solving linear systems algebraically
DESCRIPTION
Solving Linear Systems Algebraically. Solving Linear Systems Algebraically. Substitution - Section 3.2. Steps in Substitution. Steps: SOLVE for one equation into one variable REPLACE one equation into other equation SUBSTITUTE the value into either equation CHECK the solution. - PowerPoint PPT PresentationTRANSCRIPT
Solving Linear Systems Algebraically
Substitution - Section 3.2
04/21/23 04:433-2 - Solving Systems through
Substitution1
Solving Linear Systems Algebraically
Steps in Substitution
• Steps:1.SOLVE for one equation into one variable2.REPLACE one equation into other equation3.SUBSTITUTE the value into either equation4.CHECK the solution
04/21/23 04:433-2 - Solving Systems through
Substitution2
Example 1• Solve using Substitution
04/21/23 04:433-2 - Solving Systems through
Substitution3
2 9
3 4 8
x y
x y
2 9
3 4 8
x y
x y
1. SOLVE for one equation into one variable
2 9y x
04/21/23 04:433-2 - Solving Systems through
Substitution
4
2 9
3 4 8y
x y
x
23 4( 89)xx
2 9y x
3 8 36 8x x 11 36 8x
11 44x
4x
2. REPLACE one equation into other equation
04/21/23 04:433-2 - Solving Systems through
Substitution5
2 9
3 4 8
x y
x y
3. SUBSTITUTE the value into either equation
(43 ) 4 8y
4x
3 4 8x y
12 4 8y 4 4y
1y
(4,1)
Example 1• Solve using Substitution
04/21/23 04:433-2 - Solving Systems through
Substitution6
2 9
3 4 8
x y
x y
4. CHECK the solution2 9
3 4 8
x y
x y
2(4) (1) 9 3(4) 4(1) 8
12 49 89
8 8
(4,1)
04/21/23 04:433-2 - Solving Systems through
Substitution7
3 2 8 2x x
2 8y x
5 8 2x5 10x
2x
Example 2• Solve using Substitution
2 8y x
2( 2) 8y
4y
( 2,4)
2 8
3 2
x y
x y
Example 2• Solve using Substitution
04/21/23 04:433-2 - Solving Systems through
Substitution8
4. CHECK the solution
2( 2) (4) 4 4 8
3( 2) (4) 6 4 2
( 2,4)
2 8
3 2
x y
x y
04/21/23 04:433-2 - Solving Systems through
Substitution9
3 63 6yy
3x y
3 9 6 6y y 3 9 6y
3 3y
1y
Your Turn• Solve using Substitution
4 4 12
3 6 6
x y
x y
3x y
1 3x
4y
(4,1)
04/21/23 04:433-2 - Solving Systems through
Substitution10
25 6( 2) 9xx
2 2y x
5 12 12 9x x 7 12 9x
7 21x
3x
Example 3• Solve using Substitution
5 6 9
2 2
x y
x y
2 2y x
2 3 2y
4y
(3, 4)
Example 4
A coffee blend contains Sumatra beans which cost $5/lb, and Kona beans, which cost $13/lb. If the blend costs $10/lb, how much of each type of coffee is in 50 lb of the blend?
04/21/23 04:433-2 - Solving Systems through
Substitution11
Let x represent the amount of the Sumatra beans in the blend.Let y represent the amount of the Kona beans in the blend.
Example 4A coffee blend contains Sumatra beans which cost $5/lb, and Kona beans,
which cost $13/lb. If the blend costs $10/lb, how much of each type of coffee is in 50 lb of the blend?
04/21/23 04:433-2 - Solving Systems through
Substitution12
Write one equation based on the amount of each bean:Amount of Sumatra
beans plus amount of Kona
beans equals
x y
50.
50+ =
Write another equation based on cost of the beans:Cost of Sumatra
beans pluscost of Kona
beans equals
5x 13y
cost of beans.
10(50)+ =
Example 4A coffee blend contains Sumatra beans which cost $5/lb, and Kona beans,
which cost $13/lb. If the blend costs $10/lb, how much of each type of coffee is in 50 lb of the blend?
04/21/23 04:433-2 - Solving Systems through
Substitution13
Solve the system.x + y = 50
5x + 13y = 500
x + y = 50
y = 50 – x
First equation
5x + 13(50 – x) = 500
5x + 650 – 13x = 500–8x = –150 x = 18.75
Solve the first equation for y.
Substitute (50 – x) for y.Distribute.Simplify.
Example 4A coffee blend contains Sumatra beans which cost $5/lb, and Kona beans,
which cost $13/lb. If the blend costs $10/lb, how much of each type of coffee is in 50 lb of the blend?
04/21/23 04:43 3-2 - Solving Systems through Substitution 14
Substitute the value of x into one equation.
Substitute x into one of the original equations to solve for y.
18.75 + y = 50
y = 31.25 Solve for y.
The mixture will contain 18.75 lb of the Sumatra beans and 31.25 lb of the Kona beans.
Solve the system.x + y = 50
5x + 13y = 500
y = 31.25
(18.75, 31.25)
Assignment
Page 194 (2-5, 15-18)
04/21/23 04:433-2 - Solving Systems through
Substitution15