hsc head start lecture chemistry · 2020. 4. 25. · lecture overview i’ll be going through all...
TRANSCRIPT
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HSC Head Start LectureCHEMISTRY
Presented by:JIANNE PARISI
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HSC Head Start LectureCHEMISTRY
Presented by:JIANNE PARISI
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• Session 1– Who am I?– Our goals today– Static and dynamic equilibrium
• Session 2– Factors that affect equilibrium– Calculating the equilibrium constant
• Session 3– Solution equilibria– General HSC tips
Lecture OverviewI’ll be going through all of module 5!
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• I graduated high school in 2018 – I studied advanced English, extension maths, chemistry, biology, music 2 and music extension and received 2 Encore nominations!
• I’m now studying a double degree of commerce and advanced computing at Usyd
• My HSC experience was quite awful ngl!• But I would like to help make yours less bad
Who am I?
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• Get a good basic understanding of module 5• Feel confident answering questions• Learn good study strategies• Take lots of notes• Ask questions!!!
Our Goals Today
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What happens when chemical reactions do not go through to completion?
• So far you have only seen irreversible reactions• These go to completion and use the normal (à) arrow• This means that reactants become products and that’s all!
• This module familiarizes you with reversible reactions• Reactants become products but products can also become reactants• Reversible reactions use this arrow: ⇌ (it makes sense)
• For reversible reactions, changing conditions will affect the proportion of reactants to products.
5.1 Static and Dynamic Equilibrium
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Practical investigations (reversible)Cobalt(II) chloride hydrated and dehydrated• CoCl2(aq) + 6H2O(l) ⇌ CoCl2 · 6H2O(l)• Hydration/dehydration = adding or removing water• Cobalt(II) chloride becomes cobalt(II) chloride hexahydrate• There is a visible difference! The anhydrous (dehydrated) form is sky
blue and the hydrated form is purple
Iron(III) nitrate and potassium thiocyanate• Fe3+(aq) + SCN-(aq) ⇌ FeSCN2+(aq)• Iron ions are yellow in solution and potassium thiocyanate is clear but
iron thiocyanate is BLOOD RED
5.1 Static and Dynamic Equilibrium
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Practical investigations (irreversible)Burning magnesium• 2Mg(s) + O2 à 2MgO(s) + energy• Note the arrow! This is irreversible• This reaction releases A LOT of energy – we can sometimes reverse
reactions by putting as much energy back into the system but this is completely impractical for combustion because it releases so much
Burning steel wool
• 2Fe(s) + !"O2(g) à Fe2O3(s)
• Works the same way as burning magnesium
5.1 Static and Dynamic Equilibrium
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Equilibrium• A state where concentrations of reactants and products stay
approximately constant
Dynamic Equilibrium• Over time, reversible reactions will reach a state called dynamic equilibrium• Conditions for dynamic equilibrium:
– Reaction is reversible– Closed system– Rate of the forward reaction equals the rate of the reverse reaction– Concentrations of reactants and products are constant but not necessarily equal– Macroscopic properties are constant
• While concentrations are staying constant, individual particles are still oscillating between reacted and unreacted states! That’s why this equilibrium is called dynamic.
• The rate at which particles shift backward and forward is equal
5.1 Static and Dynamic Equilibrium
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Static Equilibrium• Static because all particles are at rest• They do NOT oscillate between reacted and unreacted states• For example any irreversible reaction – reactants become products and cannot
switch back to reactants• It is still an equilibrium because concentrations of reactants and products
don’t change once the reaction has gone to completion• The rate of forwards and backwards reactions are zeroOpen vs closed systems• Whether a system can or cannot interact with its surroundings• If a system is open, the external environment will have an impact on equilibrium
being reached• E.g. mixing hot and cold water:
– If in an insulated box, the water will be warm and NOT affected by changing the temperature of the environment
– If in an open box, the water will be warm and then cool down until it reached the temperature of the environment
5.1 Static and Dynamic Equilibrium
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Non-equilibrium SystemsEntropy• How many possible states can something be in?
