sci. living sys.trascription unit i sck_21.01.15 (1)
TRANSCRIPT
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Overview of transcription, translation and
recombinant DNA technology
S. C. Kundu
Department of Biotechnology
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Eukaryotic cells
with a nucleus
• Nucleus
• Mitochondria• Chloroplast• Ribosomes• RER• SER• Golgi body• Cytoplasm
• acuoles
Prokaryotic cells
without a nucleus
• Cytoplasm
• Ribosomes• Nuclear !one• DN"• #lasmid• Cell Membrane• Mesosome• Cell $all
• Capsule %or slime layer&• 'lagellum
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DN" consists of t(o strands running anti)parallel and formingdouble hellical structure
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RN"• RN" is a polymer of ribonucleotides that contain ribose rather than
deo*yribose sugars.
• +he normal base composition is made up of guanine, adenine, cytosine,and uracil
• RN" is found in nucleus and cytoplasm
• +ypes of RN" - Messenger RN" %mRN"&
Ribosomal RN" % rRN"& +ransfer RN" %tRN"&
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'ormation of the peptide bond
O
N!
"#O
O
N!
"!O
+(o amino acid molecules4
the nature of the R group %R5
and R/& determines the amino
acid
O
N!
"#
O
O
N!
"!
O
+he molecules must be
orientated so that the
carbo*ylic acid group of one
can react (ith the amine group
of the other
O
N!
"#N
O
"!
O
O!
+he peptide bond forms (ith
the elimination of a (ater
molecule.
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SG
Y
A
V
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The levels of protein structure
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DNA
mRNA
Transcription
+he Central Dogma of Molecular Biology
Cell
Polypeptide
(protein)
Translation Ribosome
+his describes the flo( of information from DN" into RN" %most commonly
mRN"& through transcription %copying the same code from one molecule to
another&, and then e*pressing the code into a functional molecule by
translation %con3erting from a nucleic acid code into an amino acid code&.
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+R"NSCR6#+60N "ND +R"NS7"+60N-
#ro8aryotic 3s Eu8aryotic
SE#"R"+E C0M#"R+MEN+SC09#7ED
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7
Prokaryotic Gene Structure
Promoter CDS erminator
transcription
Genomic DNA
mRNA
protein
!R !R
translation
#romoter is a DN" se:uence usually present upstream of coding regions
(here RN" polymerase binds to initiates transcription.
Gene is the structural and
functional unit of heridity,
(hich carry genetic
information from onegeneration to ne*t. 6n
molecular terms Gene is a
part of chromosomes
%DN"&, (hich codes for
functional RN" or protein
Gene transcription in pro8aryotes
9+R %9ntranslated se:uences&- ;2 9+R contains ribosome binding sitesfor protein synthesis4
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RN" transcript is complementary
to template strand and identical
to coding strand
"e$uirement for transcription in
prokaryotesGene or DN" to be transcribed, RN" polymerase, rN+#sand cellular en3ironment
Di""erent genes are transcribed "rom di""erent strands
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Bacterium has
one RN"
polymerase tosynthesi=e all
three RN"-
%mRN", rRN",
tRN"&
RN" polymerase binds to promoter of a gene to initiate transcription
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1
Promoter
! Promoters se"uences can vary tremen#ously$
! RNA polymerase reco%ni&es hun#re#s of
#ifferent promoters
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Stages of +ranscription
• Chain 6nitiation
• Chain Elongation
• Chain +ermination
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Bacterial +ranscription 6nitiation
• #romoter recognition by RN" polymerase
> 'ormation of +ranscription Bubble by separating DN"
strands
> Bond formation bet(een rN+#s to start RN" synthesis
> Escape of transcription apparatus from promoter
RN" # l fi d t d 6 iti t
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o( RN" #olymerase finds promoter and 6nitiates
+ranscription
•Core en=yme can synthesi=e RN" on a DN" template but cannot initiate
transcription.
•Core polymerase loosely binds at random sites in DN" (ithout
discriminating promoter and other se:uences.
•Binding of sigma in the polymerase %holoen=yme& reduced its ability to
loose binding sites, and the en=ymes mo3es along the DN".
