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TRANSCRIPT
Chapter 6Resource Masters
Geometry
Reading to Learn MathematicsVocabulary Builder
NAME ______________________________________________ DATE ____________ PERIOD _____
66
© Glencoe/McGraw-Hill vii Glencoe Geometry
Voca
bula
ry B
uild
erThis is an alphabetical list of the key vocabulary terms you will learn in Chapter 6.As you study the chapter, complete each term’s definition or description. Rememberto add the page number where you found the term. Add these pages to yourGeometry Study Notebook to review vocabulary at the end of the chapter.
Vocabulary Term Found on Page Definition/Description/Example
cross products
extremes
fractal
iteration
ID·uh·RAY·shuhn
means
(continued on the next page)
⎧ ⎪ ⎨ ⎪ ⎩
© Glencoe/McGraw-Hill viii Glencoe Geometry
Vocabulary Term Found on Page Definition/Description/Example
midsegment
proportion
ratio
scale factor
self-similar
similar polygons
Reading to Learn MathematicsVocabulary Builder (continued)
NAME ______________________________________________ DATE ____________ PERIOD _____
66
Learning to Read MathematicsProof Builder
NAME ______________________________________________ DATE ____________ PERIOD _____
66
© Glencoe/McGraw-Hill ix Glencoe Geometry
Proo
f Bu
ilderThis is a list of key theorems and postulates you will learn in Chapter 6. As you
study the chapter, write each theorem or postulate in your own words. Includeillustrations as appropriate. Remember to include the page number where youfound the theorem or postulate. Add this page to your Geometry Study Notebookso you can review the theorems and postulates at the end of the chapter.
Theorem or Postulate Found on Page Description/Illustration/Abbreviation
Theorem 6.1Side-Side-Side (SSS) Similarity
Theorem 6.2Side-Angle-Side (SAS) Similarity
Theorem 6.3
Theorem 6.4Triangle Proportionality Theorem
Theorem 6.5Converse of the TriangleProportionality Theorem
Theorem 6.6Triangle Midsegment Theorem
(continued on the next page)
© Glencoe/McGraw-Hill x Glencoe Geometry
Theorem or Postulate Found on Page Description/Illustration/Abbreviation
Theorem 6.7Proportional Perimeters Theorem
Theorem 6.8
Theorem 6.9
Theorem 6.10
Theorem 6.11Angle Bisector Theorem
Postulate 6.1Angle-Angle (AA) Similarity
Learning to Read MathematicsProof Builder (continued)
NAME ______________________________________________ DATE ____________ PERIOD _____
66
Study Guide and InterventionProportions
NAME ______________________________________________ DATE ____________ PERIOD _____
6-16-1
© Glencoe/McGraw-Hill 295 Glencoe Geometry
Less
on
6-1
Write Ratios A ratio is a comparison of two quantities. The ratio a to b, where b is not zero, can be written as !
ab! or a:b. The ratio of two quantities is sometimes called a scale
factor. For a scale factor, the units for each quantity are the same.
In 2002, the Chicago Cubs baseball team won 67 games out of 162.Write a ratio for the number of games won to the total number of games played.To find the ratio, divide the number of games won by the total number of games played. The result is !1
6672!, which is about 0.41. The Chicago Cubs won about 41% of their games in 2002.
A doll house that is 15 inches tall is a scale model of a real housewith a height of 20 feet. What is the ratio of the height of the doll house to theheight of the real house?To start, convert the height of the real house to inches.20 feet " 12 inches per foot # 240 inchesTo find the ratio or scale factor of the heights, divide the height of the doll house by theheight of the real house. The ratio is 15 inches:240 inches or 1:16. The height of the doll house is !1
16! the height of the real house.
1. In the 2002 Major League baseball season, Sammy Sosa hit 49 home runs and was atbat 556 times. Find the ratio of home runs to the number of times he was at bat.
2. There are 182 girls in the sophomore class of 305 students. Find the ratio of girls to total students.
3. The length of a rectangle is 8 inches and its width is 5 inches. Find the ratio of length to width.
4. The sides of a triangle are 3 inches, 4 inches, and 5 inches. Find the scale factor betweenthe longest and the shortest sides.
5. The length of a model train is 18 inches. It is a scale model of a train that is 48 feet long.Find the scale factor.
Example 1Example 1
Example 2Example 2
ExercisesExercises
© Glencoe/McGraw-Hill 296 Glencoe Geometry
Use Properties of Proportions A statement that two ratios are equal is called aproportion. In the proportion !
ab! # !d
c!, where b and d are not zero, the values a and d are
the extremes and the values b and c are the means. In a proportion, the product of themeans is equal to the product of the extremes, so ad # bc.
!ab! # !d
c!
a $ d # b $ c↑ ↑
extremes means
Solve !196! " !
2x7!.
!196! # !
2x7!
9 $ x # 16 $ 27 Cross products
9x # 432 Multiply.
x # 48 Divide each side by 9.
A room is 49 centimeters by 28 centimeters on a scale drawing of ahouse. For the actual room, the larger dimension is 14 feet. Find the shorterdimension of the actual room.If x is the room’s shorter dimension, then
!2489! # !1
x4!
49x # 392 Cross products
x # 8 Divide each side by 49.
The shorter side of the room is 8 feet.
Solve each proportion.
1. !12! # !
2x8! 2. !
38! # !2
y4! 3. !
xx
%%
222
! # !3100!
4. !183.2! # !
9y! 5. !
2x8% 3! # !
54! 6. !
xx
%&
11! # !
34!
Use a proportion to solve each problem.
7. If 3 cassettes cost $44.85, find the cost of one cassette.
8. The ratio of the sides of a triangle are 8:15:17. If the perimeter of the triangle is 480 inches, find the length of each side of the triangle.
9. The scale on a map indicates that one inch equals 4 miles. If two towns are 3.5 inchesapart on the map, what is the actual distance between the towns?
shorter dimension!!!longer dimension
Study Guide and Intervention (continued)
Proportions
NAME ______________________________________________ DATE ____________ PERIOD _____
6-16-1
Example 1Example 1
Example 2Example 2
ExercisesExercises
Skills PracticeProportions
NAME ______________________________________________ DATE ____________ PERIOD _____
6-16-1
© Glencoe/McGraw-Hill 297 Glencoe Geometry
Less
on
6-1
1. FOOTBALL A tight end scored 6 touchdowns in 14 games. Find the ratio of touchdownsper game.
2. EDUCATION In a schedule of 6 classes, Marta has 2 elective classes. What is the ratioof elective to non-elective classes in Marta’s schedule?
3. BIOLOGY Out of 274 listed species of birds in the United States, 78 species made theendangered list. Find the ratio of endangered species of birds to listed species in theUnited States.
4. ART An artist in Portland, Oregon, makes bronze sculptures of dogs. The ratio of theheight of a sculpture to the actual height of the dog is 2:3. If the height of the sculptureis 14 inches, find the height of the dog.
5. SCHOOL The ratio of male students to female students in the drama club at CampbellHigh School is 3:4. If the number of male students in the club is 18, what is the numberof female students?
Solve each proportion.
6. !25! # !4
x0! 7. !1
70! # !
2x1! 8. !
250! # !
46x!
9. !54x! # !
385! 10. !
x %3
1! # !
72! 11. !
135! # !
x &5
3!
Find the measures of the sides of each triangle.
12. The ratio of the measures of the sides of a triangle is 3:5:7, and its perimeter is 450 centimeters.
13. The ratio of the measures of the sides of a triangle is 5:6:9, and its perimeter is 220 meters.
14. The ratio of the measures of the sides of a triangle is 4:6:8, and its perimeter is 126 feet.
15. The ratio of the measures of the sides of a triangle is 5:7:8, and its perimeter is 40 inches.
© Glencoe/McGraw-Hill 298 Glencoe Geometry
1. NUTRITION One ounce of cheddar cheese contains 9 grams of fat. Six of the grams of fatare saturated fats. Find the ratio of saturated fats to total fat in an ounce of cheese.
2. FARMING The ratio of goats to sheep at a university research farm is 4:7. The numberof sheep at the farm is 28. What is the number of goats?
3. ART Edward Hopper’s oil on canvas painting Nighthawks has a length of 60 inches anda width of 30 inches. A print of the original has a length of 2.5 inches. What is the widthof the print?
Solve each proportion.
4. !58! # !1
x2! 5. !1.
x12! # !
15! 6. !2
67x! # !
43!
7. !x %
32
! # !89! 8. !
3x4& 5! # !
&75! 9. !
x &4
2! # !
x %2
4!
Find the measures of the sides of each triangle.
10. The ratio of the measures of the sides of a triangle is 3:4:6, and its perimeter is 104 feet.
11. The ratio of the measures of the sides of a triangle is 7:9:12, and its perimeter is 84 inches.
12. The ratio of the measures of the sides of a triangle is 6:7:9, and its perimeter is 77 centimeters.
Find the measures of the angles in each triangle.
13. The ratio of the measures of the angles is 4:5:6.
14. The ratio of the measures of the angles is 5:7:8.
15. BRIDGES The span of the Benjamin Franklin suspension bridge in Philadelphia,Pennsylvania, is 1750 feet. A model of the bridge has a span of 42 inches. What is theratio of the span of the model to the span of the actual Benjamin Franklin Bridge?
Practice Proportions
NAME ______________________________________________ DATE ____________ PERIOD _____
6-16-1
Reading to Learn MathematicsProportions
NAME ______________________________________________ DATE ____________ PERIOD _____
6-16-1
© Glencoe/McGraw-Hill 299 Glencoe Geometry
Less
on
6-1
Pre-Activity How do artists use ratios?
Read the introduction to Lesson 6-1 at the top of page 282 in your textbook.
Estimate the ratio of length to width for the background rectangles inTiffany’s Clematis Skylight.
Reading the Lesson
1. Match each description in the first column with a word or phrase from the secondcolumn.
a. The ratio of two corresponding quantities i. proportion
b. r and u in the equation !rs! # !u
t! ii. cross products
c. a comparison of two quantities iii. means
d. ru and st in the equation !rs! # !u
t! iv. scale factor
e. an equation stating that two ratios are equal v. extremes
f. s and t in the equation !rs! # !u
t! vi. ratio
2. If m, n, p, and q are nonzero numbers such that !mn! # !
pq!, which of the following
statements could be false?
A. np # mq B. !np
! # !mq!
C. mp # nq D. qm # pn
E. !mn! # !p
q! F. !p
q! # !m
n!
G. m:p # n:q H. m:n # p:q
3. Write two proportions that match each description.
a. Means are 5 and 8; extremes are 4 and 10.
b. Means are 5 and 4; extremes are positive integers that are different from means.
Helping You Remember
4. Sometimes it is easier to remember a mathematical idea if you put it into words withoutusing any mathematical symbols. How can you use this approach to remember theconcept of equality of cross products?
© Glencoe/McGraw-Hill 300 Glencoe Geometry
Golden Rectangles
Use a straightedge, compass, and the instructions belowto construct a golden rectangle.
1. Construct square ABCD with sides of 2 cm.
2. Construct the midpoint of A!B!. Call the midpoint M.
3. Draw AB!"#. Set your compass at an opening equal to MC.Use M as the center to draw an arc that intersects AB!"#. Call the point of intersection P.
4. Construct a line through P that is perpendicular to AB!"#.
5. Draw DC!"# so that it intersects the perpendicular line in step 4.Call the intersection point Q. APQD is a golden rectanglebecause the ratio of its length to its width is 1.618. Check this conclusion by finding the value of !QAP
P!. Rectangles whose sides
have this ratio are, it is said, the most pleasing to the human eye.
A figure consisting of similar golden rectangles is shown below. Use a compassand the instructions below to draw quarter-circle arcs that form a spiral like thatfound in the shell of a chambered nautilus.
6. Using A as a center, draw an arc that passes through B and C.
7. Using D as a center, draw an arc that passes through C and E.
8. Using F as a center, draw an arc that passes through E and G.
9. Using H as a center, draw an arc that passes through G and J.
10. Using K as a center, draw an arc that passes through J and L.
11. Using M as a center, draw an arc that passes through L and N.
M NH
L FD
JK
B A
C
G
E
A M B P
D C Q
Enrichment
NAME ______________________________________________ DATE ____________ PERIOD _____
6-16-1
Study Guide and InterventionSimilar Polygons
NAME ______________________________________________ DATE ____________ PERIOD _____
6-26-2
© Glencoe/McGraw-Hill 301 Glencoe Geometry
Less
on
6-2
Identify Similar Figures
Determine whether the triangles are similar.Two polygons are similar if and only if their corresponding angles are congruent and their corresponding sides are proportional.
!C " !Z because they are right angles, and !B " !X.By the Third Angle Theorem, !A " !Y.
For the sides, !BX
CZ! # !
2203!, !
BX
AY! # # !
2203!, and !
AY
CZ! # !
2203!.
The side lengths are proportional. So "BCA # "XZY.
Is polygon WXYZ ! polygon PQRS?
For the sides, !WPQ
X! # !
182! # !
32!, !Q
XYR! # !
1182! # !
32!, !R
YZS! # !
1150! # !
32!,
and !ZSWP! # !
96! # !
32!. So corresponding sides are proportional.
Also, !W " !P, !X " !Q, !Y " !R, and !Z " !S, so corresponding angles are congruent. We can conclude that polygon WXYZ # polygon PQRS.
Determine whether each pair of figures is similar. If they are similar, give theratio of corresponding sides.
1. 2.
3. 4. 10y
8y
37#
37#116#27#
5x
4x15z
12z
22
11
1610
equilateral triangles
15
9
12
18
XW
Z Y 10
6
8
12
QP
S R
20$2!!23$2!
20 23
2320 20$%2 23$%245#
45#C A X Z
B Y
ExercisesExercises
Example 1Example 1
Example 2Example 2
© Glencoe/McGraw-Hill 302 Glencoe Geometry
Scale Factors When two polygons are similar, the ratio of the lengths of corresponding sides is called the scale factor. At the right, "ABC # "XYZ. The scale factor of "ABC to "XYZ is 2 and the scale factor of "XYZ to "ABC is !
12!.
3 cm
6 cm
8 cm
10 cm5 cm4 cm
Z
Y
XC
A
B
Study Guide and Intervention (continued)
Similar Polygons
NAME ______________________________________________ DATE ____________ PERIOD _____
6-26-2
The two polygons aresimilar. Find x and y.
Use the congruent angles to write thecorresponding vertices in order."RST # "MNPWrite proportions to find x and y.
!3126! # !1
x3! !
3y8! # !
3126!
16x # 32(13) 32y # 38(16)x # 26 y # 19
x
y38
3216 13
T
S
R P
N
M
!ABC ! !CDE. Find the scale factor and find the lengths of C"D"and D"E".
AC # 3 & 0 # 3 and CE # 9 & 3 # 6. Thescale factor of "CDE to "ABC is 6:3 or 2:1.Using the Distance Formula,AB # $1 % 9! # $10! and BC # $4 % 9! # $13!. The lengths of thesides of "CDE are twice those of "ABC,so DC # 2(BA) or 2$10! and DE # 2(BC) or 2$13!.
x
y
A(0, 0)
B(1, 3)
C(3, 0)
E(9, 0)
D
Example 1Example 1 Example 2Example 2
ExercisesExercises
Each pair of polygons is similar. Find x and y.
1. 2.
3. 4.
5. In Example 2 above, point D has coordinates (5, 6). Use the Distance Formula to verifythe lengths of C!D! and D!E!.
40
36x
30
18 y12
y $ 1
18
24
x18
10
y
4.5x
2.5
5
9
12
y8
10x
Skills PracticeSimilar Polygons
NAME ______________________________________________ DATE ____________ PERIOD _____
6-26-2
© Glencoe/McGraw-Hill 303 Glencoe Geometry
Less
on
6-2
Determine whether each pair of figures is similar. Justify your answer.
1. 2.
Each pair of polygons is similar. Write a similarity statement, and find x, themeasure(s) of the indicated side(s), and the scale factor.
3. G!H! 4. S!T! and S!U!
5. W!T! 6. T!S! and S!P!
10
8
x $ 2
x % 1
SP
M N
L
T
9
103
x $ 1
5
P
S
RU V
WT
Q
x $ 5
x $ 5
9
3
44 S
W
XY
T
U26
14
12 13
B C
DA
13
76 x
G
E H
F
7.5
7.5
7.57.5
Z Y
XW
3
3
33S R
QP
10.5
6 9
59# 35#A C
B
7
4 659# 35#D F
E
© Glencoe/McGraw-Hill 304 Glencoe Geometry
Determine whether each pair of figures is similar. Justify your answer.
1. 2.
Each pair of polygons is similar. Write a similarity statement, and find x, themeasure(s) of the indicated side(s), and the scale factor.
3. L!M! and M!N! 4. D!E! and D!F!
5. COORDINATE GEOMETRY Triangle ABC has vertices A(0, 0), B(&4, 0), and C(&2, 4).The coordinates of each vertex are multiplied by 3 to create "AEF. Show that "AEF issimilar to "ABC.
6. INTERIOR DESIGN Graham used the scale drawing of his living room to decide where to place furniture. Find the dimensions of theliving room if the scale in the drawing is 1 inch # 4.5 feet.
4 in.
21–2 in.
6 12
40#
40#
x $ 1
x % 3AF
E
D
B C14
10
x $ 6
x $ 9
C N MD
A B LP
2412
14 16 2118
VUAC
B T
25 12
9
14.4
1524
20
15
JM Q R
SP
KL
Practice Similar Polygons
NAME ______________________________________________ DATE ____________ PERIOD _____
6-26-2
Reading to Learn MathematicsSimilar Polygons
NAME ______________________________________________ DATE ____________ PERIOD _____
6-26-2
© Glencoe/McGraw-Hill 305 Glencoe Geometry
Less
on
6-2
Pre-Activity How do artists use geometric patterns?
Read the introduction to Lesson 6-2 at the top of page 289 in your textbook.• Describe the figures that have similar shapes.
• What happens to the figures as your eyes move from the center to theouter edge?
Reading the Lesson1. Complete each sentence.
a. Two polygons that have exactly the same shape, but not necessarily the same size,are .
b. Two polygons are congruent if they have exactly the same shape and the same .
c. Two polygons are similar if their corresponding angles are and their corresponding sides are .
d. Two polygons are congruent if their corresponding angles are and their corresponding sides are .
e. The ratio of the lengths of corresponding sides of two similar figures is called the .
f. Multiplying the coordinates of all points of a figure in the coordinate plane by a scale factor to get a similar figure is called a .
g. If two polygons are similar with a scale factor of 1, then the polygons are .
2. Determine whether each statement is always, sometimes, or never true.a. Two similar triangles are congruent.b. Two equilateral triangles are congruent.c. An equilateral triangle is similar to a scalene triangle.d. Two rectangles are similar.e. Two isosceles right triangles are congruent.f. Two isosceles right triangles are similar.g. A square is similar to an equilateral triangle.h. Two acute triangles are similar.i. Two rectangles in which the length is twice the width are similar.j. Two congruent polygons are similar.
Helping You Remember3. A good way to remember a new mathematical vocabulary term is to relate it to words
used in everyday life. The word scale has many meanings in English. Give three phrasesthat include the word scale in a way that is related to proportions.
© Glencoe/McGraw-Hill 306 Glencoe Geometry
Constructing Similar PolygonsHere are four steps for constructing a polygon that is similar to and withsides twice as long as those of an existing polygon.
Step 1 Choose any point either inside or outside the polygon and label it O.Step 2 Draw rays from O through each vertex of the polygon.Step 3 For vertex V, set the compass to length OV. Then locate a new point
V' on ray OV such that VV' # OV. Thus, OV' # 2(OV ).Step 4 Repeat Step 3 for each vertex. Connect points V', W', X' and Y' to
form the new polygon.
