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Mining Association Mining Association Rul sRules

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Mining Association RulesMining Association Rules

What is Association rule mining

Apriori Algorithm

Measures of rule interestingness

Advanced Techniques

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Wh t I A i ti R l Mi i ?What Is Association Rule Mining?

Association rule miningFi di f t tt i ti l ti l Finding frequent patterns, associations, correlations, or causal structures among sets of items in transaction databases

Understand customer buying habits by finding associations and correlations between the different items that customers place in th i “ h i b k t”their “shopping basket”

Applications Applications Basket data analysis, cross-marketing, catalog design, loss-leader

analysis, web log analysis, fraud detection (supervisor->examiner)

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analys s, web log analys s, fraud detect on (superv sor exam ner)

Wh t I A i ti R l Mi i ?

R l f

What Is Association Rule Mining?

Rule form

Antecedent Consequent [support, confidence]q

(support and confidence are user defined measures of interestingness)

Examples buys(x, “computer”) buys(x, “financial management software”)

[0.5%, 60%]

age(x, “30..39”) ^ income(x, “42..48K”) buys(x, “car”) [1%,75%]

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g ( , ) ( , ) y ( , ) [ , ]

How can Association Rules be used?

Probably mom was

How can Association Rules be used?

Probably mom was calling dad at work to buy diapers on way ap rs on way home and he decided to buy a six-pack as well. p

The retailer could move diapers and beers to separate places and

i i hi hposition high-profit items of interest to young f th l th

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fathers along the path.

How can Association Rules be used? Let the rule discovered be

How can Association Rules be used?L t th ru sco r

{Bagels,...} {Potato Chips}

Potato chips as consequent => Can be used to determine what should be done to boost its sales

Bagels in the antecedent => Can be used to see which products would be affected if the store discontinues selling bagelswould be affected if the store discontinues selling bagels

Bagels in antecedent and Potato chips in the consequent => Bagels in antecedent and Potato chips in the consequent Can be used to see what products should be sold with Bagels to promote sale of Potato Chips

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B Basic Concepts

Given: (1) database of transactions (1) database of transactions, (2) each transaction is a list of items purchased by a customer

in a visit

Find: Find: all rules that correlate the presence of one set of items

(itemset) with that of another set of items( ) f f

E.g., 35% of people who buys salmon also buys cheese

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E.g., 35% of people who buys salmon also buys cheese

TX1 Shoes, Socks, Tie, Belt

TX2 Shoes, Socks, Tie, Belt, Shirt, Hat

TX3 Shoes TieTX3 Shoes, Tie

TX4 Shoes, Socks, Belt

Transaction Shoes Socks Tie Belt Shirt Scarf HatTransaction Shoes Socks Tie Belt Shirt Scarf Hat1 1 1 1 0 0 02 1 1 1 1 1 0 13 1 0 1 0 0 0 04 1 1 0 1 0 0 0...

Support is 50% (2/4)TieSocks

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Confidence is 66.67% (2/3)TieSocks

Rule basic MeasuresRule basic Measures

A B [ s, c ]

Support: denotes the frequency of the rule within pp q ytransactions. A high value means that the rule involves a great part of database.

support(A B [ s, c ]) = p(A B)

Confidence: denotes the percentage of transactions containing A which also contain B It is an estimation of containing A which also contain B. It is an estimation of conditioned probability .

fid (A B [ s ]) (B|A) s (A B)/s (A)

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confidence(A B [ s, c ]) = p(B|A) = sup(A,B)/sup(A).

acti

ons

tran

sa

Rule C => D support

fid /10

confidence /

ApplicationsApplications “Baskets” = documents; “

items” = words in those documents. Lets us find words that appear together unusually frequently Lets us find words that appear together unusually frequently,

i.e., linked concepts.

Word 1 Word 2 Word 3 Word 4Doc 1 1 0 1 1Doc 2 0 0 1 1Doc 3 1 1 1 0

Word 4 => Word 3

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When word 4 occurs in a document there a big probability of word 3 occurring

ApplicationsApplications

“B k ” “ ” d “Baskets” = sentences, “items” = documents containing those sentences. Items that appear together too often could represent

plagiarism.

Doc 1 Doc 2 Doc 3 Doc 4Sent 1 1 0 1 1Sent 2 0 0 1 1Sent 3 1 1 1 0

Doc 4 => Doc 3

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When a sentence occurs in document 4 there is a big probability of occurring in document 3

ApplicationsApplications

“B k ” b “ ” l k d “Baskets” = Web pages; “items” = linked pages. Pairs of pages with many common references may be about the

same topic.

