pion yields from a tantalum rod target using mars15

44
Stephen Brooks / RAL / March 2005 1 of 44 Pion Yields from a Tantalum Rod Target using MARS15 Comparisons across proton driver energies and other parameters

Upload: cayla

Post on 14-Jan-2016

27 views

Category:

Documents


2 download

DESCRIPTION

m. Pion Yields from a Tantalum Rod Target using MARS15. Comparisons across proton driver energies and other parameters. Contents. Problem and parameters Variation of proton energy Total pion yield Simple cuts Probability map “cuts” from tracking Investigation of the hole - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

1 of 44

Pion Yields from a Tantalum Rod Target using MARS15

Comparisons across proton driver energies and other parameters

Page 2: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

2 of 44

Contents

• Problem and parameters

• Variation of proton energy– Total pion yield– Simple cuts– Probability map “cuts” from tracking

• Investigation of the hole

• Variation of rod radius

• Notes on effect of rod length and tilt angle

Page 3: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

3 of 44

Basic Setup

• Pions counted at rod surface

• B-field ignored within rod (for now)

• Proton beam assumed parallel– Circular parabolic distribution, rod radius

• Rod is not tilted

20cm

1cmSolid Tantalum

Protons

Pions

Page 4: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

4 of 44

Possible Proton EnergiesProton Driver GeVSPL 2.2

34

RAL green-field study 5RAL/ISIS 5MW 6RAL/ISIS 1MW, FNAL linac 8

10RAL/ISR 15

20RAL/PS, JPARC initial 30

40JPARC final 50

75100

FNAL injector/NuMI 120

Page 5: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

5 of 44

Total Yield of + and −

2.2G

eV

3GeV

4GeV

5GeV 6G

eV 8GeV

10G

eV 15G

eV

20G

eV

30G

eV

40G

eV

50G

eV

75G

eV

100G

eV12

0GeV

0

0.02

0.04

0.06

0.08

0.1

0.12

0.14

1 10 100 1000

Proton Energy (GeV)

Pio

ns

per

Pro

ton

.GeV

(to

tal

emit

ted

)

pi+/(p.GeV)

pi-/(p.GeV)

• Normalised to unit beam power (p.GeV)

NB: Logarithmic scale!

66% more + at 30GeV than 2.2GeV

57% more − at 30GeV than 2.2GeV

Page 6: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

6 of 44

Energy Deposition in Rod (heat)

• Scaled for 5MW total beam power; the rest is kinetic energy of secondaries

2.2G

eV

3GeV

4GeV

5GeV

6GeV

8GeV

10G

eV

15G

eV

20G

eV 30G

eV

40G

eV50

GeV

75G

eV

100G

eV12

0GeV

0

200000

400000

600000

800000

1000000

1200000

1400000

1 10 100 1000

Proton Energy (GeV)

Po

wer

Dis

sip

atio

n (

Wat

ts,

no

rmal

ised

to

5M

W

inco

min

g b

eam

)

Page 7: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

7 of 44

Total Yield of + and −

2.2G

eV

3GeV 4G

eV

5GeV

6GeV 8G

eV

10G

eV

15G

eV

20G

eV

30G

eV

40G

eV

50G

eV

75G

eV

100G

eV12

0GeV

0

0.2

0.4

0.6

0.8

1

1.2

1 10 100 1000

Proton Energy (GeV)

Pio

ns

per

Pro

ton

.GeV

of

rod

hea

tin

g

pi+/(p.GeV_th)

pi-/(p.GeV_th)

• Normalised to unit rod heating (p.GeV = 1.6×10-10 J)

From a purely target point of view, ‘optimum’ moves to 10-15GeV

Page 8: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

8 of 44

Angular Distribution2.2 GeV

0

50

100

150

200

250

0 20 40 60 80 100 120 140 160 180 200

Off-axis angle (°)

Pio

ns piplus

piminus

6 GeV

0

200

400

600

800

1000

1200

1400

0 20 40 60 80 100 120 140 160 180 200

Off-axis angle (°)