Two constructions of polygons similar to and with sides twice those of VWXYare shown below. Notice that the placement of point O does not affect the sizeor shape of V'W'X'Y', only its location.
Trace each polygon. Then construct a similar polygon with sides twice as long asthose of the given polygon.
1. 2. D E F
GC
A
B
VW
Y X
VW
Y X
V'
W'
X'Y'
O
VW
YX
V'
W'
X'Y'
O
Enrichment
NAME ______________________________________________ DATE ____________ PERIOD _____
6-26-2
3. Explain how to construct a similarpolygon with sides three times the lengthof those of polygon HIJKL. Then do theconstruction.
4. Explain how to construct a similar polygon 1!
12! times the length of those of
polygon MNPQRS. Then do theconstruction.
M
S
R
N
Q
P
H I
LK
J
Study Guide and InterventionSimilar Triangles
NAME ______________________________________________ DATE ____________ PERIOD _____
6-36-3
© Glencoe/McGraw-Hill 307 Glencoe Geometry
Less
on
6-3
Identify Similar Triangles Here are three ways to show that two triangles are similar.
AA Similarity Two angles of one triangle are congruent to two angles of another triangle.
SSS Similarity The measures of the corresponding sides of two triangles are proportional.
SAS SimilarityThe measures of two sides of one triangle are proportional to the measures of two corresponding sides of another triangle, and the included angles are congruent.
Determine whether thetriangles are similar.
!DAC
F! # !69! # !
23!
!BE
CF! # !1
82! # !
23!
!DAB
E! # !1105! # !
23!
"ABC # "DEF by SSS Similarity.
15
129
D E
F
10
86
A B
C
Determine whether thetriangles are similar.
!34! # !
68!, so !MQR
N! # !
NRS
P!.
m!N # m!R, so !N " !R."NMP # "RQS by SAS Similarity.
8
4
70#
Q
R S6
370#
M
N P
Example 1Example 1 Example 2Example 2
ExercisesExercises
Determine whether each pair of triangles is similar. Justify your answer.
1. 2.
3. 4.
5. 6. 3220
154025
24
3926
1624
18
8
65#9
465#
36
2018
24
© Glencoe/McGraw-Hill 308 Glencoe Geometry
Use Similar Triangles Similar triangles can be used to find measurements.
Study Guide and Intervention (continued)
Similar Triangles
NAME ______________________________________________ DATE ____________ PERIOD _____
6-36-3
!ABC ! !DEF.Find x and y.
!DAC
F! # !BE
CF! !D
ABE! # !
BE
CF!
# !198! !1
y8! # !
198!
18x # 9(18$3!) 9y # 324x # 9$3! y # 36
18$3!!x
18$%3
B
CA
18 18 9y
x
E
FD
A person 6 feet tall castsa 1.5-foot-long shadow at the same timethat a flagpole casts a 7-foot-longshadow. How tall is the flagpole?
The sun’s rays form similar triangles.Using x for the height of the pole, !
6x! # !
17.5!,
so 1.5x # 42 and x # 28.The flagpole is 28 feet tall.
7 ft
6 ft?
1.5 ft
Example 1Example 1 Example 2Example 2
ExercisesExercises
Each pair of triangles is similar. Find x and y.
1. 2.
3. 4.
5. 6.
7. The heights of two vertical posts are 2 meters and 0.45 meter. When the shorter postcasts a shadow that is 0.85 meter long, what is the length of the longer post’s shadow to the nearest hundredth?
y
x32
10
2230yx
9
8
7.2
16
yx
6038.6
23
3024
36$%2yx
3636
20
13
26y
x $ 235
13
10 20y
x
Skills PracticeSimilar Triangles
NAME ______________________________________________ DATE ____________ PERIOD _____
6-36-3
© Glencoe/McGraw-Hill 309 Glencoe Geometry
Less
on
6-3
Determine whether each pair of triangles is similar. Justify your answer.
1. 2.
3. 4.
ALGEBRA Identify the similar triangles, and find x and the measures of theindicated sides.
5. A!C! and E!D! 6. J!L! and L!M!
7. E!H! and E!F! 8. U!T! and R!T!
6
14
S
U
V
R T
x % 4
x % 612
9
6
9
D
E
FH
Gx $ 5
16
4M
NL
J
K
x $ 18
x % 3
1512
D
E CB
Ax $ 1
x $ 5
30#60#RQ
M
S
K
T
2170#
15
MJ
P
1470#10
U
S
T
12
128
9
9 6
C P
QR
A
B
2014
13 12219
S W X
Y
R
T
© Glencoe/McGraw-Hill 310 Glencoe Geometry
Determine whether each pair of triangles is similar. Justify your answer.
1. 2.
ALGEBRA Identify the similar triangles, and find x and the measures of theindicated sides.
3. L!M! and Q!P! 4. N!L! and M!L!
Use the given information to find each measure.
5. If T!S! || Q!R!, TS # 6, PS # x % 7, 6. If E!F! || H!I!, EF # 3, EG # x % 1,QR # 8, and SR # x & 1, HI # 4, and HG # x % 3,find PS and PR. find EG and HG.
INDIRECT MEASUREMENT For Exercises 7 and 8, use the following information.A lighthouse casts a 128-foot shadow. A nearby lamppost that measures 5 feet 3 inches castsan 8-foot shadow.
7. Write a proportion that can be used to determine the height of the lighthouse.
8. What is the height of the lighthouse?
F
GE
H
I
S RP
QT
8
N
J LK
Mx $ 5
6x $ 2
24
12
18N
P
QL
M
x $ 3x % 1
18
16 12.516
14
11
M
L N
S R
T42#
42#
24
1812
16J
A K
Y S
W
Practice Similar Triangles
NAME ______________________________________________ DATE ____________ PERIOD _____
6-36-3
Reading to Learn MathematicsSimilar Triangles
NAME ______________________________________________ DATE ____________ PERIOD _____
6-36-3
© Glencoe/McGraw-Hill 311 Glencoe Geometry
Less
on
6-3
Pre-Activity How do engineers use geometry?
Read the introduction to Lesson 6-3 at the top of page 298 in your textbook.• What does it mean to say that triangular shapes result in rigid
construction?
• What would happen if the shapes used in the construction werequadrilaterals?
Reading the Lesson1. State whether each condition guarantees that two triangles are congruent or similar.
If the condition guarantees that the triangles are both similar and congruent, writecongruent. If there is not enough information to guarantee that the triangles will becongruent or similar, write neither.a. Two sides and the included angle of one triangle are congruent to two sides and the
included angle of the other triangle.b. The measures of all three pairs of corresponding sides are proportional.c. Two angles of one triangle are congruent to two angles of the other triangle.d. Two angles and a nonincluded side of one triangle are congruent to two angles and
the corresponding nonincluded side of the other triangle.e. The measures of two sides of a triangle are proportional to the measures of two
corresponding sides of another triangle, and the included angles are congruent.
f. The three sides of one triangle are congruent to the three sides of the other triangle.
g. The three angles of one triangle are congruent to the three angles of the other triangle.
h. One acute angle of a right triangle is congruent to one acute angle of another righttriangle.
i. The measures of two sides of a triangle are proportional to the measures of two sidesof another triangle.
2. Identify each of the following as an example of a reflexive, symmetric, or transitive property.a. If "RST # "UVW, then "UVW # "RST.b. If "RST # "UVW and "UVW # "OPQ, then "RST # "OPQ.c. "RST # "RST
Helping You Remember3. A good way to remember something is to explain it to someone else. Suppose one of your
classmates is having trouble understanding the difference between SAS for congruenttriangles and SAS for similar triangles. How can you explain the difference to him?
© Glencoe/McGraw-Hill 312 Glencoe Geometry
Ratio Puzzles with TrianglesIf you know the perimeter of a triangle and the ratios of the sides, you canfind the lengths of the sides.
The perimeter of a triangle is 84 units. The sides havelengths r, s, and t. The ratio of s to r is 5:3, and the ratio of t to r is2:1. Find the length of each side.
Since both ratios contain r, rewrite one or both ratios to make r the same. Youcan write the ratio of t to r as 6:3. Now you can write a three-part ratio.r : s : t # 3: 5: 6
There is a number x such that r # 3x, s # 5x, and t # 6x. Since you know theperimeter, 84, you can use algebra to find the lengths of the sides.
r % s % t # 843x % 5x % 6x # 84
14x # 84x # 6
3x # 18, 5x # 30, 6x # 36
So r # 18, s # 30, and t # 36.
Find the lengths of the sides of each triangle.
1. The perimeter of a triangle is 75 units. The sides have lengths a, b, and c. The ratio of b to a is 3:5, and the ratio of c to a is 7:5. Find the length of each side.
2. The perimeter of a triangle is 88 units. The sides have lengths d, e, and f. The ratio of e to d is 3:1, and the ratio of f to e is 10:9. Find the length of each side.
3. The perimeter of a triangle is 91 units. The sides have lengths p, q, and r. The ratio of p to r is 3:1, and the ratio of q to r is 5:2. Find the length of each side.
4. The perimeter of a triangle is 68 units. The sides have lengths g, h, and j. The ratio of j to g is 2:1, and the ratio of h to g is 5:4. Find the length of each side.
5. Write a problem similar to those above involving ratios in triangles.
Enrichment
NAME ______________________________________________ DATE ____________ PERIOD _____
6-36-3
ExampleExample
Study Guide and InterventionParallel Lines and Proportional Parts
NAME ______________________________________________ DATE ____________ PERIOD _____
6-46-4
© Glencoe/McGraw-Hill 313 Glencoe Geometry
Less
on
6-4
Proportional Parts of Triangles In any triangle, a line parallel to one side of a triangle separates the other two sides proportionally. The converse is also true.
If X and Y are the midpoints of R!T! and S!T!, then X!Y! is amidsegment of the triangle. The Triangle Midsegment Theoremstates that a midsegment is parallel to the third side and is half its length.
If XY!"# || RS!"#, then !RXTX! # !Y
SYT!.
If !RXTX! # !Y
SYT!, then XY!"# || RS!"#.
If X!Y! is a midsegment, then XY!"# || RS!"# and XY # !12!RS.
Y ST
R
X
In !ABC, E"F" || C"B". Find x.
Since E!F! || C!B!, !FA
BF! # !E
AEC!.
!xx
%%
222
! # !168!
6x % 132 # 18x % 3696 # 12x8 # x
F
C
BA
18
x $ 22 x $ 2
6E
A triangle has verticesD(3, 6), E(%3, %2), and F(7, %2).Midsegment G"H" is parallel to E"F". Find the length of G"H".G!H! is a midsegment, so its length is one-half that of E!F!. Points E and F have thesame y-coordinate, so EF # 7 & (&3) # 10.The length of midsegment G!H! is 5.
Example 1Example 1 Example 2Example 2
ExercisesExercises
Find x.
1. 2. 3.
4. 5. 6.
7. In Example 2, find the slope of E!F! and show that E!F! || G!H!.
30 10x $ 10
x11x $ 12
x33
30 10
24x
35
x9
20
x
185
5 x
7
© Glencoe/McGraw-Hill 314 Glencoe Geometry
Divide Segments Proportionally When three or more parallel lines cut two transversals,they separate the transversals into proportional parts. If the ratio of the parts is 1, then the parallellines separate the transversals into congruent parts.
If !1 || !2 || !3, If !4 || !5 || !6 and
then !ab! # !d
c!. !
uv! # 1, then !
wx! # 1.
Refer to lines !1, !2 ,and !3 above. If a " 3, b " 8, and c " 5, find d.
!1 || !2 || !3 so !38! # !d
5!. Then 3d # 40 and d # 13!
13!.
Find x and y.
1. 2.
3. 4.
5. 6.16 32
y $ 3y
3 4
x $ 4x
5
8 y $ 2
y2x $ 4
3x % 1 2y $ 2
3y
2x % 6
x $ 3
12
x $ 12 12
3x5x
a
bd
u v
xw
ctn
m
s !1
!4 !5 !6
!2
!3
Study Guide and Intervention (continued)
Parallel Lines and Proportional Parts
NAME ______________________________________________ DATE ____________ PERIOD _____
6-46-4
ExampleExample
ExercisesExercises
Skills PracticeParallel Lines and Proportional Parts
NAME ______________________________________________ DATE ____________ PERIOD _____
6-46-4
© Glencoe/McGraw-Hill 315 Glencoe Geometry
Less
on
6-4
1. If JK # 7, KH # 21, and JL # 6, 2. Find x and TV if RU # 8, US # 14,find LI. TV # x & 1 and VS # 17.5.
Determine whether B!C! || D!E!.
3. AD # 15, DB # 12, AE # 10, and EC # 8
4. BD # 9, BA # 27, and CE is one third of EA
5. AE # 30, AC # 45, and AD is twice DB
COORDINATE GEOMETRY For Exercises 6–8, use the following information.Triangle ABC has vertices A(&5, 2), B(1, 8), and C(4, 2). Point Dis the midpoint of A!B! and E is the midpoint of A!C!.
6. Identify the coordinates of D and E.
7. Show that B!C! is parallel to D!E!.
8. Show that DE # !12!BC.
9. Find x and y. 10. Find x and y.
3–2x $ 2
x $ 3
2y % 1
3y % 52x $ 1 3y % 8
y $ 5x $ 7
x
y
O
A C
B
D
E
C
B
E
D
A
R
U V
T
S
HL
K J
I
© Glencoe/McGraw-Hill 316 Glencoe Geometry
1. If AD # 24, DB # 27, and EB # 18, 2. Find x, QT, and TR if QT # x % 6,find CE. SR # 12, PS # 27, and TR # x & 4.
Determine whether J"K" || N"M".
3. JN # 18, JL # 30, KM # 21, and ML # 35
4. KM # 24, KL # 44, and NL # !56!JN
COORDINATE GEOMETRY For Exercises 5 and 6, use the following information.Triangle EFG has vertices E(&4, &1), F(2, 5), and G(2, &1). Point Kis the midpoint of E!G! and H is the midpoint of F!G!.
5. Show that E!F! is parallel to K!H!.
6. Show that KH # !12!EF.
7. Find x and y. 8. Find x and y.
9. MAPS The distance from Wilmington to Ash Grove along Kendall is 820 feet and along Magnolia, 660 feet. If the distance between Beech and Ash Grove along Magnolia is 280 feet, what is the distance between the two streets alongKendall?
Ash Grove
Beech
Magnolia Kendall
Wilmington
4–3y $ 2
3x % 4 x $ 1
4y % 43x % 4 2–
3y $ 31–3y $ 65–
4x $ 3
x
y
O
E G
F
H
K
N LJ
KM
S
Q
TRP
D
E
C
BA
Practice Parallel Lines and Proportional Parts
NAME ______________________________________________ DATE ____________ PERIOD _____
6-46-4
Reading to Learn MathematicsParallel Lines and Proportional Parts
NAME ______________________________________________ DATE ____________ PERIOD _____
6-46-4
© Glencoe/McGraw-Hill 317 Glencoe Geometry
Less
on
6-4
Pre-Activity How do city planners use geometry?
Read the introduction to Lesson 6-4 at the top of page 307 in your textbook.
Use a geometric idea to explain why the distance between Chicago Avenueand Ontario Street is shorter along Michigan Avenue than along LakeShore Drive.
Reading the Lesson
1. Provide the missing words to complete the statement of each theorem. Then state thename of the theorem.
a. If a line intersects two sides of a triangle and separates the sides into corresponding
segments of lengths, then the line is to the
third side.
b. A midsegment of a triangle is to one side of the triangle and its
length is the length of that side.
c. If a line is to one side of a triangle and intersects the other two sides
in distinct points, then it separates these sides into
of proportional length.
2. Refer to the figure at the right.
a. Name the three midsegments of "RST.
b. If RS # 8, RU # 3, and TW # 5, find the length of each of themidsegments.
c. What is the perimeter of "RST?
d. What is the perimeter of "UVW?
e. What are the perimeters of "RUV, "SVW, and "TUW?
f. How are the perimeters of each of the four small triangles related to the perimeter ofthe large triangle?
g. Would the relationship that you found in part f apply to any triangle in which themidpoints of the three sides are connected?
Helping You Remember
3. A good way to remember a new mathematical term is to relate it to other mathematicalvocabulary that you already know. What is an easy way to remember the definition ofmidsegment using other geometric terms?
R
U
V
W
T
S
© Glencoe/McGraw-Hill 318 Glencoe Geometry
Parallel Lines and Congruent PartsThere is a theorem stating that if three parallel lines cut off congruent segments on onetransversal, then they cut off congruent segments on any transversal. This can be shown forany number of parallel lines. The following drafting technique uses this fact to divide asegment into congruent parts.
A!B! is to be separated into five congruent parts. This can be done very accurately without using a ruler. All that is needed is a compass and a piece of notebook paper.
Step 1 Hold the corner of a piece of notebook paper at point A.
Step 2 From point A, draw a segment along the paper that is five spaces long. Mark where the lines of the notebook paper meet the segment. Label the fifth point, P.
Step 3 Draw P!B!. Through each of the other marks on A!P!, construct a line parallel to B!P!. The points where these lines intersect A!B! will divide A!B! into five congruent segments.
Use a compass and a piece of notebook paper to divide each segment into the given number of congruent parts.
1. six congruent parts
2. seven congruent parts A B
A B
A
P
B
A B
P
A B
A B
Enrichment
NAME ______________________________________________ DATE ____________ PERIOD _____
6-46-4
Study Guide and InterventionParts of Similar Triangles
NAME ______________________________________________ DATE ____________ PERIOD _____
6-56-5
© Glencoe/McGraw-Hill 319 Glencoe Geometry
Less
on
6-5
Perimeters If two triangles are similar, their perimeters have the same proportion as the corresponding sides.
If "ABC # "RST, then
!AR
BS
%%
BST
C%%
RA
TC
! # !AR
BS! # !
BST
C! # !R
ACT!.
Use the diagram above with !ABC ! !RST. If AB " 24 and RS " 15,find the ratio of their perimeters.Since "ABC # "RST, the ratio of the perimeters of "ABC and "RST is the same as theratio of corresponding sides.
Therefore # !2145!
# !85!
Each pair of triangles is similar. Find the perimeter of the indicated triangle.
1. "XYZ 2. "BDE
3. "ABC 4. "XYZ
5. "ABC 6. "RST
25
20
10
P T
SM
R
95
13
12
A D
E
C
B
5 68.7
13
10
X Y
Z T
R S18
20
25 15 17
8
NB
A C PM
36
9
11C
DE
A
B44
24
20 22 10
TRX Z
YS
perimeter of "ABC!!!perimeter of "RST
A C
BS
R T
ExampleExample
ExercisesExercises
© Glencoe/McGraw-Hill 320 Glencoe Geometry
Special Segments of Similar Triangles When two triangles are similar,corresponding altitudes, angle bisectors, and medians are proportional to the correspondingsides. Also, in any triangle an angle bisector separates the opposite side into segments thathave the same ratio as the other two sides of the triangle.
Study Guide and Intervention (continued)
Parts of Similar Triangles
NAME ______________________________________________ DATE ____________ PERIOD _____
6-56-5
In the figure,!ABC ! !XYZ, with angle bisectors asshown. Find x.
Since "ABC # "XYZ, the measures of theangle bisectors are proportional to themeasures of a pair of corresponding sides.
!AX
BY! # !Y
BWD!
!2x4! # !
180!
10x # 24(8)10x # 192
x # 19.2
2410
DW
Y
ZXC
B
A
8x
S"U" bisects "RST. Find x.
Since S!U! is an angle bisector, !RTU
U! # !
RTS
S!.
!2x0! # !
1350!
30x # 20(15)30x # 300
x # 10
x 20
3015
UT
S
R
Example 1Example 1 Example 2Example 2
ExercisesExercises
Find x for each pair of similar triangles.
1. 2.
3. 4.
