resonance, revisited (again)

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Resonance, Revisited (Again) March 13, 2014

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Resonance, Revisited (Again). March 13, 2014. Practicalities. I’m still working through the pile of grading… Although I can report that most of the third course project reports were really good. For today: let’s figure out how vocal tract length determines formant frequencies!. - PowerPoint PPT Presentation

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Page 1: Resonance, Revisited (Again)

Resonance, Revisited (Again)

March 13, 2014

Page 2: Resonance, Revisited (Again)

Practicalities• I’m still working through the pile of grading…

• Although I can report that most of the third course project reports were really good.

• For today: let’s figure out how vocal tract length determines formant frequencies!

Page 3: Resonance, Revisited (Again)

Resonant Frequencies• Remember: a standing wave can only be set up in the tube if pressure pulses are emitted from the loudspeaker at the appropriate frequency

• Q: What frequency might that be?

• It depends on:

• how fast the sound wave travels through the tube

• how long the tube is

• How fast does sound travel?

• ≈ 350 meters / second = 35,000 cm/sec

• ≈ 1260 kilometers per hour (780 mph)

Page 4: Resonance, Revisited (Again)

Calculating Resonance• A new pressure pulse should be emitted right when:

• the first pressure peak has traveled all the way down the length of the tube

• and come back to the loudspeaker.

Page 5: Resonance, Revisited (Again)

Calculating Resonance• Let’s say our tube is 175 meters long.

• Going twice the length of the tube is 350 meters.

• It will take a sound wave 1 second to do this

• Resonant Frequency: 1 Hz

175 meters

Page 6: Resonance, Revisited (Again)

Wavelength• New concept: a standing wave has a wavelength

• The wavelength is the distance (in space) it takes a standing wave to go:

1. from a pressure peak

2. down to a pressure minimum

3. back up to a pressure peak

• For a waveform representation of a standing wave, the x-axis represents distance, not time.

Page 7: Resonance, Revisited (Again)

First Resonance• The resonant frequencies of a tube are determined by how the length of the tube relates to wavelength ().

• First resonance (of a closed tube):

• sound must travel down and back again in the tube

• wavelength = 2 * length of the tube (L)

• = 2 * L

L

Page 8: Resonance, Revisited (Again)

Calculating Resonance• distance = rate * time

• wavelength = (speed of sound) * (period of wave)

• wavelength = (speed of sound) / (resonant frequency)

• = c / f

• f = c

• f = c /

• for the first resonance,

• f = c / 2L

• f = 350 / (2 * 175) = 350 / 350 = 1 Hz

Page 9: Resonance, Revisited (Again)

Higher Resonances• It is possible to set up resonances with higher frequencies, and shorter wavelengths, in a tube.

= L

Page 10: Resonance, Revisited (Again)

Higher Resonances• It is possible to set up resonances with higher frequencies, and shorter wavelengths, in a tube.

= L

= 2L / 3

• Q: What will the relationship between and L be for the next highest resonance?

Page 11: Resonance, Revisited (Again)

First ResonanceTime 1: initial impulse is sent down the tubeTime 2: initial impulse bounces at end of tubeTime 3: impulse returns to other end and is reinforced by a new impulse

• Resonant period = Time 3 - Time 1

Time 4: reinforced impulse travels back to far end

Page 12: Resonance, Revisited (Again)

Second ResonanceTime 1: initial impulse is sent down the tube

Time 2: initial impulse bounces at end of tube + second impulse is sent down tube

Time 3: initial impulse returns and is reinforced; second impulse bounces

Time 4: initial impulse re-bounces; second impulse returns and is reinforcedResonant period = Time 2 - Time 1

Page 13: Resonance, Revisited (Again)

Doing the Math• It is possible to set up resonances with higher frequencies, and shorter wavelengths, in a tube.

= L

f = c /

f = c / L

f = 350 / 175 = 2 Hz

Page 14: Resonance, Revisited (Again)

Doing the Math• It is possible to set up resonances with higher frequencies, and shorter wavelengths, in a tube.

= 2L / 3

f = c /

f = c / (2L/3)

f = 3c / 2L

f = 3*350 / 2*175 = 3 Hz

Page 15: Resonance, Revisited (Again)

Patterns• Note the pattern with resonant frequencies in a closed tube:

• First resonance: c / 2L (1 Hz)

• Second resonance: c / L (2 Hz)

• Third resonance: 3c / 2L (3 Hz)

............

• General Formula:

Resonance n: nc / 2L

Page 16: Resonance, Revisited (Again)

Different Patterns• This is all fine and dandy, but speech doesn’t really involve closed tubes

• Think of the articulatory tract as a tube with:

• one open end

• a sound pulse source at the closed end

(the vibrating glottis)

• At what frequencies will this tube resonate?

Page 17: Resonance, Revisited (Again)

Anti-reflections• A weird fact about nature:

• When a sound pressure peak hits the open end of a tube, it doesn’t get reflected back

• Instead, there is an “anti-reflection”

• The pressure disperses into the open air, and...

• A sound rarefaction gets sucked back into the tube.

