solutions and gases calculations (2)

12
Lone Star Chemistry Solutions A Dozen or More A Dozen or More Calculations Calculations Gases Gases Mason, Koeck, and Kulhanek Mason, Koeck, and Kulhanek

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Solutions and Gases Calculations presented by Diana Mason, Deborah Koeck and Joyce Kulhanek, ACT2 2010 The TEA has issued and implemented major revisions to the chemistry TEKS. Chemistry is usually the first course students take that requires them to understand how to solve problem that can't just simply be memorized. Even though these new standards have been aligned with algebra I, the actual use of this knowledge is in the middle to higher levels of Bloom's Taxonomy (application, analysis and synthesis). There is also a new emphasis on mathematics that will be incorporated into the Chemistry STAAR exams. This workshop will take 12 (or more) calculations from the revised TEKS that are also documented in the Texas College and Career Readiness Standards and will share teaching suggestions and activities supporting calculations of pH, redox processes, Dalton's law of partial pressure and the ideal gas law.

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Page 1: Solutions and Gases Calculations (2)

Lone Star Chemistry Solutions

A Dozen or More A Dozen or More CalculationsCalculations

GasesGasesMason, Koeck, and KulhanekMason, Koeck, and Kulhanek

Page 2: Solutions and Gases Calculations (2)

Lone Star Chemistry Solutions

BCCEBCCEAugust 1-5August 1-5

University of University of North TexasNorth Texas

Denton, TexasDenton, Texas

Page 3: Solutions and Gases Calculations (2)

Lone Star Chemistry Solutions

TEKS Development TEKS Development and Correlation to and Correlation to

CCRSCCRS Lone Star Lone Star Chemistry Chemistry SolutionsSolutions

https://callevents.unt.edu/ei/getdemo.ei?https://callevents.unt.edu/ei/getdemo.ei?id=3&s=_3000VYEX3id=3&s=_3000VYEX3

Page 4: Solutions and Gases Calculations (2)

Lone Star Chemistry Solutions

EngagementEngagement

GasesGases

Dynamic Diana’s Daring Dynamic Diana’s Daring DemoDemo

Page 5: Solutions and Gases Calculations (2)

Lone Star Chemistry Solutions

ExplorationExploration

Boyle’s LawBoyle’s Law

The pressure of a gas at The pressure of a gas at constant temperature is constant temperature is directly proportional to its directly proportional to its volume.volume.

PV= kPV= k

Page 6: Solutions and Gases Calculations (2)

Lone Star Chemistry Solutions

ExplorationExploration

Boyle’s LawBoyle’s Law

A gas that is at a constant A gas that is at a constant temperature has a volume of temperature has a volume of 5.0 L at a pressure of 2 atm. 5.0 L at a pressure of 2 atm. What is the volume of the same What is the volume of the same gas if the pressure is increased gas if the pressure is increased to 3 atm.?to 3 atm.?

Page 7: Solutions and Gases Calculations (2)

Lone Star Chemistry Solutions

ExplorationExploration

Boyle’s LawBoyle’s Law

A gas that is at a constant A gas that is at a constant temperature has a volume of temperature has a volume of 9.0 L at a pressure of 2 atm. 9.0 L at a pressure of 2 atm. What is the pressure of the What is the pressure of the same gas if the volume is same gas if the volume is decreased to 3.0 L?decreased to 3.0 L?

Page 8: Solutions and Gases Calculations (2)

Lone Star Chemistry Solutions

ExplanationExplanation

Conceptual Conceptual UnderstandingUnderstandingBoyle’s LawBoyle’s Law

5.0 L X 2 atm = 3.3 L 3 atm

P 1V1 = P2 V2

V2 = P1 V1

P2

= 5.0 L X 2 atm = 3.3 L 3 atm

Page 9: Solutions and Gases Calculations (2)

Lone Star Chemistry Solutions

ExplanationExplanation

Conceptual Conceptual UnderstandingUnderstandingBoyle’s Law #2Boyle’s Law #2

2 atm X 9.0 L = 6 atm 3.0 L

P 1V1 = P2 V2

P2 = P1 V1

V2

= 2 atm X 9.0 L = 6 atm 3.0 L

Page 10: Solutions and Gases Calculations (2)

Lone Star Chemistry Solutions

ElaborationElaboration

Derivation of Derivation of Graham’s Law of Graham’s Law of DiffusionDiffusion

Materials:

Glass Tubes 50-80 cm in length6 M HCl6 M NH4OHMeter StickCotton Balls

Page 11: Solutions and Gases Calculations (2)

Lone Star Chemistry Solutions

EvaluationEvaluation

What is the What is the Concentration?Concentration?Using the expression for kinetic energy,Using the expression for kinetic energy,

KE = ½ m vKE = ½ m v22

Derive Graham’s Law of Diffusion.Derive Graham’s Law of Diffusion.

Page 12: Solutions and Gases Calculations (2)

Lone Star Chemistry Solutions

A Dozen or More A Dozen or More CalculationsCalculations

Additional ConceptsAdditional ConceptsCharles’ Law, Dalton’s Law, Ideal Gas Law, Charles’ Law, Dalton’s Law, Ideal Gas Law,

Gas StoichiometryGas Stoichiometry