5. 6. 2x % 2x $ 1
281617
11
x $ 7
x
10
10x
8
873
34
x
69
12x
x
36
1820
Skills PracticeParts of Similar Triangles
NAME ______________________________________________ DATE ____________ PERIOD _____
6-56-5
© Glencoe/McGraw-Hill 321 Glencoe Geometry
Less
on
6-5
Find the perimeter of the given triangle.
1. "JKL, if "JKL # "RST, RS # 14, 2. "DEF, if "DEF # "ABC, AB # 27,ST # 12, TR # 10, and LJ # 14 BC # 16, CA # 25, and FD # 15
3. "PQR, if "PQR # "LMN, LM # 16, 4. "KLM, if "KLM # "FGH, FG # 30,MN # 14, NL # 27, and RP # 18 GH # 38, HF # 38, and KL # 24
Use the given information to find each measure.
5. Find FG if "RST # "EFG, S!H! is an 6. Find MN if "ABC # "MNP, A!D! is an altitude of "RST, F!J! is an altitude of altitude of "ABC, M!Q! is an altitude of"EFG, ST # 6, SH # 5, and FJ # 7. "MNP, AB # 24, AD # 14, and MQ # 10.5.
Find x.
7. "HKL # "XYZ 8.
LH
K
18
10
Y
15
x
ZX7
20
24
x
C
A
BD P NQ
M
J GE
F
H TR
S
GL
K
M
F
H
L MP Q
RN
A
B
C
D
E
F
R S
T
J K
L
© Glencoe/McGraw-Hill 322 Glencoe Geometry
Find the perimeter of the given triangle.
1. "DEF, if "ABC # "DEF, AB # 36, 2. "STU, if "STU # "KLM, KL # 12,BC # 20, CA # 40, and DE # 35 LM # 31, MK # 32, and US # 28
Use the given information to find each measure.
3. Find PR if "JKL # "NPR, K!M! is an 4. Find ZY if "STU # "XYZ, U!A! is an altitude of "JKL, P!T! is an altitude of altitude of "STU, Z!B! is an altitude of "NPR, KL # 28, KM # 18, and "XYZ, UT # 8.5, UA # 6, and PT # 15.75. ZB # 11.4.
Find x.
5. 6.
PHOTOGRAPHY For Exercises 7 and 8, use the following information.Francine has a camera in which the distance from the lens to the film is 24 millimeters.
7. If Francine takes a full-length photograph of her friend from a distance of 3 meters andthe height of her friend is 140 centimeters, what will be the height of the image on thefilm? (Hint: Convert to the same unit of measure.)
8. Suppose the height of the image on the film of her friend is 15 millimeters. If Francinetook a full-length shot, what was the distance between the camera and her friend?
x28
20 30402x $ 1 25x $ 4
YX B
Z
TS A
U
MJ L
K
TN R
P
KS
LT
UMBE
CFDA
Practice Parts of Similar Triangles
NAME ______________________________________________ DATE ____________ PERIOD _____
6-56-5
Reading to Learn MathematicsParts of Similar Triangles
NAME ______________________________________________ DATE ____________ PERIOD _____
6-56-5
© Glencoe/McGraw-Hill 323 Glencoe Geometry
Less
on
6-5
Pre-Activity How is geometry related to photography?
Read the introduction to Lesson 6-5 at the top of page 316 in your textbook.
• How is similarity involved in the process of making a photographic printfrom a negative?
• Why do photographers place their cameras on tripods?
Reading the Lesson
1. In the figure, "RST # "UVW. Complete each proportion involving the lengths of segments inthis figure by replacing the question mark. Thenidentify the definition or theorem from the listbelow that the completed proportion illustrates.
i. Definition of congruent polygons ii. Definition of similar polygons
iii. Proportional Perimeters Theorem iv. Angle Bisectors Theorem
v. Similar triangles have corresponding altitudes proportional to corresponding sides.
vi. Similar triangles have corresponding medians proportional to corresponding sides.
vii. Similar triangles have corresponding angle bisectors proportional to corresponding sides.
a. !RS % S?T % TR! # !U
RSV! b. !U
RWT! # !
S?X!
c. !RU
MN! # !V
?W! d. !U
RSV! # !
S?T!
e. !RPS
P! # !S
?T! f. !
U?N! # !
UR
WT!
g. !WTP
Q! # !R?T! h. !
UVW
W! # !Q
?V!
Helping You Remember
2. A good way to remember a large amount of information is to remember key words. Whatkey words will help you remember the features of similar triangles that are proportionalto the lengths of the corresponding sides?
W
Q N
YU
V
T
P M
XR
S
© Glencoe/McGraw-Hill 324 Glencoe Geometry
Proportions for Similar TrianglesRecall that if a line crosses two sides of a triangle and is parallel to the thirdside, then the line separates the two sides that it crosses into segments ofproportional lengths.
You can write many proportions by identifying similar triangles in thefollowing diagram. In the diagram, AM!"# & BN!"#, AE!"# & FL!"# & MR!"#, and DQ!"# & ER!"#.
Answer each question. Use the diagram above.
1. Name a triangle similar to "GNP. 2. Name a triangle similar to "CJH.
3. Name two triangles similar to "JKS. 4. Name a triangle similar to "ACP.
Complete each proportion.
5. !AA
GP! # !
A?F! 6. !C
CHP! # !
C?R! 7. !J
JRS! # !J
?L!
8. !PP
HC! # !
P?G! 9. !
ELR
R! # !J
?R! 10. !
MM
NP! # !A
?P!
Solve.
11. If CJ # 16, JR # 48, and LR # 30, find EL.
12. If DK # 5, KS # 7, and CJ # 8, find JS.
13. If MN # 12, NP # 32, and AP # 48, find AG. Round to the nearest tenth.
14. If CH # 18, HP # 82, and CR # 130, find CJ.
15. Write three more problems that can be solved using the diagram above.
A B C D E
F G H J K L
M N P RQ
S
Enrichment
NAME ______________________________________________ DATE ____________ PERIOD _____
6-56-5
Study Guide and InterventionFractals and Self-Similarity
NAME ______________________________________________ DATE ____________ PERIOD _____
6-66-6
© Glencoe/McGraw-Hill 325 Glencoe Geometry
Less
on
6-6
Characteristics of Fractals The act of repeating a process over and over, such asfinding a third of a segment, then a third of the new segment, and so on, is called iteration.When the process of iteration is applied to some geometric figures, the results are calledfractals. For objects such as fractals, when a portion of the object has the same shape orcharacteristics as the entire object, the object can be called self-similar.
In the diagram at the right, notice that the details at each stage are similar to the details at Stage 1.
1. Follow the iteration process below to produce a fractal.
Stage 1• Draw a square.• Draw an isosceles right triangle on the top side of the square.
Use the side of the square as the hypotenuse of the triangle.• Draw a square on each leg of the right triangle.
Stage 2Repeat the steps in Stage 1, drawing an isosceles triangle and two small squares for each of the small squares from Stage 1.
Stage 3Repeat the steps in Stage 1 for each of the smallest squares in Stage 2.
2. Is the figure produced in Stage 3 self-similar?
Stage 1 Stage 2 Stage 3
ExercisesExercises
ExampleExample
© Glencoe/McGraw-Hill 326 Glencoe Geometry
Nongeometric Iteration An iterative process can be applied to an algebraicexpression or equation. The result is called a recursive formula.
Find the value of x3, where the initial value of x is 2. Repeat theprocess three times and describe the pattern.
Initial value: 2First time: 23 # 8Second time: 83 # 512Third time: 5123 # 134,217,728
The result of each step of the iteration is used for the next step. For this example, the xvalues are greater with each iteration. There is no maximum value, so the values aredescribed as approaching infinity.
For Exercises 1–5, find the value of each expression. Then use that value as thenext x in the expression. Repeat the process three times, and describe yourobservations.
1. $x!, where x initially equals 5
2. !1x!, where x initially equals 2
3. 3x, where x initially equals 1
4. x & 5 where x initially equals 10
5. x2 & 4, where x initially equals 16
6. Harpesh paid $1000 for a savings certificate. It earns interest at an annual rate of 2.8%,and interest is added to the certificate each year. What will the certificate be worth afterfour years?
Study Guide and Intervention (continued)
Fractals and Self-Similarity
NAME ______________________________________________ DATE ____________ PERIOD _____
6-66-6
ExercisesExercises
ExampleExample
Skills PracticeFractals and Self-Similarity
NAME ______________________________________________ DATE ____________ PERIOD _____
6-66-6
© Glencoe/McGraw-Hill 327 Glencoe Geometry
Less
on
6-6
Stages 1 and 2 of a fractal known as the Cantor set are shown. To get Stage 2, thesegment in Stage 1 is trisected, and the interior of the middle segment is removed.(The interior of a segment is the segment with its endpoints removed.) Theprocess is repeated for subsequent stages.
1. Draw stages 3 and 4 of the Cantor set.
2. How many segments are there in Stage 3? Stage 4?
3. What happens to the length of the line segments in each stage?
4. The Cantor set is the set of points after infinitely many iterations. Is the Cantor set self-similar?
Find the value of each expression. Then, use that value as the next x in theexpression. Repeat the process three times, and describe your observations.
5. 2x & 3, where x initially equals 5
6. !2x
!, where x initially equals 1
Find the first three iterates of each expression.
7. x2 & 1, where x initially equals 2 8. !1x!, where x initially equals 8
Stage 3
Stage 4
Stage 1
Stage 2
© Glencoe/McGraw-Hill 328 Glencoe Geometry
An artist is designing a book cover and wants to show a copy of the book cover inthe lower left corner of the cover. After Stages 1 and 2 of the design, he realizesthat the design is developing into a fractal!
1. Draw Stages 3 and 4 of the book cover fractal.
2. After infinitely many iterations, will the result be a self similar fractal?
3. On what part of the book cover should you focus your attention to be sure you can find acopy of the entire figure?
Find the value of each expression. Then, use that value as the next x in theexpression. Repeat the process three times and describe your observations.
4. 2(x % 3), where x initially equals 0 5. !2x
! & 3, where x initially equals 10
Find the first three iterates of each expression.
6. !2x
! % 1, where x initially equals 1 7. 2x2, where x initially equals 2
8. HOUSING The Andrews purchased a house for $96,000. The real estate agent who soldthe house said that comparable houses in the area appreciate at a rate of 4.5% per year.If this pattern continues, what will be the value of the house in three years? Round tothe nearest whole number.
Stage 3
MATHMATH
MATH
Stage 4
MATHMATH
MATHMATH
Stage 1
MATHStage 2
MATHMATH
Practice Fractals and Self-Similarity
NAME ______________________________________________ DATE ____________ PERIOD _____
6-66-6
Reading to Learn MathematicsFractals and Self-Similarity
NAME ______________________________________________ DATE ____________ PERIOD _____
6-66-6
© Glencoe/McGraw-Hill 329 Glencoe Geometry
Less
on
6-6
Pre-Activity How is mathematics found in nature?
Read the introduction to Lesson 6-6 at the top of page 325 in your textbook.
Name two objects from nature other than broccoli in which a small pieceresembles the whole.
Reading the Lesson1. Match each definition from the first column with a term from the second column. (Some
words of phrases in the second column may be used more than once or not at all.)
Phrase Terma. a geometric figure that is created using iteration i. similar b. a pattern in which smaller and smaller details of a shape have ii. iteration
the same geometric characteristics as the original shape iii. fractalc. the result of translating an iterative process into a formula or iv. self-similar
algebraic equation v. recursiond. the process of repeating the same procedure over and over formula
again vi. congruent
2. Refer to the three patterns below.
i.
ii.
iii.
a. Give the special name for each of the fractals you obtain by continuing the patternwithout end.
b. Which of these fractals are self-similar?c. Which of these fractals are strictly self-similar?
Helping You Remember3. A good way to remember a new mathematical term is to relate it to everyday English
words. The word fractal is related to fraction and fragment. Use your dictionary to findat least one definition for each of these words that you think is related to the meaning ofthe word fractal and explain the connection.
© Glencoe/McGraw-Hill 330 Glencoe Geometry
The Möbius StripA Möbius strip is a special surface with only one side. It was discovered byAugust Ferdinand Möbius, a German astronomer and mathematician.
1. To make a Möbius strip, cut a strip of paper about 16 inches long and 1inch wide. Mark the ends with the letters A, B, C, and D as shown below.
Twist the paper once, connecting A to D and B to C. Tape the endstogether on both sides.
2. Use a crayon or pencil to shade one side of the paper. Shade around thestrip until you get back to where you started. What happens?
3. What do you think will happen if you cut the Möbius strip down themiddle? Try it.
4. Make another Möbius strip. Starting a third of the way in from one edge,cut around the strip, staying always the same distance in from the edge.What happens?
5. Start with another long strip of paper. Twist the paper twice and connectthe ends. What happens when you cut down the center of this strip?
6. Start with another long strip of paper. Twist the paper three times andconnect the ends. What happens when you cut down the center of this strip?
A
B
C
D
Enrichment
NAME ______________________________________________ DATE ____________ PERIOD _____
6-66-6
© Glencoe/McGraw-Hill A2 Glencoe Geometry
Stu
dy
Gu
ide
and I
nte
rven
tion
Pro
port
ions
NA
ME
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____
____
____
____
____
____
____
____
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__D
ATE
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PE
RIO
D__
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6-1
6-1
©G
lenc
oe/M
cGra
w-H
ill29
5G
lenc
oe G
eom
etry
Lesson 6-1
Wri
te R
atio
sA
rat
iois
a c
ompa
riso
n of
tw
o qu
anti
ties
.The
rat
io a
to b
,whe
re b
is n
ot
zero
,can
be
wri
tten
as
!a b!or
a:b
.The
rat
io o
f tw
o qu
anti
ties
is s
omet
imes
cal
led
a sc
ale
fact
or.F
or a
sca
le f
acto
r,th
e un
its
for
each
qua
ntit
y ar
e th
e sa
me.
In 2
002,
the
Ch
icag
o C
ubs
bas
ebal
l te
am w
on 6
7 ga
mes
ou
t of
162
.W
rite
a r
atio
for
th
e n
um
ber
of g
ames
won
to
the
tota
l n
um
ber
of g
ames
pla
yed
.To
fin
d th
e ra
tio,
divi
de t
he n
umbe
r of
gam
es w
on b
y th
e to
tal n
umbe
r of
gam
es p
laye
d.T
he
resu
lt is
! 16 67 2!,w
hich
is a
bout
0.4
1.T
he C
hica
go C
ubs
won
abo
ut 4
1% o
f th
eir
gam
es in
200
2.
A d
oll
hou
se t
hat
is
15 i
nch
es t
all
is a
sca
le m
odel
of
a re
al h
ouse
wit
h a
hei
ght
of 2
0 fe
et.W
hat
is
the
rati
o of
th
e h
eigh
t of
th
e d
oll
hou
se t
o th
eh
eigh
t of
th
e re
al h
ouse
?To
sta
rt,c
onve
rt t
he h
eigh
t of
the
rea
l hou
se t
o in
ches
.20
fee
t "
12 in
ches
per
foo
t #
240
inch
esTo
find
the
rat
io o
r sc
ale
fact
or o
f th
e he
ight
s,di
vide
the
hei
ght
of t
he d
oll h
ouse
by
the
heig
ht o
f th
e re
al h
ouse
.The
rat
io is
15
inch
es:2
40 in
ches
or
1:16
.The
hei
ght
of t
he d
oll
hous
e is
! 11 6!th
e he
ight
of
the
real
hou
se.
1.In
the
200
2 M
ajor
Lea
gue
base
ball
seas
on,S
amm
y So
sa h
it 4
9 ho
me
runs
and
was
at
bat
556
tim
es.F
ind
the
rati
o of
hom
e ru
ns t
o th
e nu
mbe
r of
tim
es h
e w
as a
t ba
t.
! 54 59 6!
2.T
here
are
182
gir
ls in
the
sop
hom
ore
clas
s of
305
stu
dent
s.F
ind
the
rati
o of
gir
ls t
o to
tal s
tude
nts.
!1 38 02 5!
3.T
he le
ngth
of
a re
ctan
gle
is 8
inch
es a
nd it
s w
idth
is 5
inch
es.F
ind
the
rati
o of
leng
th
to w
idth
.
!8 5!
4.T
he s
ides
of
a tr
iang
le a
re 3
inch
es,4
inch
es,a
nd 5
inch
es.F
ind
the
scal
e fa
ctor
bet
wee
nth
e lo
nges
t an
d th
e sh
orte
st s
ides
.
!5 3!
5.T
he le
ngth
of
a m
odel
tra
in is
18
inch
es.I
t is
a s
cale
mod
el o
f a
trai
n th
at is
48
feet
long
.F
ind
the
scal
e fa
ctor
.
! 31 2!
Exam
ple1
Exam
ple1
Exam
ple2
Exam
ple2
Exercis
esExercis
es
©G
lenc
oe/M
cGra
w-H
ill29
6G
lenc
oe G
eom
etry
Use
Pro
per
ties
of
Pro
po
rtio
ns
A s
tate
men
t th
at t
wo
rati
os a
re e
qual
is c
alle
d a
pro
por
tion
.In
the
prop
orti
on !a b!
#! dc ! ,
whe
re b
and
dar
e no
t ze
ro,t
he v
alue
s a
and
dar
e th
e ex
trem
esan
d th
e va
lues
ban
d c
are
the
mea
ns.
In a
pro
port
ion,
the
prod
uct
of t
hem
eans
is e
qual
to
the
prod
uct
of t
he e
xtre
mes
,so
ad#
bc.
!a b!#
! dc !
a$
d#
b$
c↑
↑ex
trem
esm
eans
Sol
ve ! 19 6!
"!2 x7 !
.
! 19 6!#
!2 x7 !
9 $
x#
16 $
27C
ross
pro
duct
s
9x#
432
Mul
tiply
.
x#
48D
ivid
e ea
ch s
ide
by 9
.
A r
oom
is
49 c
enti
met
ers
by 2
8 ce
nti
met
ers
on a
sca
le d
raw
ing
of a
hou
se.F
or t
he
actu
al r
oom
,th
e la
rger
dim
ensi
on i
s 14
fee
t.F
ind
th
e sh
orte
rd
imen
sion
of
the
actu
al r
oom
.If
xis
the
roo
m’s
sho
rter
dim
ensi
on,t
hen
!2 48 9!#
! 1x 4!
49x
#39
2C
ross
pro
duct
s
x#
8D
ivid
e ea
ch s
ide
by 4
9.
The
sho
rter
sid
e of
the
roo
m is
8 f
eet.
Sol
ve e
ach
pro
por
tion
.
1.!1 2!
#!2 x8 !
562.
!3 8!#
! 2y 4!9
3.!x x% %
2 22!
#!3 10 0!
8
4.! 18
3 .2!#
!9 y!54
.65.
!2x8%
3!
#!5 4!
3.5
6.!x x
% &1 1
!#
!3 4!#
7
Use
a p
rop
orti
on t
o so
lve
each
pro
blem
.
7.If
3 c
asse
ttes
cos
t $4
4.85
,fin
d th
e co
st o
f on
e ca
sset
te.
$14.
95
8.T
he r
atio
of
the
side
s of
a t
rian
gle
are
8:15
:17.
If t
he p
erim
eter
of
the
tria
ngle
is
480
inch
es,f
ind
the
leng
th o
f ea
ch s
ide
of t
he t
rian
gle.
96 in
.,18
0 in
.,20
4 in
.
9.T
he s
cale
on
a m
ap in
dica
tes
that
one
inch
equ
als
4 m
iles.
If t
wo
tow
ns a
re 3
.5 in
ches
apar
t on
the
map
,wha
t is
the
act
ual d
ista
nce
betw
een
the
tow
ns?
14 m
i
shor
ter
dim
ensi
on!
