sample variability consider the small population of integers {0, 2, 4, 6, 8} it is clear that the...

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Sample Variability Consider the small population of integers {0, 2, 4, 6, 8} It is clear that the mean, μ = 4. Suppose we did not know the population mean and wanted to estimate it with a sample mean with sample size 2. (We will use sampling with replacement) We take one sample and get sample mean, ū 1 = (0+2)/2 = 1 and take another sample and get a sample mean ū 2 = (4+6)/2 = 5. Why are these sample means different? Are they good estimates of the true mean of the population? What is the probability that we take a random sample and get a sample mean that would exactly equal the true mean of the population? 1 Section 7.1, Page 137

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Page 1: Sample Variability Consider the small population of integers {0, 2, 4, 6, 8} It is clear that the mean, μ = 4. Suppose we did not know the population mean

Sample VariabilityConsider the small population of integers {0, 2, 4, 6, 8}It is clear that the mean, μ = 4. Suppose we did not know the population mean and wanted to estimate it with a sample mean with sample size 2. (We will use sampling with replacement)

We take one sample and get sample mean, ū1 = (0+2)/2 = 1 and take another sample and get a sample mean ū2 = (4+6)/2 = 5.

Why are these sample means different?

Are they good estimates of the true mean of the population?

What is the probability that we take a random sample and get a sample mean that would exactly equal the true mean of the population?

1Section 7.1, Page 137

Page 2: Sample Variability Consider the small population of integers {0, 2, 4, 6, 8} It is clear that the mean, μ = 4. Suppose we did not know the population mean

Sampling Distribution

Each of these samples has a sample mean, ū. These sample means respectively are as follows:

P(ū = 1) = 2/25 = .08P(ū = 4) = 5/25 = .20

2Section 7.1, Page 138

Page 3: Sample Variability Consider the small population of integers {0, 2, 4, 6, 8} It is clear that the mean, μ = 4. Suppose we did not know the population mean

Sampling Distribution

3Section 7.1, Page 138

Shape is normal

Mean of the sampling distribution = 4, the mean of the population

Page 4: Sample Variability Consider the small population of integers {0, 2, 4, 6, 8} It is clear that the mean, μ = 4. Suppose we did not know the population mean

Sampling Distributions and Central Limit Theorem

4Section 7.2, Page 141

Sample sizes ≥ 30 will assure

a normal distribution.

Alternate notation:

SE(x )

Page 5: Sample Variability Consider the small population of integers {0, 2, 4, 6, 8} It is clear that the mean, μ = 4. Suppose we did not know the population mean

Central Limit Theorem

5Section 7.2, Page 144

Page 6: Sample Variability Consider the small population of integers {0, 2, 4, 6, 8} It is clear that the mean, μ = 4. Suppose we did not know the population mean

Central Limit Theorem

6Section 7.2, Page 145

Page 7: Sample Variability Consider the small population of integers {0, 2, 4, 6, 8} It is clear that the mean, μ = 4. Suppose we did not know the population mean

Calculating Probabilities for the Mean

Kindergarten children have heights that are approximately normally distributed about a mean of 39 inches and a standard deviation of 2 inches. A random sample of 25 is taken. What is the probability that the sample mean is between 38.5 and 40 inches?

P(38.5 < sample mean <40) =NORMDIST 1LOWER BOUND = 38.5UPPER BOUND = 40MEAN =39

ANSWER: 0.8881

7Section 7.3, Page 147

=2 / 25 = 0.4

SE(x )

Page 8: Sample Variability Consider the small population of integers {0, 2, 4, 6, 8} It is clear that the mean, μ = 4. Suppose we did not know the population mean

Calculating Middle 90%

Kindergarten children have heights that are approximately normally distributed about a mean of 39 inches and a standard deviation of 2 inches. A random sample of 25 is taken. Find the interval that includes the middle 90% of all sample means for the sample of kindergarteners.

NORMDIST 2AREA FROM LEFT = 0.05MEAN = 39 ANSWER: 38.3421

NORMDIST 2AREA FROM LEFT = .95MEAN = 39 ANSWER: 39.6579

The interval (38.3 inches, 39.7 inches) contains the middle 90% of all sample means. If we choose a random sample, there is a 90% probability that it will be in the interval.

8Section 7.3, Page 147

2 / 25 = 0.4

2 / 25 = 0.4

Sampling Distribution

ux = 39

σ x =2

25

SE(x ) =

SE(x ) =

Page 9: Sample Variability Consider the small population of integers {0, 2, 4, 6, 8} It is clear that the mean, μ = 4. Suppose we did not know the population mean

Problems

9Problems, Page 149

Page 10: Sample Variability Consider the small population of integers {0, 2, 4, 6, 8} It is clear that the mean, μ = 4. Suppose we did not know the population mean

Problems

10Problems, Page 150

Page 11: Sample Variability Consider the small population of integers {0, 2, 4, 6, 8} It is clear that the mean, μ = 4. Suppose we did not know the population mean

Problems

11Problems, Page 151