“Baskets” = Web pages pi ; “items” = pages that link to pi

Pages with many of the same links may be mirrors or about the same topic.

wp a wp b wp c wp dwp1wp1wp2

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Example Definitions:pItemset:

A B B E FTrans Id Purchased Items

Definitions:

A,B or B,E,F

Support of an itemset:

Trans. Id Purchased Items1 A,D2 A C

Sup(A,B)=1 Sup(A,C)=2

Frequent pattern:

2 A,C3 A,B,C4 B E F

Given min. sup=2, {A,C} is a frequent pattern

4 B,E,F

For minimum support = 50% and minimum confidence = 50%, we have h f ll i lthe following rules

A => C with 50% support and 66% confidence

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C => A with 50% support and 100% confidence

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Randall Matignon 2007, Data Mining Using SAS Enterprise Miner, Wiley (book).

The support probability of each rule is identified by the color of the symbols and the confidence probability of each rule is identified by the shape of the symbols. The items that have the highest confidence are

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Heineken beer, crackers, chicken, and peppers.

Randall Matignon 2007, Data Mining Using SAS Enterprise Miner, Wiley (book).



Apriori Algorithm Apriori Algorithm


Advanced Techniques

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Boolean association rulesBoolean association rules

Each transaction is converted to a Boolean vectorBoolean vector

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An ExampleAn Example

Transaction ID Items Bought Min. support 50%Transaction ID Items Bought2000 A,B,C1000 A C F t It t S t

ppMin. confidence 50%

1000 A,C4000 A,D5000 B E F

Frequent Itemset Support{A} 75%{B} 50%5000 B,E,F {B} 50%{C} 50%

{A C} 50%

For rule A C :

{A,C} 50%

support = support({A , C }) = 50%

confidence = support({A , C }) / support({A }) = 66.6%

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Finding Association RulesFinding Association Rules

Approach:Approach:

1) Find all itemsets that have high support

- These are known as frequent itemsets

2) Generate association rules from frequent itemsets

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Mining Frequent Itemsets (the Key Step)Mining Frequent Itemsets (the Key Step)

Find the frequent itemsets: the sets of items that have (at least) minimum support A subset of a frequent itemset must also be a frequent

itemset Generate length (k+1) candidate itemsets from length k

frequent itemsets, and

Test the candidates against DB to determine which are in fact Test the candidates against DB to determine which are in fact frequent

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Apriori principleApriori principle

Any subset of a frequent itemset must y qbe frequent

A transaction containing {beer diaper nuts} also contains A transaction containing {beer, diaper, nuts} also contains {beer, diaper}

{beer diaper nuts} is frequent {beer diaper} must also be {beer, diaper, nuts} is frequent {beer, diaper} must also be frequent

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Apriori principleApriori principle

No superset of any infrequent itemset should be generated or testedshould be generated or tested

Many item combinations can be prunedy m m p

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Itemset Latticenull

A B C D E

AB AC AD AE BC BD BE CD CE DE

ABC ABD ABE ACD ACE ADE BCD BCE BDE CDEABC ABD ABE ACD ACE ADE BCD BCE BDE CDE

ABCD ABCE ABDE ACDE BCDE

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ABCDE

Apriori principle for pruning candidatesApriori principle for pruning candidates

If it t i null

If an itemset is infrequent, then all of its supersets must also be A B C D E

infrequent

AB AC AD AE BC BD BE CD CE DE

Found to be Infrequent ABC ABD ABE ACD ACE ADE BCD BCE BDE CDE

ABCD ABCE ABDE ACDE BCDEPruned supersets

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ABCDE

How to Generate Candidates?

The items in Lk-1 are listed in an orderk 1

Step 1: self-joining Lk-1

insert into Ck

select p item p item p itemk q itemkselect p.item1, p.item2, …, p.itemk-1, q.itemk-1

from Lk-1 p, Lk-1 qwhere p.item1=q.item1, …, p.itemk-2=q.itemk-2, p.itemk-1 < q.itemk-1p 1 q 1 p k 2 q k 2 p k 1 q k 1

A D EA D E

A D F= = <

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The Apriori Algorithm — Example

Database D itemset sup.{1} 2 itemset supC1 L

Min. support: 2 transactions

TID Items100 1 3 4200 2 3 5

{1} 2{2} 3{3} 3

itemset sup.{1} 2{2} 3Scan D

1 L1

300 1 2 3 5400 2 5

{4} 1{5} 3

{3} 3{5} 3

Scan D

itemset{1 2}{1 3}

itemset sup{1 2} 1{1 3} 2

itemset sup{1 3} 2

L2

C2 C2

{1 3}{1 5}{2 3}{2 5}

{1 3} 2{1 5} 1{2 3} 2

{1 3} 2{2 3} 2{2 5} 3

Scan D

{2 5}{3 5}

{2 5} 3{3 5} 2

{ }{3 5} 2

C Litemset S D itemset sup

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C3 L3itemset{2 3 5}

Scan D itemset sup{2 3 5} 2

How to Generate Candidates?