– Solids – stuck in a lattice– Liquids – some freedom of movement but they’re still kinda stuck together– Gases – lots of freedom of movement – most possible states bc individual things
have the largest range of possible positions
• This can be looked at as how disordered something is• If there are more states, things are more likely to be in one of these
states• Entropy is always increasing for the universe• Just things moving to a more statistically probable arrangement, which
will tend to be more disordered (toward higher entropy)
5.1 Static and Dynamic Equilibrium
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Non-equilibrium SystemsEnthalpy• Enthalpy – heat content of a system• Chemical energy is stored in bonds and can be released as
heat• Conversely, heat energy can be stored as chemical energy
in bonds• For an endothermic reaction, enthalpy with INCREASE
– The reaction takes energy IN• For an exothermic reaction, enthalpy will DECREASE
– The reaction sends energy OUT
5.1 Static and Dynamic Equilibrium
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Entropy and enthalpy in non-equilibrium systemsCombustion reactions• C2H5OH(l) + 3O2(g) à 2CO2(g) + 3H2O(g)• Combustion reactions are entropically favoured because the entropy of the
system increases• There are more products than reactants so the system can exist in more
possible states (entropy goes UP)• Going from gas and liquid to just gas – gases can exist in more states• Enthalpy decreases because heat from the system is lost to the
environmentPhotosynthesis• Photosynthesis is NOT entropically favoured – entropy goes DOWN
– 6CO2(g) + 6H2O(l) à C6H12O6(aq) + 6O2(g)– Goes from more molecules to fewer molecules
• And it is endothermic so enthalpy goes UP• It requires energy from the sun in order to proceed
5.1 Static and Dynamic Equilibrium
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Module 5: Equilibrium and Acid Reactions
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Relationship between collision theory and reaction rateCollision Theory – in order for a successful reaction between gas particles:• A collision must occur• It must have sufficient speed• Particles must be in the right orientationActivation Energy• There is a minimum energy required for a reaction to occur. Granted that
particles are in the right orientation, a collision with sufficient energy (i.e. with sufficient speed) will be successful
Reaction rateA reaction will proceed faster if there are more collisions above the activation energy.• Increasing concentration of reactants increases the likelihood of a collision
happening, and of it being in the correct orientation• Increasing the temperature of reactants increases their kinetic energy, thereby
increasing their speed, so the likelihood of a collision being above the activation energy is increased
5.1 Static and Dynamic Equilibrium
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5.1 Practice Questions
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5.1 Practice Questions
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What factors affect equilibrium and how?• Temperature• Concentration• Volume/pressure (FOR GASES)
Le Chatelier’s Principle• “A system at equilibrium, when introduced to a change, will shift in
equilibrium to minimise that change.”• So a system will favour either the forward or reverse reaction in order to
get comfy again
So for example: If I increased the concentration of a particular substance, the system would favour the reaction that decreases its concentration.
5.2 Factors that Affect Equilibrium
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Concentration• If the concentration of the reactants is increased, the
equilibrium will favour the reaction that decreases the concentration of reactants (remember equilibrium shifts to minimise a change according to Le Chatelier’s Principle)
• The forward reaction is favoured (uses up reactants and makes more products)– This is called shifting to the right as more products are produced
• Conversely, if we increase the products, the equilibrium will shift to the left– Why?