Pio

ns piplus

piminus

15 GeV

0

500

1000

1500

2000

2500

3000

3500

4000

4500

0 20 40 60 80 100 120 140 160 180 200

Off-axis angle (°)

Pio

ns piplus

piminus

120 GeV

0

5000

10000

15000

20000

25000

30000

0 20 40 60 80 100 120 140 160 180 200

Off-axis angle (°)

Pio

ns piplus

piminus

2.2GeV 6GeV

15GeV 120GeV

Backwards+ 18%− 33%

8%12%

8%11%

7%10%

Page 9: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

9 of 44

Angular Distribution

2.2

Ge

V

3G

eV

4G

eV

5G

eV

6G

eV

8G

eV

10

Ge

V

15

Ge

V

20

Ge

V

30

Ge

V

40

Ge

V5

0G

eV

75

Ge

V

10

0G

eV

12

0G

eV

0

20

40

60

80

100

120

1 10 100 1000

Proton Energy (GeV)

An

gle

fro

m A

xis

(°)

pi+ 1st Quartile

pi+ Median

pi+ 3rd Quartile

pi- 1st Quartile

pi- Median

pi- 3rd Quartile

What causes the strange kink in the graph between 3GeV and 5GeV?

Page 10: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

10 of 44

Some Artifacts?

• MARS15 uses two hadron production models:– The “Cascade-Exciton Model” CEM2003 for E<5GeV– “Inclusive” hadron production for E>3GeV

• Nikolai Mokhov says:

A mix-and-match algorithm is used between 3 and 5 GeV to provide a continuity between the two domains. The high-energy model is used at 5 GeV and above. Certainly, characteristics of interactions are somewhat different in the two models at the same energy. Your results look quite reasonable, although there is still something to improve in the LANL's low-energy model, especially for pion production. The work is in progress on that. A LAQGSM option coming soon, will give you an alternative possibility to study this intermediate energy region in a different somewhat more consistent way.

Page 11: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

11 of 44

Possible Remedies

• Ideally, we would want HARP data to fill in this “gap” between the two models

• K. Walaron at RAL is also working on benchmarking these calculations against a GEANT4-based simulation

• Activating LAQGSM is another option

• We shall treat the results as ‘roughly correct’ for now, though the kink may not be as sharp as MARS shows

Page 12: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

12 of 44

Summary 1

• So far, it appears that a 10-30GeV proton beam:– Produces ~60% more pions per p.GeV– …in a more focussed angular distribution– …with ~40% less rod heating

…than the low-energy option

• BUT: the useful yield is crucially dependent on the capture system

With certain provisos on the accuracy of MARS’s pion model over the transition region

Page 13: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

13 of 44

Simple Cuts

• It turns out geometric angle is a badly-normalised measure of beam divergence

• Transverse momentum and the magnetic field dictate the Larmor radius in the solenoidal decay channel:

z

T

eB

pr

z

T

z

T

B

p

B

cpr

3]T[

)/10](MeV/c[]cm[

8

Page 14: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

14 of 44

Simple Cuts

• Acceptance of the decay channel in (pL,pT)-space should look roughly like this:

pL

pTLarmor radius = ½ aperture limit

Angular limit (eliminate backwards/sideways pions)

Pions in this region transmitted

max

pTmax

Page 15: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

15 of 44

Simple Cuts

• So, does it?

• Pions from one of the MARS datasets were tracked through an example decay channel and plotted by (pL,pT)

– Coloured green if they got the end– Red otherwise

• This is not entirely deterministic due to pion muon decays and finite source

Page 16: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

16 of 44

Simple Cuts

• So, does it?

Page 17: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

17 of 44

Simple Cuts

• So, does it? Roughly.

Page 18: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

18 of 44

Simple Cuts

• So, does it? Roughly.

