(1)
2
2
n aP V nb
V = nRT
(2) P =
2
RT a
V b V
(3) PV = RT
1b a
1V V
(4)C C
C
P V
RT = 3
8
92. Which of the following is not correct match of
hydrolysis ?
(1) CH3COONa – Anionic hydrolysis
(2) CuCN – Both type hydrolysis
(3) NH4NO
3 – Anionic hydrolysis
(4) KClO4 – No hydrolysis
93. Which of the following is correct
(1) S3O
9 Contains no S – S linkage
(2) S2O
6–2 Contains – O – O – linkage
(3) (HPO3)3 Contains P – P linkage
(4) S2O8
–2 Contains S – S linkage
94. Suppose the following reaction
KMnO /OH4
(Baeyer's reagent) product
The structure of main product will be :-
(1)
OH
OH(2)
OH
OH
(3)
O
HH
O(4)
O
91. ?
(1)
2
2
n aP V nb
V = nRT
(2) P =
2
RT a
V b V
(3) PV = RT
1b a
1V V
(4)C C
C
P V
RT = 3
8
92. ?
(1) CH3COONa –
(2) CuCN –
(3) NH4NO
3 –
(4) KClO4 –
93.
(1) S3O
9 S – S
(2) S2O6–2 – O – O –
(3) (HPO3)3 P – P
(4) S2O8–2 S – S
94.
KMnO /OH4
(Baeyer's reagent) product
(1)
OH
OH(2)
OH
OH
(3)
O
HH
O(4)
O
Take it Easy and Make it Easy
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95. Suppose the following reaction
HCN A LiAlH4 BNaNO +HCl2 C
O
CH3
0–5°C
The product C will be :-
(1)
O
CH3
(2)
CH –NH2 2
O
CH3
–
(3)
O
CH3
(4) O
CH3
NH2
96. Diamond and carborundum is an example of :-
(1) Molecular solids only
(2) Ionic solids only
(3) Covalent solids only
(4) Covalent and molecular solids
97. In the reaction N2(g) + 3H
2(g)
1
2
k
k2NH
3(g) before
equilibrium rate law is given as
r = 2 × 10–3 k1 – 4 × 10–7 k
2 what will be
equilibrium constant for above reaction ?
(1) 2 × 10–4 (2) 0
(3) 5×103 (4) 2×104
98. Which of the following statements is false
(1) H3PO
2, H
3PO
3 and H
3PO
4 all are tribasic and
reducing in nature
(2) Among anions, NO3–, SO3
–2, CO3–2 and
BO3–3, only SO3
–2 have P– d bonding
(3) Among anions SO3–2, SO
4–2, S
2O
4–2 and
HSO4–, SO3
–2 is basic and reducing in nature
(4) Number of lone pairs of electrons on Xe atoms
in XeF2 , XeF4 and XeF6 are 3, 2 and 1
respectively
95. C :-
HCN A LiAlH4 BNaNO +HCl2 C
O
CH3
0–5°C
(1)
O
CH3
(2)
CH –NH2 2
O
CH3
–
(3)
O
CH3
(4) O
CH3
NH2
96. :-(1) (2) (3) (4)
97. N2(g)
+ 3H2(g)
1
2
k
k2NH
3(g)
r = 2 × 10–3 k1 – 4 × 10–7 k
2
kC ?
(1) 2×10–4 (2) 0
(3) 5×103 (4) 2×104
98.
(1) H3PO2, H3PO3 H3PO4
(2) NO3–, SO3
–2, CO3–2 BO3
–3,
SO3–2 P– d
(3) SO3–2, SO4
–2, S2O4–2 HSO4
–
SO3–2
(4) XeF2 , XeF4 XeF6 Xe e– 3,2 1
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99. Which of the following molucule gives two moles
of acetone on ozonolysis reaction ?
(1) CH3
C
CH3
CH3
CH3
(2)
C
CH3
CH3H
(3)
CCH3
C
CH3
CH3CH3
(4)
CH3
C
CH3
CH3
CH3
100. Which is not a lyophilic colloid :-
(1) Milk (2) Gum (3) Fog (4) Blood
101. For calculation of density of CsCl crystal molar
mass is given as M, edge length is a pm.
N0 = 6 × 1023 can be calculated as d = 3
0
Z M
N a
then what will be possible value of 'Z' ? :-
(1) Z = 2 (2) Z = 8 (3) Z = 3 (4) Z = 1
102. Which of the following order is correct
(1) Na2O < MgO < ZnO < P
4O
10(Acidic property)
(2) Na < Si > Mg < A (First ionization potential)
(3) F > C > Br (Electron affinity)
(4) Te–2 < I– < Cs+ < Ba+2(ionic size)
103. In which of the following pairs both the complex
show optical isomerism
(1) Cis – [Cr(C2O
4)Cl
2]–3, mer – [Co(gly)
3]
(2) [Co(en)3]Cl
3, Trans – [Co(en)
2Cl
2]Cl
(3) [Pt Cl (dien)] Cl, [NiCl2(PPh3)2]
(4) [Co(NO3)3
(NH3)3], cis – [Pt(en)
2Cl
2]Cl
2
99.