5.2 Factors that Affect Equilibrium
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Notes:• Reactants are on the left and products are on the right
– You shouldn’t switch the names around for the reverse reaction! The reverse reaction involves products becoming reactants
• The system doesn’t want to get back to exactly where it was – it wants to find a new equilibrium under the new conditions and this new equilibrium will either be to the left or right of the previous equilibrium
• Shifting to the left = concentration of reactants goes up and concentration of products goes down
• Shifting to the right = concentration of products goes up and concentration of reactants goes down
5.2 Factors that Affect Equilibrium
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Pressure• Only affects GAS (!!!!!!!)• If we increase the pressure of a system, it will shift to
decrease pressure by favouring the side with fewer moles of gas– Each mole of gas (any gas) occupies the same volume
• If we decrease the pressure of a system, it will shift to increase pressure by shifting to the side with more moles of gas
5.2 Factors that Affect Equilibrium
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TemperatureRecall:• Endothermic reactions absorb heat to move forward
– It might help to think about heat as a reactant• Exothermic reactions release heat to move forward
– it might help to think about heat as a product• If a forward reaction is endothermic, the reverse reaction will be
exothermic and vice versa
• If we increase the temperature of a system, then by Le Chatelier’sPrinciple, the system will shift to minimize this change and lower the temperature of the system by favouring the endothermic reaction
• If we decrease the temperature of a system, it will shift to minimize this change and increase temperature by favouring the exothermic reaction
5.2 Factors that Affect Equilibrium
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In practice:• Heating cobalt(II) chloride hydrate:
– CoCl2(aq) + 6H2O(l) ⇌ CoCl2 · 6H2O(l)– We know that warming it up will cause the water to evaporate, dehydrating the
system– This means that the equilibrium shifts to the left when there is an increase in
temperature– So the reverse reaction must be endothermic (uses up heat)– And that means that the forward reaction is exothermic– We know that the dehydrated form is sky blue and the hydrated form is purple – SO heating the mixture will make the solution turn blue
5.2 Factors that Affect Equilibrium
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In practice:• Interaction between nitrogen dioxide and dinitrogen tetroxide
– 2NO2(g) ⇌ N2O4(g) ΔH = -57.20 kJ/mol– What happens if we increase concentration of NO2 or N2O4? (equilibrium shifts away
from the increase)– What happens if we increase the pressure of the vessel? (equilibrium shifts to the
right to decrease pressure because there are fewer moles of gas)– ΔH is negative so the reaction is exothermic. What would happen if we increased
temperature (equilibrium shifts to the left to decrease temperature)– To maximise yield: continuously add more reactant, continuously remove product,
increase pressure, decrease temperature
• iron(III) thiocyanate and varying concentration of ions– Fe3+(aq) + SCN-(aq) ⇌ FeSCN2+(aq)– Adding silver nitrate will cause a silver thiocyanate precipitate to form, reducing the
concentration of SCN- in solution and causing the equilibrium to shift to the left to increase concentration. Solution should become less red.
5.2 Factors that Affect Equilibrium
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Observations about equilibrium in terms of collision theory• Higher concentration = more reactant particles = more collisions• Higher pressure basically increases the concentration of gases• Higher temperature = more kinetic energy = more collisions that are
above the activation energy
How do activation energy and heat of reaction affect the position of equilibrium?• Lower activation energy means it’s easier for a reaction to take place• The higher the activation energy, the more kinetic energy is required in
order for a reaction to take place• Endothermic reactions are favoured when temperature is increased and
exothermic reactions are favoured when temperature is decreased
5.2 Factors that Affect Equilibrium
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5.2 Practice Questions
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5.2 Practice Questions
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5.2 Practice Questions
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5.2 Practice Questions
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How can the position of equilibrium be described and what does the equilibrium constant represent?
aA +bB ⇌ cC + dDKeq =
C - D /A 0 B 1
• Square brackets mean concentration (specifically use concentration at equilibrium)
• Turn coefficients into exponents and the multiple everything
• High K = lots of product• Low K = not as much product
Homogenous reactions?• A reaction that occurs in a single phase – all reactants and products are of
the same state
5.3 Calculating the Equilibrium Constant
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Q vs KYou get Q when you use the K calculation but the system isn’t at equilibrium – Q means reaction quotient
• Q < K = not enough product = favours the forward reaction to reach equilibrium
• Q > K = too much product = favours the reverse reaction to reach equilibrium
5.3 Calculating the Equilibrium Constant
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Equilibrium math: using ICE tablesFinding other concentrations in a system given one concentration• Write out the equation to get molar ratios• 2HI(g) ⇌ H2(g) + I2(g) (this is 2:1:1)• So 2 moles of HI will produce 1 mole of H2 and 1 mole of I2
• Hypothetically, if we let 2 moles of HI decompose in a 1L vessel, waited a while and then found that there were 0.7 moles of I2 at equilibrium:– There would also be 0.7 moles of H2 because H2:I2 is 1:1– An increase of 0.7 moles of I2 or H2 equals a decrease of twice as much HI
(remember it takes 2 moles of HI to produce 1 mole of either product)
5.3 Calculating the Equilibrium Constant
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HI H2 I2Initial 2 moles 0 0
Change -1.4 +0.7 +0.7
Equilibrium 0.6 0.7 0.7
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Temperature• The only factor that can change K• Remember:
– Increasing temperature in an exothermic reaction will decrease Keq– Increasing temperature in an endothermic reaction will increase Keq
Uses of Keq
• Keq = %&'()(*+ (&, [,+./)(*+ (&,][(&,(1 1&2%&3,4]– Dissociation of ionic compounds– This will tell us how much something dissolves in water
• Ka = 67 [89][86]
– Used to describe how the degree to which an acid ionises
5.3 Calculating the Equilibrium Constant
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5.3 Practice Questions
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5.3 Practice Questions
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5.3 Practice Questions
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5.3 Practice Questions
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5.3 Practice Questions
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5.3 Practice Questions
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How does solubility relate to chemical equilibrium?