• If we choose:– max = 45°

– pTmax = 250 MeV/c

• Now we can re-draw the pion yield graphs for this subset of the pions

Page 19: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

19 of 44

Cut Yield of + and −

• Normalised to unit beam power (p.GeV)

3GeV

     4G

eV  

  5G

eV  

   8GeV

    

10G

eV  

  

20G

eV  

  

40G

eV  

  

50G

eV  

  

75G

eV  

  

100G

eV  

  12

0GeV

    

15G

eV  

  

2.2G

eV  

  

6GeV

    

30G

eV  

  

0

0.005

0.01

0.015

0.02

0.025

0.03

0.035

0.04

0.045

1 10 100 1000

Proton Energy (GeV)

Pio

ns

per

Pro

ton

.GeV

(w

ith

in 4

5°,

pt<

250M

eV/c

)

pi+/(p.GeV)

pi-/(p.GeV)

High energy yield now appears a factor of 2 over low energy, but how much of that kink is real?

Page 20: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

20 of 44

2.2

Ge

V  

   

3G

eV

    

 

4G

eV

    

 5

Ge

V  

    6G

eV

    

 

8G

eV

    

 1

0G

eV

    

 

15

Ge

V  

   

20

Ge

V  

   

30

Ge

V  

   

40

Ge

V  

   

50

Ge

V  

   

75

Ge

V  

   

10

0G

eV

    

 1

20

Ge

V  

   

0

0.05

0.1

0.15

0.2

0.25

0.3

0.35

1 10 100 1000

Proton Energy (GeV)

Cu

t P

ion

s p

er P

roto

n.G

eV(h

eat)

pi+/(p.GeV_th)

pi-/(p.GeV_th)

Cut Yield of + and −

• Normalised to unit rod heating

This cut seems to have moved this optimum down slightly, to 8-10GeV

Page 21: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

21 of 44

Tracking through Two Designs

• Possible non-cooling front end– Uses bunch compression chicane after decay

channel– Then an 88MHz muon linac to 400±100MeV

• RF phase-rotation system– Continues the linear solenoid channel– 31.4MHz cavities reduce the energy spread– Goal is 180±23MeV for cooling ring injection

Page 22: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

22 of 44

Fate Plot for Chicane/LinacMagenta Went backwards

Red Hit rod again

Orange Hit inside first solenoid

Yellow/Green Lost in decay channel

Cyan Lost in chicane

Blue Lost in linac

Grey Wrong energy

White Transmitted OK

(Pion distribution used here is from a 2.2GeV proton beam)

Page 23: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

23 of 44

Fate Plot for Phase RotationMagenta Went backwards

Red Hit rod again

Orange Hit inside first solenoid

Yellow/Green Lost in decay channel

Blue Lost in phase rotator

Grey Wrong energy

White Transmitted OK

Page 24: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

24 of 44

Probability Grids

• Can bin the plots into 30MeV/c squares and work out the transmission probability within each

Chicane/Linac Phase Rotation

Page 25: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

25 of 44

Probability Grids

• Can bin the plots into 30MeV/c squares and work out the transmission probability within each

• These can then be used to estimate the transmission quickly from MARS output datasets at various proton energies

Page 26: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

26 of 44

Chicane/Linac Transmission

    

3GeV

    

4GeV

    

8GeV

    

40G

eV  

  50

GeV

    

75G

eV

    

100G

eV  

  12

0GeV

    

30G

eV    

6GeV

    

2.2G

eV     

15G

eV

    

10G

eV

    

5GeV

    

20G

eV

0

0.001

0.002

0.003

0.004

0.005

0.006

0.007

1 10 100 1000

Proton Energy (GeV)

Pio

ns

per

Pro

ton

.GeV

(es

t. C

hic

ane/

Lin

ac)

pi+/(p.GeV)

pi-/(p.GeV)

Energy dependency is much flatter now we are selecting pions by energy range

• Normalised to unit beam power (p.GeV)

Page 27: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

27 of 44

Chicane/Linac Transmission

   

  2

.2G

eV

   

  3

Ge

V

   

