impulse and momentum chapter problems serway –5,6,10,13,16,17,18,27,29,33,43,44,52,54,59,60...
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Impulse and Momentum
• Chapter problems Serway– 5,6,10,13,16,17,18,27,29,33,43,44,52,54,59,60
– cw.prenhall.com/~bookbind/pubbooks/giancoli
Linear momentum & impulse
• Linear momentum is defined as the product of mass and velocity– p=mv, px=mvx , py= mvy
– units of momentum are kgm/s
• From Newtons 2nd law• F= ma F=mdv/dt F= dp/dt
• The rate of momentum change with respect to time is equal to the resultant force on an object
• The product of Force and time is known as IMPULSE
• J= Fdt
• units of impulse are Ns
Linear momentum & impulse
Examples of impulses being applied on everyday objects
Impulse Momentum Theorem
Fdt=mdv
You apply an impulse on an object and you get an equal change in momentum
IFdtmdvdppf
pi
tf
ti
vf
vi
tf
ti
Fdt Area under a Force vs time graph
v m t F
Impulse Graph
Linear Momentum and Impulse
Example problems 1,2,3
Chapter questions 5,6,10,13,16
Conservation of momentum2 particle system
For gravitational or electrostatic force
m1m2
F12
F21
F12 is force of 1 on 2
F21 is force of 2 on 1
F12 =dp1/dt F21 = dp2/dt
Conservation of momentum2 particle system
From Newton’s 3rd Law
F12 = - F21 or F12 + F21 = 0
m1m2
F12
F21
F12 is force of 1 on 2
F21 is force of 2 on 1
F12 + F21 =dp1/dt + dp2/dt = 0
d(p1 + p2)/dt= 0
Since this derivative is equal to 0
Conservation of momentum2 particle system
d(p1 + p2)/dt= 0then integration yieldsp1 + p2 = a CONSTANT
m1m2
F12
F21
F12 is force of 1 on 2
F21 is force of 2 on 1
Since this derivative is equal to 0
Thus the total momentum of the system of 2 particles is a constant.
Conservation of linear momentum
m1
m2
F12
F21
Simply stated: when two particles collide,their total
momentum remains constant.
pi = pf
p1i + p2i = p1f + p2f
(m1v1)i + (m2v2)i = (m1v1)f + (m2v2)f
Provided the particles are isolated from external forces, the total momentum of the particles will remain constant regards of the interaction between them
Conservation of linear momentum
Serway problems 9.2
17 & 18
Collisions
Collisions
Event when two particles come together for a short time producing impulsive forces on each other., No external forces acting. Or for the enthusiast: External forces are very small compared to the impulsive forces
Types of collisions
1) Elastic- Momentum and Kinetic energy conserved
2) Inelastic- Momentum conserved, some KE lost
3) Perfectly(completely) Inelastic- Objects stick together
Collisions in 1 d
Perfectly Elastic
1) Cons. of mom.
2) KE lost in collision
3) KE changes to PE
Elastic C
ollis ion Calculation
2 objects
Collisions - Examples
Computer Simulations
example 2, problems 5,24,29
Serway Problems 27,29,33,37
Collisions in 2 dimensions
mavax
mb
vel=0
p=0
Before collision
After Collision
mavaf
mbvbf
mavafx
mbvbxf
x momentum before collision equals x momentum after the collision
xfxi pp
1
2
Collisions in 2 dimensions xfxi pp
mavax= mavafx + mbvbxf
or
mavax= mavaf cos1 + mbvbf cos2
Collisions in 2 dimensions
mavax
mb
vel=0
p=0
Before collision
After Collision
mavaf
mbvbf
mavayf
Mbvbyf
y momentum before collision equals y momentum after the collision
yfyi pp
Velocity
y axis =0
py=o
2
1
Collisions in 2 dimensions yfyi pp
0= mavafy - mbvbfy
or
0= mavaf sin1 -mbvbf sin2
Collisions in 2 dimensions
xfxi pp
0= mavaf sin1 -mbvbf sin2
yfyi pp
mavax= mavaf cos1 + mbvbf cos2
Problems ex 9.9
43,44