theory of radio wave vibration sensorrev2optoelec-engineering.com/tech/theory of radio wave...author...
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-
Confidentia
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Copyright by Opto-Electronic Engineering Corporation. All rights reserved.
At ANT position, x=0. Then equation of transmitter source electromagnetic wave is eq.- 3
The reflected electromagnetic wave is received at ANT x=0 with the phase delay relative to the transmitter source wave. The equation of received electromagnetic wave is eq.- 4
Here, φr is a phase shift by reflection which has π[rad] in the case of ideal metal surface. The distance R(t) is expressed with following equation. eq.- 5
Only assumed that having a mono-tone vibration with frequency fv. Then the received electro- magnetic wave is
eq.- 6
3. Detecting method The detecting system is noted below.
Fig.- 2 The detecting system
( )000 2cos)( ϕπ +⋅⋅= tfAtytx
( )( )
( ) ⎟⎟⎠
⎞⎜⎜⎝
⎛++⋅−⋅⋅=
++⋅−⋅⋅=
00
00
000
222cos
22cos)(
ϕϕλππ
ϕϕπ
r
rrx
tRtfB
tRktfBty
( ) ( ) ( )tfRRtRRtR v⋅⋅Δ+=Δ+= π2sin000
( )( )
( ) ⎟⎟⎠
⎞⎜⎜⎝
⎛++⋅−⋅⋅
Δ⋅−⋅⋅=
⎟⎟⎠
⎞⎜⎜⎝
⎛++⋅⋅Δ+⋅−⋅⋅=
0000
000
0000
00
42sin4
2cos
2sin42cos)(
ϕϕλππ
λπ
π
ϕϕπλππ
rv
rvrx
RtfR
tfB
tfRRtfBty
×
ANT
ANT
Diode Mixer
Transmtted wave
Oscilator
Local OscilatorReceived wave
DopplerSignal
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The detecting method applies the homodyne detection which has local oscillator frequency f0 same as transmitted wave’s frequency. The homodyne detection applies the mixing operation for the trans- mitted wave and for the received wave. The equation of detected signal is obtained by multiplying eq.- 3 and eq.- 6, and then is expressed by the following equation such as below.
eq.- 7
Here, replaced the each terms such as the following, eq.- 8
Then eq.- 7 becomes the following with eliminating double high-frequency term 2*f0 eq.- 9
It is shown the process of detecting a mechanical vibration by radio wave in Fig.- 4 with a fringe phenomena of Fig.- 3. It is discussed with more detail at the section 4. Please check them in the next.
( ) ( ) ⎟⎟⎠
⎞⎜⎜⎝
⎛++⋅−⋅⋅
Δ⋅−⋅⋅×+⋅⋅=
×=
0000
000000
det
42sin4
2cos2cos
)()()(
ϕϕλππ
λπ
πϕπ rv
rxtx
RtfR
tfBtfA
tytyty
( ) 0000
0 42sin4
ϕϕλππ
λπ
++⋅−⋅⋅Δ⋅
−= rv RtfR
B
( ) ( )
( ) ( )
( )
( ) ⎟⎟⎠
⎞⎜⎜⎝
⎛+⋅−⋅⋅
Δ⋅−⋅⋅=
−⋅⋅≈
−+++⋅⋅⋅=
+⋅⋅×+⋅⋅=
×=
rv
rxtx
RtfR
BA
BBA
BBtfBA
BtfBtfA
tytyty
ϕλππ
λπ
ϕ
ϕϕπ
πϕπ
000
000
000
00000
00000
det
42sin4
cos21
cos21
cos22cos21
2cos2cos
)()()(
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4. Relationship between a fringe phenomena of received signal strength and the distance
When no mechanical vibration has occurred, the eq.- 9 becomes the following. eq.- 10
We examine the relationship with distance parameter R, then we get these results in Fig.- 3. We assumed that A0*B0/2=1. Here, λ0=12.465mm, f0=24.05GHz. So the amplitude of a mechanical vibration is limited up to ±1.5mm.
eq.- 11
Fig.- 3 a fringe phenomena with distance parameter (f0=24.05GHz)
We have to take the relationship about the setting position x=R0 from the radio wave source ANT location to the reflection surface into consideration. The location of R0 affects distortion of the detected signal. That is, the bad position of R0 occur a large distortion for the detected signal. The worst condition about position of R0 converts the detected signal into double frequency 2*fv. So if we want to measure the precise signal shape for the detected signal, we have to adjust the position R0 properly.