!!
long
er d
imen
sion
Stu
dy
Gu
ide
and I
nte
rven
tion
(con
tinu
ed)
Pro
port
ions
NA
ME
____
____
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____
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____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-1
6-1
Exam
ple1
Exam
ple1
Exam
ple2
Exam
ple2
Exercis
esExercis
es
Answers (Lesson 6-1)
© Glencoe/McGraw-Hill A3 Glencoe Geometry
An
swer
s
Skil
ls P
ract
ice
Pro
port
ions
NA
ME
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____
____
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____
____
____
__D
ATE
____
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PE
RIO
D__
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6-1
6-1
©G
lenc
oe/M
cGra
w-H
ill29
7G
lenc
oe G
eom
etry
Lesson 6-1
1.FO
OTB
ALL
A t
ight
end
sco
red
6 to
uchd
owns
in 1
4 ga
mes
.Fin
d th
e ra
tio
of t
ouch
dow
nspe
r ga
me.
0.43
:1
2.E
DU
CA
TIO
NIn
a s
ched
ule
of 6
cla
sses
,Mar
ta h
as 2
ele
ctiv
e cl
asse
s.W
hat
is t
he r
atio
of e
lect
ive
to n
on-e
lect
ive
clas
ses
in M
arta
’s s
ched
ule?
1:2
3.B
IOLO
GY
Out
of
274
liste
d sp
ecie
s of
bir
ds in
the
Uni
ted
Stat
es,7
8 sp
ecie
s m
ade
the
enda
nger
ed li
st.F
ind
the
rati
o of
end
ange
red
spec
ies
of b
irds
to
liste
d sp
ecie
s in
the
Uni
ted
Stat
es.
! 13 39 7!
4.A
RTA
n ar
tist
in P
ortl
and,
Ore
gon,
mak
es b
ronz
e sc
ulpt
ures
of
dogs
.The
rat
io o
f th
ehe
ight
of
a sc
ulpt
ure
to t
he a
ctua
l hei
ght
of t
he d
og is
2:3
.If
the
heig
ht o
f th
e sc
ulpt
ure
is 1
4 in
ches
,fin
d th
e he
ight
of
the
dog.
21 in
.
5.SC
HO
OL
The
rat
io o
f m
ale
stud
ents
to
fem
ale
stud
ents
in t
he d
ram
a cl
ub a
t C
ampb
ell
Hig
h Sc
hool
is 3
:4.I
f th
e nu
mbe
r of
mal
e st
uden
ts in
the
clu
b is
18,
wha
t is
the
num
ber
of f
emal
e st
uden
ts?
24
Sol
ve e
ach
pro
por
tion
.
6.!2 5!
#! 4x 0!
167.
! 17 0!#
!2 x1 !30
8.!2 50 !
#!4 6x !
6
9.!5 4x !
#!3 85 !
3.5
10.!
x% 3
1!
#!7 2!
9.5
11.!
1 35 !#
!x& 5
3!
28
Fin
d t
he
mea
sure
s of
th
e si
des
of
each
tri
angl
e.
12.T
he r
atio
of
the
mea
sure
s of
the
sid
es o
f a
tria
ngle
is 3
:5:7
,and
its
peri
met
er is
45
0 ce
ntim
eter
s.90
cm
,150
cm
,210
cm
13.T
he r
atio
of t
he m
easu
res
of t
he s
ides
of a
tri
angl
e is
5:6
:9,a
nd it
s pe
rim
eter
is 2
20 m
eter
s.55
m,6
6 m
,99
m
14.T
he r
atio
of
the
mea
sure
s of
the
sid
es o
f a
tria
ngle
is 4
:6:8
,and
its
peri
met
er is
126
fee
t.28
ft,
42 f
t,56
ft
15.T
he r
atio
of t
he m
easu
res
of t
he s
ides
of a
tri
angl
e is
5:7
:8,a
nd it
s pe
rim
eter
is 4
0 in
ches
.10
in.,
14 in
.,16
in.
©G
lenc
oe/M
cGra
w-H
ill29
8G
lenc
oe G
eom
etry
1.N
UTR
ITIO
NO
ne o
unce
of c
hedd
ar c
hees
e co
ntai
ns 9
gra
ms
of fa
t.Si
x of
the
gra
ms
of fa
tar
e sa
tura
ted
fats
.Fin
d th
e ra
tio
of s
atur
ated
fats
to
tota
l fat
in a
n ou
nce
of c
hees
e.2:
3
2.FA
RM
ING
The
rat
io o
f go
ats
to s
heep
at
a un
iver
sity
res
earc
h fa
rm is
4:7
.The
num
ber
of s
heep
at
the
farm
is 2
8.W
hat
is t
he n
umbe
r of
goa
ts?
16
3.A
RTE
dwar
d H
oppe
r’s o
il on
can
vas
pain
ting
Nig
htha
wks
has
a le
ngth
of
60 in
ches
and
a w
idth
of
30 in
ches
.A p
rint
of
the
orig
inal
has
a le
ngth
of
2.5
inch
es.W
hat
is t
he w
idth
of t
he p
rint
?1.
25 in
.
Sol
ve e
ach
pro
por
tion
.
4.!5 8!
#! 1x 2!
7.5
5.! 1.
x 12!#
!1 5!0.
224
6.! 26 7x !
#!4 3!
6
7.!x
% 32
!#
!8 9!!2 3!
8.!3x
4&5
!#
!& 75 !!5 7!
9.!x
& 42
!#
!x% 2
4!
#10
Fin
d t
he
mea
sure
s of
th
e si
des
of
each
tri
angl
e.
10.T
he r
atio
of
the
mea
sure
s of
the
sid
es o
f a
tria
ngle
is 3
:4:6
,and
its
peri
met
er is
104
fee
t.24
ft,
32 f
t,48
ft
11.T
he r
atio
of t
he m
easu
res
of t
he s
ides
of a
tri
angl
e is
7:9
:12,
and
its
peri
met
er is
84
inch
es.
21 in
.,27
in.,
36 in
.
12.T
he r
atio
of
the
mea
sure
s of
the
sid
es o
f a
tria
ngle
is 6
:7:9
,and
its
peri
met
er is
77
cen
tim
eter
s.21
cm
,24.
5 cm
,31.
5 cm
Fin
d t
he
mea
sure
s of
th
e an
gles
in
eac
h t
rian
gle.
13.T
he r
atio
of
the
mea
sure
s of
the
ang
les
is 4
:5:6
.48
,60,
72
14.T
he r
atio
of
the
mea
sure
s of
the
ang
les
is 5
:7:8
.45
,63,
72
15.B
RID
GES
The
spa
n of
the
Ben
jam
in F
rank
lin s
uspe
nsio
n br
idge
in P
hila
delp
hia,
Penn
sylv
ania
,is
1750
fee
t.A
mod
el o
f th
e br
idge
has
a s
pan
of 4
2 in
ches
.Wha
t is
the
rati
o of
the
spa
n of
the
mod
el t
o th
e sp
an o
f th
e ac
tual
Ben
jam
in F
rank
lin B
ridg
e?! 51 00!
Pra
ctic
e (A
vera
ge)
Pro
port
ions
NA
ME
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____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-1
6-1
Answers (Lesson 6-1)
© Glencoe/McGraw-Hill A4 Glencoe Geometry
Rea
din
g t
o L
earn
Math
emati
csP
ropo
rtio
ns
NA
ME
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____
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____
____
____
____
__D
ATE
____
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PE
RIO
D__
___
6-1
6-1
©G
lenc
oe/M
cGra
w-H
ill29
9G
lenc
oe G
eom
etry
Lesson 6-1
Pre-
Act
ivit
yH
ow d
o ar
tist
s u
se r
atio
s?
Rea
d th
e in
trod
ucti
on t
o L
esso
n 6-
1 at
the
top
of
page
282
in y
our
text
book
.
Est
imat
e th
e ra
tio
of le
ngth
to
wid
th f
or t
he b
ackg
roun
d re
ctan
gles
inT
iffa
ny’s
Cle
mat
is S
kylig
ht.
Sam
ple
answ
er:a
bout
5 t
o 2
Rea
din
g t
he
Less
on
1.M
atch
eac
h de
scri
ptio
n in
the
fir
st c
olum
n w
ith
a w
ord
or p
hras
e fr
om t
he s
econ
dco
lum
n.
a.T
he r
atio
of
two
corr
espo
ndin
g qu
anti
ties
ivi.
prop
orti
on
b.r
and
uin
the
equ
atio
n !r s!
#! ut !
vii
.cro
ss p
rodu
cts
c.a
com
pari
son
of t
wo
quan
titi
esvi
iii.
mea
ns
d.ru
and
stin
the
equ
atio
n !r s!
#! ut !
iiiv
.sc
ale
fact
or
e.an
equ
atio
n st
atin
g th
at t
wo
rati
os a
re e
qual
iv.
extr
emes
f.s
and
tin
the
equ
atio
n !r s!
#! ut !
iiivi
.rat
io
2.If
m,n
,p,a
nd q
are
nonz
ero
num
bers
suc
h th
at !m n!
#!p q! ,
whi
ch o
f th
e fo
llow
ing
stat
emen
ts c
ould
be
fals
e?B
,C,E
A.n
p#
mq
B.!
np !#
! mq !
C.m
p#
nqD
.qm
#pn
E.!
m n!#
! pq !F.
! pq !#
! mn !
G.m
:p#
n:q
H.m
:n#
p:q
3.W
rite
tw
o pr
opor
tion
s th
at m
atch
eac
h de
scri
ptio
n.
a.M
eans
are
5 a
nd 8
;ext
rem
es a
re 4
and
10.
any
two
of !4 5!
"! 18 0!
,!4 8!
"! 15 0!
,!1 50 !
"!8 4! ,
!1 80 !"
!5 4!
b.M
eans
are
5 a
nd 4
;ext
rem
es a
re p
osit
ive
inte
gers
tha
t ar
e di
ffer
ent
from
mea
ns.
any
two
of !2 5!
"! 14 0!
,!2 4!
"! 15 0!
,!1 4!
"! 25 0!
,!1 5!
"! 24 0!
,!1 50 !
"!4 2! ,
!1 40 !"
!5 2! ,!2 40 !
"!5 1! ,
or !2 50 !
"!4 1!
Hel
pin
g Y
ou
Rem
emb
er
4.So
met
imes
it is
eas
ier
to r
emem
ber
a m
athe
mat
ical
idea
if y
ou p
ut it
into
wor
ds w
itho
utus
ing
any
mat
hem
atic
al s
ymbo
ls.H
ow c
an y
ou u
se t
his
appr
oach
to
rem
embe
r th
eco
ncep
t of
equ
alit
y of
cro
ss p
rodu
cts?
Sam
ple
answ
er:T
he p
rodu
ct o
f th
e m
eans
equa
ls t
he p
rodu
ct o
f th
e ex
trem
es.
©G
lenc
oe/M
cGra
w-H
ill30
0G
lenc
oe G
eom
etry
Gol
den
Rec
tang
les
Use
a s
trai
ghte
dge
,com
pas
s,an
d t
he
inst
ruct
ion
s be
low
to c
onst
ruct
a g
old
en r
ecta
ngl
e.
1.C
onst
ruct
squ
are
AB
CD
wit
h si
des
of 2
cm
.
2.C
onst
ruct
the
mid
poin
t of
A !B!
.Cal
l the
mid
poin
t M
.
3.D
raw
AB
! "# .
Set
your
com
pass
at
an o
peni
ng e
qual
to
MC
.U
se M
as t
he c
ente
r to
dra
w a
n ar
c th
at in
ters
ects
AB
! "# .
Cal
l th
e po
int
of in
ters
ecti
on P
.
4.C
onst
ruct
a li
ne t
hrou
gh P
that
is p
erpe
ndic
ular
to
AB
! "# .
5.D
raw
DC
! "#
so t
hat
it in
ters
ects
the
per
pend
icul
ar li
ne in
ste
p 4.
Cal
l the
inte
rsec
tion
poi
nt Q
.AP
QD
is a
gol
den
rec
tan
gle
beca
use
the
rati
o of
its
leng
th t
o it
s w
idth
is 1
.618
.Che
ck t
his
conc
lusi
on b
y fi
ndin
g th
e va
lue
of !Q A
PP !.R
ecta
ngle
s w
hose
sid
es
have
thi
s ra
tio
are,
it is
sai
d,th
e m
ost
plea
sing
to
the
hum
an e
ye.
A f
igu
re c
onsi
stin
g of
sim
ilar
gol
den
rec
tan
gles
is
show
n b
elow
.Use
a c
omp
ass
and
th
e in
stru
ctio
ns
belo
w t
o d
raw
qu
arte
r-ci
rcle
arc
s th
at f
orm
a s
pir
al l
ike
that
fou
nd
in
th
e sh
ell
of a
ch
ambe
red
nau
tilu
s.
6.U
sing
Aas
a c
ente
r,dr
aw
an a
rc t
hat
pass
es t
hrou
gh
Ban
d C
.
7.U
sing
Das
a c
ente
r,dr
aw
an a
rc t
hat
pass
es t
hrou
gh
Can
d E
.
8.U
sing
Fas
a c
ente
r,dr
aw
an a
rc t
hat
pass
es t
hrou
gh
Ean
d G
.
9.U
sing
Has
a c
ente
r,dr
aw
an a
rc t
hat
pass
es t
hrou
gh
Gan
d J.
10.U
sing
Kas
a c
ente
r,dr
aw
an a
rc t
hat
pass
es t
hrou
gh
Jan
d L
.
11.U
sing
Mas
a c
ente
r,dr
aw
an a
rc t
hat
pass
es t
hrou
gh
Lan
d N
.
MN H
LF
D JK
BAC
G
E
AM
BP
DC
Q
Che
ck s
tude
nts’
cons
truc
tion
mar
ks.T
he f
inal
figur
e sh
ould
look
like
the
one
belo
w.
En
rich
men
t
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-1
6-1
Answers (Lesson 6-1)
© Glencoe/McGraw-Hill A5 Glencoe Geometry
An
swer
s
Stu
dy
Gu
ide
and I
nte
rven
tion
Sim
ilar
Poly
gons
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-2
6-2
©G
lenc
oe/M
cGra
w-H
ill30
1G
lenc
oe G
eom
etry
Lesson 6-2
Iden
tify
Sim
ilar
Fig
ure
s
Det
erm
ine
wh
eth
er t
he
tria
ngl
es
are
sim
ilar
.T
wo
poly
gons
are
sim
ilar
if a
nd o
nly
if t
heir
cor
resp
ondi
ng
angl
es a
re c
ongr
uent
and
the
ir c
orre
spon
ding
sid
es a
re
prop
orti
onal
.
!C
"!
Zbe
caus
e th
ey a
re r
ight
ang
les,
and
!B
"!
X.
By
the
Thi
rd A
ngle
The
orem
,!A
"!
Y.
For
the
side
s,!B X
C Z!#
!2 20 3!,!
B XA Y!
##
!2 20 3!,a
nd !A Y
C Z!#
!2 20 3!.
The
sid
e le
ngth
s ar
e pr
opor
tion
al.S
o "
BC
A#
"X
ZY
.
Is p
olyg
on W
XY
Z!
pol
ygon
PQ
RS
?
For
the
side
s,!W P
QX !#
!1 82 !#
!3 2! ,! QX
Y R!#
!1 18 2!#
!3 2! ,! RY
Z S!#
!1 15 0!#
!3 2! ,
and
!Z SW P!#
!9 6!#
!3 2! .So
cor
resp
ondi
ng s
ides
are
pro
port
iona
l.
Als
o,!
W"
!P
,!X
"!
Q,!
Y"
!R
,and
!Z
"!
S,s
o co
rres
pond
ing
angl
es a
re c
ongr
uent
.We
can
conc
lude
tha
t po
lygo
n W
XY
Z#
poly
gon
PQ
RS
.
Det
erm
ine
wh
eth
er e
ach
pai
r of
fig
ure
s is
sim
ilar
.If
they
are
sim
ilar
,giv
e th
era
tio
of c
orre
spon
din
g si
des
.
1.2.
yes;
!5 8!no
3.4.
yes;
!1 2!ye
s;!5 4!
10y
8y
37$
37$
116$
27$
5x
4x15
z12
z
2211
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late
ral t
riang
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15
9
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8
12
QP S
R
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2023
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CA
XZ
BY
Exercis
esExercis
es
Exam
ple1
Exam
ple1
Exam
ple2
Exam
ple2
©G
lenc
oe/M
cGra
w-H
ill30
2G
lenc
oe G
eom
etry
Scal
e Fa
cto
rsW
hen
two
poly
gons
are
sim
ilar,
the
rati
o of
the
leng
ths
of c
orre
spon
ding
sid
es is
cal
led
the
scal
e fa
ctor
.At
the
righ
t,"
AB
C#
"X
YZ
.The
sca
le
fact
or o
f "A
BC
to "
XY
Zis
2 a
nd t
he s
cale
fac
tor
of
"X
YZ
to "
AB
Cis
!1 2! .3
cm
6 cm
8 cm
10 c
m5
cm4
cm ZY
XCA
B
Stu
dy
Gu
ide
and I
nte
rven
tion
(con
tinu
ed)
Sim
ilar
Poly
gons
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-2
6-2
Th
e tw
o p
olyg
ons
are
sim
ilar
.Fin
d x
and
y.
Use
the
con
grue
nt a
ngle
s to
wri
te t
heco
rres
pond
ing
vert
ices
in o
rder
."
RS
T#
"M
NP
Wri
te p
ropo
rtio
ns t
o fi
nd x
and
y.
!3 12 6!#
! 1x 3!!3 y8 !
#!3 12 6!
16x
#32
(13)
32y
#38
(16)
x#
26y
#19
x
y38
3216
13T
S
RP
N
M
!A
BC
!!
CD
E.F
ind
th
e sc
ale
fact
or a
nd
fin
d t
he
len
gth
s of
C "D"
and
D"E"
.
AC
#3
&0
#3
and
CE
#9
&3
#6.
The
scal
e fa
ctor
of "
CD
Eto
"A
BC
is 6
:3 o
r 2:
1.U
sing
the
Dis
tanc
e Fo
rmul
a,A
B#
$1
%9
!#
$10!
and
BC
#$
4 %
9!
#$
13!.T
he le
ngth
s of
the
side
s of
"C
DE
are
twic
e th
ose
of "
AB
C,
so D
C#
2(B
A)
or 2
$10!
and
DE
#2(
BC
) or
2$
13!.
x
y
A( 0
, 0)
B( 1
, 3) C( 3
, 0)
E( 9
, 0)
D
Exam
ple1
Exam
ple1
Exam
ple2
Exam
ple2
Exercis
esExercis
es
Eac
h p
air
of p
olyg
ons
is s
imil
ar.F
ind
xan
d y
.
1.2.
x"
6;y
"15
x"
2.25
;y"
5
3.4.
x"
27;y
"15
x"
24;y
"27
5.In
Exa
mpl
e 2
abov
e,po
int
Dha
s co
ordi
nate
s (5
,6).
Use
the
Dis
tanc
e Fo
rmul
a to
ver
ify
the
leng
ths
of C !
D!an
d D!
E!.
CD
"2#
10",D
E"
2#13"
40
36x
30
18y
12
y %
1
18
24
x18
10y
4.5
x2.
5 5
9
12y8 10
x
Answers (Lesson 6-2)
© Glencoe/McGraw-Hill A6 Glencoe Geometry
Skil
ls P
ract
ice
Sim
ilar
Poly
gons
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-2
6-2
©G
lenc
oe/M
cGra
w-H
ill30
3G
lenc
oe G
eom
etry
Lesson 6-2
Det
erm
ine
wh
eth
er e
ach
pai
r of
fig
ure
s is
sim
ilar
.Ju
stif
y yo
ur
answ
er.
1.2.
!A
BC
!!