S 2 i Step 2: pruningfor all itemsets c in Ck do

for all (k-1)-subsets s of c doif (s is not in Lk-1) then delete c from Ck

A D E FA D E F

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Example of Generating CandidatesExample of Generating Candidates

L = {abc abd acd ace bcd} L3 = {abc, abd, acd, ace, bcd}

Self-joining: L3*L3 Self joining: L3 L3

joining abc and abd gives abcd joining abc and abd gives abcd

j i i d d i d joining acd and ace gives acde

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Example of Generating CandidatesExample of Generating Candidates L3 = {abc, abd, acd, ace, bcd} L3 {abc, abd, acd, ace, bcd}

Pruning (before counting its support): Pruning (before counting its support):

abcd: check if abc, abd, bcd are in L3 abcd: check if abc, abd, bcd are in L3

acde: check if acd, ace, ade are in L3, ,

acde is removed because ade is not in L3

Thus C4={abcd}

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The Apriori Algorithmp g Ck: Candidate itemset of size k Lk : frequent itemset of size k

J i St : C is t d b j i i L ith its lf Join Step: Ck is generated by joining Lk-1 with itself

Prune Step: Any (k-1)-itemset that is not frequent cannot be a b f f k isubset of a frequent k-itemset

Algorithm:L {f i }L1 = {frequent items};for (k = 1; Lk !=; k++) do beginCk+1 = candidates generated from Lk;Ck+1 candidates generated from Lk;for each transaction t in database do

increment the count of all candidates in Ck+1 that are contained in tLk+1 = candidates in Ck+1 with min_support

end

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endreturn L = k Lk;

Counting Support of CandidatesCounting Support of Candidates

Wh ti t f did t bl ? Why counting supports of candidates a problem? The total number of candidates can be very large One transaction may contain many candidates One transaction may contain many candidates

Method: Candidate itemsets are stored in a hash-tree Match candidates to transactions supporting it

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Counting Support of Candidate ItemsetsCounting Support of Candidate Itemsets Frequent Itemsets are found by counting candidates

Naive way: Search for each candidate in each transaction Expensive!!!p

Candidates Count

A B 0A B 1A B 1A B 2Transactions

A B C D

A B 0

A C 0

A D 01A D

A C

A B

1

1

1A D

A C

A B

2

1

2A D

A C

A B

2

2Naïve approachrequires O(NM)comparisons

M

A C E

B C D

A E 0

B C 0

B D 0

0A E

B D

B C

1

1

1A E

B D

B C

1

1Reduce the number

2A E

B D

B C

4

3

comparisons

N MA B D E

B C E

B D 0

A B E 0

B C D 0

A B D E 0B C D

A B E

B D

1

0

1

B C D

A B E

B D

1

0

1 Reduce the number of comparisons(NM) by using hashtables to store theB C D

A B E

B D

2

2

4

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B C E

B DA B D E 0

A B C D E 0A B C D E

A B D E

0

0

A B C D E

A B D E

0

0 candidate itemsetsA B C D E

A B D E

0

1

Reducing Number of ComparisonsReducing Number of Comparisons

h d d h h Store the candidate itemsets in a hash structure Hash each transaction to its appropriate buckets

Match transaction only to candidates stored in the hashed bucket(s)

Hash

TID Items

TransactionsHash

Structure

1 Bread, Milk 2 Bread, Diaper, Beer, Eggs 3 Milk, Diaper, Beer, Coke N k4 Bread, Milk, Diaper, Beer 5 Bread, Milk, Diaper, Coke

Buckets

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Buckets

Example I: itemset{cucumber, parsley, onion, tomato, salt, bread, olives, cheese,

butter}

D: set of transactions1 {{cucumber, parsley, onion, tomato, salt, bread},2 {tomato, cucumber, parsley},3 {tomato, cucumber, olives, onion, parsley},4 {tomato, cucumber, onion, bread},5 {tomato, salt, onion},6 {bread, cheese}6 {bread, cheese}7 {tomato, cheese, cucumber}8 {bread, butter}}

35from: http://www.cs.bilkent.edu.tr/~guvenir/courses/CS558/Association%20Rules.ppt

For Support = 30% ‐> at least 3 transactionsL = {{bread} {cucumber} {onion} {parsley} {tomato}}L1 = {{bread}, {cucumber}, {onion}, {parsley}, {tomato}}