(1) CH3
C
CH3
CH3
CH3
(2)
C
CH3
CH3H
(3)
CCH3
C
CH3
CH3CH3
(4)
CH3
C
CH3
CH3
CH3
100. :-
(1) (2) (3) (4)
101. CsCl M
a pm, N0 = 6 × 1023 Z
d = 30
Z M
N a
(1) Z = 2 (2) Z = 8 (3) Z = 3 (4) Z = 1
102.
(1) Na2O < MgO < ZnO < P4O10()
(2) Na < Si > Mg < A ( )
(3) F > C > Br ()
(4) Te–2 < I– < Cs+ < Ba+2()
103.
(1) [Cr(C2O
4)Cl
2]–3, – [Co(gly)
3]
(2) [Co(en)3]Cl
3, – [Co(en)
2Cl
2]Cl
(3) [Pt Cl (dien)] Cl, [NiCl2(PPh3)2]
(4) [Co(NO3)3
(NH3)3], – [Pt(en)
2Cl
2]Cl
2
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104. Suppose the following reaction.
CH –OH2
2 4conc.H SO NBS
(Major (Majorproduct) product)
A B
The structure of B will be :-
(1)
CH –Br2
(2)
Br
(3)
Br
Br(4) CH2
BrBr
105. In superoxides, oxygen is present in which form:-
(1) O2–2 (2) O2
–1
(3) O3–2 (4) O
2+2
106. Three particles of a solute A associate in benzene
to form a trimer A3. Calculate the freezing point
of 0.25 molar solution. The degree of association
of solute A is 0.80. The freezing point of benzene
is 5.5°C and Kf is 5.12 k/m ?
(1)152 K (2) 274.3 K
(3) 272.4 K (4) 301 K
107. NaNO3 500°C
A(s) + B(g)
NaNO3
800°C C(S) + B(g) + D(g)
A,B,C and D are respectively
(1) Na2O, O
2, NaNO
2, N
2
(2) NaNO2, O
2, Na
2O, N
2
(3) NaNO2, N
2, Na
2O, O
2
(4) Na2O
2, N
2O, NaNO
2,N
2
108. Select the incorrect statements
(1) In K2MnO4 and CrO2Cl2, the central transition
metals/ions have the same Oxidation state
(2) Both sodium and potassium dichromate can
be used as primary standard in volumetric
estimations
(3) Potassium dichromate on strong heating
evolves oxygen gas
(4) MnO2 on fusion with KOH liberates oxygen
gas leaving behind green residue
104. B :-
CH –OH2
2 4conc.H SO NBS
( () )
A B
(1)
CH –Br2
(2)
Br
(3)
Br
Br(4) CH2
BrBr
105. :-(1) O2
–2 (2) O2–1
(3) O3–2 (4) O
2+2
106. A 3 A3
0.25 m
0.80
5.5°C Kf 5.12 k/m
(1)152 K (2) 274.3 K
(3) 272.4 K (4) 301 K
107. NaNO3 500°C
A() + B()
NaNO3
800°C C() + B() + D()
A,B,C D
(1) Na2O, O
2, NaNO
2, N
2
(2) NaNO2, O
2, Na
2O, N
2
(3) NaNO2, N
2, Na
2O, O
2
(4) Na2O2, N2O, NaNO2,N2
108. (1) K2MnO4 CrO2Cl2,
(2)
(3)
(4) MnO2, KOH
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109. Consider the following reaction
SOCl2 A
O
CH –CH –NH3 2 2 BC–OH LiAlH4(excess) C
The final product C will be :-
(1)
CH –NH–CH –CH2 2 3
(2)
O
C–NH–CH –CH2 3
(3)
O
C–OH
CH –CH –HN3 2
(4)
CH –NH2 2
110. Which of the following statement is/are correct
about half life period for a reaction ?
(1) For a first order reaction t1/2 a
(2) For a zero order reation 1
2
1t
a
(3) Time taken for 75% completion of I order
reaction in twice of t1/2
(4) For a reaction t1/2 does not depend on initial
concentration of reactant
111. For which of the following elements, the
conventional standard molar enthalpy is not zero?
(1) Cdiamond
(2) C(graphite)
(3) Br2()
(4) Iodine(S)
109. C :-
SOCl2 A
O
CH –CH –NH3 2 2 BC–OH LiAlH4(excess) C
(1)
CH –NH–CH –CH2 2 3
(2)
O
C–NH–CH –CH2 3
(3)
O
C–OH
CH –CH –HN3 2
(4)
CH –NH2 2
110. ?
(1) t1/2 a
(2) 1
2
1t
a
(3) 75%
t1/2
(4) t1/2
111.
?
(1) C() (2) C()
(3) Br2()
(4) ()
H-24/37
Major Test For Target : Pre-Medical 2015/25-04-2015
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112.