DE
F;"
A$
"D
,rh
ombu
s P
QR
S!
rhom
bus
WX
YZ;
"C
$"
F,an
d "
B$
"E
"P
$"
W,"
Q$
"X
,"R
$"
Y,
beca
use
if tw
o an
gles
of
one
"S
$"
Z;tr
iang
le a
re c
ongr
uent
to
two
! WPQ X!
"!Q X
YR !"
!R YS Z!
"! ZS WP !
"! 73 .5!
"0.
4an
gles
of
a se
cond
tri
angl
e,th
en
the
thir
d an
gles
are
con
grue
nt;
!A DB E!
"!B EC F!
"!C FDA !
"!3 2! .
Eac
h p
air
of p
olyg
ons
is s
imil
ar.W
rite
a s
imil
arit
y st
atem
ent,
and
fin
d x
,th
em
easu
re(s
) of
in
dic
ated
sid
e(s)
,an
d t
he
scal
e fa
ctor
.
3.G !
H!4.
S!T!an
d S!U!
AB
CD
!E
FGH
;!
WX
Y!
!S
TU(o
r !
SU
T)
6!1 2! ;
6!1 2! ;
27;
12;1
2;!1 3!
5.W!
T!6.
T!S!
and
S!P!
PQ
RS
!U
VW
T;
!LM
N!
!TS
P;
5;6;
!3 2!13
;12;
15;!
2 3!
10
8
x %
2
x #
1
SP
MN
L
T
9
10 3
x %
1
5
P
S
RU
V
WT
Q
x %
5
x %
5
9
3
44
S
W
XY
T U2614
1213
BC
DA
1376
x G
EH
F
7.5
7.5
7.5
7.5
ZY
XW
3
3
33
SR
QP
10.5
69
59$
35$
AC
B
7
46
59$
35$
DF
E
©G
lenc
oe/M
cGra
w-H
ill30
4G
lenc
oe G
eom
etry
Det
erm
ine
wh
eth
er e
ach
pai
r of
fig
ure
s is
sim
ilar
.Ju
stif
y yo
ur
answ
er.
1.2.
JKLM
!Q
RS
P;
!A
BC
!!
UV
T;"
A$
"U
,"
J$
"Q
,"K
$"
R,
"B
$"
V,a
nd "
C$
"T
by t
he
"L
$"
S,"
M$
"P
,and
Th
ird
Ang
le T
heor
em a
nd
! QJKR!
"! RK
SL !"
!L SM P!"
! PM QJ !"
!5 3!or
1.6
7!A U
B V!"
!B VC T!"
!C TUA !"
!2 3! .
Eac
h p
air
of p
olyg
ons
is s
imil
ar.W
rite
a s
imil
arit
y st
atem
ent,
and
fin
d x
,th
em
easu
re(s
) of
in
dic
ated
sid
e(s)
,an
d t
he
scal
e fa
ctor
.
3.L !M!
and
M!N!
4.D!
E!an
d D!
F!
AB
CD
!LM
NP
;!
AB
C!
!D
EF;
!3 2! ;10
!1 2! ;7!
1 2! ;!4 3!
7;4;
8;!3 2!
5.C
OO
RD
INA
TE G
EOM
ETRY
Tri
angl
e A
BC
has
vert
ices
A(0
,0),
B(&
4,0)
,and
C(&
2,4)
.T
he c
oord
inat
es o
f ea
ch v
erte
x ar
e m
ulti
plie
d by
3 t
o cr
eate
"A
EF
.Sho
w t
hat
"A
EF
issi
mila
r to
"A
BC
.
AB
"4,
BC
"C
A"
2#5"
and
AE
"12
,EF
"FA
"6#
5".!A A
B E!"
!B EC F!"
!C FAA !"
!1 3! ;"
A$
"A
and
sinc
e B"
C"|| E"
F","
B$
"E
and
"C
$"
F.S
ince
the
cor
resp
ondi
ng a
ngle
s ar
e co
ngru
ent
and
the
corr
espo
ndin
g si
des
are
prop
ortio
nal,
!A
BC
!!
AE
F.
6.IN
TER
IOR
DES
IGN
Gra
ham
use
d th
e sc
ale
draw
ing
of h
is li
ving
ro
om t
o de
cide
whe
re t
o pl
ace
furn
itur
e.F
ind
the
dim
ensi
ons
of t
heliv
ing
room
if t
he s
cale
in t
he d
raw
ing
is 1
inch
#4.
5 fe
et.
18 f
t by
11
ft 3
in.
4 in
.
21 – 2 in.
612
40$
40$
x %
1
x #
3A
F
E
D
BC
14
10
x %
6
x %
9
CN
MD
AB
LP
2412
1416
2118
VU
AC
BT
2512
9
14.4
1524
20
15
JM
QRS
PK
LPra
ctic
e (A
vera
ge)
Sim
ilar
Poly
gons
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-2
6-2
Answers (Lesson 6-2)
© Glencoe/McGraw-Hill A7 Glencoe Geometry
An
swer
s
Rea
din
g t
o L
earn
Math
emati
csS
imila
r Po
lygo
ns
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-2
6-2
©G
lenc
oe/M
cGra
w-H
ill30
5G
lenc
oe G
eom
etry
Lesson 6-2
Pre-
Act
ivit
yH
ow d
o ar
tist
s u
se g
eom
etri
c p
atte
rns?
Rea
d th
e in
trod
ucti
on t
o L
esso
n 6-
2 at
the
top
of
page
289
in y
our
text
book
.•
Des
crib
e th
e fi
gure
s th
at h
ave
sim
ilar
shap
es. S
ampl
e an
swer
:Li
ght
and
dark
fig
ures
are
arr
ange
d in
alte
rnat
ing
patt
erns
.Fi
gure
s th
at h
ave
thei
r fe
et p
oint
ing
tow
ard
the
cent
er o
f th
eci
rcle
hav
e th
e sa
me
shap
e bu
t di
ffer
ent
size
s.•
Wha
t ha
ppen
s to
the
fig
ures
as
your
eye
s m
ove
from
the
cen
ter
to t
heou
ter
edge
?S
ampl
e an
swer
:The
fig
ures
bec
ome
smal
ler.
Rea
din
g t
he
Less
on
1.C
ompl
ete
each
sen
tenc
e.a.
Tw
o po
lygo
ns t
hat
have
exa
ctly
the
sam
e sh
ape,
but
not
nece
ssar
ily t
he s
ame
size
,ar
e .
b.T
wo
poly
gons
are
con
grue
nt if
the
y ha
ve e
xact
ly t
he s
ame
shap
e an
d th
e sa
me
.c.
Tw
o po
lygo
ns a
re s
imila
r if
the
ir c
orre
spon
ding
ang
les
are
and
thei
r co
rres
pond
ing
side
s ar
e .
d.T
wo
poly
gons
are
con
grue
nt if
the
ir c
orre
spon
ding
ang
les
are
and
thei
r co
rres
pond
ing
side
s ar
e .
e.T
he r
atio
of
the
leng
ths
of c
orre
spon
ding
sid
es o
f tw
o si
mila
r fi
gure
s is
cal
led
the
.f.
Mul
tipl
ying
the
coo
rdin
ates
of
all p
oint
s of
a f
igur
e in
the
coo
rdin
ate
plan
e by
a s
cale
fa
ctor
to
get
a si
mila
r fi
gure
is c
alle
d a
.g.
If t
wo
poly
gons
are
sim
ilar
wit
h a
scal
e fa
ctor
of 1
,the
n th
e po
lygo
ns a
re
.
2.D
eter
min
e w
heth
er e
ach
stat
emen
t is
alw
ays,
som
etim
es,o
r ne
ver
true
.a.
Tw
o si
mila
r tr
iang
les
are
cong
ruen
t.so
met
imes
b.T
wo
equi
late
ral t
rian
gles
are
con
grue
nt.
som
etim
esc.
An
equi
late
ral t
rian
gle
is s
imila
r to
a s
cale
ne t
rian
gle.
neve
rd.
Tw
o re
ctan
gles
are
sim
ilar.
som
etim
ese.
Tw
o is
osce
les
righ
t tr
iang
les
are
cong
ruen
t.so
met
imes
f.T
wo
isos
cele
s ri
ght
tria
ngle
s ar
e si
mila
r.al
way
sg.
A s
quar
e is
sim
ilar
to a
n eq
uila
tera
l tri
angl
e.ne
ver
h.
Tw
o ac
ute
tria
ngle
s ar
e si
mila
r.so
met
imes
i.T
wo
rect
angl
es in
whi
ch t
he le
ngth
is t
wic
e th
e w
idth
are
sim
ilar.
alw
ays
j.T
wo
cong
ruen
t po
lygo
ns a
re s
imila
r.al
way
s
Hel
pin
g Y
ou
Rem
emb
er3.
A g
ood
way
to
rem
embe
r a
new
mat
hem
atic
al v
ocab
ular
y te
rm is
to
rela
te it
to
wor
dsus
ed in
eve
ryda
y lif
e.T
he w
ord
scal
eha
s m
any
mea
ning
s in
Eng
lish.
Giv
e th
ree
phra
ses
that
incl
ude
the
wor
d sc
ale
in a
way
tha
t is
rel
ated
to
prop
orti
ons.
Sam
ple
answ
er:
scal
e dr
awin
g,sc
ale
mod
el,s
cale
of
mile
s (o
n a
map
)
cong
ruen
t
dila
tion
scal
e fa
ctor
cong
ruen
tco
ngru
ent
prop
ortio
nal
cong
ruen
tsi
zesim
ilar
©G
lenc
oe/M
cGra
w-H
ill30
6G
lenc
oe G
eom
etry
Con
stru
ctin
g S
imila
r Po
lygo
nsH
ere
are
four
ste
ps f
or c
onst
ruct
ing
a po
lygo
n th
at is
sim
ilar
to a
nd w
ith
side
s tw
ice
as lo
ng a
s th
ose
of a
n ex
isti
ng p
olyg
on.
Ste
p 1
Cho
ose
any
poin
t ei
ther
insi
de o
r ou
tsid
e th
e po
lygo
n an
d la
bel i
t O
.S
tep
2D
raw
ray
s fr
om O
thro
ugh
each
ver
tex
of t
he p
olyg
on.
Ste
p 3
For
vert
ex V
,set
the
com
pass
to
leng
th O
V.T
hen
loca
te a
new
poi
ntV
'on
ray
OV
such
tha
t V
V'
#O
V.T
hus,
OV
'#
2(O
V).
Ste
p 4
Rep
eat
Step
3 f
or e
ach
vert
ex.C
onne
ct p
oint
s V
',W
',X
'an
d Y
'to
form
the
new
pol
ygon
.
Tw
o co
nstr
ucti
ons
of p
olyg
ons
sim
ilar
to a
nd w
ith
side
s tw
ice
thos
e of
VW
XY
are
show
n be
low
.Not
ice
that
the
pla
cem
ent
of p
oint
Odo
es n
ot a
ffec
t th
e si
zeor
sha
pe o
f V'W
'X'Y
',on
ly it
s lo
cati
on.
Tra
ce e
ach
pol
ygon
.Th
en c
onst
ruct
a s
imil
ar p
olyg
on w
ith
sid
es t
wic
e as
lon
g as
thos
e of
th
e gi
ven
pol
ygon
.S
ee s
tude
nts’
cons
truc
tions
.
1.2.
DE
F
GC
A
B
VW
YX
VW
YX
V'
W'
X'
Y'
O
VW
YX
V'
W'
X'
Y'
O
En
rich
men
t
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-2
6-2
3.E
xpla
in h
ow t
o co
nstr
uct
a si
mila
rpo
lygo
n w
ith
side
s th
ree
tim
es t
he le
ngth
of t
hose
of
poly
gon
HIJ
KL
.The
n do
the
cons
truc
tion
.S
ee s
tude
nts’
wor
k.
4.E
xpla
in h
ow t
o co
nstr
uct
a si
mila
r po
lygo
n 1!
1 2!ti
mes
the
leng
th o
f th
ose
of
poly
gon
MN
PQ
RS
.The
n do
the
cons
truc
tion
.S
ee s
tude
nts’
wor
k.M
S
R
N
Q
P
HI
LK
J
Answers (Lesson 6-2)
© Glencoe/McGraw-Hill A8 Glencoe Geometry
Stu
dy
Gu
ide
and I
nte
rven
tion
Sim
ilar T
rian
gles
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-3
6-3
©G
lenc
oe/M
cGra
w-H
ill30
7G
lenc
oe G
eom
etry
Lesson 6-3
Iden
tify
Sim
ilar
Tria
ng
les
Her
e ar
e th
ree
way
s to
sho
w t
hat
two
tria
ngle
s ar
e si
mila
r.
AA
Sim
ilari
tyTw
o an
gles
of o
ne tr
iang
le a
re c
ongr
uent
to tw
o an
gles
of a
noth
er tr
iang
le.
SS
S S
imila
rity
The
mea
sure
s of
the
corr
espo
ndin
g si
des
of tw
o tr
iang
les
are
prop
ortio
nal.
SA
S S
imila
rity
The
mea
sure
s of
two
side
s of
one
tria
ngle
are
pro
port
iona
l to
the
mea
sure
s of
tw
o co
rres
pond
ing
side
s of
ano
ther
tria
ngle
, and
the
incl
uded
ang
les
are
cong
ruen
t.
Det
erm
ine
wh
eth
er t
he
tria
ngl
es a
re s
imil
ar.
! DAC F!
#!6 9!
#!2 3!
!B EC F!
#! 18 2!
#!2 3!
! DAB E!
#!1 10 5!
#!2 3!
"A
BC
#"
DE
Fby
SSS
Sim
ilari
ty.
15
129
DE
F
10
86
AB
C
Det
erm
ine
wh
eth
er t
he
tria
ngl
es a
re s
imil
ar.
!3 4!#
!6 8! ,so
!M QRN !
#!N R
SP !.
m!
N#
m!
R,s
o !
N"
!R
."
NM
P#
"R
QS
by S
AS
Sim
ilari
ty.
8
4 70$Q
RS
6
3 70$
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NP
Exam
ple1
Exam
ple1
Exam
ple2
Exam
ple2
Exercis
esExercis
es
Det
erm
ine
wh
eth
er e
ach
pai
r of
tri
angl
es i
s si
mil
ar.J
ust
ify
you
r an
swer
.
1.2.
yes;
AA
Sim
ilari
tyno
;!3 26 4!
&!2 10 8!
3.4.
yes;
AA
Sim
ilari
tyye
s;S
AS
Sim
ilari
ty
5.6.
yes;
SA
S S
imila
rity
yes;
SS
S S
imila
rity
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©G
lenc
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cGra
w-H
ill30
8G
lenc
oe G
eom
etry
Use
Sim
ilar
Tria
ng
les
Sim
ilar
tria
ngle
s ca
n be
use
d to
fin
d m
easu
rem
ents
.
Stu
dy
Gu
ide
and I
nte
rven
tion
(con
tinu
ed)
Sim
ilar T
rian
gles
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-3
6-3
!A
BC
!!
DE
F.
Fin
d x
and
y.
! DAC F!
#!B E
C F!! DA
B E!#
!B EC F!
#!1 98 !
! 1y 8!#
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18x
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4x
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18$
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x
18$
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B CA
1818
9y
x
E FD
A p
erso
n 6
fee
t ta
ll c
asts
a 1.
5-fo
ot-l
ong
shad
ow a
t th
e sa
me
tim
eth
at a
fla
gpol
e ca
sts
a 7-
foot
-lon
gsh
adow
.How
tal
l is
th
e fl
agp
ole?
The
sun
’s r
ays
form
sim
ilar
tria
ngle
s.U
sing
xfo
r th
e he
ight
of
the
pole
,!6 x!
#!1 7.5 !
,so
1.5
x#
42 a
nd x
#28
.T
he f
lagp
ole
is 2
8 fe
et t
all.
7 ft
6 ft
?
1.5
ft
Exam
ple1
Exam
ple1
Exam
ple2
Exam
ple2
Exercis
esExercis
es
Eac
h p
air
of t
rian
gles
is
sim
ilar
.Fin
d x
and
y.
1.2.
x"
26;y
"17
.5x
"24
;y"
30
3.4.
x"
12;y
"24
#2"
x"
19.3
;y"
46
5.6.
x"
18;y
"10
.8x
"10
!2 3! ;y
"16
!1 2!
7.T
he h
eigh
ts o
f tw
o ve
rtic
al p
osts
are
2 m
eter
s an
d 0.
45 m
eter
.Whe
n th
e sh
orte
r po
stca
sts
a sh
adow
tha
t is
0.8
5 m
eter
long
,wha
t is
the
leng
th o
f th
e lo
nger
pos
t’s s
hado
w
to t
he n
eare
st h
undr
edth
?3.
78 m
y
x32
10
2230
yx
9 87.2
16
yx
6038
.623
3024
36$
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x
3636
20 13
26y
x %
235
13
1020
y
x
Answers (Lesson 6-3)
© Glencoe/McGraw-Hill A9 Glencoe Geometry
An
swer
s
Skil
ls P
ract
ice
Sim
ilar T
rian
gles
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-3
6-3
©G
lenc
oe/M
cGra
w-H
ill30
9G
lenc
oe G
eom
etry
Lesson 6-3
Det
erm
ine
wh
eth
er e
ach
pai
r of
tri
angl
es i
s si
mil
ar.J
ust
ify
you
r an
swer
.
1.2.
No;
the
side
s ar
e no
t pr
opor
tiona
l.ye
s;!
AB
C!
!P
QR
(or
!Q
PR
);S
SS
Sim
ilari
ty
3.4.
yes;
!S
TU!
!JP
M;
yes;
!S
KM
!!
RTQ
;S
AS
Sim
ilari
tyA
A S
imila
rity
ALG
EBR
AId
enti
fy t
he
sim
ilar
tri
angl
es,a
nd
fin
d x
and
th
e m
easu
res
of t
he
ind
icat
ed s
ides
.
5.A !
C!an
d E!
D!6.
J!L!an
d L!M!
!A
BC
!!
DB
E;1
5;16
;20
!JK
L!
!M
NL
;10;
28;7
7.E!
H!an
d E!
F!8.
U!T!
and
R!T!
!D
EF
!!
GE
H;4
;9;1
8!
RS
T!
!U
VT;
12;6
;14
6
14
S
U
V
RT
x #
4 x #
612
9
6
9
D
E
FH G
x %
5
16
4MN
L
J
K
x %
18
x #
3
1512
D
EC
BAx
% 1
x %
5
30$
60$
RQM
S
K
T
2170
$
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MJ
P
1470
$10
U
S
T
12
128
9
96
CP
QR
A
B
2014
1312
219 S
WX
Y
R
T
©G
lenc
oe/M
cGra
w-H
ill31
0G
lenc
oe G
eom
etry
Det
erm
ine
wh
eth
er e
ach
pai
r of
tri
angl
es i
s si
mil
ar.J
ust
ify
you
r an
swer
.
1.2.
yes;
!JA
K!
!W
SY
;N
o;th
e si
des
are
not
prop
ortio
nal.
SA
S S
imila
rity
ALG
EBR
AId
enti
fy t
he
sim
ilar
tri
angl
es,a
nd
fin
d x
and
th
e m
easu
res
of t
he
ind
icat
ed s
ides
.
3.L !M!
and
Q!P!
4.N!
L!an
d M!
L!
!LM
N!
!P
QN
;9;1
2;8
!JL
N!
!K
LM;2
;21;
14
Use
th
e gi
ven
in
form
atio
n t
o fi
nd
eac
h m
easu
re.
5.If
T!S!
|| Q!R!
,TS
#6,
PS
#x
%7,
6.If
E!F!
|| H!I!,
EF
#3,
EG
#x
%1,
QR
#8,
and
SR
#x
&1,
HI
#4,
and
HG
#x
%3,
find
PS
and
PR
.fi
nd E
Gan
d H
G.
