reflection and mirrors

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Reflection and Mirrors The Law of Reflection always applies: “The angle of reflection is equal to the angle of incidence.”

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Reflection and Mirrors. The Law of Reflection always applies: “The angle of reflection is equal to the angle of incidence.”. “Plane” Mirrors form virtual images. Virtual : light APPEARS to come from this location, but does not actually start there. - PowerPoint PPT Presentation

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Page 1: Reflection  and Mirrors

Reflection and MirrorsThe Law of Reflection always applies:“The angle of reflection is equal to the

angle of incidence.”

Page 2: Reflection  and Mirrors

“Plane” Mirrors form virtual images.

Virtual: light APPEARS to come from this location, but does not actually start there.

The image is the same distance behind the mirror as the object is in front of the mirror.

The image is the same size as the object.

Page 3: Reflection  and Mirrors

If you wish to take a picture of your image while standing 2 meters in front of a plane mirror, for what distance should you set your camera to provide the sharpest focus?

Since the image is the same distance BEHIND the mirror as the object is in front of the mirror….

Set the distance for 4 meters

Page 4: Reflection  and Mirrors

How big does a mirror have to be in order for you to see your entire image?

Page 5: Reflection  and Mirrors
Page 6: Reflection  and Mirrors

Concave Mirrors

*Form “real”, inverted (upside down) images are formed UNLESS the object is inside the focal length…

…Then the images are “virtual” and upright!

Page 8: Reflection  and Mirrors
Page 9: Reflection  and Mirrors

Measurements with mirrors

f - focal lengthdo – distance from the mirror to the object being observed.di – distance from the mirror to where an image is formedm- magnification- compares the size of the object being observed and the image formed by the mirror.

Page 10: Reflection  and Mirrors

The Mirror Equation

io d1

d1

f1

Where f is the focal length, do is the distance from the mirror to the object, and di is the distance from the mirror to the image.

Page 11: Reflection  and Mirrors

Magnification

The magnification provided by a mirror is given by

Where hi is the height of the image and

ho is the height of the object

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i

o

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Page 12: Reflection  and Mirrors

Yep, it’s time for you to try one…

A concave mirror has a radius of curvature of 15.0 cm. A 1.5 cm tall gummy bear is placed 19.0 cm from the mirror. Where will the image be formed? What is the magnification? How tall is the image?

First find the focal length. f = ½ Rf = 7.5 cmNow solve for di using the mirror equation.di = 12.39 cm Now, get the magnification, m = -di / do

m = - 0.65 it’s negative because the image is inverted.Now for the height of the image: m = hi / hohi = -0.98 cm

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d1

f1

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Page 13: Reflection  and Mirrors
Page 14: Reflection  and Mirrors

Concave and Convex LensesLight REFRACTS as it

passes through lenses, forming images.

Convex lenses are CONVERGINGlenses

Concave lenses are DIVERGING lenses

Refraction: the change in direction as a wave passes from one medium into another

Page 15: Reflection  and Mirrors

Measurements with lenses

f - focal lengthdo – distance from the lens to the object being observed.di – distance from the lens to where an image is formedm- magnification- compares the size of the object being observed and the image formed by the lens.

Page 16: Reflection  and Mirrors

Convex Lenses

The “focal length” will be ½ the “radius of curvature”.

Page 17: Reflection  and Mirrors

Images formed by Convex lensesIf the object is beyond twice the focal length, the image is smaller, inverted, and real- if a piece of paper was placed at the image location, you would see the image on the paper.

If the object is placed at exactly twice the focal length, the image will be exactly the same size as the object, inverted, and real

If the object is placed exactly at the focal point, the light rays are perfectly parallel, and NO image will be formed!

If the object is placed within the focal length, the image will be larger, upright, and VIRTUAL.NO image would appear on a paper screen placed at the image location!

Page 18: Reflection  and Mirrors

“Virtual”A “virtual” focal point- real light waves would appear to converge at that point, but they actually do not. Concave lenses have a virtual focal point. Convex lenses have a real focal point.A “virtual” image- No real image will appear on a screen. The light rays that reach your eye just behave as if they came from the image position

Page 19: Reflection  and Mirrors

Your Eye

Page 20: Reflection  and Mirrors

Magnifying glasses

Magnifying glasses are convex lensesthat converge the light towards a focal point

Page 21: Reflection  and Mirrors

Diverging Lenses

Concave (diverging) lenses ALWAYS form smaller, upright, virtual images.

SUV

Page 22: Reflection  and Mirrors

People who are near-sighted can see up close but not far away.

They use concave (diverging) lenses, which will make something far away look like it’s up closer.

People who are far-sighted use convex (converging) lenses that make near objects look as if they are further away.