Column I Column II
(i) [Ni(NH3)
6]+2 (a) d2sp3 and diamagnetic
(ii) [Cr(NH3)
6]+3 (b) sp3d2 and diamagnetic
(iii) [Co(NH3)
6]+3 (c) sp3d2 and two unpaired electrons
(iv) [Zn(NH3)
6]+2 (d) d2sp3 and three unpaired electrons
(i) (ii) (iii) (iv)
(1) c d a b
(2) d c b a
(3) c d b a
(4) a b c d
113. The following compounds are related with each
other as :-
PhC
CH O3
CCH3
H(I)
PhC
HO–CH2
CCH3
H
(II)Ph
CCH O3
CCH3
H(I)
PhC
HO–CH2
CCH3
H
(II)Ph
CCH O3
CCH3
H(I)
PhC
HO–CH2
CCH3
H
(II)Ph
CCH O3
CCH3
H(I)
PhC
HO–CH2
CCH3
H
(II)Ph
CCH O3
CCH3
H(I)
PhC
HO–CH2
CCH3
H
(II)
(1) Metamers
(2) Geometrical isomers
(3) Functional isomers
(4) Both functional as well as geometrical isomers
114. Which of the following is correct structure of
glucosazone of D-Glucose ?
(1) H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
(2)
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
(3)H – C – OH
H – C – OH
C=O
C=N–NH–Ph
CH=N–NH–Ph
CH –OH2
H – C – OH
H – C – OH
C=O
C=N–NH–Ph
CH=N–NH–Ph
CH –OH2
H – C – OH
H – C – OH
C=O
C=N–NH–Ph
CH=N–NH–Ph
CH –OH2
H – C – OH
H – C – OH
C=O
C=N–NH–Ph
CH=N–NH–Ph
CH –OH2
H – C – OH
H – C – OH
C=O
C=N–NH–Ph
CH=N–NH–Ph
CH –OH2
(4)
HO – C – H
H – C – OH
CHO
C=N–NH–Ph
H – C – OH
C=N–NH–Ph
H
112.
Column I Column II
(i) [Ni(NH3)
6]+2 (a) d2sp3
(ii) [Cr(NH3)
6]+3 (b) sp3d2
(iii) [Co(NH3)
6]+3 (c) sp3d2
(iv) [Zn(NH3)
6]+2 (d) d2sp3
(i) (ii) (iii) (iv)
(1) c d a b
(2) d c b a
(3) c d b a
(4) a b c d
113. :-
PhC
CH O3
CCH3
H(I)
PhC
HO–CH2
CCH3
H
(II)Ph
CCH O3
CCH3
H(I)
PhC
HO–CH2
CCH3
H
(II)Ph
CCH O3
CCH3
H(I)
PhC
HO–CH2
CCH3
H
(II)Ph
CCH O3
CCH3
H(I)
PhC
HO–CH2
CCH3
H
(II)Ph
CCH O3
CCH3
H(I)
PhC
HO–CH2
CCH3
H
(II)
(1)
(2)
(3)
(4)
114. D-
(1) H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
(2)
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
H – C – OH
H – C – OH
CH OH2
C=N–NH–Ph
CH=N–NH–Ph
HO – C – H
(3)H – C – OH
H – C – OH
C=O
C=N–NH–Ph
CH=N–NH–Ph
CH –OH2
H – C – OH
H – C – OH
C=O
C=N–NH–Ph
CH=N–NH–Ph
CH –OH2
H – C – OH
H – C – OH
C=O
C=N–NH–Ph
CH=N–NH–Ph
CH –OH2
H – C – OH
H – C – OH
C=O
C=N–NH–Ph
CH=N–NH–Ph
CH –OH2
H – C – OH
H – C – OH
C=O
C=N–NH–Ph
CH=N–NH–Ph
CH –OH2
(4)
HO – C – H
H – C – OH
CHO
C=N–NH–Ph
H – C – OH
C=N–NH–Ph
H
Phase/ENTHUSIAST, LEADER & ACHIEVER/25-04-2015
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115. Calculate the emf of the cell :
Cr | Cr3+(0.1 M) || Fe2+ (0.01 M) | Fe
Given : 30
Cr / CrE 0.75V ; 2
0
Fe / FeE 0.45V
Cell reaction :
2Cr(s) + 3Fe2+ (aq.) 2Cr3+(aq) + 3Fe(s)
(1) 0.2606 V (2) 0.5212 V
(3) 0.1303 V (4) Zero
116. The equivalent mass of Na2S2O3 in its reaction
with I2 is equal to :-
(1) molar mass (2) molar mass
2
(3) molar mass
3(4)
molar mass
4
117. Molecular shape of XeF3
+, SF3
+ and CF3+ are :-
(1) the same with 2, 1 and 0 lone pairs of electrons
respectively
(2) different with 2, 1 and 0 lone pair of electrons
respectively
(3) different with 0, 1 and 2 lone pair of electrons
respectively
(4) the same with 2, 0 and 1 lone pairs of electrons
respectively
118. The IUPAC name of following compound is :-CN
Br
NO2
(1) 4-nitro-3-bromo-1-cyanobenzene
(2) 3-bromo-1-cyano-4-nitrobenzene
(3) 3-bromo-4-nitro benzonitrile
(4) 1-bromo-2-nitro-4-cyanobenzene
119. The correct order of reactivity of following
compound toward nucleophilic substitution
reaction will be :-
(I) (II) (IV)
CH –Cl2
OCH3
(III)
CH–OCH3 CH –Cl2 Cl
OCH3
Cl
CH3
OCH3
(1) II > I > III > IV (2) III > II > IV > I
(3) I > IV > III > II (4) IV > II > I > II
115. :Cr | Cr3+(0.1 M) || Fe2+ (0.01 M) | Fe
: 30
Cr / CrE 0.75V ; 2
0
Fe / FeE 0.45V
:2Cr(s) + 3Fe2+ (aq.) 2Cr3+(aq) + 3Fe(s)
(1) 0.2606 V (2) 0.5212 V
(3) 0.1303 V (4) 116. Na2S2O3 I2Na2S2O3
(1) (2) 2
(3) 3
(4)
4
117. XeF3
+, SF3
+ CF3
+ (1) 2, 1 0
(2) 2, 1 0
(3) 0, 1 2
(4) 2, 0 1
118. IUPAC :-
CN
Br
NO2
(1) 4--3--1-(2) 3--1--4-(3) 3--4- (4) 1--2--4-
119.