C2 = {{bread cucumber} {bread onion} {bread parsley}C2 {{bread, cucumber}, {bread, onion}, {bread, parsley}, {bread, tomato}, {cucumber, onion}, {cucumber, parsley},{cucumber, tomato}, {onion, parsley},{ , }, { , p y},{onion, tomato}, {parsley, tomato}}

L2 = {{cucumber, onion}, {cucumber, parsley}, {cucumber, tomato}, {onion, tomato}, {parsley, tomato}}

L3 = {{cucumber, parsley, tomato}}L = L L LL = L1 L2 L3


C2 = {{bread, cucumber}, {bread, onion}, {bread, parsley}, {bread tomato} {cucumber onion} {cucumber parsley}{bread, tomato}, {cucumber, onion}, {cucumber, parsley},{cucumber, tomato}, {onion, parsley},{onion tomato} {parsley tomato}}

The hash‐tree constructed for C2:

{onion, tomato}, {parsley, tomato}}

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root|_______________________|__________________________

| | | |bread cucumber onion parsley| | | |

{bread, cucumber} {cucumber, onion} {onion, parsley} {parsley, tomato}{bread, onion} {cucumber, parsley} {onion, tomato}{bread, parsley} {cucumber, tomato}{bread, tomato}

For any itemset c contained in transaction t the first item of cmust be in t


For any itemset c contained in transaction t, the first item of cmust be in t.At root, by hashing on every item in t, we ensure that we only ignore itemsets that start with an item not in t.

Generating AR from frequent intemsetsGenerating AR from frequent intemsets

f d ( B) P(B| ) support count({A B}) Confidence (AB) = P(B|A) = ,support_count({A B})

support_count({A})

For every frequent itemset x, generate all non-empty subsets of x

f h l For every non-empty subset s of x, output the rule

“ s (x-s) ” if ( )

min_confunt({s})support count({x})support_co

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unt({s})support_co

Rule GenerationRule Generation

ff l l f f How to efficiently generate rules from frequent itemsets? In general, confidence does not have an anti-monotone

property

But confidence of rules generated from the same itemset has an anti-monotone property

L {A B C D} L = {A,B,C,D}:

c(ABC D) c(AB CD) c(A BCD)( ) ( ) ( )

Confidence is non-increasing as number of items in rule

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f g fconsequent increases

From Frequent Itemsets to Association Rules From Frequent Itemsets to Association Rules

Q: Given frequent set {A,B,E}, what are possible Q G n fr qu n { , ,E}, w r passociation rules? A => B, E,

A, B => E

A, E => B,

B => A, E

B, E => A,

E => A, B

__ => A,B,E (empty rule), or true => A,B,E__ , , ( p y ), , ,

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Generating Rules: exampleg p

Trans-ID Items Min_support: 60%

1 ACD2 BCE

Min_confidence: 75%

3 ABCE4 BE5 ABCE Frequent Itemset Support

{BCE},{AC} 60%{BC} {CE} {A} 60%R le Conf {BC},{CE},{A} 60%{BE},{B},{C},{E} 80%

Rule Conf.{BC} =>{E} 100%{BE} =>{C} 75%{BE} {C} 75%{CE} =>{B} 100%{B} =>{CE} 75%

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{C} =>{BE} 75%{E} =>{BC} 75%

ExerciceExerciceTID Items1 Bread Milk Chips Mustard1 Bread, Milk, Chips, Mustard2 Beer, Diaper, Bread, Eggs3 Beer, Coke, Diaper, Milk

Converta os dados para o formato booleano e para um suporte de 40% aplique o

4 Beer, Bread, Diaper, Milk, Chips5 Coke, Bread, Diaper, Milk6 B B d Di Milk M t d

suporte de 40%, aplique o algoritmo apriori.

6 Beer, Bread, Diaper, Milk, Mustard7 Coke, Bread, Diaper, Milk

Bread Milk Chips Mustard Beer Diaper Eggs Coke1 1 1 1 0 0 0 01 0 0 0 1 1 1 00 1 0 0 1 1 0 11 1 1 0 1 1 0 01 1 0 0 0 1 0 11 1 0 1 1 1 0 0

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1 1 0 1 1 1 0 01 1 0 0 0 1 0 1