  4

Ge

V  

   

 5G

eV

   

  6

Ge

V

   

  8

Ge

V

   

  1

5G

eV

   

  2

0G

eV

   

  3

0G

eV

   

  4

0G

eV

   

  5

0G

eV

   

  7

5G

eV

   

  1

00

Ge

V  

   

 12

0G

eV

   

  1

0G

eV

0

0.01

0.02

0.03

0.04

0.05

0.06

1 10 100 1000

Proton Energy (GeV)

Ch

ican

e/L

inac

Pio

ns

per

Pro

ton

.GeV

(hea

t)

pi+/(p.GeV_th)

pi-/(p.GeV_th)

• Normalised to unit rod heating

6-10GeV now looks good enough if we are limited by target heating

Page 28: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

28 of 44

Phase Rotator Transmission

• Normalised to unit beam power (p.GeV)

    

  3G

eV

    

  4G

eV

    

  8G

eV

    

  40

GeV

    

  50

GeV

    

  75

GeV

    

  10

0GeV

    

  12

0GeV

    

  30

GeV    

  6G

eV

    

  2.

2GeV

    

  15

GeV    

  10

GeV

    

  5G

eV

    

  20

GeV

0

0.001

0.002

0.003

0.004

0.005

0.006

0.007

0.008

0.009

1 10 100 1000

Proton Energy (GeV)

Pio

ns

per

Pro

ton

.GeV

(es

t. P

has

e R

ota

tor)

pi+/(p.GeV)

pi-/(p.GeV)

Page 29: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

29 of 44

Phase Rotator Transmission

• Normalised to unit rod heating

   

   

 2G

eV

   

   

 3G

eV

   

   

 4G

eV

   

   

 5G

eV

   

   

 6G

eV

   

   

 8G

eV

   

   

 15

Ge

V

   

   

 20

Ge

V

   

   

 30

Ge

V

   

   

 40

Ge

V  

   

   5

0G

eV

   

   

 75

Ge

V

   

   

 10

0G

eV

   

   

 12

0G

eV

   

   

 10

Ge

V

0

0.01

0.02

0.03

0.04

0.05

0.06

0.07

1 10 100 1000

Proton Energy (GeV)

Ph

ase

Ro

tato

r P

ion

s p

er P

roto

n.G

eV(h

eat)

pi+/(p.GeV_th)

pi-/(p.GeV_th)

Page 30: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

30 of 44

Summary 2

• While 30GeV may be excellent in terms of raw pion yields, the pions produced are increasingly lost due to:– Large transverse momenta (above 10-20GeV)– A high energy spread, outside the acceptance

of bunching systems (above 6-10GeV)

• This work suggests the optimal energy is around 6-10GeV, providing a 50% yield improvement over 2.2GeV With certain provisos on the

accuracy of MARS’s pion model over the transition region

Page 31: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

31 of 44

Rod with a Hole

• Idea: hole still leaves 1-(rh/r)2 of the rod available for pion production but could decrease the path length for reabsorption

Rod cross-section r

rh

Page 32: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

32 of 44

Rod with a Hole

• Idea: hole still leaves 1-(rh/r)2 of the rod available for pion production but could decrease the path length for reabsorption

• Used a uniform beam instead of the parabolic distribution, so the per-area efficiency could be calculated easily

• r = 1cm

• rh = 2mm, 4mm, 6mm, 8mm

Page 33: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

33 of 44

Yield Decreases with Hole

0

0.02

0.04

0.06

0.08

0.1

0.12

0.14

0 0.001 0.002 0.003 0.004 0.005 0.006 0.007 0.008 0.009

0

0.2

0.4

0.6

0.8

1

1.2

pi+/(p.GeV)

pi-/(p.GeV)

Area fraction

30 GeV

2.2 GeV

Page 34: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

34 of 44

0

0.02

0.04

0.06

0.08

0.1

0.12

0.14

0 0.001 0.002 0.003 0.004 0.005 0.006 0.007 0.008 0.009

pi+ eff.

pi- eff.