:-
(I) (II) (IV)
CH –Cl2
OCH3
(III)
CH–OCH3 CH –Cl2 Cl
OCH3
Cl
CH3
OCH3
(1) II > I > III > IV (2) III > II > IV > I
(3) I > IV > III > II (4) IV > II > I > II
H-26/37
Major Test For Target : Pre-Medical 2015/25-04-2015
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120. Calculate molar conductance at infinite dilution
for acetic acid, given :-
m (HCl) = 425 –1 cm2 mol–1
m (NaCl) = 188 –1 cm2 mol–1
m (CH
3COONa) = 96 –1 cm2 mol–1
(1) 524 –1 cm2 mol–1 (2) 284 –1 cm2 mol–1
(3) 333 –1 cm2 mol–1 (4) 123 –1 cm2 mol–1
121. The volume of H2 gas obtained by heating 5 mole
NH3 at NTP is :-
(1) 174 L (2) 168 L (3) 120 L (4) 11.2 L
122. Which does not represent correct method
(1) TiCl2 + 2 Mg Ti + 2 MgCl
2 (Kroll)
(2) Ni(CO)4 Ni + 4 CO (Mond)
(3) Ag2CO3 2 Ag + CO2 +1/2 O2 (van arkel)
(4) ZrI4 Zr + 2 I2 (Van Arkel)
123. Suppose the following structures
H – C – Br
HO – C – H
COOCH3
COOH
(I)
HO – C – H HO – C – H
Br – C – H H – C – Br
COOCH3 COOH
COOH COOCH3
(II) (III)Which of the following statement is correct for them:-
(1) I and II are diastereomers
(2) I and III are enantiomers
(3) I and III are diastereomers
(4) II and III are homomerss
124. Which of the following reaction will not be
feasiable ?
(1)
NH2
NH H
NH2
NH2
(2)
NH2
N
H
NH2
N
H
(3)
NH2
H
NH3
N N
(4) H
NNN N
H
H H
120. :-
m (HCl) = 425 –1 cm2 mol–1
m (NaCl) = 188 –1 cm2 mol–1
m (CH
3COONa) = 96 –1 cm2 mol–1
(1) 524 –1 cm2 mol–1 (2) 284 –1 cm2 mol–1
(3) 333 –1 cm2 mol–1 (4) 123 –1 cm2 mol–1
121. 5 NH3 H2 NTP
:-(1) 174 L (2) 168 L (3) 120 L (4) 11.2 L
122. (1) TiCl
2 + 2 Mg Ti + 2 MgCl
2 ()
(2) Ni(CO)4 Ni + 4 CO ()
(3) Ag2CO3 2 Ag + CO2 +1/2 O2 ()
(4) ZrI4 Zr + 2 I2 ()
123.
H – C – Br
HO – C – H
COOCH3
COOH
(I)
HO – C – H HO – C – H
Br – C – H H – C – Br
COOCH3 COOH
COOH COOCH3
(II) (III)
(1) I II
(2) I III
(3) I III (4) II III
124.
(1)
NH2
NH H
NH2
NH2
(2)
NH2
N
H
NH2
N
H
(3)
NH2
H
NH3
N N
(4) H
NNN N
H
H H
Phase/ENTHUSIAST, LEADER & ACHIEVER/25-04-2015
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125. Which of the following complex show low spin,
paramagnetic and innerorbital complex :-
(1) [Co(H2O)6]3+ (2) [Cu(NH3)4]
(3) [Co(CN)6]4– (4) [Ni(Co)4]
126. For which of the following reaction enthalpy
change represents, enthalpy of formation of
NaOH ?
(1) aq aqNa OH NaOH(s)
(2) (s) 2(g) 2g (S)
1 1Na O H NaOH
2 2
(3) (s) 2 ( ) (aq) 2(g)2Na 2H O 2NaOH H
(4) All of above
127. A Metal [x] on heating in Nitrogen gas gives [y].
[y] on treatment with H2O gives a colourless gas
which when passed through CuSO4 solution gives
a blue colour.[y] is
(1) Mg(NO3)
2(2) Mg
3N
2
(3) NaN3
(4) MgO
128. Which of the following can show keto enol
toutomerism.