Dissolution of ionic compounds in water• Oxygen has 2 lone pairs in water molecules• O is very electronegative (hogs the electrons in the covalent bonds),
leaving H quite positive• So water is a polar molecule• Positive ions are attracted to O and negative ions are attracted to H,
forming ion-dipole bonds
5.4 Solution Equilibria
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Removing toxins in cycad fruit• Cycad fruit is highly toxic and carcinogenic• Indigenous peoples needed a method for reducing the toxicity• One of these methods was to cut open a fruit and leave it in running
water• The toxins would dissolve into the water: Toxin(s) ⇌ Toxin(aq)• Moving water means that the aqueous toxin is continually carried away
and, continually decreasing the concentration of aqueous toxin• SO equilibrium is constantly shifting to the right and the toxins in the
fruit decrease
5.4 Solution Equilibria
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Solubility Rules• A useful mnemonic (credit to Jacob Silove)
• More active metals will displace less active metals from solution• The table of standard potentials on your reference sheet is in order from
most to least active– E.g. KCL(s) + AgNO3(aq) ⇌ AgCl(s) + KNO3(aq)
5.4 Solution Equilibria
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Mixing ionic solutions• Potassium chloride and silver nitrate
– KCl(aq) + AgNO3(aq) ⇌ AgCl(s) + KNO3(aq)– Silver chloride is insoluble (it’s a white precipitate)
• Potassium iodide and lead nitrate– Pb(NO3)2(aq) + 2KI(aq) ⇌ PbI2(s) + 2KNO3(aq)– Lead iodide is insoluble (it’s a yellow precipitate)
• Sodium sulfate and barium nitrate– Ba(NO3)2(aq) + Na2SO4(aq) ⇌ BaSO4(s) + 2NaNO3(aq)– Barium sulfate is insoluble (it’s a white precipitate)
5.4 Solution Equilibria
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Ksp (solubility product)• Ksp = [A-][B+]• No denominator because it’s a solid!• Saturated solution
To get from Ksp to solubility• Solubility = grams dissolved/volume of water dissolved into• Ksp is the product of concentrations of the products
– Use it to work out moles of products
• And then use moles of product to work out moles of reactant (solubility is based on the initial substance you were trying to dissolve)
• Convert moles of reactant to grams of reactant using m = nM• Solubility = grams per litre
5.4 Solution Equilibria
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Predicting if a Precipitate will formA precipitate forms when the quantity of a soluble substance exceeds a saturation point
• Find the limiting reagent• Calculate the solubility (from Ksp) (this is the saturation
point)• Determine whether you have tried to dissolve more than
can physically dissolve (more grams than the solubility allows)
5.4 Solution Equilibria
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5.4 Practice Questions
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5.4 Practice Questions
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CaSO4(s) ⇌ Ca2+(aq) + SO42-(aq)
H2SO4(aq) ⇌ 2H+(aq) + SO42-(aq)
Because more sulfate ions are added to the equilibrium, by Le Chatelier’s principle, the system will shift in the direction that decreases concentration of these ions. (ignore the hydrogenions bc they don’t matter for this question) So the reverse reaction is favoured (equilibrium shifts to the left), calcium and sulfate ions get used up and converted into solid calcium sulfate, meaning that there are fewer ions in solution
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5.4 Practice Questions
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5.4 Practice Questions
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Solution
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5.4 Practice Questions
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Why chlorine ions have a charge of -1
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5.4 Practice Questions
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5.4 Practice Questions
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Cheeky shortcut to make calculation easier: just get rid of one x to isolate the other
(given)
(from your table)
The x has just been disregarded (it’s so minute it doesn’t make enough of a difference to matter)
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5.4 Practice Questions
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(molecular mass of calcium hydroxide is 74.093)
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5.4 Practice Questions
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MODULE 5 DONE
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• Scientific drawings– Don’t close things that aren’t closed– Don’t shade
• Graphing– As always, independent variable on the x axis– Use at least 50% of the space
• Mole calculations– If you get lost, just write down each of the values you’ve been given
and then all the calculations you actually can do (even if you don’t get anywhere, this is a good way to scavenge marks)
Skills
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GET A GOOD STARTBecause catching up is 1000000000 times harder than just
being on top of things from the beginning
You will have 4 internal assessments that make up 50% of your overall mark
It ultimately doesn’t matter if you fuck one up!
