Review Test 2

Ch 6, 7, 8ECE 2110

Western Michigan University

For the circuit shown solve for the transfer function H(s). R1 = 1.5k, C1 = 4.7mF, C2 = 6.2mF.

𝐴 .𝑣𝑜

𝑣 𝑖𝑛

= 1.5 𝑘1+ 𝑗𝜔 10.9𝜇 ∙1.5𝑘

+

vo

-

𝐸 .𝑣𝑜

𝑣𝑖𝑛= 𝑗 𝜔10.9𝜇 ∙1.5𝑘1+ 𝑗 𝜔10.9𝜇 ∙1.5𝑘

𝐶 .𝑣𝑜

𝑣 𝑖𝑛

= 11+ 𝑗 𝜔2.67𝜇 ∙1.5𝑘

𝐷 .𝑣𝑜

𝑣𝑖𝑛= 𝑗 𝜔2.67𝜇 ∙1.5𝑘1+ 𝑗 𝜔2.67𝜇 ∙1.5𝑘

𝐵 .𝑣𝑜

𝑣 𝑖𝑛

= 11+ 𝑗 𝜔10.9𝜇 ∙1.5 𝑘

𝑋 𝑐=1

𝑗𝜔𝐶

𝑣𝑜=𝑋 𝑐

𝑋 𝑐+𝑅𝑣 𝑖𝑛

𝑣𝑜=

1𝑗 𝜔𝐶1

𝑗𝜔𝐶+𝑅

𝑣 𝑖𝑛

𝐵 .𝑣𝑜

𝑣 𝑖𝑛

= 11+ 𝑗 𝜔10.9𝜇 ∙1.5 𝑘

ANS

For the diode circuit solve for the DC biases point. V+ = 3v, R1 = 750W, R2 = 250W, and Rs = 50W.

𝐼𝐷=3𝑣−0.7𝑣750

𝐼𝐷=3.07𝑚𝐴ANS

𝐴 .4.20𝑚𝐴

𝐸 .3.07𝑚𝐴

𝐶 .5.03𝑚𝐴

𝐷 .4.05𝑚𝐴

𝐵 .5.60𝑚𝐴

Solve for the DC Q-point current IE of the transistor. b = 110

𝐼𝐵=34𝜇 𝐴(𝛽+1)𝐼 𝐵= 𝐼𝐸

𝐼𝐸=3.77𝑚𝐴ANS

𝐴 .11.4𝑚𝐴

𝐸 .6.87𝑚𝐴

𝐶 .3.77𝑚𝐴

𝐷 .34𝜇 𝐴

𝐵 .3.4𝑚𝐴

Draw the AC circuit with the transistor replaced with the small signal model.

For the AC circuit of the transistor solve for the voltage vo/vi. b = 110

bib

ib

𝑖𝑏=𝑣 𝑖𝑛

1497

+

vo

-

𝑣𝑜=𝛽𝑖𝑏∙375

𝑣𝑜=110 ∙𝑣 𝑖𝑛

1497∙375

𝑣𝑜𝑣 𝑖𝑛

=27.6 𝑣𝑣

ANS

𝐴 .38.9𝑚𝐴 /𝑣

𝐸 .27.6𝑣 /𝑣

𝐶 .55 𝑣 /𝑣

𝐷 .110𝑣 /𝑣

𝐵 .55𝑚𝐴 /𝑣

Add the two hex numbers together in binary and convert the result to hex.

+FFA48

𝐸 .2𝐸4

𝐶 .𝐶 46

𝐷 .𝐷1𝐴

𝐵 .𝐵47

𝐵∨4∨7 1011

0∨𝐹∨𝐹 0000∨1111∨1111

𝐶 46

+

1100∨0011∨0110

ANS

0000 00001 10010 20011 30100 40101 50110 60111 71000 81001 91010 A1011 B1100 C1101 D1110 E1111 F

Convert the two dec numbers to binary. 300 and 40. Chose the answer for 40 in binary.

1110|0111

𝐸 .0001∨0100

𝐶 .0010∨1000

𝐷 .1000∨0010

𝐵 .0100∨100020 0

10 0

5 0

2.5 1

0 0

0.5 1

ANS

Subtract the two numbers given in binary and convert the results to hex.

𝐴 .42B

𝐸 .2𝐸4

𝐶 .104

𝐷 . 𝐴 47

𝐵 .823

0000 00001 10010 20011 30100 40101 50110 60111 71000 81001 91010 A1011 B1100 C1101 D1110 E1111 F

0

0-

1

1+

1

1

0+

01

-40