(1)
O
CH3 CH3
(2)
O
CH3
CH3
(3)
O
CH3
(4)
O
O
129. Which of the following is used as anti metarial?
(1) Atropine (2) Equanil
(3) Quinine (4) Sulphadiazine
130. Calculate total no. of stereoisomer in
[Co(en)(NH3)(H2O)ClBr] :-
(1) 12 (2) 6 (3) 4 (4) 8
131. What will be pH of solution at 25°C obtained by
mixing 100 ml N
10NH
4 OH solution with 100 ml
N
20HCl solution. (given pkb NH4OH = 4.74 :-
(1) 10.74 (2) 4.74 (3) 9.26 (4) 8.47
125. :-(1) [Co(H
2O)
6]3+ (2) [Cu(NH
3)
4]
(3) [Co(CN)6]4– (4) [Ni(CO)4]
126. NaOH
?
(1) aq aqNa OH NaOH(s)
(2) (s) 2(g) (2g) (S)
1 1Na O H NaOH
2 2
(3) (s) 2 ( ) (aq) 2(g)2Na 2H O 2NaOH H
(4)
127. [x] [y]
[y]
CuSO4 [y]
(1) Mg(NO3)
2(2) Mg
3N
2
(3) NaN3
(4) MgO
128.
(1)
O
CH3 CH3
(2)
O
CH3
CH3
(3)
O
CH3
(4)
O
O
129. (1) Atropine (2) Equanil(3) Quinine (4) Sulphadiazine
130. [Co(en)(NH3)(H
2O)ClBr]
:-(1) 12 (2) 6 (3) 4 (4) 8
131. 100 ml N
10NH4 OH 100 ml
N
20HCl
pH 25°C
(given pkb NH4OH = 4.74) :-
(1) 10.74 (2) 4.74 (3) 9.26 (4) 8.47
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Major Test For Target : Pre-Medical 2015/25-04-2015
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132.
Column I Column II
(i) N2 N
2+ (a) Bond order increases and
Magnetic property changed
(ii) O2+O
2+2 (b) Bond order decreases and
Magnetic property is not changed
(iii) B2B
2+ (c) Bond order increases and
magnetic property not changed
(iv) NO– NO (d) Bond order decreases and
magnetic property is changed
Note : Here change in Magnetic property refers
to change from diamagnetic to paramagnetic or
paramagnetic to diamagnetic
(i) (ii) (iii) (iv)
(1) d a c b
(2) d a b c
(3) c b d a
(4) a d b c
133. Which of the following alkyne results into
formation of aldehyde on hydration reaction.
(1) CH3 – C CH
(2) CH CH
(3) Ph – C CH
(4) – C CH
134. Among the following which one will form most
stable hydrate, when reacts with H2O.
(1) – C – H
O
(2)
O
O
C=O
(3)
O
O
(4)
O
O
O
135. Complex which is represent maximum C.F.S.E :-
(1) [Co(CN)6]3– (2) [Co(CN)
6]4–
(3) [Fe(H2O)6]3+ (4) [Co(H2O)6]
3+
132.
Column I Column II
(i) N2 N
2+ (a)
(ii) O2
+O2
+2 (b)
(iii) B2B
2+ (c)
(iv) NO– NO (d)
Note :
(i) (ii) (iii) (iv)
(1) d a c b
(2) d a b c
(3) c b d a
(4) a d b c
133. (1) CH3 – C CH
(2) CH CH
(3) Ph – C CH
(4) – C CH
134. H2O
(1) – C – H
O
(2)
O
O
C=O
(3)
O
O
(4)
O
O
O
135. :-(1) [Co(CN)6
]3– (2) [Co(CN)6]4–
(3) [Fe(H2O)6]3+ (4) [Co(H2O)6]
3+
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136. According to Joule's law of heating, heat
produced H = I2 Rt, where I is current, R is
resistance and t is time. If the errors in the
measurement of I, R and t are 3%, 4% and 6%
respectively then error in the measurement of H
is :-
(1) ±17% (2) ±16%
(3) ±19% (4) ±25%
137. A B C
Three identical blocks A, B and C are placed on
horizontal frictionless surface. The blocks B and
C are at rest block A is approaching towards B with
a speed 10m/sec. If the coefficient of restitution
for all collision is 0.5 then the speed of the block
C just after collision is approximately :-
(1) 5.6 m/sec. (2) 6.4 m/sec.
(3) 3.2 m/sec. (4) 4.6 m/sec.
138. The equation of particle executing SHM is
y = A cos t. What will be the acceleration of
the particle after time t = T/4, where T = time
period.
(1) 2A (2) 2A/2 (3) –2A (4) 0
139. A block has dimensions 1 cm, 2 cm and 3 cm.
Ratio of the maximum resistance to minimum re-
sistance between any pair of opposite faces of this
block is :
(1) 9 : 1 (2) 1 : 9
(3) 18 : 1 (4) 1 : 6
140. The electric field and magnetic field associated
with in e.m. wave, propagating along the –z axis,
can be represented by :
(1)
0 0ˆ ˆE E i, B B j
(2)
0 0ˆˆE E k, B B i
(3)
0 0ˆ ˆE E j,B B i
(4)
0 0ˆ ˆE E j,B B k
141. Liquid drops of mass m falling slowly one by
one from a capillary tube of radius r. The surface
tension of the liquid is :-
(1) mg/r (2) mg/2r
(3) 2mg/r (4) mg/r2
136. H = I2 Rt
I R t I, R
t 3%, 4% 6%
H :-
(1) ±17% (2) ±16%
(3) ±19% (4) ±25%
137. A B C
A, B C
B C A,
B 10m/sec
0.5
C :-
(1) 5.6 m/sec. (2) 6.4 m/sec.