0.4*7= 2.8

C1 L1 C2 L2Bread 6 Bread 6 Bread,Milk 5 Bread,Milk 5Milk 6 Milk 6 Bread Beer 3 Bread Beer 3Milk 6 Milk 6 Bread,Beer 3 Bread,Beer 3Chips 2 Beer 4 Bread,Diaper 5 Bread,Diaper 5Mustard 2 Diaper 6 Bread,Coke 2 Milk,Beer 3Beer 4 Coke 3 Milk,Beer 3 Milk,Diaper 5, , pDiaper 6 Milk,Diaper 5 Milk,Coke 3Eggs 1 Milk,Coke 3 Beer,Diaper 4Coke 3 Beer,Diaper 4 Diaper,Coke 3

Beer,Coke 1Diaper,Coke 3

C3 L3C3 L3Bread,Milk,Beer 2 Bread,Milk,Diaper 4Bread,Milk,Diaper 4 Bread,Beer,Diaper 3Bread Beer Diaper 3 Milk Beer Diaper 3Bread,Beer,Diaper 3 Milk,Beer,Diaper 3Milk,Beer,Diaper 3 Milk,Diaper,Coke 3Milk,Beer,CokeMilk,Diaper,Coke 3

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, p ,8 8

2 38 92 24 C C





Advanced Techniques

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Interestingness Measurementsg

Are all of the strong association rules discovered interesting Are all of the strong association rules discovered interesting enough to present to the user?

How can we measure the interestingness of a rule? How can we measure the interestingness of a rule?

Subjective measures

A rule (pattern) is interesting if

• it is unexpected (surprising to the user); and/or

• actionable (the user can do something with it)actionable (the user can do something with it)

• (only the user can judge the interestingness of a rule)

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Objective measures of rule interestObjective measures of rule interest

Support

Confidence or strengthg

Lift or Interest or Correlation

C i i Conviction

Leverage or Piatetsky-Shapirog y p

Coverage

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Criticism to Support and Confidencepp Example 1: (Aggarwal & Yu,

PODS98) basketball not basketball sum(row)PODS98)

Among 5000 students 3000 play basketball

( )cereal 2000 1750 3750 75%

not cereal 1000 250 1250 2 5%

sum(col ) 3000 2000 5000 3000 play basketball 3750 eat cereal 2000 both play basket ball

nd t c l

sum(col.) 3000 2000 50006 0 % 4 0 %

and eat cereal

play basketball eat cereal [40% 66 7%] play basketball eat cereal [40%, 66.7%]

misleading because the overall percentage of students eating cereal is 75% which is higher than 66 7%75% which is higher than 66.7%.

play basketball not eat cereal [20%, 33.3%]

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is more accurate, although with lower support and confidence

Lift of a RuleL f f

Lift (Correlation Interest) Lift (Correlation, Interest)

s ( ) ( | )A B P B Asup( , ) ( | )Lift( )sup( ) sup( ) ( )

A B P B AA BA B P B

A and B negatively correlated, if the value is less than 1; th r is A nd B p sitiv l c rr l t dotherwise A and B positively correlated

X 1 1 1 1 0 0 0 0 rule Support Lift0 0 0 0Y 1 1 0 0 0 0 0 0Z 0 1 1 1 1 1 1 1

X Y 25% 2.00XZ 37.50% 0.86YZ 12 50% 0 57

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Z 0 1 1 1 1 1 1 1 YZ 12.50% 0.57

Lift of a RuleLift of a RuleExample 1 (cont)

play basketball eat cereal [40%, 66.7%] 89.03750300050002000

LIFT

50005000

1000

play basketball not eat cereal [20%, 33.3%] 33.1

50001250

50003000

50001000

LIFT

basketball not basketball sum(row)cereal 2000 1750 3750not cereal 1000 250 1250

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sum(col.) 3000 2000 5000

Problems With LiftProblems With Lift

Rules that hold 100% of the time may not have the highest Rules that hold 100% of the time may not have the highest possible lift. For example, if 5% of people are Vietnam veterans and 90% of the people are more than 5 years old, we get a lift of 9 f p p m y , w g f f0.05/(0.05*0.9)=1.11 which is only slightly above 1 for the rule

Vietnam veterans -> more than 5 years old Vietnam veterans > more than 5 years old.

And, lift is symmetric:

not eat cereal play basketball [20%, 80%]p y [ ]

33150001000

LIFT

50

33.1

50003000

50001250LIFT

Conviction of a RuleConviction of a Rule

1sup( ) sup( ) ( ) ( ) ( )( ( ))( ) A B P A P B P A P BC A B 1sup( ) sup( ) ( ) ( ) ( )( ( ))( )( ) ( , )sup( , ) ( , )

A B P A P B P A P BConv A BP A P A BA B P A B

Conviction is a measure of the implication and has value 1 if items are unrelated.

play basketball eat cereal [40%, 66.7%] 75.0

50002000

50003000

500037501

50003000

Conv

eat cereal play basketball conv:0.85

play basketball not eat cereal [20% 33 3%] 125.110003000500012501

50003000

Conv

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play basketball not eat cereal [20%, 33.3%] not eat cereal play basketball conv:1.43 5000

100050003000

ConvictionConviction

f b d h conviction of X=>Y can be interpreted as the

ratio of the expected frequency that X occurs without p q yY (that is to say, the frequency that the rule makes an incorrect prediction) if X and Y were independent

divided by the observed frequency of incorrect predictions. predictions.