Page 23: Reflection  and Mirrors

The Lens/Mirror Equation

io d1

d1

f1

Where f is the focal length, do is the distance from the mirror or lens to the object, and di is the distance from the mirror or lens to the image.

Page 24: Reflection  and Mirrors

Magnification

The magnification provided by a lens or mirrorWhere hi is the height of the image and

ho is the height of the object

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i

o

iddmand

hhm

Page 25: Reflection  and Mirrors

Yep, it’s time for you to try one…

A convex lens has a radius of curvature of 8.0 cm. A 12 cm tall troll is placed 7.0 cm from the lens. How far from the lens should a screen be placed in order to have a sharp image? What is the magnification? How tall is the image?

First find the focal length. f = ½ Rf = 4.0 cmNow solve for di using the lens equation.di = 9.33 cm Now, get the magnification, m = -di / do

m = - 1.33 it’s negative because the image is inverted.Now for the height of the image: m = hi / hohi = -16 cm

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f1

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Page 26: Reflection  and Mirrors

Using the lens equation for concave lenses

The focal point is VIRTUAL, so use a negative value for the focal length.Example: if the radius of curvature of a concave lens is 10 cm, the focal length f = -5 cm.

Page 27: Reflection  and Mirrors

io d1

d1

f1

Page 28: Reflection  and Mirrors
Page 29: Reflection  and Mirrors

Optometrists and opthalmologists, instead of using the focal length to specify the strength of a lens, use a measurement called the

power or diopter of a lens.

The power (diopter) = 1 / fFor example, a 20 cm focal length

lens has a power of 1 / 0.20 = 5.0 Diopters

Page 30: Reflection  and Mirrors

Cameras

Page 31: Reflection  and Mirrors

Camera Settings

Shutter speed: how long the shutter is open. Speeds faster than 1/100 s are normally used. Fast action requires a very small shutter speed.

Page 32: Reflection  and Mirrors

Camera Settings

F-stop: changes the diameter of the iris diaphragm to control the amount of light reaching the film.

The SMALLER the f-stop, the LARGER the opening.

Page 33: Reflection  and Mirrors

The f-stop determines “depth of field”.

A larger f-stop (a smaller opening)- will produce an image

where everything is in focus.

A smaller f-stop (a larger opening)- will produce an image in

which only the subject is in focus and everything in the foreground and background is out of focus.

Page 34: Reflection  and Mirrors

A TELEPHOTO lens has a longer focal length to magnify images.

A WIDE-ANGLE lens has a shorter focal length.

Page 35: Reflection  and Mirrors

TelescopesRefracting telescopes have two lenses,

the objective and the eyepiece.

The eyepiece lens has a smaller focal length.

The objective lens has a larger focal length.

Page 36: Reflection  and Mirrors

MicroscopesMicroscopes also have

two lenses, the eyepiece and the objective.

The eyepiece lens has the longer focal length.

The objective has the smaller focal length.

Page 37: Reflection  and Mirrors

Fresnel Lens

The weight and bulk of a large diameter lens can be reduced by constructing the lens from small wedged segments that follow the curvature of the original lens and collapse down to a thin layer.

Page 38: Reflection  and Mirrors

Augustin Fresnel Fresnel invented

this type of lens in 1822.

Page 39: Reflection  and Mirrors

Fresnel lenses can take a small diverging light source and change it into a powerful straight beam of light.

Page 40: Reflection  and Mirrors

Small plastic Fresnel lenses are sold at office supply stores as “Magnifying Lenses”

Fresnel Lenses are also used in overhead projectors

Page 41: Reflection  and Mirrors

Large glass lenses that have Fresnel surfaces surrounding a small light source have provided an invaluable contribution to coastline areas for more than 150 years. These lenses are used in…..

Page 42: Reflection  and Mirrors

Lighthouses

Page 43: Reflection  and Mirrors

Tests showed that while an open flame lost nearly 97% of its light, and a flame with reflectors behind it still lost 83% of its light, the fresnel lens was able to capture all but 17% of its light.

Because of its amazing efficiency, a fresnel lens could easily throw its light 20 or more miles to the horizon.

Page 44: Reflection  and Mirrors
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Refraction• When waves enter a

new medium, they change direction and speed. The change in direction is called Refraction.

Page 48: Reflection  and Mirrors

Different frequencies (colors) refract slightly different amounts.

This means that the index of refraction, “n”, for blue light is slightly different than “n” for red light.

This results in a dispersions of colors as seen in a prism or a rainbow.

Blue Bends Best!(ok, actually violet refracts the

most…)

Page 49: Reflection  and Mirrors

Rainbows!

Sunlight refracts as it enters a raindrop.

Different colors refract different amounts.

