obj. 45 surface area

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Surface Area The student is able to (I can): Calculate the surface area prisms, cylinders, pyramids, and cones

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  • Surface Area

    The student is able to (I can):

    Calculate the surface area prisms, cylinders, pyramids, and cones

  • The surface area is the total area of all faces and curved surfaces of a three-dimensional figure. The lateral area of a prism is the sum of the areas of the lateral faces.

    Lets look at a net for a hexagonal prism:

    What shape do the lateral faces make?

    (a rectangle)

  • If each side of the hexagon is 1 in., what is the perimeter of the hexagon?

    What is the length of the base of the big rectangle?

    6 in.

    6 in.

  • This relationship leads to the formula for the lateral area of a prism:

    L = Ph

    where P is the perimeter and h is the height of the prism.

    For the total surface area, add the areas of the two bases:

    S = L + 2B

  • We know that a net of a cylinder looks like:

    The length of the lateral surface is the circumference of the circle, so the formula changes to:

    L = Ch where C = pid or 2pir

    and the formula for the total area is now:

    S = L + 2pir2

  • Examples Find the lateral and total surface area of each.

    1.

    2. 10 cm

    14 cm

    4"3"

    8"

    5"

    P = 3+4+5 = 12 in.B = (3)(4) = 6 in2

    L = (12)(8) = 96 in2

    S = 96 + 2(6) = 108 in2

    C = 10pi cmB = 52pi = 25pi cm2

    L = (10pi)(14) = 140pi cm2

    S = 140pi + 2(25pi)= 190pi cm2

  • To find the lateral area of the pyramid, find the area of each of the faces.

    Perimeter of base

    slant height()

    1L P

    2=

    For the total surface area, add the area of the base.

    S = L + B

  • Likewise, for a cone, the lateral area is

    ( )1L 2 r r2

    = pi = pi

    and the total surface area is2S L r= + pi

  • Examples Find the lateral and surface area of the following:

    1.

    2.

    8 in.

    20 in.

    5 m

    5 m

    28 3B 6

    4

    =

    296 3 in=

    1L [(6)(8)](20)

    2=

    2480 in=

    2S 480 96 3 in= +2646.3 in

    5 2 m L (5)(5 2)= pi225 2 m= pi

    2S 25 2 25 m= pi + pi2189.6 m