properties of real numbers
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3 4. – is between –1 and 0. Use a calculator to find that 7 2.65. Properties of Real Numbers. ALGEBRA 2 LESSON 1-1. 3 4. Graph the numbers – , 7 , and 3.6 on a number line. 1-1. 9 = 3, so – 9 = –3. –9 < – 9. Properties of Real Numbers. - PowerPoint PPT PresentationTRANSCRIPT
Graph the numbers – , 7 , and 3.6 on anumber line.
ALGEBRA 2 LESSON 1-1ALGEBRA 2 LESSON 1-1
Properties of Real NumbersProperties of Real Numbers
34
1-1
Use a calculator to find that 7 2.65.
– is between –1 and 0.34
Compare –9 and – 9. Use the symbols < and >.
ALGEBRA 2 LESSON 1-1ALGEBRA 2 LESSON 1-1
Properties of Real NumbersProperties of Real Numbers
Since –9 < –3, it follows that
9 = 3, so – 9 = –3.
–9 < – 9.
1-1
Find the opposite and the reciprocal of each number.
ALGEBRA 2 LESSON 1-1ALGEBRA 2 LESSON 1-1
Properties of Real NumbersProperties of Real Numbers
a. –317
Opposite: –4
1-1
Opposite: –(–3 ) = 317
17
Reciprocal: = = – 7 2222
7
1
–317
1
–Reciprocal: 1
4
b. 4
Which property is illustrated?
ALGEBRA 2 LESSON 1-1ALGEBRA 2 LESSON 1-1
Properties of Real NumbersProperties of Real Numbers
a. (–7)(2 • 5) = (–7)(5 • 2) b. 3 • (8 + 0) = 3 • 8
The given equation is true because 2 • 5 = 5 • 2.
So, the equation uses the Commutative Propertyof Multiplication.
The given equation is true because 8 + 0 = 8.
This is an instance of the Identity Property of Addition.
1-1
Simplify | 4 |, |–9.2|, and |3 – 8|.
ALGEBRA 2 LESSON 1-1ALGEBRA 2 LESSON 1-1
Properties of Real NumbersProperties of Real Numbers
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–9.2 is 9.2 units from 0, so |–9.2| = 9.2.
|3 – 8| = |–5| and –5 is 5 units from 0. So, |–5| = 5, and hence |3 – 8| = 5.
1-1
4 is 4 units from 0, so | 4 | = 4 .13
13
13
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