DON’T BE LAZYBurnout is real but so is laziness. Find a balance and be
honest with yourself. It’s ok if you can’t do more. It’s not ok if you can but you can’t be bothered
HSC Tips
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WRITE NOTES AS YOU GONo, you canNOT do it later there will not be time
I’d advise that you do them electronically so you can go back and edit! And then print them, highlight them, draw on them
and get to know them like a really good friend
AVOID CRAMMING WHEN YOU CANBy doing weekly recaps! Each weekend, go over what you
learnt that week and also what you learnt the previous week and it will make exam revision a shitload easier
HSC Tips
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FOLLOW THE SYLLABUSThings are much less overwhelming if you know wtf is going on. Also the syllabus is there for a reason! Stuff that isn’t in
the syllabus isn’t assessable
PLAN YOUR TIMEWrite things down for goodness sake or you will forget to do
them. Keep to-do lists and make sure you PRIORITISE
PRIORITISEI can almost guarantee you won’t have time for everything
unless you’re a literal robot. Things that are assessable always come first (but not before your mental health)
HSC Tips
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CHANGE UP YOUR STUDY ENVIRONMENTSometimes it will be really hard to focus! Try studying outside,
studying lying on the ground, studying at other people’s houses, studying on the toilet to give your brain the change it wants
TAKE BREAKSDon’t waste time bashing away at something when you can’t
focus! Go for a walk or do anything but study for a set amount of time to reset and you’ll ultimately save time
USE A STUDY/BREAK SPLITYou can go as small as 5 minutes of study to 10 minutes of
break, it’s better than getting nothing done at all!
HSC Tips
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THE INTERNET IS FULL OF USEFUL STUFFYou can learn almost anything by googling it. You’ll only get
stuck when you can’t be bothered to do it
DON’T MURDER YOUR SOCIAL LIFEBecause studying is going to drive you crazy and your friends
will keep you sane
STUDYING = SOCIALISING?Study with your friends! Not only do you get to spend time with
them but teaching is the best way to learn and many heads reduce the workload
HSC Tips
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WORK ACCORDING TO YOUR GOALSThere is no point in working your butt off and stressing if you
don’t even need a high ATAR, especially because after the HSC, you’re never going to use a good 90% of what you learnt. Get the ATAR you need and move on (no one cares about your
ATAR anyway)
YOU GET OUT WHAT YOU PUT INYou can’t do minimal work and expect a high ATAR. The HSC generally favours people who work hard over people who are
naturally smart.
HSC Tips
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IT’S ONLY ONE YEARYes it’s shit but you only get so much time to do as well as you
can and it has a definite end (wahoo!!!)
DON’T BE ANGRY AT YOURSELF FOR THINGS YOU HAVE NO CONTROL OVER
This is probably at the top of the list of completely useless and quite destructive things
TAKE CARE OF YOURSELF AND DON’T GIVE UP!The HSC is HARD but it doesn’t have to be the most stressful
experience of your life
HSC Tips
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• Everyone is in the same boat. At the time you’re crying there is almost definitely someone else also crying.
• Sometimes it’s helpful to find someone to cry with/at and you’d be surprised by how many people are willing.
• The best way to minimize crying is to do things early BUT you can’t change the past and being angry at yourself solves nothing so get over it and make the most of the time you’ve got.
• The best you can do is the best you can do.• Your ATAR is an easy way into a course but it’s a perfectly valid plan to
do a similar course if you don’t get into your first choice, take the units you’d be taking for the course you want and have them count as credit when you transfer so you don’t even lose that much time (not that losing time should even matter)
• (You’ve heard it a million times but) Other than making it into a course, your ATAR counts for nothing and no one gives any fucks about it!
Emotional Support Slide