⎟⎟⎠
⎞⎜⎜⎝
⎛+⋅−⋅⋅= rRBAty ϕλ
π0
000det
4cos21)(
‐1.5
‐1
‐0.5
0
0.5
1
1.5
‐10 ‐9 ‐8 ‐7 ‐6 ‐5 ‐4 ‐3 ‐2 ‐1 0 1 2 3 4 5 6 7 8 9 10
Normalized
Amplitud
e of detected signal [A.U.]
Relative displacement [mm]
[ ]mmR 5.10 ±≤Δ
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Fig.- 4 Process of detecting a mechanical vibration by radio wave
We have to take the relationship about the setting position x=R0 from the radio wave source ANT location to the reflection surface into consideration. The location of x=R0 affects distortion of the detected signal. That is, the bad position of R0 occur a large distortion for the detected signal. The worst condition about position of R0 converts the detected signal into double frequency 2*fv. So if we want to measure the precise signal shape for the detected signal, we have to adjust the position R0 properly. One of the detecting systems is the I,Q-channel type which detects the radio wave signal with orthogonalization by π/2 phase shift. (See Fig.- 5) The fringe phenomena for the detected I,Q-ch signals is in Fig.- 6. We are able to select a proper channel, I-ch or Q-ch in order to get a less distorted signal. Namely the most distorted signal position for I-ch gives the least distorted signal position for Q-ch. Vice versa. See Fig.- 6 carefully. So the way how to avoid getting the distorted signal is to select either proper channel I-ch/Q-ch, or to adjust the location of x=R0 such as by slightly rotating the ANT direction with camera motor platform stage. We are able to discriminate a proper position of distance R0 with maximum amplitude of detected signal ydet with a least distortion.
‐1.5
‐1
‐0.5
0
0.5
1
1.5
‐10 ‐9 ‐8 ‐7 ‐6 ‐5 ‐4 ‐3 ‐2 ‐1 0 1 2 3 4 5 6 7 8 9 10
Normalized
Amplitud
e of detected signal [A.U.]
Relative displacement [mm]
time
time
Detected Signal
Mechanical Vibration
-
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Fig.- 5 I,Q channel type of detector
Fig.- 6 fringe phenomena for the detected I,Q-ch signals
×
ANT
ANT
Diode Mixer
Transmission wave
Oscilator
Local Oscilator Received wave
DopplerSignal I
×
Diode Mixer
Local Oscilator
DopplerSignal Q
π/2
‐1.5
‐1
‐0.5
0
0.5
1
1.5
‐10 ‐9 ‐8 ‐7 ‐6 ‐5 ‐4 ‐3 ‐2 ‐1 0 1 2 3 4 5 6 7 8 9 10
Normalized
Amplitud
e of detected signal [A.U.]