(3) 3.2 m/sec. (4) 4.6 m/sec.
138. SHM y = A cos t
t = T/4
T =
(1) 2A (2) 2A/2 (3) –2A (4) 0
139. 1 , 2 3
:
(1) 9 : 1 (2) 1 : 9
(3) 18 : 1 (4) 1 : 6
140. –z :
(1)
0 0ˆ ˆE E i, B B j
(2)
0 0ˆˆE E k, B B i
(3)
0 0ˆ ˆE E j,B B i
(4)
0 0ˆ ˆE E j,B B k
141. m r
:-
(1) mg/r (2) mg/2r
(3) 2mg/r (4) mg/r2
H-30/37
Major Test For Target : Pre-Medical 2015/25-04-2015
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142. Two pendulum bobs of mass m and 2m are
released from same height H. If they collide
inelastically at mean position then the height upto
which the composite mass would rise is :-
m 2m
(1) H
3(2)
H
9
(3) 2H
3(4)
4H
9
143. A sound is produced in water and moves towards
surface of water and some sound moves in air
velocity of sound in water is 1450 m/s and that in
air is 330 m/s. When sound moves from water to
air then the effect on frequency f and wave length
will be:
(1) f and will remain same
(2) f will remain same but will increase
(3) f will remain same but will decrease
(4) f will increase and will decrease
144. In the adjoining circuit, the potential difference
across 3 is :
6
32
4
2 Amp
(1) 2 V (2) 4 V (3) 8 V (4) 16 V
145. Concave and convex lenses are placed touching
each other. The ratio of magnitudes of their power
is 2:3. The focal length of the system is 30 cm.
Then the focal lengths of individual lenses are:
(1) –75, 50 (2) –15, 10
(3) 75, 50 (4) 75, –50
146. A wire of length L and radius r is fiexed at one
end and force F applied to the other end produces
an extension y. The extension produced in
another wire of the same material of length 2L
and radius 2r by a force 2F is :-
(1) y (2) 2y (3) y/2 (4) 4/y
142. m 2m H :-
m 2m
(1) H
3(2)
H
9
(3) 2H
3(4)
4H
9
143.
1450 m/s 330 m/s f :(1) f (2) f (3) f
(4) f
144. 3 :
6
32
4
2
(1) 2 V (2) 4 V (3) 8 V (4) 16 V
145. 2:3 30 cm (1) –75, 50 (2) –15, 10
(3) 75, 50 (4) 75, –50
146. L r
F y
2L
2r 2F
(1) y (2) 2y (3) y/2 (4) 4/y
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147. o
2ˆ ˆJ ai bt j
, a b
( )
J45°
o :-
(1) a / b (2) a
2b
(3)a
2bb
(4)b
2aa
148.
900
(1) 1:1 (2) 2:1
(3) 2:1 (4) 4:1
149. 100ºC 100
0.005/ºC
200 (1) 200ºC (2) 300ºC
(3) 400ºC (4) 500ºC
150. :-(1) (2) (3) (4)
151. t :-
(1)
2 2
t
(2)
2 2
t
(3)
( )t(4)
t
152. M R
:-
(1) MR2
(2) 2MR2
(3) 3MR2
(4)
147. The angular momentum of a particle relative to
a point o varies with time as 2ˆ ˆJ ai bt j
, where
a and b are constants. The moment of force ( )
relative to the point o acting on the particle when
the angle between the vector and J
equal 45°:-
(1) a / b (2) a
2b
(3)a
2bb
(4)b
2aa
148. Waves from two sources superpose on each other
at a particular point amplitude and frequency of
both the waves are equal. The ratio of intensities
when both waves reach in the same phase and
they reach with the phase difference of 900 will
be
(1) 1:1 (2) 2:1
(3) 2:1 (4) 4:1
149. The resistance of a bulb filaments is 100 at a
temperature of 100ºC. If its temperature coeffi-cient of resistance be 0.005/ºC, its resistance will
become 200 at a temperature of :(1) 200ºC (2) 300ºC
(3) 400ºC (4) 500ºC
150. In order to increase the angular magnification of
a simple microscope, one should increase :-
(1) The object size
(2) The aperature of the lens
(3) The focal length of the lens
(4) The power of the lens
151. A car accelerates from rest at a constant rate for
some time, after which it decelerates at a constant
rate and comes to rest. If total time elapsed is t,
then the maximum velocity acquired by the car is:-
(1)
2 2
t
(2)
2 2
t
(3) ( )t
(4)
t
152. A ring of mass M and radius R can have moment
of inertia :-
(1) MR2
(2) 2MR2
(3) 3MR2
(4) All
Key Filling
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153. If a star emitting light of wavelength 5000 Å is
moving towards earth with a velocity of
1.5 x 106 m/s then the shift in the wave length
due to Doppler's effect will be :
(1) 2.5 Å (2) 250 Å
(3) 25 Å (4) Zero
154. A magnet of magnetic moment
M is moulded according to
figure, then magnetic
moment becomes :–
(1) 2M
(2)
2M
(3)
2 2M
(4)
M
155. In deriving the single slit diffraction pattern, it is
observed that the intensity is zero at angle n
a
.