This spreads out the colors.The light reflects off the back of the

raindrop.The light refracts again, spreading out

the colors even more.We see the rainbow!

Page 50: Reflection  and Mirrors

The angles of incidence, reflection, and refraction are all measured from a line drawn “normal” (perpendicular) to the surface.

The angle of reflection is ALWAYS equal to the angle of incidence.

That is the Law of Reflection.

incidence reflected

refracted

q q

q

Page 51: Reflection  and Mirrors

The amount that the wave refracts depends on the kind of medium it is moving through.

The index of refraction, “n”, of each medium determines both the refraction and the average speed.

c / v = nwhere c is the speed of light in a vacuum and

v is the average speed of light through the medium.

Page 52: Reflection  and Mirrors

For example: what is the velocity of light through water with an index of refraction, n = 1.54?

Rearranging c/v = n givesv = c ÷ n

v = 3 x 108 ÷ 1.54 =1.95 x 108 m/s

The average speed of light slows down when it goes through water!!

Page 53: Reflection  and Mirrors
Page 54: Reflection  and Mirrors

Snell’s LawSnell’s Law describes refraction as

light strikes the boundary between two media

n1 sin q1 = n2 sin q2

The index of refraction of a pure vacuum and of air is n = 1.

The index of refraction of every other substance is greater than 1.

incidence reflected

refracted

q q

q

Page 55: Reflection  and Mirrors

Example:

Light traveling through air enters a block of glass at an angle of 30° and refracts at an angle of 22°.

What is the index of refraction of the glass?

2

11sinsinnqq

incidence reflected

refracted

q q

q2211 sinnsinn qq

2

112 sin

sinnnqq

33.122sin30sin1n2

Page 56: Reflection  and Mirrors

Different frequencies (colors) refract slightly different amounts.

This means that the index of refraction, “n”, for blue light is slightly different than “n” for red light.

This results in a dispersions of colors as seen in a prism or a rainbow.

Blue Bends Best!(ok, actually violet refracts the

most…)

Page 57: Reflection  and Mirrors

Rainbows!

Sunlight refracts as it enters a raindrop.

Different colors refract different amounts.

This spreads out the colors.The light reflects off the back of the

raindrop.The light refracts again, spreading out

the colors even more.We see the rainbow!

Page 58: Reflection  and Mirrors

The Critical Angle and Total Internal Reflection

q

inci

denc

e

refracted

When light passes from a material that is MORE dense to one that is LESS dense, its refracts AWAY from the Normal line.

As the angle of incidence increase, the angle of refraction also increases.

Page 59: Reflection  and Mirrors

The Critical Angle and Total Internal Reflection

At some Critical Angle of incidence, the angle of refraction is 90°.

Beyond that critical angle, no light that is refracted!

All of the light is reflected back into the original medium.

This is called Total Internal Reflection

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reflected

qcritical

1

2critical n

nsin q

n1

n2

)190(sinsinsin 2211 qq nn

Page 60: Reflection  and Mirrors

The most useful application of the phenomenon of

Total Internal Reflection is in

Fiber Optics

Page 61: Reflection  and Mirrors
Page 62: Reflection  and Mirrors

When wavefronts pass through a narrow slit they spread out. This effect is called diffraction.

Page 66: Reflection  and Mirrors

Thomas Young’s Double-Slit Experiment

• He allowed sunlight to fall on two slits.• He knew that if light was a wave, it would diffract as it

passed through the slits.• The diffracted waves would have areas of both

constructive and destructive interference.• This interference would produce bright and dark areas

on a screen.

Page 67: Reflection  and Mirrors
Page 68: Reflection  and Mirrors

If the wavelength of light is longer, the pattern on the screen is more spread out.

(700 nm- 400 nm) Red light spreads out more than violet.If the screen is farther, the pattern on the screen is more spread out.If the slits are CLOSER to each other, the pattern on the screen is more spread out.

Page 72: Reflection  and Mirrors

• The pattern of bright and dark fringes did appear on a screen.

• The brightest area, in the center, he called the “central bright spot”.

• He was able to mathematically determine the wavelength by measuring the distance from the central bright spot to each fringe.

Page 73: Reflection  and Mirrors

ml = d(x ÷ L) = dsinqm- “order” (m = 0 is the central bright spot)l- wavelength of lightd- distance between the slitsx- distance from central bright spot to another

bright fringeL- distance from the slits to the screenq- the angle between the line to the central bright

spot and the observed bright fringe.

Page 74: Reflection  and Mirrors

Different frequencies (colors) of lightdiffract by different amounts

Page 75: Reflection  and Mirrors

• The more slits there are, the narrower the fringes become.

• The fringes on top are from two slits.• The fringes on bottom are from eight slits.• A “diffraction grating” has hundreds of slits per

millimeter.