Yield per Rod Area with Hole

30 GeV

2.2 GeV

This actually decreases at the largest hole size!

Page 35: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

35 of 44

Rod with a Hole Summary

• Clearly boring a hole is not helping, but:

• The relatively flat area-efficiencies suggest reabsorption is not a major factor– So what if we increase rod radius?

• The efficiency decrease for a hollow rod suggests that for thin (<2mm) target cross-sectional shapes, multiple scattering of protons in the tantalum is noticeable

Page 36: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

36 of 44

Variation of Rod Radius

• We will change the incoming beam size with the rod size and observe the yields

Page 37: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

37 of 44

Variation of Rod Radius

• We will change the incoming beam size with the rod size and observe the yields

• This is not physical for the smallest rods as a beta focus could not be maintained

Emittance x Focus radius Divergence Focus length

25 mm.mrad extracted from proton machine

10mm 2.5 mrad 4m

5mm 5 mrad 1m

2.5mm 10 mrad 25cm

2mm 12.5 mrad 16cm

Page 38: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

38 of 44

Variation of Rod Radius

• We will change the incoming beam size with the rod size and observe the yields

• For larger rods, the increase in transverse emittance may be a problem downstream

• Effective beam-size adds in quadrature to the Larmor radius:

2

2

z

Teff eB

prr

Page 39: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

39 of 44

Total Yield with Rod Radius

0

0.02

0.04

0.06

0.08

0.1

0.12

0.14

0.16

0 0.5 1 1.5 2 2.5 3 3.5 4

Rod Radius (cm)

Pio

n Y

ield

pi+/(p.GeV)

pi-/(p.GeV)

30GeV

2.2GeV

Page 40: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

40 of 44

Cut Yield with Rod Radius

0

0.005

0.01

0.015

0.02

0.025

0.03

0.035

0.04

0.045

0.05

0 0.5 1 1.5 2 2.5 3 3.5 4

Rod Radius (cm)

Pio

n Y

ield

Wit

hin

45

° o

f A

xis

an

d T

ran

sv

ers

e M

om

en

tum

Be

low

25

0M

eV

/c

pi+/(p.GeV)

pi-/(p.GeV)

30GeV

2.2GeV

Rod heating per unit volume and hence shock amplitude decreases as 1/r2 !

Multiple scattering decreases yield at r = 5mm and below Fall-off due to

reabsorption is fairly shallow with radius

Page 41: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

41 of 44

Note on Rod Tilt

• All tracking optimisations so far have set the rod tilt to zero

• The only time a non-zero tilt appeared to give better yields was when measuring immediately after the first solenoid

• Theory: tilting the rod gains a few pions at the expense of an increased horizontal emittance (equivalent to a larger rod)

Page 42: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

42 of 44

Note on Rod Length

• Doubling the rod length would:– Double the heat to dissipate– Also double the pions emitted per proton– Increase the longitudinal emittance

• The pions already have a timespread of RMS 1ns coming from the proton bunch

• The extra length of rod would add to this the length divided by c

Page 43: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

43 of 44

Conclusion

• Current results indicate 6-10GeV is an optimal proton driver energy for current front-ends– If we can accept larger energy spreads, can go to a

higher energy and get more pions

• A larger rod radius is a shallow tradeoff in pion yield but would make solid targets much easier

• Tilting the rod could be a red herring– Especially if reabsorption is not as bad as we think

• So making the rod coaxial and longer is possible

Page 44: Pion Yields from a Tantalum Rod Target using MARS15

Stephen Brooks / RAL / March 2005

44 of 44

Future Work

• Resimulating with the LAQGSM added

• Benchmarking of MARS15 results against a GEANT4-based system (K. Walaron)

• Tracking optimisation of front-ends based on higher proton energies (sensitivity?)

• Investigating scenarios with longer rods– J. Back (Warwick) also available to look at

radioprotection issues and adding B-fields using MARS