A 100kva alternator is connected with 10kv bus bar.a 3 phase to ground fault occurs at the bus-bar.the

bus bar impedance is 1+2j pu.find fault current.

Current =1

1+2𝑗pu

Base Current=100𝑘𝑣𝑎

3 (10𝑘𝑣)

Current in ampere=pu current*base current=2.582 < −63.43

1 pu

source

1+2j pu