sm9_7

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PROBLEM 9.7 KNOWN: Thin, vertical plates of length 0.15m at 54°C being cooled in a water bath at 20°C. FIND: Minimum spacing between plates such that no interference will occur between free-convection oundary layers. b SCHEMATIC: ASSUMPTIONS: (a) Water in bath is quiescent, (b) Plates are at uniform temperature. PROPERTIES: Table A-6, Water (T f = (T s + T )/2 = (54 + 20)°C/2 = 310K): ρ = 1/v f = 993.05 g/m 3 , µ = 695 ×10 -6 Ns/m 2 , ν = µ/ρ = 6.998 × 10 -7 m 2 /s, Pr = 4.62, β = 361.9 × 10 -6 K -1 . k ANALYSIS: The minimum separation distance will be twice the thickness of the boundary layer at the trailing edge where x = 0.15m. Assuming laminar, free convection boundary layer conditions, the similarity parameter, η, given by Eq. 9.13, is ( ) y 1/4 Gr /4 x x η = where y is measured normal to the plate (see Fig. 9.3). According to Fig. 9.4, the boundary layer thickness occurs at a value η 5. It follows then that, ( ) 1/4 y x Gr /4 bl x η = where ( ) 3 g T T x s Gr x 2 β ν = ( ) ( ) ( ) 2 3 2 6 1 7 2 Gr 9.8 m/s 361.9 10 K 54 20 K 0.15m / 6.998 10 m /s 8.310 10 . x = × × × × = × 8 5 0.15m 8.310 10 /4 6.247 10 m 6.3 mm bl < Hence, y ( ) 1/4 8 3 = × × = × = and the minimum separation is < d 2 y 2 6.3 mm 12.6 mm. bl = = × = COMMENTS: According to Eq. 9.23, the critical Grashof number for the onset of turbulent conditions in the boundary layer is Gr x,c Pr 10 9 . For the conditions above, Gr x Pr = 8.31 × 10 8 × 4.62 = 3.8 × 10 9 . We conclude that the boundary layer is indeed turbulent at x = 0.15m and our calculation is only an estimate which is likely to be low. Therefore, the plate separation should be greater than 12.6 mm.

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  • PROBLEM 9.7 K NOWN: Thin, vertical plates of length 0.15m at 54C being cooled in a water bath at 20C. FIND: Minimum spacing between plates such that no interference will occur between free-convection

    oundary layers. b SCHEMATIC:

    A SSUMPTIONS: (a) Water in bath is quiescent, (b) Plates are at uniform temperature.

    PROPERTIES: Table A-6, Water (Tf = (Ts + T)/2 = (54 + 20)C/2 = 310K): = 1/vf = 993.05 g/m

    3, = 695 10-6 Ns/m2, = / = 6.998 10-7 m2/s, Pr = 4.62, = 361.9 10-6 K-1. k ANALYSIS: The minimum separation distance will be twice the thickness of the boundary layer at the trailing edge where x = 0.15m. Assuming laminar, free convection boundary layer conditions, the similarity parameter, , given by Eq. 9.13, is ( )y 1/ 4Gr / 4xx = where y is measured normal to the plate (see

    Fig. 9.3). According to Fig. 9.4, the boundary layer thickness occurs at a value 5. I t follows then that,

    ( ) 1/ 4y x Gr / 4bl x =

    where ( ) 3g T T xsGrx 2

    =

    ( ) ( ) ( )232 6 1 7 2Gr 9.8 m/s 361.9 10 K 54 20 K 0.15m / 6.998 10 m / s 8.310 10 .x = = 85 0.15m 8.310 10 / 4 6.247 10 m 6.3 mmbl

    <

    Hence, y ( ) 1/ 48 3 = = = a nd the minimum separation is

    < d 2 y 2 6.3 mm 12.6 mm.bl= = = COMMENTS: According to Eq. 9.23, the critical Grashof number for the onset of turbulent conditions in the boundary layer is Grx,c Pr 109. For the conditions above, Grx Pr = 8.31 108 4.62 = 3.8 109. We conclude that the boundary layer is indeed turbulent at x = 0.15m and our calculation is only an estimate which is likely to be low. Therefore, the plate separation should be greater than 12.6 mm.

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