PS
"12
;PR
"16
EG
"6;
HG
"8
IND
IREC
T M
EASU
REM
ENT
For
Exe
rcis
es 7
an
d 8
,use
th
e fo
llow
ing
info
rmat
ion
.A
ligh
thou
se c
asts
a 1
28-f
oot
shad
ow.A
nea
rby
lam
ppos
t th
at m
easu
res
5 fe
et 3
inch
es c
asts
an 8
-foo
t sh
adow
.
7.W
rite
a p
ropo
rtio
n th
at c
an b
e us
ed t
o de
term
ine
the
heig
ht o
f th
e lig
htho
use.
Sam
ple
answ
er:I
f x
"he
ight
of
light
hous
e,! 5.
x 25!"
!12 88 !.
8.W
hat
is t
he h
eigh
t of
the
ligh
thou
se?
84 f
t
F
GE
H
I
SR
P
QT
8N
JL
K
Mx
% 5
6x %
2
24
12
18N
P
QL
M
x %
3x
# 1
18
1612
.516
14
11
M
LN
SR
T42
$
42$
24
1812
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AK
YS
W
Pra
ctic
e (A
vera
ge)
Sim
ilar T
rian
gles
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-3
6-3
Answers (Lesson 6-3)
© Glencoe/McGraw-Hill A10 Glencoe Geometry
Rea
din
g t
o L
earn
Math
emati
csS
imila
r Tri
angl
es
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-3
6-3
©G
lenc
oe/M
cGra
w-H
ill31
1G
lenc
oe G
eom
etry
Lesson 6-3
Pre-
Act
ivit
yH
ow d
o en
gin
eers
use
geo
met
ry?
Rea
d th
e in
trod
ucti
on t
o L
esso
n 6-
3 at
the
top
of
page
298
in y
our
text
book
.•
Wha
t do
es it
mea
n to
say
tha
t tr
iang
ular
sha
pes
resu
lt in
rig
idco
nstr
ucti
on?
Sam
ple
answ
er:A
tri
angu
lar
stru
ctur
e w
ill n
otch
ange
its
shap
e or
siz
e if
you
push
on
its s
ides
with
out
brea
king
or
bend
ing
them
.•
Wha
t w
ould
hap
pen
if t
he s
hape
s us
ed in
the
con
stru
ctio
n w
ere
quad
rila
tera
ls?
Sam
ple
answ
er:T
he s
truc
ture
mig
ht c
olla
pse,
beca
use
quad
rila
tera
ls a
re n
ot r
igid
.
Rea
din
g t
he
Less
on
1.St
ate
whe
ther
eac
h co
ndit
ion
guar
ante
es t
hat
two
tria
ngle
s ar
e co
ngru
ent
or s
imil
ar.
If t
he c
ondi
tion
gua
rant
ees
that
the
tri
angl
es a
re b
oth
sim
ilar
and
cong
ruen
t,w
rite
cong
ruen
t.If
the
re is
not
eno
ugh
info
rmat
ion
to g
uara
ntee
tha
t th
e tr
iang
les
will
be
cong
ruen
t or
sim
ilar,
wri
te n
eith
er.
a.T
wo
side
s an
d th
e in
clud
ed a
ngle
of
one
tria
ngle
are
con
grue
nt t
o tw
o si
des
and
the
incl
uded
ang
le o
f th
e ot
her
tria
ngle
.co
ngru
ent
b.T
he m
easu
res
of a
ll th
ree
pair
s of
cor
resp
ondi
ng s
ides
are
pro
port
iona
l.si
mila
rc.
Tw
o an
gles
of
one
tria
ngle
are
con
grue
nt t
o tw
o an
gles
of
the
othe
r tr
iang
le.
sim
ilar
d.T
wo
angl
es a
nd a
non
incl
uded
sid
e of
one
tri
angl
e ar
e co
ngru
ent
to t
wo
angl
es a
ndth
e co
rres
pond
ing
noni
nclu
ded
side
of
the
othe
r tr
iang
le.
cong
ruen
te.
The
mea
sure
s of
tw
o si
des
of a
tri
angl
e ar
e pr
opor
tion
al t
o th
e m
easu
res
of t
wo
corr
espo
ndin
g si
des
of a
noth
er t
rian
gle,
and
the
incl
uded
ang
les
are
cong
ruen
t.si
mila
rf.
The
thr
ee s
ides
of
one
tria
ngle
are
con
grue
nt t
o th
e th
ree
side
s of
the
oth
er t
rian
gle.
cong
ruen
tg.
The
thr
ee a
ngle
s of
one
tri
angl
e ar
e co
ngru
ent
to t
he t
hree
ang
les
of t
he o
ther
tri
angl
e.si
mila
rh
.O
ne a
cute
ang
le o
f a
righ
t tr
iang
le is
con
grue
nt t
o on
e ac
ute
angl
e of
ano
ther
rig
httr
iang
le.
sim
ilar
i.T
he m
easu
res
of t
wo
side
s of
a t
rian
gle
are
prop
orti
onal
to
the
mea
sure
s of
tw
o si
des
of a
noth
er t
rian
gle.
neith
er2.
Iden
tify
eac
h of
the
follo
win
g as
an
exam
ple
of a
ref
lexi
ve,s
ymm
etri
c,or
tran
siti
vepr
oper
ty.
a.If
"R
ST
#"
UV
W,t
hen
"U
VW
#"
RS
T.
sym
met
ric
b.If
"R
ST
#"
UV
Wan
d "
UV
W#
"O
PQ
,the
n "
RS
T#
"O
PQ
.tr
ansi
tive
c."
RS
T#
"R
ST
refle
xive
Hel
pin
g Y
ou
Rem
emb
er3.
A g
ood
way
to
rem
embe
r so
met
hing
is t
o ex
plai
n it
to
som
eone
els
e.Su
ppos
e on
e of
you
rcl
assm
ates
is h
avin
g tr
oubl
e un
ders
tand
ing
the
diff
eren
ce b
etw
een
SAS
for
cong
ruen
ttr
iang
les
and
SAS
for
sim
ilar
tria
ngle
s.H
ow c
an y
ou e
xpla
in t
he d
iffe
renc
e to
him
?S
ampl
e an
swer
:In
SA
S fo
r co
ngru
ence
,cor
resp
ondi
ng s
ides
are
cong
ruen
t,w
hile
in S
AS
for
sim
ilari
ty,c
orre
spon
ding
sid
es a
repr
opor
tiona
l.(In
bot
h,th
e in
clud
ed a
ngle
s ar
e co
ngru
ent.)
©G
lenc
oe/M
cGra
w-H
ill31
2G
lenc
oe G
eom
etry
Rat
io P
uzzl
es w
ith T
rian
gles
If y
ou k
now
the
per
imet
er o
f a
tria
ngle
and
the
rat
ios
of t
he s
ides
,you
can
find
the
leng
ths
of t
he s
ides
.
Th
e p
erim
eter
of
a tr
ian
gle
is 8
4 u
nit
s.T
he
sid
es h
ave
len
gth
s r,
s,an
d t
.Th
e ra
tio
of s
to r
is 5
:3,a
nd
th
e ra
tio
of t
to r
is2
:1.F
ind
th
e le
ngt
h o
f ea
ch s
ide.
Sinc
e bo
th r
atio
s co
ntai
n r,
rew
rite
one
or
both
rat
ios
to m
ake
rth
e sa
me.
You
can
wri
te t
he r
atio
of t
to r
as 6
:3.N
ow y
ou c
an w
rite
a t
hree
-par
t ra
tio.
r:s:
t#
3:5
:6
The
re is
a n
umbe
r x
such
tha
t r
#3
x,s
#5
x,an
d t
#6
x.Si
nce
you
know
the
peri
met
er,8
4,yo
u ca
n us
e al
gebr
a to
fin
d th
e le
ngth
s of
the
sid
es.
r%
s%
t#
843
x%
5x%
6x#
8414
x#
84x
#6
3x
#18
,5x
#30
,6x
#36
So r
#18
,s#
30,a
nd t
#36
.
Fin
d t
he
len
gth
s of
th
e si
des
of
each
tri
angl
e.
1.T
he p
erim
eter
of
a tr
iang
le is
75
unit
s.T
he s
ides
hav
e le
ngth
s a,
b,an
d c.
The
ra
tio
of b
to a
is 3
:5,a
nd t
he r
atio
of c
to a
is 7
:5.F
ind
the
leng
th o
f ea
ch s
ide.
a"
25,b
"15
,c"
35
2.T
he p
erim
eter
of
a tr
iang
le is
88
unit
s.T
he s
ides
hav
e le
ngth
s d,
e,an
d f.
The
ra
tio
of e
to d
is 3
:1,a
nd t
he r
atio
of f
to e
is 1
0:9.
Fin
d th
e le
ngth
of
each
sid
e.
d"
12,e
"36
,f"
40
3.T
he p
erim
eter
of
a tr
iang
le is
91
unit
s.T
he s
ides
hav
e le
ngth
s p,
q,an
d r.
The
ra
tio
of p
to r
is 3
:1,a
nd t
he r
atio
of q
to r
is 5
:2.F
ind
the
leng
th o
f ea
ch s
ide.
p"
42,q
"35
,r"
14
4.T
he p
erim
eter
of
a tr
iang
le is
68
unit
s.T
he s
ides
hav
e le
ngth
s g,
h,an
d j.
The
ra
tio
of j
to g
is 2
:1,a
nd t
he r
atio
of h
to g
is 5
:4.F
ind
the
leng
th o
f ea
ch s
ide.
g"
16,h
"20
,j"
32
5.W
rite
a p
robl
em s
imila
r to
tho
se a
bove
invo
lvin
g ra
tios
in t
rian
gles
.
See
stu
dent
s’w
ork.
En
rich
men
t
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-3
6-3
Exam
ple
Exam
ple
Answers (Lesson 6-3)
© Glencoe/McGraw-Hill A11 Glencoe Geometry
An
swer
s
Stu
dy
Gu
ide
and I
nte
rven
tion
Para
llel L
ines
and
Pro
port
iona
l Par
ts
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-4
6-4
©G
lenc
oe/M
cGra
w-H
ill31
3G
lenc
oe G
eom
etry
Lesson 6-4
Pro
po
rtio
nal
Par
ts o
f Tr
ian
gle
sIn
any
tri
angl
e,a
line
para
llel t
o on
e si
de o
f a
tria
ngle
sep
arat
es t
he o
ther
tw
o si
des
prop
orti
onal
ly.T
he c
onve
rse
is a
lso
true
.
If X
and
Yar
e th
e m
idpo
ints
of R !
T!an
d S!T!
,the
n X!
Y!is
am
idse
gmen
tof
the
tri
angl
e.T
he T
rian
gle
Mid
segm
ent
The
orem
stat
es t
hat
a m
idse
gmen
t is
par
alle
l to
the
thir
d si
de a
nd is
hal
f it
s le
ngth
.
If X
Y! "
#|| R
S!"
# ,th
en !R X
TX !#
! YSY T!
.
If !R X
TX !#
! YSY T!
,the
n X
Y!"
#|| R
S!"
# .
If X!
Y!is
a m
idse
gmen
t,th
en X
Y!"
#|| R
S!"
#an
d X
Y#
!1 2! RS
.
YS
T
R
X
In !
AB
C,E"
F"|| C"
B".F
ind
x.
Sinc
e E!
F!|| C!
B!,!
FABF !
#! EA
E C!.
!x x% %2 22
!#
!1 68 !
6x%
132
#18
x%
3696
#12
x8
#x
F
C
BA
18
x %
22
x %
2
6E
A t
rian
gle
has
ver
tice
sD
(3,6
),E
(#3,
#2)
,an
d F
(7,#
2).
Mid
segm
ent
G "H"
is p
aral
lel
to E"
F".F
ind
th
e le
ngt
h o
f G "
H".
G !H!
is a
mid
segm
ent,
so it
s le
ngth
is o
ne-
half
tha
t of
E !F!.
Poin
ts E
and
Fha
ve t
hesa
me
y-co
ordi
nate
,so
EF
#7
&(&
3) #
10.
The
leng
th o
f m
idse
gmen
t G !
H!is
5.
Exam
ple1
Exam
ple1
Exam
ple2
Exam
ple2
Exercis
esExercis
es
Fin
d x
.
1.7
2.10
3.17
.5
4.8
5.12
6.5
7.In
Exa
mpl
e 2,
find
the
slo
pe o
f E!F!
and
show
tha
tE!
F!|| G!
H!.
The
endp
oint
s of
G"H"
are
at (
0,2)
and
(5,
2).T
he s
lope
of
G"H"
is 0
and
the
sl
ope
of E"
F"is
0.G"
H"an
d E"F"
are
para
llel.
3010
x %
10
x11
x %
12
x33
3010
24x
35x9
20
x
185
5x
7
©G
lenc
oe/M
cGra
w-H
ill31
4G
lenc
oe G
eom
etry
Div
ide
Seg
men
ts P
rop
ort
ion
ally
Whe
n th
ree
or m
ore
para
llel l
ines
cut
tw
o tr
ansv
ersa
ls,
they
sep
arat
e th
e tr
ansv
ersa
ls in
to p
ropo
rtio
nal
part
s.If
the
rat
io o
f th
e pa
rts
is 1
,the
n th
e pa
ralle
llin
es s
epar
ate
the
tran
sver
sals
into
con
grue
nt p
arts
.
If !
1|| !
2|| !
3,If
!4
|| !5
|| !6
and
then
!a b!#
! dc ! .!u v!
#1,
then
!w x!#
1.
Ref
er t
o li
nes
!1,
! 2,a
nd
!3
abov
e.If
a"
3,b
"8,
and
c"
5,fi
nd
d.
! 1|| !
2|| !
3so
!3 8!#
! d5 ! .T
hen
3d#
40 a
nd d
#13
!1 3! .
Fin
d x
and
y.
1.2.
x"
8x
"9
3.4.
x"
5;y
"2
y"
3!1 3!
5.6.
x"
12y
"3
1632
y %
3y
34
x %
4x
5
8y
% 2
y2x
% 4
3 x #
12y
% 2
3 y
2x #
6
x %
3
12
x %
12
123x5x
a
bd
uv x
w
ct
n m
s! 1
! 4! 5
! 6
! 2
! 3
Stu
dy
Gu
ide
and I
nte
rven
tion
(con
tinu
ed)
Para
llel L
ines
and
Pro
port
iona
l Par
ts
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-4
6-4
Exam
ple
Exam
ple
Exercis
esExercis
es
Answers (Lesson 6-4)
© Glencoe/McGraw-Hill A12 Glencoe Geometry
Skil
ls P
ract
ice
Para
llel L
ines
and
Pro
port
iona
l Par
ts
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-4
6-4
©G
lenc
oe/M
cGra
w-H
ill31
5G
lenc
oe G
eom
etry
Lesson 6-4
1.If
JK
#7,
KH
#21
,and
JL
#6,
2.F
ind
xan
d T
Vif
RU
#8,
US
#14
,fi
nd L
I.T
V#
x&
1 an
d V
S#
17.5
.
1811
;10
Det
erm
ine
wh
eth
er B!
C!|| D!
E!.
3.A
D#
15,D
B#
12,A
E#
10,a
nd E
C#
8ye
s
4.B
D#
9,B
A#
27,a
nd C
Eis
one
thi
rd o
f EA
no
5.A
E#
30,A
C#
45,a
nd A
Dis
tw
ice
DB
yes
CO
OR
DIN
ATE
GEO
MET
RYF
or E
xerc
ises
6–8
,use
th
e fo
llow
ing
info
rmat
ion
.T
rian
gle
AB
Cha
s ve
rtic
es A
(&5,
2),B
(1,8
),an
d C
(4,2
).Po
int
Dis
the
mid
poin
t of
A !B!
and
Eis
the
mid
poin
t of
A!C!
.
6.Id
enti
fy t
he c
oord
inat
es o
f Dan
d E
.D
(#2,
5);E
(#0.
5,2)
7.Sh
ow t
hat
B!C!
is p
aral
lel t
o D!
E!.
Sin
ce th
e sl
ope
of B"
C"is
#2
and
the
slop
e of
D"E"
is #
2,B"
C"is
par
alle
l to
D"E".
8.Sh
ow t
hat
DE
#!1 2! B
C.
The
leng
th o
f D"
E"is
#11
.25
"or
an
d th
e le
ngth
of
B"C"
is #
45".
9.F
ind
xan
d y.
10.F
ind
xan
d y.
x"
6,y
"6.
5x
"2,
y"
4
3 – 2x %
2
x %
3
2 y #
1
3y #
52x
% 1
3 y #
8y
% 5
x %
7
#45"
!2
x
y
O
AC
B
D
E
CB
ED
A
R
UV
T
S
HL
KJ
I
©G
lenc
oe/M
cGra
w-H
ill31
6G
lenc
oe G
eom
etry
1.If
AD
#24
,DB
#27
,and
EB
#18
,2.
Fin
d x,
QT
,and
TR
if Q
T#
x%
6,fi
nd C
E.
SR
#12
,PS
#27
,and
TR
#x
&4.
1612
;18;
8
Det
erm
ine
wh
eth
er J"
K"|| N"
M".
3.JN
#18
,JL
#30
,KM
#21
,and
ML
#35
no
4.K
M#
24,K
L#
44,a
nd N
L#
!5 6! JN
yes
CO
OR
DIN
ATE
GEO
MET
RYF
or E
xerc
ises
5 a
nd
6,u
se t
he
foll
owin
g in
form
atio
n.
Tri
angl
e E
FG
has
vert
ices
E(&
4,&
1),F
(2,5
),an
d G
(2,&
1).P
oint
Kis
the
mid
poin
t of
E !G!
and
His
the
mid
poin
t of
F!G!
.
5.Sh
ow t
hat
E!F!
is p
aral
lel t
o K!
H!.
The
slop
e of
E"F"
is 1
and
the
slo
pe o
f K"
H"is
1,
so E"
F"is
par
alle
l to
K"H"
.
6.Sh
ow t
hat
KH
#!1 2! E
F.
The
leng
th o
f K"
H"is
3#
2",an
d th
e le
ngth
of
E"F"is
6#
2".
7.F
ind
xan
d y.
8.F
ind
xan
d y.
x"
4,y
"9
x"
!5 2! ,y
"!9 4!
9.M
APS
The
dis
tanc
e fr
om W
ilmin
gton
to
Ash
Gro
ve a
long
K
enda
ll is
820
fee
t an
d al
ong
Mag
nolia
,660
fee
t.If
the
di
stan
ce b
etw
een
Bee
ch a
nd A
sh G
rove
alo
ng M
agno
lia is
28
0 fe
et,w
hat
is t
he d
ista
nce
betw
een
the
two
stre
ets
alon
gK
enda
ll?ab
out
348
ft
Ash
Grov
e
Beec
h
Mag
nolia
Kend
all
Wilm
ingt
on
4 – 3y %
2
3 x #
4x
% 1
4 y #
43x
# 4
2 – 3y %
31 – 3y
% 6
5 – 4x %
3
x
y
O
EGF H
K
NL
J
KM
S
Q
TR
P
D
EC BA
Pra
ctic
e (A
vera
ge)
Para
llel L
ines
and
Pro
port
iona
l Par
ts
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-4
6-4
Answers (Lesson 6-4)
© Glencoe/McGraw-Hill A13 Glencoe Geometry
An
swer
s
Rea
din
g t
o L
earn
Math
emati
csPa
ralle
l Lin
es a
nd P
ropo
rtio
nal P
arts
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-4
6-4
©G
lenc
oe/M
cGra
w-H
ill31
7G
lenc
oe G
eom
etry
Lesson 6-4
Pre-
Act
ivit
yH
ow d
o ci
ty p
lan
ner
s u
se g
eom
etry
?
Rea
d th
e in
trod
ucti
on t
o L
esso
n 6-
4 at
the
top
of
page
307
in y
our
text
book
.