•$hen it reaches the promoter se:uences, sigma factor recogni=e
specifically )
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Finding and bindingthe promoter
Closed complex
formation
RNAP bound -40 to
+20
Open complexformation
RNAP unwinds from-10 to +2
Binding of 1st NTPRequires highpurine[NTP]
Addition of next NTPs
Requires lower
purine[NTPs]
Dissociation of sigmaAfter RNA chainis 6-10 NTPslong
initiation
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%ubse$uent
hydrolysis of PPi drives the
reaction forward
"NA strand
0.
0.
DNA strand
RN" Synthesis is in the ;# to
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RNA polymeraseelongation
'()*+(,-1./*0*0 *233*4
•During Elongation
RN" polymerase
un(inds DN" ahead
of it, transcribe theregion and re(inds
the DN" at the bac8
and RN" comes out
of the comple*.
•+ranscription occursin the +ranscription•Bubble at the rate of
;@ ntsec.
•Elongation continuestill Core en=ymes
reaches the
terminator
se:uences.
•
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+ranscription +ermination
+ranscription ends after a terminator is transcribed
>
+(o types of terminators in bacteria-
& Rho)dependent terminators
& Rho)independent terminators
7
Prokaryotic Gene Structure
Promoter CDS erminator
transcription
Ge nomic DNA
mRNA
protein
!R !R
translation
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Rho-Independent TranscriptionTermination
(depends on DNA sequence -NOT a protein factor)
Stem-loop structure
$hen a nascent RN" transcript contains a series of 9 residues at the
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Rho independent transcription termination
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+he termination function of factor
+he factor, a he*amer, is a "+#ase
and a helicase.
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Rho-Dependent Transcription Termination(depends on a protein AND a DNA sequence)
G/C -rich site
RNAP slows down
Rho helicasecatches up
Elongating complex is disrupted
5& Rho binds astretch of GC rich
se:uence of
nacent RN"
upstream of the
terminator .
/& Rho acts as
he*amer, brea8s
"+# and (ith the
energy mo3es
through RN" tocatch DN")RN"
hybrid and
polymerase
comple* and
terminates
transcription.
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Lactose operon: a regulatory gene and 3stuctural genes, and 2 control elements
lac$
Regulatory gene
lacZ lacY lacA DNA
m%RNA
&%'alactosidase
Permease
ransacetylase
Protein
Structural 'enesCis%actingelements
P lac 6 P lac O lac
The Lac operon
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5. $hen lactose is absent
• A repressor protein is continuously synthesi'ed( )t sits ona se$uence of DNA *ust in the lac operon, the 0perator site
• +he repressor protein blocks the #romoter site where
the "NA polymerase settles before it starts transcribing
Re%ulator
%ene lac operon
5perator
site
y aDN"
$ O
Repressor
protein
RNA
polymeraseloc*ed
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/. $hen lactose is present
• A small amount of a sugar allolactose is formed within
the bacterial cell( +his fits onto the repressor protein atanother active site allosteric site-
• +his causes the repressor protein to change its shape a conformational change-( )t can no longer sit on the
operator site( "NA polymerase can now reach itspromoter site and initiates transcription(
Promotor site
y aDN"
$ O
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Eu8aryotic transcription is much complicated
+hree different polymerases-
RN" polymerase 6- synthesi=es rRN" in the nucleolus.
RN" polymerase 66- synthesi=es mRN" in the nucleoplasm.
RN" polymerase 666- synthesi=es tRN", ;S rRN", small RN"s in the nucleoplasm
"ll eu8aryotic RN" polymerases ha3e 5/)5 subunits %aggregates of H;@@ 8D&.
Some subunits are common to all three RN" polymerases such as +B#.
