n=n => width = 1/n us = =1/n 3 [1+4+9+….+n 2 ] us =
DESCRIPTION
. N=n => width = 1/n US = =1/n 3 [1+4+9+….+n 2 ] US =. =. Definite Integral. We will define to be the limit as n approaches oo of where D x i = (b-a)/n and is any point in the ith interval. where D x i = (b-a)/n - PowerPoint PPT PresentationTRANSCRIPT
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..
N=n => width = 1/nN=n => width = 1/n
US = =1/nUS = =1/n33[1+4+9+….+n[1+4+9+….+n22]]
US = US =
2
1
1( )
n
i
i
n n
3 22
3 31
1 2 3
6
n
i
n n ni
n n
2
1
n
i
i
3 22 3
6
n n n
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==
3 2
3
2 3lim
6n
n n nArea
n
3 2
3 3 3
3
3
2 3
lim6x
x x xx x x
xx
2
3 12
lim6x
x x
1
3
3 2
3
2 3lim
6n
n n n
n
0
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DefiniteDefiniteIntegralIntegral
We will defineWe will define
to be the limit as nto be the limit as n
approaches oo ofapproaches oo of
where where xxii = (b-a)/n = (b-a)/n
and is any point in the ith interval. and is any point in the ith interval.
( )b
af x dx
*
1
( )n
i ii
f x x
*ix
*Area height width
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where where xxii = (b-a)/n = (b-a)/n
and is any point in the iand is any point in the ithth interval, [x interval, [xi-i-
11,x,xii]. ].
*ix
*
1
( ) lim ( )nb
i ia ni
f x dx f x x
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> 0 when f(x) > 0, > 0 when f(x) > 0, but it is but it is negative when f(x)<0.negative when f(x)<0.
We will defineWe will define
to be the limit as nto be the limit as n
approaches oo ofapproaches oo of
and is any point in the iand is any point in the ithth interval, [x interval, [xi-i-
11,x,xii]. ].
( )b
af x dx
* *
1 1
( )( ) ( )
n n
i i ii i
b af x x f x
n
*ix
( )b
af x dx
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DefinitionDefinitionTheoremsTheorems
1. 1.
2. 2.
3.3.
4.4.
*
1
( ) lim ( )nb
i ia ni
f x dx f x x
( ) ( )a b
b af x dx f x dx
( ) 0a
af x dx
( ) ( )b b
a akf x dx k f x dx
( ) ( ) ( ) ( )b
b b
a aa
f x g x dx f x dx g x dx
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DefinitionDefinitionTheoremsTheorems
5. 5.
6. 6.
7.7.
8.8.
( ) ( ) ( )b c c
a b af x dx f x dx f x dx
min ( )[ ] ( ) max ( )[ ]b
af x b a f x dx f x b a
( ) ( ) [ , ] ( ) ( )b b
a af x g x on a b f x dx g x dx 0 ( ) [ , ] 0 ( )
b
ag x on a b g x dx
*
1
( ) lim ( )nb
i ia ni
f x dx f x x
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3
1
( )f x dx
1
3
( ) 2.3f x dx 4
3
( ) 2f x dx 4
1
( ) 6g x dx 4
1
( )f x dx 4
1
( ) ( )f x g x dx 4 4 4
1 1 1
2 ( ) 3 ( ) 2 ( ) 3 ( )f x g x dx f x dx g x dx
2.3 0.3
6.3
2(.3) 3(6) 18.6
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If f(x) >= 0 on [a,b]If f(x) >= 0 on [a,b]
then is the area under f(x) then is the area under f(x) and and
over the x-axis between a and b. over the x-axis between a and b.
( )b
a
f x dx
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If f(x) <= 0 on [a,b]If f(x) <= 0 on [a,b]
then is the negative of the then is the negative of the area area
over f(x) and under the x-axis over f(x) and under the x-axis between between
a and b. a and b.
( )b
a
f x dx
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[[
0.500.50
0.10.1
1
0
( )f x dx
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[[
2.02.0
0.10.1
1
0
4 ( )f x dx
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]]
0.00.0
0.10.1
2
2
( )f x dx
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[[
1.01.0
0.10.1
2
1
( )f x dx
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3
2
( ) 0f x dx
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[[
1.51.5
0.10.1
3
0
( )f x dx
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00
2
0
sin( )x dx
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]]
1.01.0
0.10.1
1
1
| |x dx
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where where xxii = (b-a)/n = (b-a)/n
and is any point in the iand is any point in the ithth interval, [x interval, [xi-i-
11,x,xii].].
If the interval is [-4, 4] evaluate If the interval is [-4, 4] evaluate
88
*ix
*2
1
lim 16n
i ink
x x
4
2
4
16 x dx
*
1
( ) lim ( )nb
i ia ni
f x dx f x x
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Pi = Pi = 3.143.14
6.286.28
0.10.1
22
2
4 x dx
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Pi = Pi = 3.143.14
-6.28-6.28
0.10.1
22
2
4 x dx