power, simple circuits, resistor combinationspages.erau.edu/~snivelyj/ps250/ps250-lecture14.pdf ·...

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PS 250: Lecture 14 Power, Simple Circuits, Resistor Combinations J. B. Snively September 30 th , 2015

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Page 1: Power, Simple Circuits, Resistor Combinationspages.erau.edu/~snivelyj/ps250/PS250-Lecture14.pdf · Power Dissipation of Resistors First, recall that: P = V ab I and V ab = IR By substituting

PS 250: Lecture 14 Power, Simple Circuits, Resistor Combinations

J. B. Snively September 30th, 2015

Page 2: Power, Simple Circuits, Resistor Combinationspages.erau.edu/~snivelyj/ps250/PS250-Lecture14.pdf · Power Dissipation of Resistors First, recall that: P = V ab I and V ab = IR By substituting

Today’s Class

Energy and Power Resistors in Series and Parallel Kirchhoff’s Rules for Circuit Calculations Summary

Page 3: Power, Simple Circuits, Resistor Combinationspages.erau.edu/~snivelyj/ps250/PS250-Lecture14.pdf · Power Dissipation of Resistors First, recall that: P = V ab I and V ab = IR By substituting

Rate of energy transfer [J]/[s] = [W]

Recall: Volts [J]/[C], Amperes [C]/[s]

“Rate [per second] at which energy [Joules] is delivered or extracted from a circuit element”

Power (Rate of Energy Transfer)

P = VabI[J]

[C]

[C]

[s]=

[J]

[s]= [W]

Page 4: Power, Simple Circuits, Resistor Combinationspages.erau.edu/~snivelyj/ps250/PS250-Lecture14.pdf · Power Dissipation of Resistors First, recall that: P = V ab I and V ab = IR By substituting

Power Dissipation of Resistors

First, recall that:P = VabI and Vab = IR

By substituting in Ohm’s Law, we can obtain:

P = VabI = I2R =V 2ab

R

In a resistor, power is dissipated as heat! Practical resistors have a max power rating.

Page 5: Power, Simple Circuits, Resistor Combinationspages.erau.edu/~snivelyj/ps250/PS250-Lecture14.pdf · Power Dissipation of Resistors First, recall that: P = V ab I and V ab = IR By substituting

Today’s Class

Energy and Power Resistors in Series and Parallel Kirchhoff’s Rules for Circuit Calculations Summary

Page 6: Power, Simple Circuits, Resistor Combinationspages.erau.edu/~snivelyj/ps250/PS250-Lecture14.pdf · Power Dissipation of Resistors First, recall that: P = V ab I and V ab = IR By substituting

Series Combination: Equal current through

each resistor.

Parallel Combination: Equal potential

difference across each resistor.

R2R1

R2R1

Combinations of Resistors

V

V

+

-

+

-

I

Page 7: Power, Simple Circuits, Resistor Combinationspages.erau.edu/~snivelyj/ps250/PS250-Lecture14.pdf · Power Dissipation of Resistors First, recall that: P = V ab I and V ab = IR By substituting

Series Resistors

...RNR2R1

V+

-

Current through each resistor is constant:V = IR1 + IR2 + ...IRN = I(R1 +R2 + ...RN )

Series Equivalent Resistance REQ:

REQ = R1 +R2 + ...RN

I

Page 8: Power, Simple Circuits, Resistor Combinationspages.erau.edu/~snivelyj/ps250/PS250-Lecture14.pdf · Power Dissipation of Resistors First, recall that: P = V ab I and V ab = IR By substituting

Parallel Resistors

RN...R2R1V+

-

Potential difference across each resistor is constant:I =

V

REQ=

V

R1+

V

R2+ ...

V

RN

Parallel Equivalent Resistance REQ:1

REQ=

1

R1+

1

R2+ ...

1

RN

Page 9: Power, Simple Circuits, Resistor Combinationspages.erau.edu/~snivelyj/ps250/PS250-Lecture14.pdf · Power Dissipation of Resistors First, recall that: P = V ab I and V ab = IR By substituting

Today’s Class

Energy and Power Resistors in Series and Parallel Kirchhoff’s Rules for Circuit Calculations Summary

Page 10: Power, Simple Circuits, Resistor Combinationspages.erau.edu/~snivelyj/ps250/PS250-Lecture14.pdf · Power Dissipation of Resistors First, recall that: P = V ab I and V ab = IR By substituting

The algebraic sum of the currents into an junction (“node”) is zero:

The algebraic sum of the potential differences in any loop is zero:

Kirchhoff’s Rules

XI = 0

XV = 0

Page 11: Power, Simple Circuits, Resistor Combinationspages.erau.edu/~snivelyj/ps250/PS250-Lecture14.pdf · Power Dissipation of Resistors First, recall that: P = V ab I and V ab = IR By substituting

Junction Rule:

RN...R2R1V+

-

Sum of the currents entering and leaving a junction point (“node”) equals zero:

XI = Isrc �

V

R1� V

R2� ...

V

RN= 0

Page 12: Power, Simple Circuits, Resistor Combinationspages.erau.edu/~snivelyj/ps250/PS250-Lecture14.pdf · Power Dissipation of Resistors First, recall that: P = V ab I and V ab = IR By substituting

Loop Rule:

...RNR2R1

Vsrc+

-

Sum of the potential differences across each source and resistor equals zero:

I

XV = Vsrc � IR1 � IR2 � ...IRN = 0

Page 13: Power, Simple Circuits, Resistor Combinationspages.erau.edu/~snivelyj/ps250/PS250-Lecture14.pdf · Power Dissipation of Resistors First, recall that: P = V ab I and V ab = IR By substituting

Applies to all circuits (assuming no external time-varying magnetic flux).

Can be used to find individual currents (or potentials) through (or across) circuit elements in complex configurations.

Can be used for circuits with multiple sources and multiple loops or nodes.

When multiple loops or nodes are present, it becomes necessary to solve simultaneous equations.

Kirchhoff’s Rules

Page 14: Power, Simple Circuits, Resistor Combinationspages.erau.edu/~snivelyj/ps250/PS250-Lecture14.pdf · Power Dissipation of Resistors First, recall that: P = V ab I and V ab = IR By substituting

Summary / Next Class:

Homework for Friday

Prepare to discuss 26.4.