Multiple promoter types -+"+" Bo*, 6nitiator elements,
CpG island for pol 6&,
core elements,
upstream core elements %pol 6&,%" bo*, B Bo*, C Bo* for pol 666&
•Each RN" polymerase recogni=es its o(n promoter
•Many proteins %transcription factors& are in3ol3ed in promoter
recognition by RN" #olymerase
Eu8aryotic +ranscription
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6
7ukaryotic Gene Structure
+# % Promoter ,xon- $ntron- ,xon. erminator / 0#
!R splice splice !R
transcription
translation
Poly A
protein
7ukaryote Promoter 8Pol 99:
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+ranscription by #olymerase 66
+hree Steps-
6ntiation-
Binding of transcription factors and #ol 66 to promoter,DN" strand separation and beginning of RN" synthesis.
Elongation-
Continuous process of RN" synthesis by RN" pol 66.
+ermination-
Ending of transcription after transcribing a poly " signalse:uence.
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+ i i i i
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+ranscription termination
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)n eukaryotes, the primary transcript pre m"NA- must be
modified by.
& addition of a ;2 cap
& addition of a
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ppp;JNpNp
pp;J
NpNp
G+#
##i
G;J
ppp;J
NpNp
methylating at '1
methylating at C.J o" the
"irst and second
nucleotides a"ter '
"orming +2%+2
triphosphate group
remo3ing
phosphate group
mGpppNpNp
mGpppm
/JNpm
/JNp
#i
Capping at ;2 end of mRN"
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! pA ' p!+2 02+2exon 02exon
intron
p'%O4
p'pA
' p! 02!+2 O4
first transesterification
+(ice transesterification
second transesterification
!+2 p! 02
p'pA
'O4
+2
02
Splicing mechanism
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DNA
;ytoplasm
Nucleus
Eukaryotic +ranscription
,xport
G AAAAAA
RNA
ranscription
Nuclear
pores
G AAAAAA
RNAProcessing
mRNA
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! http566777%class8unl8edu6biochem6gp.6m
9biology6animation6gene6gene9a.8html
http://www-class.unl.edu/biochem/gp2/m_biology/animation/gene/gene_a2.htmlhttp://www-class.unl.edu/biochem/gp2/m_biology/animation/gene/gene_a2.htmlhttp://www-class.unl.edu/biochem/gp2/m_biology/animation/gene/gene_a2.htmlhttp://www-class.unl.edu/biochem/gp2/m_biology/animation/gene/gene_a2.html
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+ranslation is the process of decoding a m"NAmolecule into a polypeptide chain or protein
+ranslation- #rotein synthesis
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•Transcription and translation ineukaryotic cells are separated inspace and time. Extensive processing of primaryRNA transcripts in eukaryotic cells.
+ranslation
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+ranslation
)t is process of protein synthesis assembly of amino
acids- using m"NA as template with the help of t"NAand ribosomes r"NA with several proteins-(
+herefore, it re$uires the participation of multiple types
of "NAs.
• messenger RN" %mRN"& carries the information from DNA thatencodes proteins
• ribosomal RN" %rRN"& is a structural component of theribosome
• transfer RN" %tRN"& carries amino acids to the ribosome fortranslation
+h G ti C d
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+he Genetic Code
+he genetic code is the (ay in (hich the nucleotide se:uence innucleic acids specifies the amino acid se:uence in proteins.
" codon is a set of < nucleotides that specifies a particular aminoacid.
+herefore, mRN" carries information from DN" in a three letter
genetic code.
• " three)letter code is used because there are /@ different aminoacids that are used to ma8e proteins.
• 6f a t(o)letter code (ere used there (ould not be enough codons to
select all /@ amino acids.
• +hat is, there are ? bases in RN", so ?/ %?* ?&54
(here as for < lettered code the number is ?
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S
A ; ? > 5 N 7
> A
S 7
S
4
P O
O
4O
O
O
C4.N4.N
N4
N
N
4O4
P
O
O
4O
O
O
C4.
N4.
N
N
N
N
4
P
O
O4
4O
O
O
C4.
N4.
N
NN
N
O
A 1odon
Guanine
A#enine
A#enine
Ar%inine
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GENE+6C C0DE
+herefore, there is a total of ? codons (ith mRN", 5
specify particular amino acid.
+he remaining three codons %9"", 9"G, L 9G"& are stop
codons, (hich signify the end of a polypeptide chain%protein&.
+his means there are more than one codon for each of
the /@ amino acids.