In how many equal parts the slit may be dividedto justify this observations?
(1) n
2(2) 2n
(3) n (4) n/4
156. A particle is dropped vertically from rest from
a height. The time taken by it to fall through
sucessive distance of 1m each will then be :-
(1) All equal, being equal to / g second
(2) In the ratio of the square roots of the integers
1, 2, 3....
(3) In the ratio of the difference in the square
roots of the integers i.e. 1,( 2 1) ,
( 3 2),( 4 3) ......
(4) In the ratio of the reciprocal of the square
roots of the integers i.e. = 1 1 1 1
, , ,1 2 3 4
157. A bullet of mass 10 × 10–3 kg moving with a speed
of 20 ms–1 hits an ice block (0°C) of 990 g kept
at rest on a frictionless floor and gets embedded
in it. If ice takes 50% of KE lost by the system,
the amount of ice melted (in grams) approximately
is:-
(J = 4.2 J/cal; latent heat of ice = 80 cal/g)
(1) 6 (2) 3
(3) 6 × 10–3 (4) 3 × 10–3
153. 5000 Å
1.5 x 106
(1) 2.5 Å (2) 250 Å
(3) 25 Å (4) 154. M
(1) 2M
(2)
2M
(3)
2 2M
(4)
M
155. n
a
:-
(1) n
2(2) 2n
(3) n (4) n/4
156.
1-1
:-
(1) / g
(2) 1, 2, 3....
(3)
1,( 2 1) , ( 3 2),( 4 3) ....
(4)
= 1 1 1 1
, , ,1 2 3 4
157. 20 10 × 10–3 990 (0°C)
50%
()
(J = 4.2 = 80 cal/g)
(1) 6 (2) 3
(3) 6 × 10–3 (4) 3 × 10–3
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158. The period of a satellite in a circular orbit around
a planet is independent of :
(1) The mass of the planet
(2) The radius of the planet
(3) The mass of the satellite
(4) All the three parameters (1), (2) and (3)
159. A charge q move in a circle of radius 'r' with speed
v. The magnetic field produces at the centre of
circle 'B', then radius of circle is directly
proportional to –
(1) v
B(2)
B
v
(3) Bv (4) v
B
160. A photon of energy E ejects a photoelectron from
a metal surface whose work function is W0. If this
electron enters into a uniform magnetic field of
induction B in a direction perpendicular to the
field and describes a circular path of radius r, then
the radius r is given by (in the usual notation) :-
(1) 0m(E W )
eB
(2)
02m(E W )eB
(3) 02e(E W )
mB
(4) 02m(E W )
eB
161. A block of mass M is pulled along a horizontal
frictionless surface by a rope of mass m. If a force
P is applied at the free end of the rope, the force
exerted by the rope on the block is-
(1) P (2) PM
M m
(3) Pm
M m(4)
Pm
M m
162. In which of the following heat loss is primarily
not due to convection ?
(1) Boiling of water
(2) Land and sea breeze
(3) Heating of glass surface of a bulb due to
current in filament
(4) Circulation of air around blast furnace
158. :(1) (2) (3)
(4) (1), (2) (3)
159. q 'v' r
'B'
–
(1) v
B(2)
B
v
(3) Bv (4) v
B
160. E
W0
B
r
r :-
(1) 0m(E W )
eB
(2)
02m(E W )eB
(3) 02e(E W )
mB
(4) 02m(E W )
eB
161. M m P m
(1) P (2) PM
M m
(3) Pm
M m(4)
Pm
M m
162. ?
(1) (2) (3)
(4) (Blast) (Circulation)
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163. The escape velocity of an object from the earth
depends upon the mass of the earth(M), its mean
density(), its radius(R) and the gravitational
constant(G), thus the formula for escape velocity
is :
(1) 8
V R G3
(2) 8
V M GR3
(3) V 2GMR
(4) 2
2GMV
R
164. The direction of net magnetic force on each infinite
length wire shown in figure:-
(1) P towards left, Q towards left,
R towards left
(2) P towards left, Q towards right,
R towards right
(3) P towards right, Q towards left,
R towards right
(4) P towards left, Q towards left,
R towards right
165. The rate of disintegration of a fixed quantity of
a radioactive element can be increased by :-
(1) increasing the temperature
(2) increasing the pressure
(3) chemical reaction
(4) it is not possible
166. The coefficient of static friction between two
planes depends upon –
(1) The area of contact
(2) The normal reaction
(3) Nature of the surfaces in contact
(4) All of the above
163. (M),
(), (R)
(G),
:
(1) 8
V R G3
(2) 8
V M GR3
(3) V 2GMR
(4) 2
2GMV
R
164. :-
(1) P, Q , R
(2) P , Q , R
(3) P , Q , R
(4) P , Q , R
165. :-(1) (2) (3) (4)
166.