Use
a g
eom
etri
c id
ea t
o ex
plai
n w
hy t
he d
ista
nce
betw
een
Chi
cago
Ave
nue
and
Ont
ario
Str
eet
is s
hort
er a
long
Mic
higa
n A
venu
e th
an a
long
Lak
eSh
ore
Dri
ve.S
ampl
e an
swer
:The
sho
rtes
t di
stan
ce b
etw
een
two
para
llel l
ines
is t
he p
erpe
ndic
ular
dis
tanc
e.
Rea
din
g t
he
Less
on
1.P
rovi
de t
he m
issi
ng w
ords
to
com
plet
e th
e st
atem
ent
of e
ach
theo
rem
.The
n st
ate
the
nam
e of
the
the
orem
.
a.If
a li
ne in
ters
ects
tw
o si
des
of a
tri
angl
e an
d se
para
tes
the
side
s in
to c
orre
spon
ding
segm
ents
of
leng
ths,
then
the
line
is
to t
he
thir
d si
de.
Con
vers
e of
the
Tri
angl
e P
ropo
rtio
nalit
y Th
eore
mb.
A m
idse
gmen
t of
a t
rian
gle
is
to o
ne s
ide
of t
he t
rian
gle
and
its
leng
th is
th
e le
ngth
of t
hat
side
.Tr
iang
le M
idse
gmen
t The
orem
c.If
a li
ne is
to
one
sid
e of
a t
rian
gle
and
inte
rsec
ts t
he o
ther
tw
o si
des
in
dist
inct
poi
nts,
then
it s
epar
ates
the
se s
ides
into
of p
ropo
rtio
nal l
engt
h.Tr
iang
le P
ropo
rtio
nalit
y Th
eore
m
2.R
efer
to
the
figu
re a
t th
e ri
ght.
a.N
ame
the
thre
e m
idse
gmen
ts o
f "R
ST
.U"
V",V"W"
,U"W"
b.If
RS
#8,
RU
#3,
and
TW
#5,
find
the
leng
th o
f ea
ch o
f th
em
idse
gmen
ts.
UV
"5,
VW
"3,
UW
"4
c.W
hat
is t
he p
erim
eter
of "
RS
T?
24d.
Wha
t is
the
per
imet
er o
f "U
VW
?12
e.W
hat
are
the
peri
met
ers
of "
RU
V,"
SV
W,a
nd "
TU
W?
12;1
2;12
f.H
ow a
re t
he p
erim
eter
s of
eac
h of
the
fou
r sm
all t
rian
gles
rel
ated
to
the
peri
met
er o
fth
e la
rge
tria
ngle
?Th
e pe
rim
eter
of
each
sm
all t
rian
gle
is o
ne-h
alf
the
peri
met
er o
f th
e la
rge
tria
ngle
.g.
Wou
ld t
he r
elat
ions
hip
that
you
fou
nd in
par
t f
appl
y to
any
tri
angl
e in
whi
ch t
hem
idpo
ints
of
the
thre
e si
des
are
conn
ecte
d?ye
s
Hel
pin
g Y
ou
Rem
emb
er
3.A
goo
d w
ay t
o re
mem
ber
a ne
w m
athe
mat
ical
ter
m is
to
rela
te it
to
othe
r m
athe
mat
ical
voca
bula
ry t
hat
you
alre
ady
know
.Wha
t is
an
easy
way
to
rem
embe
r th
e de
fini
tion
of
mid
segm
ent
usin
g ot
her
geom
etri
c te
rms?
Sam
ple
answ
er:A
mid
segm
enti
s a
segm
entt
hat
conn
ects
the
mid
poin
tsof
tw
o si
des
of a
tri
angl
e.R U
V W
T
S
segm
ents
two
para
llel
one-
half
para
llel
para
llel
prop
ortio
nal
©G
lenc
oe/M
cGra
w-H
ill31
8G
lenc
oe G
eom
etry
Para
llel L
ines
and
Con
grue
nt P
arts
The
re is
a t
heor
em s
tati
ng t
hat
if t
hree
par
alle
l lin
es c
ut o
ff c
ongr
uent
seg
men
ts o
n on
etr
ansv
ersa
l,th
en t
hey
cut
off
cong
ruen
t se
gmen
ts o
n an
y tr
ansv
ersa
l.T
his
can
be s
how
n fo
ran
y nu
mbe
r of
par
alle
l lin
es.T
he f
ollo
win
g dr
afti
ng t
echn
ique
use
s th
is f
act
to d
ivid
e a
segm
ent
into
con
grue
nt p
arts
.
A !B!
is t
o be
sep
arat
ed in
to f
ive
cong
ruen
t pa
rts.
Thi
s ca
n be
do
ne v
ery
accu
rate
ly w
itho
ut u
sing
a r
uler
.All
that
is n
eede
d is
a c
ompa
ss a
nd a
pie
ce o
f no
tebo
ok p
aper
.
Ste
p 1
Hol
d th
e co
rner
of
a pi
ece
of n
oteb
ook
pape
r at
po
int
A.
Ste
p 2
Fro
m p
oint
A,d
raw
a s
egm
ent
alon
g th
e pa
per
that
is f
ive
spac
es lo
ng.M
ark
whe
re t
he li
nes
of t
he n
oteb
ook
pape
r m
eet
the
segm
ent.
Lab
el
the
fift
h po
int,
P.
Ste
p 3
Dra
w P!
B!.T
hrou
gh e
ach
of t
he o
ther
mar
ks
on A !
P!,co
nstr
uct
a lin
e pa
ralle
l to
B!P!.
The
po
ints
whe
re t
hese
line
s in
ters
ect
A !B!
will
di
vide
A !B!
into
fiv
e co
ngru
ent
segm
ents
.
Use
a c
omp
ass
and
a p
iece
of
not
eboo
k p
aper
to
div
ide
each
seg
men
t in
to t
he
give
n n
um
ber
of c
ongr
uen
t p
arts
.S
eest
uden
t’s w
ork.
1.si
x co
ngru
ent
part
s
2.se
ven
cong
ruen
t pa
rts
AB
AB
A
P
B
AB
P
AB
AB
En
rich
men
t
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-4
6-4
Answers (Lesson 6-4)
© Glencoe/McGraw-Hill A14 Glencoe Geometry
Stu
dy
Gu
ide
and I
nte
rven
tion
Part
s of
Sim
ilar T
rian
gles
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-5
6-5
©G
lenc
oe/M
cGra
w-H
ill31
9G
lenc
oe G
eom
etry
Lesson 6-5
Peri
met
ers
If t
wo
tria
ngle
s ar
e si
mila
r,th
eir
peri
met
ers
have
the
sam
e pr
opor
tion
as
the
corr
espo
ndin
g si
des.
If "
AB
C#
"R
ST
,the
n
!A RB S
% %B S
TC%%
RATC
!#
!A RB S!
#!B S
TC !#
! RAC T!
.
Use
th
e d
iagr
am a
bove
wit
h !
AB
C!
!R
ST
.If
AB
"24
an
d R
S"
15,
fin
d t
he
rati
o of
th
eir
per
imet
ers.
Sinc
e "
AB
C#
"R
ST
,the
rat
io o
f th
e pe
rim
eter
s of
"A
BC
and
"R
ST
is t
he s
ame
as t
hera
tio
of c
orre
spon
ding
sid
es.
The
refo
re
#!2 14 5!
#!8 5!
Eac
h p
air
of t
rian
gles
is
sim
ilar
.Fin
d t
he
per
imet
er o
f th
e in
dic
ated
tri
angl
e.
1."
XY
Z2.
"B
DE
3345
3."
AB
C4.
"X
YZ
8455
.4
5."
AB
C6.
"R
ST
5411
0
25 20
10
PT
SM
R
95
13
12
AD
E
C
B
56
8.7
13
10
XY
ZT
RS
18
202515
17 8
NB
AC
PM
36
9 11 CDE
A
B44
24
2022
10
TR
XZ
YS
peri
met
er o
f "A
BC
!!
!pe
rim
eter
of "
RS
T
AC
BS
RT
Exam
ple
Exam
ple
Exercis
esExercis
es
©G
lenc
oe/M
cGra
w-H
ill32
0G
lenc
oe G
eom
etry
Spec
ial S
egm
ents
of
Sim
ilar
Tria
ng
les
Whe
n tw
o tr
iang
les
are
sim
ilar,
corr
espo
ndin
g al
titu
des,
angl
e bi
sect
ors,
and
med
ians
are
pro
port
iona
l to
the
corr
espo
ndin
gsi
des.
Als
o,in
any
tri
angl
e an
ang
le b
isec
tor
sepa
rate
s th
e op
posi
te s
ide
into
seg
men
ts t
hat
have
the
sam
e ra
tio
as t
he o
ther
tw
o si
des
of t
he t
rian
gle.
Stu
dy
Gu
ide
and I
nte
rven
tion
(con
tinu
ed)
Part
s of
Sim
ilar T
rian
gles
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-5
6-5
In t
he
figu
re,
!A
BC
!!
XY
Z,w
ith
an
gle
bise
ctor
s as
show
n.F
ind
x.
Sinc
e "
AB
C#
"X
YZ
,the
mea
sure
s of
the
angl
e bi
sect
ors
are
prop
orti
onal
to
the
mea
sure
s of
a p
air
of c
orre
spon
ding
sid
es.
!A XB Y!
#! YB WD !
!2 x4 !#
!1 80 !
10x
#24
(8)
10x
#19
2x
#19
.2
2410 D
W
Y
ZX
C
B
A
8x
S"U"bi
sect
s "
RS
T.F
ind
x.
Sinc
e S !U!
is a
n an
gle
bise
ctor
,!R T
UU !#
!R TSS !
.
! 2x 0!#
!1 35 0!
30x
#20
(15)
30x
#30
0x
#10
x2030
15
UT
S
R
Exam
ple1
Exam
ple1
Exam
ple2
Exam
ple2
Exercis
esExercis
es
Fin
d x
for
each
pai
r of
sim
ilar
tri
angl
es.
1.2.
108
3.4.
2.25
8.75
5.6.
12!5 6!
15
2x #
2x
% 1
2816
17
11
x %
7
x
10
10x
8
87
3
34
x
69
12x
x
36
1820
Answers (Lesson 6-5)
© Glencoe/McGraw-Hill A15 Glencoe Geometry
An
swer
s
Skil
ls P
ract
ice
Part
s of
Sim
ilar T
rian
gles
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-5
6-5
©G
lenc
oe/M
cGra
w-H
ill32
1G
lenc
oe G
eom
etry
Lesson 6-5
Fin
d t
he
per
imet
er o
f th
e gi
ven
tri
angl
e.
1."
JKL
,if
"JK
L#
"R
ST
,RS
#14
,2.
"D
EF
,if "
DE
F#
"A
BC
,AB
#27
,S
T#
12,T
R#
10,a
nd L
J#
14B
C#
16,C
A#
25,a
nd F
D#
15
50.4
40.8
3."
PQ
R,i
f "
PQ
R#
"L
MN
,LM
#16
,4.
"K
LM
,if "
KL
M#
"F
GH
,FG
#30
,M
N#
14,N
L#
27,a
nd R
P#
18G
H#
38,H
F#
38,a
nd K
L#
24
3884
.8
Use
th
e gi
ven
in
form
atio
n t
o fi
nd
eac
h m
easu
re.
5.F
ind
FG
if "
RS
T#
"E
FG
,S!H!
is a
n 6.
Fin
d M
Nif
"A
BC
#"
MN
P,A!
D!is
an
alti
tude
of "
RS
T,F !
J!is
an
alti
tude
of
alti
tude
of "
AB
C,M!
Q!is
an
alti
tude
of
"E
FG
,ST
#6,
SH
#5,
and
FJ
#7.
"M
NP
,AB
#24
,AD
#14
,and
MQ
#10
.5.
8.4
18
Fin
d x
.
7."
HK
L#
"X
YZ
8.
8!1 3!
8.4
LH
K
18
10
Y
15
x
ZX
7
20
24
x
C
A
BD
PN
QM
JG
E
F
HT
R
S
GL K
M
F
H
LM
PQ
RN
A
BC
D
EF
RS
T
JK
L
©G
lenc
oe/M
cGra
w-H
ill32
2G
lenc
oe G
eom
etry
Fin
d t
he
per
imet
er o
f th
e gi
ven
tri
angl
e.
1."
DE
F,i
f "A
BC
#"
DE
F,A
B#
36,
2."
ST
U,i
f "
ST
U#
"K
LM
,KL
#12
,B
C#
20,C
A#
40,a
nd D
E#
35L
M#
31,M
K#
32,a
nd U
S#
28
93.3"
65.6
25
Use
th
e gi
ven
in
form
atio
n t
o fi
nd
eac
h m
easu
re.
3.F
ind
PR
if "
JKL
#"
NP
R,K!
M!is
an
4.F
ind
ZY
if "
ST
U#
"X
YZ
,U!A!
is a
n al
titu
de o
f "JK
L,P !
T!is
an
alti
tude
of
alti
tude
of "
ST
U,Z!
B!is
an
alti
tude
of
"N
PR
,KL
#28
,KM
#18
,and
"
XY
Z,U
T#
8.5,
UA
#6,
and
PT
#15
.75.
ZB
#11
.4.
24.5
16.1
5
Fin
d x
.
5.6.
13.5
16.8
PHO
TOG
RA
PHY
For
Exe
rcis
es 7
an
d 8
,use
th
e fo
llow
ing
info
rmat
ion
.F
ranc
ine
has
a ca
mer
a in
whi
ch t
he d
ista
nce
from
the
lens
to
the
film
is 2
4 m
illim
eter
s.
7.If
Fra
ncin
e ta
kes
a fu
ll-le
ngth
pho
togr
aph
of h
er f
rien
d fr
om a
dis
tanc
e of
3 m
eter
s an
dth
e he
ight
of
her
frie
nd is
140
cen
tim
eter
s,w
hat
will
be
the
heig
ht o
f th
e im
age
on t
hefi
lm?
(Hin
t:C
onve
rt t
o th
e sa
me
unit
of
mea
sure
.)11
.2 m
m
8.Su
ppos
e th
e he
ight
of
the
imag
e on
the
film
of
her
frie
nd is
15
mill
imet
ers.
If F
ranc
ine
took
a f
ull-
leng
th s
hot,
wha
t w
as t
he d
ista
nce
betw
een
the
cam
era
and
her
frie
nd?
2.24
m
x28
2030
402x
% 1
25x
% 4
YX
BZ
TS
AU
MJ
L
K
TN
R
P
KS
LT
UM
B E
CF
DA
Pra
ctic
e (A
vera
ge)
Part
s of
Sim
ilar T
rian
gles
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-5
6-5
Answers (Lesson 6-5)
© Glencoe/McGraw-Hill A16 Glencoe Geometry
Rea
din
g t
o L
earn
Math
emati
csPa
rts
of S
imila
r Tri
angl
es
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-5
6-5
©G
lenc
oe/M
cGra
w-H
ill32
3G
lenc
oe G
eom
etry
Lesson 6-5
Pre-
Act
ivit
yH
ow i
s ge
omet
ry r
elat
ed t
o p
hot
ogra
ph
y?
Rea
d th
e in
trod
ucti
on t
o L
esso
n 6-
5 at
the
top
of
page
316
in y
our
text
book
.
•H
ow is
sim
ilari
ty in
volv
ed in
the
pro
cess
of
mak
ing
a ph
otog
raph
ic p
rint
from
a n
egat
ive?
Sam
ple
answ
er:T
he p
rint
is a
n en
larg
ed v
ersi
on o
f th
ene
gativ
e.Th
e im
age
on t
he p
rint
is s
imila
r to
the
imag
e on
the
nega
tive,
so w
hen
you
look
at
the
prin
t,yo
u w
ill s
eeex
actly
the
sam
e th
ings
in t
he s
ame
prop
ortio
ns a
s on
the
nega
tive,
just
larg
er.
•W
hy d
o ph
otog
raph
ers
plac
e th
eir
cam
eras
on
trip
ods?
Sam
ple
answ
er:T
hree
poi
nts
dete
rmin
e a
plan
e,so
the
thr
eefe
et o
f th
e tr
ipod
are
cop
lana
r an
d th
e tr
ipod
will
not
wob
ble.
Rea
din
g t
he
Less
on
1.In
the
fig
ure,
"R
ST
#"
UV
W.C
ompl
ete
each
pr
opor
tion
invo
lvin
g th
e le
ngth
s of
seg
men
ts in
this
fig
ure
by r
epla
cing
the
que
stio
n m
ark.
The
nid
enti
fy t
he d
efin
itio
n or
the
orem
fro
m t
he li
stbe
low
tha
t th
e co
mpl
eted
pro
port
ion
illus
trat
es.
i.D
efin
itio
n of
con
grue
nt p
olyg
ons
ii.
Def
init
ion
of s
imila
r po
lygo
ns
iii.
Pro
port
iona
l Per
imet
ers
The
orem
iv.
Ang
le B
isec
tors
The
orem
v.Si
mila
r tr
iang
les
have
cor
resp
ondi
ng a
ltit
udes
pro
port
iona
l to
corr
espo
ndin
g si
des.
vi.
Sim
ilar
tria
ngle
s ha
ve c
orre
spon
ding
med
ians
pro
port
iona
l to
corr
espo
ndin
g si
des.
vii.
Sim
ilar
tria
ngle
s ha
ve c
orre
spon
ding
ang
le b
isec
tors
pro
port
iona
l to
corr
espo
ndin
g si
des.
a.!R
S%
S ?T%
TR
!#
! URS V!
UV
%V
W%
WU
;iii
b.! UR
WT !#
!S ?X !V
Y;v
c.!R U
M N!#
! V? W!S
T;vi
d.! UR
S V!#
!S ?T !V
W;i
i
e.!R P
SP !#
! S? T!R
T;iv
f.!U ?N !
#!U R
W T!R
M;v
i
g.! WT
P Q!#
!R ?T !U
W;v
iih
.!U V
WW !#
! Q? V!U
Q;i
v
Hel
pin
g Y
ou
Rem
emb
er
2.A
goo
d w
ay t
o re
mem
ber
a la
rge
amou
nt o
f in
form
atio
n is
to
rem
embe
r ke
y w
ords
.Wha
tke
y w
ords
will
hel
p yo
u re
mem
ber
the
feat
ures
of
sim
ilar
tria
ngle
s th
at a
re p
ropo
rtio
nal
to t
he le
ngth
s of
the
cor
resp
ondi
ng s
ides
?pe
rim
eter
s,al
titud
es,a
ngle
bis
ecto
rs,m
edia
ns
W
QN
YU
V
T
PM
XR
S
©G
lenc
oe/M
cGra
w-H
ill32
4G
lenc
oe G
eom
etry
Pro
port
ions
for
Sim
ilar T
rian
gles
Rec
all t
hat
if a
line
cro
sses
tw
o si
des
of a
tri
angl
e an
d is
par
alle
l to
the
thir
dsi
de,t
hen
the
line
sepa
rate
s th
e tw
o si
des
that
it c
ross
es in
to s
egm
ents
of
prop
orti
onal
leng
ths.
You
can
wri
te m
any
prop
orti
ons
by id
enti
fyin
g si
mila
r tr
iang
les
in t
hefo
llow
ing
diag
ram
.In
the
diag
ram
,AM
! "#
& BN
!"# ,
AE
!"#
& FL
!"#
& MR
!"# ,
and
DQ
!"#
& ER
!"# .
An
swer
eac
h q
ues
tion
.Use
th
e d
iagr
am a
bove
.
1.N
ame
a tr
iang
le s
imila
r to
"G
NP
.2.
Nam
e a
tria
ngle
sim
ilar
to "
CJH
.
!A
MP
or !
GB
Aor
!A
FG!
CR
P
3.N
ame
two
tria
ngle
s si
mila
r to
"JK
S.
4.N
ame
a tr
iang
le s
imila
r to
"A
CP
.
Sam
ple
answ
er:!
