precise definition of limits the phrases “x is close to a” and “f(x) gets closer and closer to...

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Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as long as x approaches 3 sufficiently. How close to 3 does x have to be so that f(x) differs from 5 by less than 0.1? Solving the inequality |(2x-1)-5|<0.1, we get |x-3|<0.05, i.e., we find a number =0.05 such that whenever |x-3|< we have |f(x)-5|<0.1

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Page 1: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Precise definition of limits The phrases “x is close to a” and “f(x) gets closer

and closer to L” are vague. since f(x) can be arbitrarily close to 5 as long as x approaches 3 sufficiently. How close to 3 does x have to be so that f(x)

differs from 5 by less than 0.1? Solving the inequality |(2x-1)-5|<0.1, we get |x-3|<0.05, i.e., we find a number =0.05 such that whenever |x-3|< we have |f(x)-5|<0.1

Page 2: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

definition of a limit If we change the number 0.1 to other smaller

numbers, we can find other s. Changing 0.1 to

any positive real number , we have the following Definition: We say that the limit of f(x) as x

approaches a is L, and we write if

for any number >0 there is a number >0 such that

Page 3: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Remark expresses “arbitrarily” and expresses

“sufficiently” Generally depends on To prove a limit, finding is the key point means that for every >0 (no matter

how small is) we can find >0 such that if x lies in

the open interval (a-,a+) and xa then f(x) lies in

the open interval (L-,L+).

Page 4: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Example

Ex. Prove that

Sol. We solve the question in two steps.

1. Preliminary analysis of the problem (deriving a

value for ). Let be a given positive number, we

want to find a number such that

But |(4x-5)-7|=|4x-12|=4|x-3|, therefore we want

Page 5: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Example (cont.)

This suggests that we should choose =/.

2. Proof (showing the above works). Given choose If 0<|x-3|<, then

|(4x-5)-7|=|4x-12|=4|x-3|<4Thus

Therefore, by definition we have

Page 6: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Example

Ex. Prove that

Sol. 1. Deriving a value for . Let >0 be given, we

want to find a number such that

Since |(x2-x+2)-4|=|x-2||x+1|,if we can find a positive

constant C such that |x+1|<C, then |x-2||x+1|<C|x-2|

and we can make C|x-2|< by taking |x-2|</CAs we

are only interested in values of x that are close to 2,

Page 7: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Example (cont.)

it is reasonable to assume |x-2|<1. Then 1<x<3, so

2<x+1<4, and |x+1|<4. Thus we can choose C=4 for

the constant. But note that we have two restrictions on

|x-2|, namely, |x-2|<1 and |x-2|</C=/4. To make sure

both of the two inequalities are satisfied, we take to

be the smaller of 1 and /4. The notation for this is

=min{1,/4}.

2. Showing above works. Given >0, let =min{1,/4}.

Page 8: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Example (cont.)

If 0<|x-2|<, then |x-2|<1) 1<x<3) |x+1|<4. We also

have |x-2|</4, so |(x2-x+2)-4|=|x-2||x+1|</4¢4=This

shows that

can be found by solving the inequality, but no need to solve the inequality: is not unique, finding one is enough

Page 9: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Example

Ex. Prove that

Sol. For any given >0, we want to find a number >0

such that

By rationalization of numerator,

If we first restrict x to |x-4|<1, then 3<x<5 and

Page 10: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Example (cont.)

Now we have and we can make

by taking Therefore

If >0 is given, let

When 0<|x-4|<we have firstly

and then

This completes the proof.

Page 11: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Proof of uniqueness of limits(uniqueness) If and then K=L.

Proof. Let >0 be given, there is a number 1>0 such that

|f(x)-K|< whenever 0<|x-a|<1. On the other hand, there is

a number 2>0 such that |f(x)-L|<whenever 0<|x-a|<2.

Now put =min{1,2} and x0=a+Then|f(x0)-K|<

and |f(x0)-L|<. Thus |K-L|=|(f(x0)-K)-(f(x0)-L)|·|f(x0)-K|+

|f(x0)-L|<2. Since is arbitrary, |K-L|<2 implies K=L.