(1)
(2)
(3)
(4)
Use stop, look and go method in reading the question
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167. A gas is to obey the law P2V = constant. The initial
temperature and volume are T0 and V0. If the gasexpends to a volume 2V0, its final temperature
becomes :-
(1) 02T (2) 2T0 (3) T0/2 (4)
0T / 2
168. The eight charged water drops each of radius 8mm
and charge of 2 × 10–10 C are merged into a singledrop, the potential of the big drop is :-
(1) 300 V (2) 1800 V (3) 900 V (4) 200 V169. A coil of N = 100 turns carries a current I = 5A
and creates a magnetic flux = 10–5 Tm–2 per turn.
The value of its inductance L will be :-
(1) 0.05 mH (2) 0.10 mH
(3) 0.15 mH (4) 0.20 mH
170. The energy released by the fission of one uranium
atom is 200 MeV. The number of fissions persecond required to produce 3.2 W of power is :-
(Take 1 eV = 1.6 × 10–19 J)(1) 107 (2) 1010 (3) 1015 (4) 1011
171. A ring of radius r and mass per unit length mrotates with an angular velocity in a free space.
The tension in the ring is :-
(1) zero (2) 1
2m
2r2
(3) m2r
2(4) m
2r
172. Two moles of an ideal gas at 300 K were cooledat constant volume, so that the pressure is reduced
to half the initial value. Then, as a result of heatingat constant pressure the gas has expanded till it
attains the original temperature. Find the total heatabsorbed by gas, if R is the gas constant. :-
(1) 150R joules (2) 300R joules(3) 75R joules (4) 100R joules
173. In the given figure, the potential differencebetween A and B is :-
(1) 18V (2) 6 V (3) 12 V (4) zero
174. An inductance L and resistance R are firstconnected to a battery. After some time the batteryis disconnected but L and R remain connected ina closed circuit. Then the current reduces to 37%of its initial value in :-(1) RL sec (2) R/L sec(3) L/R sec (4) 1/LR sec
167. P2V = V0 T0 2V0
:-
(1) 02T (2) 2T
0(3) T
0/2 (4)
0T / 2
168. 2 × 10–10 :-(1) 300 V (2) 1800 V (3) 900 V (4) 200 V
169. N = 100 I = 5A
= 10–5 Tm–2 (L)
:-
(1) 0.05 mH (2) 0.10 mH
(3) 0.15 mH (4) 0.20 mH
170. 200 MeV3.2 :-(1 eV = 1.6 × 10–19 )(1) 107 (2) 1010 (3) 1015 (4) 1011
171. r m :-
(1) (2) 1
2m
2r2
(3) m2r
2(4) m
2r
172. 300 K R :-(1) 150R (2) 300R (3) 75R (4) 100R
173. A B :-
(1) 18V (2) 6 V (3) 12 V (4) zero
174. L R L R 37% :-(1) RL sec (2) R/L sec
(3) L/R sec (4) 1/LR sec
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175. The mobility of electron in Ge is 0.4 m2/Vs and
electronic charge is 1.6 × 10–19 C. How many
donor atom have in semi conductor of
conductivity 500 mho/m. :-
(1) 8 × 1021 m–3 (2) 8 × 1015 m–3
(3) 5 × 1021 m–3 (4) 8 × 1016 m–3
176. A particle of mass m is moving in a circular path
of constant radius r such that its centripetal
acceleration ac is varying with time t as ac=k2rt
2.
The power delivered to the particle by the forces
acting on it :-
(1) 2mk2r
2t (2) mk
2r
2t
(3)4 2 5mk r t
3(4) zero
177. A spring mass system oscillates with a frequency n.
If it is taken in an elevator slowly accelerating
upward the frequency will
(1) increase (2) decrease
(3) remain same (4) become zero
178. Find the force of attraction between the two plates
of a parallel plate capacitor.
(1)
2
0
1 q
2 A(2)
2
0
1 q
2 A
(3) 2
0
q4
A (4)
2
0
1 q
A
179. An inductor L and a capacitor C are connected in
the circuit as shown in the figure the frequencyof the power supply is equal to the resonant
frequency of the circuit. Which ammeter will readzero ampere :-
A1
A2
A3
C
L
E = E sin tn
(1) A1 (2) A2
(3) A3 (4) None of these
180. For a common emitter transistor, input current is
5A and = 100. If circuit is operated at load
resistance of 10 k then voltage across load
resistance will be :-
(1) 5 V (2) 10 V (3) 12.5 V (4) 7.5 V
175. Ge 0.4 m2/Vs 1.6 × 10–19 C 500
:-
(1) 8 × 1021 m–3 (2) 8 × 1015 m–3
(3) 5 × 1021 m–3 (4) 8 × 1016 m–3
176. r m
ac t ac=k2rt
2
:-
(1) 2mk2r2t (2) mk
2r
2t
(3)4 2 5mk r t
3(4)
177. n (1) (2) (3) (4)
178.
(1)
2
0
1 q
2 A(2)
2
0
1 q
2 A
(3) 2
0
q4
A (4)
2
0
1 q
A
179. L C
:-
A1
A2
A3
C
L
E = E sin tn (1) A1 (2) A2
(3) A3 (4) 180. 5A
= 100 10 k
:-
(1) 5 V (2) 10 V (3) 12.5 V (4) 7.5 V
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