Besides selecting the amino acid methionine, the codon
"9G also ser3es as the initiator codon, (hich starts
the synthesis of a protein
Deciphering the Genetic code
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p g
Marshall Nirenberg, Khorana and their collegues deciphered the genetic code by
adding homopolymers such as 999, """, CCC, or co)polymers such as "C",
C"", ""C of synthetic nucleotide triplets to cell e*tracts containing /@ amino
acyl tRN", (hich are capable of limited translation.6n each e*pt. one amino acid is radioacti3ely labeled and rest 5 are unlabeled
and the reaction mi*ture are passed through filter. Since, ribosomes binds to filter
if the added trinucleotide caused the labeled aminoacyl tRN" to the ribosome,
then radioacti3ity (ould be detected on the filter %positi3e test& other(ise label
(ill pass through)a negati3e test)bind filter
RN" t i d hi h d f i id
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mRN" contains codons, (hich code for amino acids(
tRN" ) +ransfer RN"(
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Each tRN" molecule has / important sites of attachment.
•"nticodon binds to the codon on the mRN" molecule.
•"mino acid acceptor site attaches to a particular amino acid.
During protein synthesis, the anticodon of a tRN" molecule
base pairs (ith the appropriate mRN" codon.
t"NA Activation
tRNAStructure
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tRNA Structure
Aminoacyl tRNA synthetase
+here are !2 different aminoacyl t"NA synthetases, one for each amino acid(
Rib
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Ribosome
• Are made up of ! subunits, a large one and a smaller one,
each subunit contains ribosomal RN" %rRN"& L proteins(
• Protein synthesis starts when the t(o subunits bind tomRN"(
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+he ribosome hasmultiple t"NA bindingsites.
& # site & binds the t"NAattached to the growingpeptide chain
& " site & binds the t"NAcarrying the ne0t aminoacid
& E site & binds the t"NAthat carried the last aminoacid
T lti h 3St h ii
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Translation has 3 Steps, each requiringdifferent supporting proteins
•Initiation
–Requires Initiation Factors
•Elongation
–Requires Elongation Factors
•Termination
–Requires Termination Factor
I
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Initiation:
1. Binding of initiationfactors to small subunit.Of ribosome andattachment to mRNA
2. Binding of first tRNAto mRNA attached tosmall subunit.
3. Binding of largesubunit.
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First step in elongation
(bacteria ):
Binding of the secondaminoacyl-tRNA
S d t i
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Second step in
elongation:
Formation of the first
peptide bond
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hird step in elongation:
translocation
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A7
Large
subunitP
Small
subunit
+ranslation / )nitiation
":et
!AC
'A'888C!%A!'%%!!C%%C!!%%A'!%%''!%%A'A%%'C!%%'!A%%!'A%A 'CA888AAAAAA@mRNA
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A7
Ribosome P ! C !
Arg
Aminoacyl tRNA
PheLeu
:et
Ser
'ly
Polypeptide
CCA
+ranslation / Elongation
'A'888C!%A!'%%!!C%%C!!%%A'!%%''!%%A'A%%'C!%%'!A%%!'A%A 'CA888AAAAAA@mRNA
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A7
Ribosome P
PheLeu
:et
Ser
'ly
Polypeptide
Arg
Aminoacyl tRNA
!C!CCA
+ranslation / Elongation
'A'888C!%A!'%%!!C%%C!!%%A'!%%''!%%A'A%%'C!%%'!A%%!'A%A 'CA888AAAAAA@mRNA
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A7
Ribosome P
CCA
Arg
!C!
PheLeu
:et
Ser
'ly
Polypeptide
+ranslation / Elongation
'A'888C!%A!'%%!!C%%C!!%%A'!%%''!%%A'A%%'C!%%'!A%%!'A%A 'CA888AAAAAA@mRNA
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A7
Ribosome P
+ranslation / Elongation
Aminoacyl tRNA
C ' A
Ala
CCA
Arg
!C!
PheLeu
:et
Ser
'ly
Polypeptide
'A'888C!%A!'%%!!C%%C!!%%A'!%%''!%%A'A%%'C!%%'!A%%!'A%A 'CA888AAAAAA@mRNA
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A7Ribosome
P
+ranslation / Elongation
C C A
Arg
!C!