JLR
,!C
DS
!G
HP
Com
ple
te e
ach
pro
por
tion
.
5.!A A
G P!#
!A ?F !A
M6.
! CCHP !
#!C ?R !
CJ
7.! JJ RS !
#! J? L!
JK
8.!P PH C!
#!P ?G !
PA9.
!E LRR !
#! J? R!
CR
10.
!M MN P!
#! A? P!
GA
Sol
ve.
11.I
f C
J#
16,J
R#
48,a
nd L
R#
30,f
ind
EL
.10
12.I
f D
K#
5,K
S#
7,an
d C
J#
8,fi
nd J
S.
11.2
13.I
f M
N#
12,N
P#
32,a
nd A
P#
48,f
ind
AG
.Rou
nd t
o th
e ne
ares
tte
nth.
13.1
14.I
f C
H#
18,H
P#
82,a
nd C
R#
130,
find
CJ.
23.4
15.W
rite
thr
ee m
ore
prob
lem
s th
at c
an b
e so
lved
usi
ng t
he d
iagr
am a
bove
.S
ee s
tude
nts’
wor
k.
AB
CD
E
FG
HJ
KL
MN
PR
Q
S
En
rich
men
t
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-5
6-5
Answers (Lesson 6-5)
© Glencoe/McGraw-Hill A17 Glencoe Geometry
An
swer
s
Stu
dy
Gu
ide
and I
nte
rven
tion
Frac
tals
and
Sel
f-S
imila
rity
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-6
6-6
©G
lenc
oe/M
cGra
w-H
ill32
5G
lenc
oe G
eom
etry
Lesson 6-6
Ch
arac
teri
stic
s o
f Fr
acta
lsT
he a
ct o
f re
peat
ing
a pr
oces
s ov
er a
nd o
ver,
such
as
find
ing
a th
ird
of a
seg
men
t,th
en a
thi
rd o
f th
e ne
w s
egm
ent,
and
so o
n,is
cal
led
iter
atio
n.
Whe
n th
e pr
oces
s of
iter
atio
n is
app
lied
to s
ome
geom
etri
c fi
gure
s,th
e re
sult
s ar
e ca
lled
frac
tals
.For
obj
ects
suc
h as
fra
ctal
s,w
hen
a po
rtio
n of
the
obj
ect
has
the
sam
e sh
ape
orch
arac
teri
stic
s as
the
ent
ire
obje
ct,t
he o
bjec
t ca
n be
cal
led
self
-sim
ilar
.
In t
he
dia
gram
at
the
righ
t,n
otic
e th
at t
he
det
ails
at
each
sta
ge a
re s
imil
ar t
o th
e d
etai
ls a
t S
tage
1.
1.Fo
llow
the
iter
atio
n pr
oces
s be
low
to
prod
uce
a fr
acta
l.
Stag
e 1
• D
raw
a s
quar
e.•
Dra
w a
n is
osce
les
righ
t tr
iang
le o
n th
e to
p si
de o
f th
e sq
uare
.U
se t
he s
ide
of t
he s
quar
e as
the
hyp
oten
use
of t
he t
rian
gle.
• D
raw
a s
quar
e on
eac
h le
g of
the
rig
ht t
rian
gle.
Stag
e 2
Rep
eat
the
step
s in
Sta
ge 1
,dra
win
g an
isos
cele
s tr
iang
le a
nd t
wo
smal
l squ
ares
for
eac
h of
the
sm
all
squa
res
from
Sta
ge 1
.
Stag
e 3
Rep
eat
the
step
s in
Sta
ge 1
for
eac
h of
the
sm
alle
st s
quar
es in
Sta
ge 2
.
2.Is
the
fig
ure
prod
uced
in S
tage
3 s
elf-
sim
ilar?
yes
Stag
e 1
Stag
e 2
Stag
e 3
Exercis
esExercis
es
Exam
ple
Exam
ple
©G
lenc
oe/M
cGra
w-H
ill32
6G
lenc
oe G
eom
etry
No
ng
eom
etri
c It
erat
ion
An
iter
ativ
e pr
oces
s ca
n be
app
lied
to a
n al
gebr
aic
expr
essi
on o
r eq
uati
on.T
he r
esul
t is
cal
led
a re
curs
ive
form
ula
.
Fin
d t
he
valu
e of
x3 ,
wh
ere
the
init
ial
valu
e of
xis
2.R
epea
t th
ep
roce
ss t
hre
e ti
mes
an
d d
escr
ibe
the
pat
tern
.
Init
ial v
alue
:2
Fir
st t
ime:
23#
8Se
cond
tim
e:83
#51
2T
hird
tim
e:51
23#
134,
217,
728
The
res
ult
of e
ach
step
of
the
iter
atio
n is
use
d fo
r th
e ne
xt s
tep.
For
this
exa
mpl
e,th
e x
valu
es a
re g
reat
er w
ith
each
iter
atio
n.T
here
is n
o m
axim
um v
alue
,so
the
valu
es a
rede
scri
bed
as a
ppro
achi
ng i
nfin
ity.
For
Exe
rcis
es 1
–5,f
ind
th
e va
lue
of e
ach
exp
ress
ion
.Th
en u
se t
hat
val
ue
as t
he
nex
t x
in t
he
exp
ress
ion
.Rep
eat
the
pro
cess
th
ree
tim
es,a
nd
des
crib
e yo
ur
obse
rvat
ion
s.
1.$
x!,w
here
xin
itia
lly e
qual
s 5
#5"
"2.
24;1
.50,
1.22
,1.1
1;th
e x
valu
es g
et s
mal
ler
with
eac
h ite
ratio
n.
2.!1 x! ,
whe
re x
init
ially
equ
als
2
!1 2! ;2,
!1 2! ,2;
the
xva
lues
alte
rnat
e be
twee
n !1 2!
and
2.
3.3x
,whe
re x
init
ially
equ
als
1
31"
3;33
"27
,327
"7.
6 '
1012
;the
xva
lues
get
gre
ater
with
eac
hite
ratio
n,ap
proa
chin
g in
finity
.
4.x
&5
whe
re x
init
ially
equ
als
10
10 #
5 "
5;0,
#5,
#10
;the
xva
lues
dec
reas
e by
5 w
ith e
ach
itera
tion.
5.x2
&4,
whe
re x
init
ially
equ
als
16
162
#4
"25
2;25
22#
4 "
63,5
00;6
3,50
02#
4 "
4.0
'10
9 ;(4
.0 '
109 )
2#
4 "
1.6
'10
19;t
he x
valu
es in
crea
se w
ith e
ach
itera
tion,
appr
oach
ing
infin
ity.
6.H
arpe
sh p
aid
$100
0 fo
r a
savi
ngs
cert
ific
ate.
It e
arns
inte
rest
at
an a
nnua
l rat
e of
2.8
%,
and
inte
rest
is a
dded
to
the
cert
ific
ate
each
yea
r.W
hat
will
the
cer
tifi
cate
be
wor
th a
fter
four
yea
rs?
$111
6.79
Stu
dy
Gu
ide
and I
nte
rven
tion
(con
tinu
ed)
Frac
tals
and
Sel
f-S
imila
rity
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-6
6-6
Exercis
esExercis
es
Exam
ple
Exam
ple
Answers (Lesson 6-6)
© Glencoe/McGraw-Hill A18 Glencoe Geometry
Skil
ls P
ract
ice
Frac
tals
and
Sel
f-S
imila
rity
NA
ME
____
____
____
____
____
____
____
____
____
____
____
__D
ATE
____
____
____
PE
RIO
D__
___
6-6
6-6
©G
lenc
oe/M
cGra
w-H
ill32
7G
lenc
oe G
eom
etry
Lesson 6-6
Sta
ges
1 an
d 2
of
a fr
acta
l k
now
n a
s th
e C
anto
r se
t ar
e sh
own
.To
get
Sta
ge 2
,th
ese
gmen
t in
Sta
ge 1
is
tris
ecte
d,a
nd
th
e in
teri
or o
f th
e m
idd
le s
egm
ent
is r
emov
ed.
(Th
e in
teri
or o
f a
segm
ent
is t
he
segm
ent
wit
h i
ts e
nd
poi
nts
rem
oved
.) T
he
pro
cess
is
rep
eate
d f
or s
ubs
equ
ent
stag
es.
1.D
raw
sta
ges
3 an
d 4
of t
he C
anto
r se
t.
2.H
ow m
any
segm
ents
are
the
re in
Sta
ge 3
? St
age
4?4
segm
ents
;8 s
egm
ents
3.W
hat
happ
ens
to t
he le
ngth
of
the
line
segm
ents
in e
ach
stag
e?Th
e lin
e se
gmen
ts d
ecre
ase
in le
ngth
by
two-
thir
ds a
t ea
ch s
tage
.
4.T
he C
anto
r se
t is
the
set
of
poin
ts a
fter
infi
nite
ly m
any
iter
atio
ns.I
s th
e C
anto
r se
t se
lf-s
imila
r?ye
s
Fin
d t
he
valu
e of
eac
h e
xpre
ssio
n.T
hen
,use
th
at v
alu
e as
th
e n
ext
xin
th
eex
pre
ssio
n.R
epea
t th
e p
roce
ss t
hre
e ti
mes
,an
d d
escr
ibe
you
r ob
serv
atio
ns.
5.2x
&3,
whe
re x
init
ially
equ
als
5
2(5)
#3
"7;
2(7)
#3
"11
;2(1
1) #
3 "
19;2
(19)
#3
"35
The
itera
tes
incr
ease
by
cons
ecut
ive
pow
ers
of 2
.
6.! 2x ! ,
whe
re x
init
ially
equ
als
1
!1 2!"
0.5;
!0 2.5 !"
0.25
;!0.
225 !"
0.12
5;!0.
1 225 !"
0.06
25
The
itera
tes
are
halv
ed w
ith e
ach
itera
tion,
appr
oach
ing
zero
.
Fin
d t
he
firs
t th
ree
iter
ates
of
each
exp
ress
ion
.
7.x2
&1,
whe
re x
init
ially
equ
als
28.
!1 x! ,w
here
xin
itia
lly e
qual
s 8
3,8,
630.
125,
8,0.
125
Stag
e 3
Stag
e 4
Stag
e 1
Stag
e 2
©G
lenc
oe/M
cGra
w-H
ill32
8G
lenc
oe G
eom
etry
An
art
ist
is d
esig
nin
g a
book
cov
er a
nd
wan
ts t
o sh
ow a
cop
y of
th
e bo
ok c
over
in
the
low
er l
eft
corn
er o
f th
e co
ver.
Aft
er S
tage
s 1
and
2 o
f th
e d
esig
n,h
e re
aliz
esth
at t
he
des
ign
is
dev
elop
ing
into
a f
ract
al!
1.D
raw
Sta
ges
3 an
d 4
of t
he b
ook
cove
r fr
acta
l.
2.A
fter
infi
nite
ly m
any
iter
atio
ns,w
ill t
he r
esul
t be
a s
elf
sim
ilar
frac
tal?
yes
3.O
n w
hat
part
of
the
book
cov
er s
houl
d yo
u fo
cus
your
att
enti
on t
o be
sur
e yo
u ca
n fi
nd a
copy
of
the
enti
re f
igur
e?th
e lo
wer
left
cor
ner
Fin
d t
he
valu
e of
eac
h e
xpre
ssio
n.T
hen
,use
th
at v
alu
e as
th
e n
ext
xin
th
eex
pre
ssio
n.R
epea
t th
e p
roce
ss t
hre
e ti
mes
an
d d
escr
ibe
you
r ob
serv
atio
ns.
4.2(
x%
3),w
here
xin
itia
lly e
qual
s 0
5.! 2x !
&3,
whe
re x
init
ially
equ
als
10
6,18
,42,
902,
#2,
#4,
#5
The
diff
eren
ce b
etw
een
valu
es
The
diff
eren
ce b
etw
een
valu
es is
do
uble
s w
ith e
ach
term
.m
ultip
lied
by !1 2!
with
eac
h te
rm.
Fin
d t
he
firs
t th
ree
iter
ates
of
each
exp
ress
ion
.
6.! 2x !
%1,
whe
re x
init
ially
equ
als
17.
2x2 ,
whe
re x
init
ially
equ
als
2
1.5;
1.75
;1.8
758;
128;
32,7
68
8.H
OU
SIN
GT
he A
ndre
ws
purc
hase
d a
hous
e fo
r $9
6,00
0.T
he r
eal e
stat
e ag
ent
who
sol
dth
e ho
use
said
tha
t co
mpa
rabl
e ho
uses
in t
he a
rea
appr
ecia
te a
t a
rate
of
4.5%
per
yea
r.If
thi
s pa
tter
n co
ntin
ues,
wha
t w
ill b
e th
e va
lue
of t
he h
ouse
in t
hree
yea
rs?
Rou
nd t
oth
e ne
ares
t w
hole
num
ber.
$109
,552
Stag
e 3 MAT
HM
ATH
MAT
H
Stag
e 4 MAT
HM
ATH
MAT
HM
ATH
Stag
e 1 MAT
HSt
age
2 MAT
HM
ATH
Pra
ctic
e (A
vera
ge)
Frac
tals
and
Sel
f-S
imila
rity
NA
ME
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6-6
6-6
Answers (Lesson 6-6)
© Glencoe/McGraw-Hill A19 Glencoe Geometry
An
swer
s
Rea
din
g t
o L
earn
Math
emati
csFr
acta
ls a
nd S
elf-
Sim
ilari
ty
NA
ME
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ATE
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RIO
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6-6
6-6
©G
lenc
oe/M
cGra
w-H
ill32
9G
lenc
oe G
eom
etry
Lesson 6-6
Pre-
Act
ivit
yH
ow i
s m
ath
emat
ics
fou
nd
in
nat
ure
?
Rea
d th
e in
trod
ucti
on t
o L
esso
n 6-
6 at
the
top
of
page
325
in y
our
text
book
.
Nam
e tw
o ob
ject
s fr
om n
atur
e ot
her
than
bro
ccol
i in
whi
ch a
sm
all p
iece
rese
mbl
es t
he w
hole
.S
ampl
e an
swer
:rin
gs o
f a
tree
tru
nk;
spir
al s
hell
Rea
din
g t
he
Less
on
1.M
atch
eac
h de
fini
tion
fro
m t
he f
irst
col
umn
wit
h a
term
fro
m t
he s
econ
d co
lum
n.(S
ome
wor
ds o
f ph
rase
s in
the
sec
ond
colu
mn
may
be
used
mor
e th
an o
nce
or n
ot a
t al
l.)
Ph
rase
Term
a.a
geom
etri
c fi
gure
tha
t is
cre
ated
usi
ng it
erat
ion
iiii.
sim
ilar
b.a
patt
ern
in w
hich
sm
alle
r an
d sm
alle
r de
tails
of
a sh
ape
have
ii.i
tera
tion
th
e sa
me
geom
etri
c ch
arac
teri
stic
s as
the
ori
gina
l sha
peiv
iii.
frac
tal
c.th
e re
sult
of
tran
slat
ing
an it
erat
ive
proc
ess
into
a f
orm
ula
oriv
.se
lf-s
imila
ral
gebr
aic
equa
tion
vv.
recu
rsio
nd.
the
proc
ess
of r
epea
ting
the
sam
e pr
oced
ure
over
and
ove
rfo
rmul
aag
ain
iivi
.con
grue
nt
2.R
efer
to
the
thre
e pa
tter
ns b
elow
.
i. ii.
iii.
a.G
ive
the
spec
ial n
ame
for
each
of
the
frac
tals
you
obt
ain
by c
onti
nuin
g th
e pa
tter
nw
itho
ut e
nd.
i.K
och
snow
flake
;ii.
Sie
rpin
ski t
rian
gle;
iii.K
och
curv
eb.
Whi
ch o
f th
ese
frac
tals
are
sel
f-si
mila
r?S
ierp
insk
i tri
angl
e,K
och
curv
ec.
Whi
ch o
f th
ese
frac
tals
are
str
ictl
y se
lf-s
imila
r?S
ierp
insk
i tri
angl
e
Hel
pin
g Y
ou
Rem
emb
er3.
A g
ood
way
to
rem
embe
r a
new
mat
hem
atic
al t
erm
is t
o re
late
it t
o ev
eryd
ay E
nglis
hw
ords
.The
wor
d fr
acta
lis
rel
ated
to
frac
tion
and
frag
men
t.U
se y
our
dict
iona
ry t
o fi
ndat
leas
t on
e de
fini
tion
for
eac
h of
the
se w
ords
tha
t yo
u th
ink
is r
elat
ed t
o th
e m
eani
ng o
fth
e w
ord
frac
tal
and
expl
ain
the
conn
ecti
on.
Sam
ple
answ
er:F
ract
ion:
a sm
all
part
;a d
isco
nnec
ted
piec
e;fr
agm
ent:
a pi
ece
deta
ched
or
brok
en o
ff;
som
ethi
ng in
com
plet
e;in
a f
ract
al,t
he s
mal
ler
piec
es o
f th
e sh
ape
rese
mbl
e th
e w
hole
.
©G
lenc
oe/M
cGra
w-H
ill33
0G
lenc
oe G
eom
etry
The
Möb
ius
Str
ipA
Möb
ius
stri
p is
a s
peci
al s
urfa
ce w
ith
only
one
sid
e.It
was
dis
cove
red
byA
ugus
t Fe
rdin
and
Möb
ius,
a G
erm
an a
stro
nom
er a
nd m
athe
mat
icia
n.
1.To
mak
e a
Möb
ius
stri
p,cu
t a
stri
p of
pap
er a
bout
16
inch
es lo
ng a
nd 1
inch
wid
e.M
ark
the
ends
wit
h th
e le
tter
s A
,B,C
,and
Das
sho
wn
belo
w.
Tw
ist
the
pape
r on
ce,c
onne
ctin
g A
to D
and
Bto
C.T
ape
the
ends
toge
ther
on
both
sid
es.
See
stu
dent
s’w
ork.
2.U
se a
cra
yon
or p
enci
l to
shad
e on
e si
de o
f th
e pa
per.
Shad
e ar
ound
the
stri
p un
til y
ou g
et b
ack
to w
here
you
sta
rted
.Wha
t ha
ppen
s?
The
entir
e st
rip
is s
hade
d on
bot
h si
des.
3.W
hat
do y
ou t
hink
will
hap
pen
if y
ou c
ut t
he M
öbiu
s st
rip
dow
n th
em
iddl
e? T
ry it
.
Inst
ead
of t
wo
loop
s,yo
u ge
t on
e lo
op t
hat
is t
wic
e as
long
as t
he o
rigi
nal o
ne.
4.M
ake
anot
her
Möb
ius
stri
p.St
arti
ng a
thi
rd o
f th
e w
ay in
fro
m o
ne e
dge,
cut
arou
nd t
he s
trip
,sta
ying
alw
ays
the
sam
e di
stan
ce in
fro
m t
he e
dge.
Wha
t ha
ppen
s?
Two
inte
rloc
king
loop
s ar
e fo
rmed
.
5.St
art
wit
h an
othe
r lo
ng s
trip
of
pape
r.T
wis
t th
e pa
per
twic
e an
d co
nnec
tth
e en
ds.W
hat
happ
ens
whe
n yo
u cu
t do
wn
the
cent
er o
f th
is s
trip
?
Two
inte
rloc
king
loop
s ar
e fo
rmed
.
6.St
art
wit
h an
othe
r lo
ng s
trip
of p
aper
.Tw
ist
the
pape
r th
ree
tim
es a
ndco
nnec
t th
e en
ds.W
hat
happ
ens
whe
n yo
u cu
t do
wn
the
cent
er o
f thi
s st
rip?
One
tw
o-si
ded
loop
with
a k
not
is fo
rmed
.
A B
C D
En
rich
men
t
NA
ME
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__D
ATE
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PE
RIO
D__
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6-6
6-6
Answers (Lesson 6-6)