Page 18: Resonance, Revisited (Again)

Open Tubes, part 1

Page 19: Resonance, Revisited (Again)

Open Tubes, part 2

Page 20: Resonance, Revisited (Again)

The Upshot

• In open tubes, there’s always a pressure node at the open end of the tube

• Standing waves in open tubes will always have a pressure anti-node at the glottis

First resonance in the articulatory tract

glottislips (open)

Page 21: Resonance, Revisited (Again)

Open Tube Resonances• Standing waves in an open tube will look like this:

= 4L

L

= 4L / 3

= 4L / 5

Page 22: Resonance, Revisited (Again)

Open Tube Resonances• General pattern:

• wavelength of resonance n = 4L / (2n - 1)

• Remember: f = c /

• fn = c

4L / (2n - 1)

• fn = (2n - 1) * c

4L

Page 23: Resonance, Revisited (Again)

Deriving Schwa• Let’s say that the articulatory tract is an open tube of length 17.5 cm (about 7 inches)

• What is the first resonant frequency?

• fn = (2n - 1) * c

4L

• f1 = (2*1 - 1) * 350 = 1 * 350 = 500

(4 * .175) .70

• The first resonant frequency will be 500 Hz

Page 24: Resonance, Revisited (Again)

Deriving Schwa, part 2• What about the second resonant frequency?

• fn = (2n - 1) * c

4L

• f2 = (2*2 - 1) * 350 = 3 * 350 = 1500

(4 * .175) .70

• The second resonant frequency will be 1500 Hz

• The remaining resonances will be odd-numbered multiples of the lowest resonance:

• 2500 Hz, 3500 Hz, 4500 Hz, etc.

• Want proof?

Page 25: Resonance, Revisited (Again)

The Big Picture• The fundamental frequency of a speech sound is a complex periodic wave.

• In speech, a series of harmonics, with frequencies at integer multiples of the fundamental frequency, pour into the vocal tract from the glottis.

• Those harmonics which match the resonant frequencies of the vocal tract will be amplified.

• Those harmonics which do not will be damped.

• The resonant frequencies of a particular articulatory configuration are called formants.

• Different patterns of formant frequencies =

• different vowels

Page 26: Resonance, Revisited (Again)

Vowel Resonances

• The series of harmonics flows into the vocal tract.

• Those harmonics at the “right” frequencies will resonate in the vocal tract.

• fn = (2n - 1) * c

4L

• The vocal tract filters the source sound

lipsglottis

Page 27: Resonance, Revisited (Again)

“Filters”• In speech, the filter = the vocal tract

• This graph represents how much the vocal tract would resonate for sinewaves at every possible frequency:

• The resonant frequencies are called formants

Page 28: Resonance, Revisited (Again)

Source + Filter = Output

+

=

This is the source/filter

theory of speech production.

Page 29: Resonance, Revisited (Again)

Source + Filter(s)

Note:

F0 160 Hz

F1

F2

F3 F4

Page 30: Resonance, Revisited (Again)

Schwa at different pitches

100 Hz 120 Hz

150 Hz

Page 31: Resonance, Revisited (Again)

More Than Schwa

• Formant frequencies differ between vowels…

• because vowels are produced with different articulatory configurations

Page 32: Resonance, Revisited (Again)

Remember…• Vowels are articulated with characteristic tongue and lip shapes.

Page 33: Resonance, Revisited (Again)

Vowel Dimensions• For this reason, vowels have traditionally been

described according to four (pseudo-)articulatory parameters:

1. Height (of tongue)

2. Front/Back (of tongue)

3. Rounding (of lips)

4. Tense/Lax

= amount of effort?

= muscle tension?

Page 34: Resonance, Revisited (Again)

The Vowel Space

o

The Vowel Space

Page 35: Resonance, Revisited (Again)

Formants and the Vowel Space• It turns out that we can get to the same diagram in a different way…

• Acoustically, vowels are primarily distinguished by their first two formant frequencies: F1 and F2

• F1 corresponds to vowel height:

• lower F1 = higher vowel

• higher F1 = lower vowel

• F2 corresponds to front/backness:

• higher F2 = fronter vowel

• lower F2 = backer vowel

Page 36: Resonance, Revisited (Again)

Male Formant Averages

200

300

400

500

600

700

800

900

1000

10001500200025003000

F2

F1

[i][u]

[æ]

(From some old phonetics class data)

Page 37: Resonance, Revisited (Again)

Female Formant Averages

200

300

400

500

600

700

800

900

1000

10001500200025003000

F2

F1

[i] [u]

[æ]

(From some old phonetics class data)

Page 38: Resonance, Revisited (Again)

Combined Formant Averages

200

300

400

500

600

700

800

900

1000

10001500200025003000

F2

F1

(From some old phonetics class data)

Page 39: Resonance, Revisited (Again)

Women and Men• Both source and filter characteristics differ reliably between men and women

• F0: depends on length of vocal folds

shorter in women higher average F0

longer in men lower average F0

• Formants: depend on length of vocal tract

shorter in women higher formant frequencies

longer in men lower formant frequencies

Page 40: Resonance, Revisited (Again)

Prototypical Voices• Andre the Giant: (very) low F0, low formant frequencies

• Goldie Hawn/Pretty Tiffany: high F0, high formant frequencies

Page 41: Resonance, Revisited (Again)

F0/Formant mismatches• The fact that source and filter characteristics are independent of each other…

• means that there can sometimes be source and filter “mismatches” in men and women.

• What would high F0 combined with low formant frequencies sound like?

• Answer: Julia Child.

Page 42: Resonance, Revisited (Again)

F0/Formant mismatches• Another high F0, low formants example:

Roy Forbes, of Roy’s Record Room (on CKUA 93.7 FM)

• The opposite mis-match =

Popeye: low F0, high formant frequencies