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PERSAMAAN DIFERENSIALPertemuan 9, PD Bernouli
Nikenasih [email protected]
http://uny.ac.idTAKWA, MANDIRI, CENDEKIA
http://fmipa.uny.ac.idTAKWA, MANDIRI, CENDEKIA
1β’ Review PD Homogen
2β’ Review PD Linear
3β’ PD Bernoulli
PRESENTATION PARTS
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Review PD Homogen
Definisi homogen
A function π of two variables x and y is saidhomogeneous if it satisfies
π π‘π₯, π‘π¦ = π π₯, π¦for any number t.
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Definition
A function M of two variables x and y is said to behomogenous of degree-n if it satisfies
π π‘π₯, π‘π¦ = π‘ππ π₯, π¦
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Definition
A first differential equation
π π₯, π¦ ππ₯ + π π₯, π¦ ππ¦ = 0 orππ¦
ππ₯= π(π₯, π¦)
is called homogeneous differential equation if Mand N are homogeneous functions of the samedegree n or f is a homogenous function.
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Menyelesaikan PD Homogen
PD Homogen (dalam x dan y)
Transform y = vx
PD separabel (dalam v dan x)
Selesaikan PD separabel
Inverse transform v = y/x
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PD Linear
Definition
A first-order ordinary differential equation is linearin the dependent variable y and the independentvariable x if it is, or can be, written in the form
ππ¦
ππ₯+ π π₯ π¦ = π π₯
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Menyelesaikan PD Linear
Suppose the integrating factor
π π₯ = π π π₯ ππ₯
The general solution of linear differential equationas follows
π¦ = πβ1 π₯ π π₯ π π₯ ππ₯ + π
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PD Bernoulli
Definition
An equation of the formππ¦
ππ₯+ π π₯ π¦ = π π₯ π¦π
is called a Bernoulli differential equation.
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TheoremSuppose n β 0 or n β 1, then the transformation π£ =π¦1βπ reduces the Bernoulli equation
ππ¦
ππ₯+ π π₯ π¦ = π π₯ π¦π
into a linear equation in v.
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ExampleSolve the differential equation below
π₯ππ¦
ππ₯+ π¦ = π₯2π¦2
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Answer :To solve the differential equations above, first wehave to divided both side with π₯π¦2. Here we get,
π¦β2ππ¦
ππ₯+ π₯β1π¦β1 = π₯
Suppose π£ = π¦β1 thenππ£
ππ¦= βπ¦β2 or else
ππ£
ππ₯=
β π¦β2ππ¦
ππ₯. By here, we get
ππ£
ππ₯+ π₯β1π£ = π₯
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To solve the equation, we use integrating factor
π π₯ = π 1π₯ππ₯ = πln π₯ = π₯
Then the solution is
π£ = πβ1 π₯ π π₯ π π₯ ππ₯ + π
π£ = π₯β1 π₯2 ππ₯ + π β π£ = π₯β11
3π₯3 + π
=1
3π₯2 + ππ₯β1
π¦β1 =1
3π₯2 + ππ₯β1
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Solve the following differential equations.
1.ππ¦
ππ₯β1
π₯π¦ = π₯π¦2
2.ππ¦
ππ₯+π¦
π₯= π¦2
3.ππ¦
ππ₯+1
3π¦ = ππ₯π¦4
4. π₯ππ¦
ππ₯+ π¦ = π₯π¦3
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Referensi :
1. Ross, L. Differential Equations. John Wiley &Sons.
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THANK YOU
Nikenasih [email protected]
Karangmalang Sleman Yogyakarta