A conviction value of 1.2 shows that the rule would be incorrect 20% more often (1 2 times as often) if the incorrect 20% more often (1.2 times as often) if the association between X and Y was purely random chance.

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Leverage of a RuleLeverage of a Rule

Leverage or Piatetsky Shapiro Leverage or Piatetsky-Shapiro

P ( ) sup( , ) sup( ) sup( )S A B A B A B

PS (or Leverage):

is the proportion of additional elements covered by both the premise and consequence above the expected if independent.

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Coverage of a RuleCoverage of a Rule

( ) s p( )A B Acoverage( ) sup( )A B A

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CommentComment

d l h d h d b Traditional methods such as database queries: support hypothesis verification about a relationship such as

the co-occurrence of diapers & beer.

Data Mining methods automatically discover significant associations rules from data.

Find whatever patterns exist in the database, without the user having to specify in advance what to look for (data driven).

Therefore allow finding unexpected correlations

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ASSOCIATION RULES WITH

56

Using Scripts in RUsing Scripts in R

Menu “File; New script”

write down the following commands

a <‐ runif(100,10,20)

hist(a)

Menu “File;Save as...” test.R

source(‘teste.R’) ‐ to run the script

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Another scriptAnother script

for (i in 1:5){

a <‐ runif(10*i, 10, 20)a runif(10 i, 10, 20)

hist(a, main=paste("uniform n=", 10*i))

savePlot(filename= paste("uniform n=", 10*i),type="jpeg")

} }

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Association Rules in R package: arules library(arules) data(Groceries) summary(Groceries) length(Groceries) LIST(Groceries[1:5]) image(Groceries[1:500]) image(Groceries[1:500])

my_rules <‐ apriori(Groceries, parameter = list(supp=0.001, conf=0.5)) inspect(my_rules) inspect(my_rules[1:10]) my_rules_2 <‐ SORT(rule, by = "lift") inspect(SORT(rule, by="lift")[1:3])~ summary(my rules) summary(my_rules)

itemFrequencyPlot(Groceries, support = 0.1, cex.names = 0.8) itemFrequencyPlot(Groceries, support = 0.05, cex.names = 0.8)

butter_rules <‐ subset(my_rules,subset = lhs %in% "butter" & lift > 1.2) butter_rules <‐ subset(my_rules,subset = lhs %in% "butter" & lhs %in% "rice" & lift > 1.2)

Groceries.sample <‐ sample(Groceries,1000,replace=TRUE) itemFrequency(Groceries.sample) > 0.002

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APRIORI EXTENSIONS

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Challenges of Frequent Pattern MiningChallenges of Frequent Pattern Mining

Ch ll Challenges Multiple scans of transaction database

Huge number of candidates

Tedious workload of support counting for candidates

Improving Apriori: general ideas Reduce number of transaction database scans

Shrink number of candidates

Facilitate support counting of candidates

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Improving Apriori’s EfficiencyImproving Apriori s Efficiency

Problem with Apriori: every pass goes over whole data Problem with Apriori: every pass goes over whole data.

AprioriTID: Generates candidates as apriori but DB is d f ti t l th fi t used for counting support only on the first pass.

Needs much more memory than Apriori

Builds a storage set C^k that stores in memory the frequent sets per transaction

AprioriHybrid: Use Apriori in initial passes; Estimate the size of C^k; Switch to AprioriTid when C^k is expected to s z of k; Sw tch to pr or wh n k s p ct to fit in memory The switch takes time but it is still better in most cases

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The switch takes time, but it is still better in most cases

