perfect score add maths 2011 ans module 1- module 5

8/3/2019 Perfect Score Add Maths 2011 Ans Module 1- Module 5

1/16

PERFECT SCORE SBP 2011 / MATEMATIK TAMBAHAN KERTAS 1 MODUL 1

Soalan Jawapan

1h(2) = 1 2

m

= 5

m = 8

2m =

2

3; n = 4

3 1 1( 2)

2f g

f-1

(-2k+ 10) = -

61

12

= - 2k+ 10

k= 3

4 x2 + 2x -px +p2

= 0

(2p)24(1)(p

2) > 0

Range : - 2 < p 3 (c) 13 m

6a) (i) yxBD 3220

(ii) xEC 25

b) yxBD 3220

)85(4 yx

)(4 BF

c) 4 481

13 a) (i) 57.23

(ii) 106.07(iii) 80.96 cm2

b) (i)

(ii) 122.777 b) 8.3a , 2.0b

c) 0.1214

(a) 3 + 2 30, 2 + 24, 2 x y x y y x (b) Graf (c)(i) 8 (ii)RM420

15 (a) (i) RM2.00

(ii) 137.(iii)RM2.4(b) 131.1

(c) RM3279.25(d) 103.12

B B


10/16

5) b) (i) & (ii)

Number of solution = 3

2

22

3 xy

1

5/4

/3 2O

-1

xy2

3cos2 -2


11/16

m=2.2704, n= -0.6352

m= -1.6990, n=1.3495

(a) dL/dT=5

2

(b)2

640

(b) ii- = 3 3

n.o.s=5 no of solution(a)d=r2

(b)h=5 r=2

(a) 69.5

(b) 233.7428

(a)(i) 13

~ +

13

~

(i i)2

3

~+

1

3

~

(b)( i)23

~ + 13 ~

(i i)

~+

~

m=2 n=3

Answer For Module 5


12/16

k = 6

b) y = -2x + 10

b) R ( 2,6)

d) 22 unit2

1. (b)(i) k = 0.4 (ii) 10 (c) 25.5

(a) A(-1,2), B(0,-3), C(0,-1)

(b)( i)3

8unit2

(i i)33

28 unit3

(a)73.74

(b)102.24 unit2

(c)344.985 unit2

(a)( i )0.5248

(i i)mean=360 s.d=14.70

((b) = 8, = 40

(a)( i)134.9

(i i )RU=7.16cm

(b)( i i)area=3.245cm2

(a)( i) 110

(i i) RM3.25

(b) m=4

(c)( i) x=99.21(i i) x=4.69

(a) 0


13/16

(a)


14/16

8


15/16

15


16/16

perfect score add maths 2011 ans module 1- module 5

Documents