natural selection can create linkage disequilibrium

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  • Slide 1
  • Natural Selection Can Create Linkage Disequilibrium
  • Slide 2
  • Slide 3
  • Detecting Postive Selection by Linkage Disequilibrium Sabeti, et al. 2002
  • Slide 4
  • Admixture Can Create Linkage Disequilibrium
  • Slide 5
  • Recombination Reduces Linkage Disequilibrium
  • Slide 6
  • Chaos Paper
  • Slide 7
  • Bacteriophage 6 dsRNA
  • Slide 8
  • Mllers Ratchet dsRNA The fate of asexually reproducing organisms dsRNA Assume a single bacteriophage per bacterium = asexual reproduction dsRNA
  • Slide 9
  • Experimental Mllers Ratchet with 6 dsRNA 0.22 m filter 40X Pseudomonas phaseolicola
  • Slide 10
  • Paired Growth and Fitness of 6 Pseudomonas phaseolicola dsRNA marked parent marked parent wt parent Mller parent Pseudomonas phaseolicola Pseudomonas alcaligenes W t = R t /R 0 I.e., W 37A = (150:200)/(200:200) = 0.75
  • Slide 11
  • Fitness Results of 6
  • Slide 12
  • Experimental Sex with 6 0.22 m filter 40X Pseudomonas phaseolicola dsRNA
  • Slide 13
  • Fitness of Improvement of selfed and hybrids
  • Slide 14
  • Disequilibrium Disrupts HWE model
  • Slide 15
  • Slide 16
  • Mendelian Genetics of Quantitative Traits
  • Slide 17
  • Quantitative Results for Nicotiana longiflora
  • Slide 18
  • Diopsids - Stalk-eyed Flies (Cyrtodiopsis dalmanni) Wilkinson, Amitin & Johns Integr. Comp. Biol., 2005
  • Slide 19
  • QTL mapping: Mimulus phylogeny
  • Slide 20
  • QTL mapping: Mimulus hybrids
  • Slide 21
  • CharacteristicsM. CardinalisM. Lewisii Pollinator attraction Puple Yellow Lateral petal width
  • Slide 22
  • QTL mapping: predictions
  • Slide 23
  • Slide 24
  • Selection gradients
  • Slide 25
  • Slide 26
  • Skypilots
  • Slide 27
  • Heritability of flower size 1/2h 2 =0.5
  • Slide 28
  • Slide 29
  • Relative fitness
  • Slide 30
  • Selection gradient = slope Selection gradient = 0.13 S (selection differential) = selection gradient*variance S = 0.13*5.66 mm = 0.74 mm S = 0.74 mm/14.2 mm mean flower size = 0.05
  • Slide 31
  • Expected R = h 2 S = 1 x 0.05 = 0.05 Observed = 9% larger
  • Slide 32
  • Heritability of abdominal bristles in D. melanogaster Clayton, et al. 1957
  • Slide 33
  • Slide 34
  • Flies with >22 bristles bred to create generation 2 Mean bristle number G1 = 19.3 Mean bristle number of selected G1 = 22.7 Mean bristle number G2 = 20.1
  • Slide 35
  • G1 n = 115; mean bristle number = = 2221/115 = 19.3 G1 selected n = 22; mean bristles = 22.7 G2 n = 101; mean bristles = 20.1

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