ItemsTID Set-of-itemsetsTID SupportItemset

C^1 L1ItemsTID1 3 41002 3 5200

Set of itemsetsTID

{ {1},{3},{4} }100{ {2},{3},{5} }200

SupportItemset2{1}3{2}

1 2 3 53002 5400

{ {1},{2},{3},{5} }300{ {2},{5} }400

3{3}3{5}

itemsetSI

L2Set-of-itemsetsTID

C2 C^2

{1 2}{1 3}{1 5}

SupportItemset2{1 3}3{2 3}

{ {1 3} }100{ {2 3},{2 5} {3 5} }200{ {1 2} {1 3} {1 5}300{1 5}

{2 3}{2 5}

3{2 3}3{2 5}2{3 5}

{ {1 2},{1 3},{1 5},

{2 3}, {2 5}, {3 5} }

300

{ {2 5} }400{3 5}

SupportItemset

{ { } }

C^3 L3C3 Set-of-itemsetsTID

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itemset{2 3 5}

SupportItemset2{2 3 5}

{ {2 3 5} }200{ {2 3 5} }300

Improving Apriori’s EfficiencyImproving Apriori s Efficiency

Transaction reduction: A transaction that does not Transaction reduction A transaction that does not contain any frequent k-itemset is useless in subsequent scans

S li i i b t f i d t Sampling: mining on a subset of given data. The sample should fit in memory

Use lower support threshold to reduce the probability of missing some itemsets.

The rest of the DB is used to determine the actual itemset count.

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Improving Apriori’s Efficiency

P i i i A i h i i ll f i DB b Partitioning: Any itemset that is potentially frequent in DB must be frequent in at least one of the partitions of DB (2 DB scans) (support in a partition is lowered to be proportional to the number of (support in a partition is lowered to be proportional to the number of

elements in the partition)

Phase I

Divide D Fi d f t Combine Fi d l b l

Phase IPhase II

Trans.in D

Divide D into nNon-

overlappin

Find frequent itemsets local

to each partition

Combine results to

form a global set of

did t

Find global frequent itemsets among

Freq. itemsets

in Dgpartitions

partition(parallel alg.) candidate

itemsets

among candidates

in D

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Improving Apriori’s Efficiencyp g p ff y

Dynamic itemset counting: partitions the DB into several blocks each marked by a start point.

At each start point, DIC estimates the support of all itemsets that are currently counted and adds new itemsets to the set of candidate i if ll i b i d b f itemsets if all its subsets are estimated to be frequent.

If DIC adds all frequent itemsets to the set of candidate itemsets d i th fi t it ill h t d h it t’ t t during the first scan, it will have counted each itemset’s exact support at some point during the second scan;

th DIC l t i t thus DIC can complete in two scans.

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Association Rules VisualizationAssociation Rules Visualization

The coloured column indicates the association rule BC. Diff t i l d t h diff t t d t l f

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Different icon colours are used to show different metadata values of the association rule.


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Association Rules VisualizationAssociation Rules VisualizationAssociation Rules VisualizationAssociation Rules Visualization

Size of ball equates to total support

Height Height equates to confidence

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Association Rules Visualization Association Rules Visualization -- Ball graphBall graph

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The Ball graph ExplainedThe Ball graph Explained

A b ll h i t f t f d d All th d ll A ball graph consists of a set of nodes and arrows. All the nodes are yellow, green or blue. The blue nodes are active nodes representing the items in the rule in which the user is interested. The yellow nodes are passive representing items related to the active nodes in some way The green nodes merely assist in visualizing two or the active nodes in some way. The green nodes merely assist in visualizing two or more items in either the head or the body of the rule.

A circular node represents a frequent (large) data item. The volume of the ball t th t f th it O l th it hi h ffi i tl represents the support of the item. Only those items which occur sufficiently

frequently are shown

An arrow between two nodes represents the rule implication between the two items. An arrow will be drawn only when the support of a rule is no less than the minimum support

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FP-tree Algorithm

Additional Measures of rule interestingness

Advanced Techniques

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Multiple-Level Association RulesMultiple Level Association Rules

FoodStuffFoodStuff

Frozen Refrigerated Fresh Bakery Etc...

Vegetable Fruit Dairy Etc....

Banana Apple Orange Etc...

Fresh Bakery [20%, 60%]

Dairy Bread [6%, 50%]

Fruit Bread [1%, 50%] is not valid

Items often form hierarchy.

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Flexible support settings: Items at the lower level are expected to have lower support.Transaction database can be encoded based on dimensions and levels explore shared multi-level mining

Multi-Dimensional Association RulesMulti Dimensional Association Rules

Single-dimensional rules: buys(X, “milk”) buys(X, “bread”)

Multi-dimensional rules: 2 dimensions or predicatesp Inter-dimension association rules (no repeated predicates)

age(X,”19-25”) occupation(X,“student”) buys(X,“coke”) age(X, 19 25 ) occupation(X, student ) buys(X, coke )

hybrid-dimension association rules (repeated predicates) age(X ”19-25”) buys(X “popcorn”) buys(X “coke” age(X, 19-25 ) buys(X, popcorn ) buys(X, coke

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Q i i A i i R lQuantitative Association Rules

age(X,”30-34”) income(X,”24K - 48K”) buys(X,”high resolution TV”)

Mining Sequential Patterns

10% of customers bought “Foundation” and “Ringworld” in one transaction, gfollowed by “Ringworld Engineers” in another transaction.