PheLeu
:et
Ser
'ly
Polypeptide
C'A
Ala
'A'888C!%A!'%%!!C%%C!!%%A'!%%''!%%A'A%%'C!%%'!A%%!'A%A 'CA888AAAAAA@mRNA
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Termination:
1. Binding of
Release Factor toStop Codon UGA,UAA, UAG.
2. Disassembly
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Overview of Prokaryotic Translation
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Summary
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Summary
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http-((()class.unl.edubiochemgp/
mObiologyanimationgenegeneOa
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Recombinant DN"
• #roduction of a uni:ue DN" molecule by
Poining together t(o or more DN" fragmentsnot normally associated (ith each other
• DN" fragments are usually deri3ed fromdifferent biological sources
•" series of procedures used to recombineDN" segments and are called Recombinant
DN" +echnology
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History of recombinant DNAtechnology
Recombinant DNA technology is one
of the recent advances inbiotechnology, which was developedby two scientists named Boyer and
Cohen in 197!
DNA Bi
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DNA recomBinant
technolo%y
asic principle o" recombinant DNA
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p p
technology
0ne DN" molecule %called insert& is isolated from one
sources and then this DN" is inserted into another DN"
molecule called 13ector2
Mostly bacterial plasmid is used as 3ector
+he recombinant 3ector is then introduced into a host
cell (here it replicates, transcribes and translates to
produce protein.
3asic steps in "ecobinant DNA
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3asic steps in "ecobinant DNA
+echnology
#( )solate the gene
!( )nsert it in a host using a vector plasmid-
4( Produce as many copies of the host as
possible
5( %eparate and purify the product of the gene
S+E# 5 D6GES+60N 0' DN"
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S+E# 5. D6GES+60N 0' DN"
S"M#7E +0 6S07"+E GENE
S+E# / D6GES+60N 0'
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S+E# /. D6GES+60N 0'
#7"SM6D DN"
%tep 4. )nserting gene into digested
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6
Recombinant
#lasmid
E. co R5
digestedpector
!"co R6 digested 6nsert% gene&
%tep 4. )nserting gene into digested
vector to create recombinant plasmid
7igase
%tep 5. inserting recombinant plasmid into
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"mpicillin resistance gene %"mpr &
and target gene on bacterial plasmid
Bacterial clones
+ransformation mi*ture is plated
on to agar plate containing
"mpicillin
0nly E. coli containing plasmid
sur3i3e on "mpicillin plates
6ndi3idual colony is selected and
cultured to amplify recombinant DN"
#lasmid enters some
bacteria
host E. coli bacteria and selection
Overall cloning strategy
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7Ctracte# DNA from
any or%anism
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Applications of
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Applications of
Recombinant DNA
"echnology#arge$scale prod%ction of h%man
proteins by genetically
engineered bacteria!
&%ch as ' ins%lin, (rowthhormone, )nterferons and
Blood clotting factors *+))) )-.
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/rod%ction of 0%man
)ns%lin*???
.1) Obtaining the human insulin gene0%man ins%lin gene can be obtained bymaing a complementary DNA *cDNA. copyof the messenger RNA *mRNA. for h%manins%lin!
) i i h h i li
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2)Joining the human insulin geneinto a plasmid( ) vector
"he bacterial plasmids and the cDNA aremi2ed together! "he h%man ins%lin gene
*cDNA. is inserted into the plasmid thro%gh
complementary base pairing at sticy ends!
3)I t d i th bi t
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3)Introducing the recombinant
DNA plasmids into bacteria
"he bacteria E.coli is %sed as the host cell! )f E.coli and the recombinant plasmids are mi2ed
together in a test$t%be!
4)electing the bacteria !hich
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4)electing the bacteria !hich
have ta"en up the correct
piece o# DNA"he bacteria are spread onto n%trient agar! "he
agar also contains s%bstances s%ch as an
antibiotic which allows growth of only the
transformed bacteria!
#urification of recombinant protein by affinity
h h
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chromatography