Page 12: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

definition of one-sided limits

Definition: If for any number >0 there is a number

>0 such that

then

Definition: If for any number >0 there is a number

>0 such that

then

Page 13: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Useful notations 9 means “there exist”, 8 means “for any”. definition using notations

such that

there holds

,

0, 0, : 0 | | ,x x a

| ( ) | .f x L

Page 14: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

M- definition of infinite limits

Definition. means that

8 M>0, 9 >0, such that

whenever

Remark. M represents “arbitrarily large”

( )f x M 0 | | .x a

Page 15: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Negative infinity means

Page 16: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Continuity Definition A function f is continuous at a number a if

Remark The continuity of f at a requires three things:

1. f(a) is defined

2. The limit exists

3. The limit equals f(a)

otherwise, we say f is discontinuous at a.

).()(lim afxfax

)(lim xfax

)(lim xfax

Page 17: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Continuity of essential functionsTheorem The following types of functions are continuous

at every number in their domains:

polynomials algebraic functions power functions

trigonometric functions inverse trigonometric functions

exponential functions logarithmic functions

Page 18: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Example Ex. Find the limits:(a) (b)

Sol. (a)

(b)

)1

2

1

1(lim

21

xxx.

1lim

2

1

x

nxxx n

x

.2

1

1

1lim

1

1lim

1

21lim)

1

2

1

1(lim

1212121

xx

x

x

x

xx xxxx

.2

)1(21

)]1()1(1[lim

1

)1()1()1(lim

1lim

21

1

2

1

2

1

nnn

xxx

x

xxx

x

nxxx

nn

x

n

x

n

x

Page 19: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Continuous on an interval A function f is continuous on an interval if

it is continuous at every number in the interval. If f is defined only on one side of an

endpoint of the interval, we understand

continuous at the endpoint to mean continuous

from the right or continuous from the left.

Page 20: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Continuity of composite functions

Theorem If f is continuous at b and

then

In other words, If g is continuous at a and f is continuous at

g(a), then the composite function f(g(x)) is

continuous at a.

lim ( ) ,x a

g x b

lim ( ( )) ( ).x a

f g x f b

lim ( ( )) (lim ( )).x a x a

f g x f g x

Page 21: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Property of continuous functions

The Intermediate Value Theorem If f is

continuous on the closed interval [a,b] and let

N be any number between f(a) and f(b), where

Then there exists a number c in

(a,b) such that f(c)=N.

( ) ( ).f a f b

Page 22: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Example The intermediate value theorem is often

used to locate roots of equations. Ex. Show that there is a root of the equation

between 1 and 2. Sol. f(1)=-1<0, f(2)=12>0, there exists a

number c such that f(c)=0.

3 24 6 3 2 0x x x

Page 23: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Limits at infinity

Definition means for every >0 there

exists a number N>0 such that |f(x)-L|< whenever

x>N.

means 8>0, 9 N>0, such that

|f(x)-L|< whenever x<-N.

Lxfx

)(lim

Lxfx

)(lim

Page 24: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Properties All the properties for the limits as x! a hold true

for the limits as x!1 and Theorem If r>0 is a rational number, then

If r>0 is a rational number such that is defined for

all x, then

.x

1lim 0.

rx x

rx

1lim 0.

rx x

Page 25: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Examples

Ex. Find the limits

(a) (b)

Sol. (a)

(b)

145

23lim

2

2

xx

xxx

)1(lim 2 xxx

.5

3

/1/45

/2/13lim

145

23lim

2

2

2

2

xx

xx

xx

xxxx

.01/11

/1lim

1

1lim)1(lim

22

2

x

x

xxxx

xxx

Page 26: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Horizontal asymptoteDefinition The line y=L is called a horizontal asymptote if

either or

For instance, x-axis (y=0) is a horizontal asymptote of the

hyperbola y=1/x, since

The other example, both and

are horizontal asymptotes of

Lxfx

)(lim Lxfx

)(lim

.01

lim xx

/ 2y / 2y arctan .y x

Page 27: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Infinite limits at infinity

Definition means 8 M>0, 9 N>0, such

that f(x)>M whenever x>N.

means 8 M>0, 9 N>0, such that

f(x)<-M whenever x>N.

Similarly, we can define and

)(lim xfx

)(lim xfx

limx

lim .x

Page 28: Precise definition of limits The phrases “x is close to a” and “f(x) gets closer and closer to L” are vague. since f(x) can be arbitrarily close to 5 as

Homework 3 Section 2.4: 28, 36, 37, 43

Section 2.5: 16, 20, 36, 38, 42

Section 2.6: 24, 32, 43, 53

Page 181: 1, 2, 3, 5, 7