Relative displacement [mm]
I‐ch
Q‐ch
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It is going to calculate properly the harmonic components of eq.- 9. Here, φr=π. Then
eq.- 12
It is applied Bessel function formula to eq.- 12. (m = integer) eq.- 13
eq.- 14
Jn(x) is Bessel functions of the first kind. (m,k are positive integer) eq.- 15
Fig.- 7 Bessel function of the first kind
( )
( ) ( )
( ) ( )⎟⎟⎠
⎞⎜⎜⎝
⎛⋅⋅
Δ⋅⎟⎟⎠
⎞⎜⎜⎝
⎛⋅+⎟⎟
⎠
⎞⎜⎜⎝
⎛⋅⋅
Δ⋅⎟⎟⎠
⎞⎜⎜⎝
⎛⋅
−=
⎟⎟⎠
⎞⎜⎜⎝
⎛⋅⋅
Δ−⋅⎟⎟
⎠
⎞⎜⎜⎝
⎛−⋅+⎟⎟
⎠
⎞⎜⎜⎝
⎛⋅⋅
Δ−⋅⎟⎟
⎠
⎞⎜⎜⎝
⎛−⋅
−=
⎟⎟⎠
⎞⎜⎜⎝
⎛⎟⎟⎠
⎞⎜⎜⎝
⎛⋅
Δ+⋅−⋅
−=
tfRRBA
tfRRBA
tfRRBA
tfRRBA
tfRRRBA
ty
vv
vv
v
πλπ
λπ
πλπ
λπ
πλπ
λπ
πλπ
λπ
πλπ
2sin4
sin4
sin2
2sin4
cos4
cos2
2sin4
sin4
sin2
2sin4
cos4
cos2
2sin14
cos2
)(
0
0
0
000
0
0
0
000
0
0
0
000
0
0
0
000
0
0
0
000det
( )( ) ( ) ( ) ( )∑∞
=
⋅⋅+=⋅1
20 2cos2sincosm
m mxJxJx θθ
( )( ) ( ) ( )( )∑∞
=+ +⋅⋅=⋅
012 12sin2sinsin
mm mxJx θθ
‐0.6
‐0.4
‐0.2
0
0.2
0.4
0.6
0.8
1
1.2
0 1 2 3 4 5 6 7 8 9 10
Bessel fu
nction
Jm(x)
x
Bessel function of the first kind
J0
J1
J2
J3
J4
J5
( ) ( )( )km
k
k
mx
mkkxJ
2
0 2!!1 +∞
=⎟⎠⎞
⎜⎝⎛⋅
+⋅−
= ∑
( ) ( )( )km
k
k
mx
mkkxJ
2
0 2!!1 +∞
=⎟⎠⎞
⎜⎝⎛⋅
+⋅−
= ∑
-
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Here we replace each parameter such as following. eq.- 16
eq.- 17
Then eq.- 12 becomes eq.- 18
And then, eq.- 19
a) Case of No vibration ΔR0=0, x=0
If no vibration x=0 occurs and the position R0 = mπ*λ0/ (4π), then we get from eq.- 19. eq.- 20
If no vibration x=0 occurs and the position R0 = (m+1/2)π*λ0/ (4π), then we get from eq.- 19. eq.- 21
That is meaning that J0(x) expresses DC component. And J1(x) expresses fundamental frequency fv of vibration wave, J2(x) is 2nd harmonic vibration 2*fv, J3(x) is 3rd harmonic vibration 3*fv, and so on.
b) Case of which vibration occurs at position R0 = (m+1/2)π*λ0/ (4π) The best position of R0 with a least distorted vibration signal is R0 = (m+1/2)π*λ0/ (4π) as will be noted from Fig.- 4, and gives us the equation eq.- 22 at R0 = (m+1/2)π*λ0/ (4π). eq.- 22
The eq.- 22 includes a fundamental vibration mode with frequency fv expressed by J1(x). The parameter x indicates a depth of vibration strength with ΔR0. When the depth ΔR0 of vibration is increasing with the condition R0 = (m+1/2)π*λ0/ (4π), the a fundamental vibration component is
tf v⋅= πθ 2
0
04λπ R
xΔ
=
( )( ) ( )( )θλπ
θλπ
sinsin4
sin2
sincos4
cos2
)(0
000
0
000det ⋅⋅⎟⎟
⎠
⎞⎜⎜⎝
⎛⋅+⋅⋅⎟⎟
⎠
⎞⎜⎜⎝
⎛⋅
−= x
RBAx
RBAty
( ) ( ) ( )
( ) ( )( )⎭⎬⎫
⎩⎨⎧
+⋅⋅⋅⎟⎟⎠
⎞⎜⎜⎝
⎛⋅+
⎭⎬⎫
⎩⎨⎧
⋅⋅+⋅⎟⎟⎠
⎞⎜⎜⎝
⎛⋅
−=
∑
∑∞
=+
∞
=
012
0
000
120
0
000det
12sin24
sin2
2cos24
cos2
)(
mm
mm
mxJRBA
mxJxJRBA
ty
θλπ
θλπ
( )2
012
)( 00000
detBA
JBA
tymm
=⋅⋅=
( ) ( )( ) 012sin0212
)(0
1200
det =⎭⎬⎫
⎩⎨⎧
+⋅⋅⋅⋅= ∑∞
=+
mm mJ
BAty θ
( ) ( )( )⎭⎬⎫
⎩⎨⎧
+⋅⋅⋅±
= ∑∞
=+
012
00det 12sin22
)(m
m mxJBA
ty θ
-
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Copyright by Opto-Electronic Engineering Corporation. All rights reserved.