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g g

Sequential Pattern Mining Given

Sequential Pattern Mining

A database of customer transactions ordered by increasingtransaction timeEach transaction is a set of items Each transaction is a set of items

A sequence is an ordered list of itemsets

Example: Example: 10% of customers bought “Foundation“ and “Ringworld" in one

transaction, followed by “Ringworld Engineers" in another transaction. 10% is called the support of the pattern

(a transaction may contain more books than those in the pattern)

Problem Find all sequential patterns supported by more than a user-specified

percentage of data sequences

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percentage of data sequences

Sequential Patterns RulesSequential Patterns Rules

(F ) ( E) (FE) h % d % (F, R) (RE) (FE) with 3% support and 40% confidence.

Confidence: 40% of occurrences of (F, R) (RE) are followed by (FE).

(FE- foundation and empire)

Problem Decomposition:Fi d ll i l i h i i Find all sequential patterns with minimum support.

Use the sequential patterns to generate rules.

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Applications

Applications of sequential pattern miningApplications of sequential pattern mining Attached mailing, e.g., customized mailings for a

b k l bbook club.

Customer satisfaction / retention

Web log analysis

Medical research, e.g., sequences of symptoms

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The AprioriAll Algorithm [AgSr95]

A 3-phase algorithm Phase 1: finds all frequent itemsets with minimum support that is Phase 1: finds all frequent itemsets with minimum support, that is,

with a minimum number of customers containing it

Ph 2 t f th DB t h t ti i l d b Phase 2: transforms the DB s.t. each transaction is replaced by the set of all frequent itemsets contained in the transaction

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Phase 3: finds all sequential patterns

The AprioriAll Algorithm (cont.) The sequence phase: In each phase it uses the large sequences from

previous phase to generate the candidate sequences, and then m s s th s t f did t smeasures the support of candidates.

Customer sequences min_support = 0.4Maximal sequences

(2 customer sequences)

81C4

Application DifficultiesApplication Difficulties

l k h h b B b d ll Wal-Mart knows that customers who buy Barbie dolls (it sells one every 20 seconds) have a 60% likelihood of b i f th t f d b Wh t d buying one of three types of candy bars. What does Wal-Mart do with information like that?

'I don't have a clue,' says Wal-Mart's chief of merchandising, Lee Scott.

See KDnuggets 98:01 for many ideas See - KDnuggets 98:01 for many ideas www.kdnuggets.com/news/98/n01.html

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Some SuggestionsSome Suggestions

B i i h i f B bi d ll d i i h f d b By increasing the price of Barbie doll and giving the type of candy bar free, wal-mart can reinforce the buying habits of that particular types of buyer

Highest margin candy to be placed near dolls.

Special promotions for Barbie dolls with candy at a slightly higher margin.

Take a poorly selling product X and incorporate an offer on this which is based on buying Barbie and Candy. If the customer is likely to buy these two products anyway then why not try to increase sales on X? two products anyway then why not try to increase sales on X?

Probably they can not only bundle candy of type A with Barbie dolls, but can also introduce new candy of Type N in this bundle while offering y yp gdiscount on whole bundle. As bundle is going to sell because of Barbie dolls & candy of type A, candy of type N can get free ride to customers houses. And with the fact that you like something, if you see it often,

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f y m g, f y f ,Candy of type N can become popular.

ReferencesReferences Jiawei Han and Micheline Kamber, “Data Mining:

Concepts and Techniques”, 2000

Vipin Kumar and Mahesh Joshi “Tutorial on High Vipin Kumar and Mahesh Joshi, Tutorial on High Performance Data Mining ”, 1999

R k h A l R k i h S ik “F Al i h Rakesh Agrawal, Ramakrishnan Srikan, “Fast Algorithms for Mining Association Rules”, Proc VLDB, 1994(h // l/ f /d /F % l h % f % % %(http://www.cs.tau.ac.il/~fiat/dmsem03/Fast%20Algorithms%20for%20Mining%20Association%20Rules.ppt)

Alípio Jorge “selecção de regras: medidas de interesse Alípio Jorge, selecção de regras: medidas de interesse e meta queries”, (http://www.liacc.up.pt/~amjorge/Aulas/madsad/ecd2/ecd2_Aulas_AR_3_2003.pdf)

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Thank you !!!Thank you !!!85

Thank you !!!Thank you !!!

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