increasing simultaneously, but also the harmonic components Jk(x) (odd k>=3) is increasing gradually as will be noted from Fig.- 7.
c) Case of which vibration occurs at position R0 = mπ*λ0/ (4π) The worst position of R0 with no fundamental vibration mode is R0 = mπ*λ0/ (4π) as will be noted from Fig.- 4, and gives us the equation eq.- 23 at R0 = mπ*λ0/ (4π). eq.- 23
The eq.- 23 has DC component, but has no fundamental vibration component fv. When the vibration ΔR0 is increasing, the second harmonic components 2*fv is also increasing gradually as will be noted from Fig.- 7.
d) Case of which vibration occurs at arbitrary position R0 The equation of detected vibration signal at arbitrary position R0 is eq.- 19. So we may resolve the eq.- 19 into each harmonic order term such as the following. The range what we need as the radio wave vibration sensor is up to x=2, so it is enough to take up to 5th-order harmonic component into consideration as will be noted from Fig.- 7. (d-1) DC component term eq.- 24
(d-2) fundamental vibration term fv eq.- 25
strength (amplitude) of signal eq.- 26
(d-3) 2nd order harmonic component term 2*fv eq.- 27
strength (amplitude) of signal eq.- 28
( ) ( ) ( )⎭⎬⎫
⎩⎨⎧
⋅⋅+⋅= ∑∞
=120
00det 2cos22
)(m
m mxJxJBA
ty θm
( )xJRBAty 00
000det
4cos
2)( ⋅⎟⎟
⎠
⎞⎜⎜⎝
⎛⋅
−=
λπ
( ) ( ){ }θλπ
sin24
sin2
)( 10
000det ⋅⋅⋅⎟⎟
⎠
⎞⎜⎜⎝
⎛⋅+= xJ
RBAty
( ) ( ){ }θλπ
2cos24
cos2
)( 20
000det ⋅⋅⋅⎟⎟
⎠
⎞⎜⎜⎝
⎛⋅
−= xJ
RBAty
( )xJRBAVtyofAmplitude st 10
000
max1det
4sin)(__ ⋅⎟⎟
⎠
⎞⎜⎜⎝
⎛⋅+==
λπ
( )xJRBAVtyofAmplitude nd 20
000
max2det
4cos)(__ ⋅⎟⎟
⎠
⎞⎜⎜⎝
⎛⋅−==
λπ
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(d-4) 3rd order harmonic component term 3*fv eq.- 29
strength (amplitude) of signal eq.- 30
(d-5) 4th order harmonic component term 4*fv eq.- 31
strength (amplitude) of signal eq.- 32
(d-6) 5th order harmonic component term 5*fv eq.- 33
strength (amplitude) of signal eq.- 34
Now we get some results of the relationship between the received signal strength ΔR0 and the distance R0. And more we are able to know the total harmonic distortion (THD). eq.- 35
Here a root mean square value is defined as the following eq.- 36
We assumed that A0*B0/2 = 1. The effective area as the radio wave vibration sensor is up to ΔR0 = 1.5mm which is indicated in eq.- 11.
( ) ( ){ }θλπ
3sin24
sin2
)( 30
000det ⋅⋅⋅⎟⎟
⎠
⎞⎜⎜⎝
⎛⋅+= xJ
RBAty
( ) ( ){ }θλπ
4cos24
cos2
)( 40
000det ⋅⋅⋅⎟⎟
⎠
⎞⎜⎜⎝
⎛⋅
−= xJ
RBAty
( ) ( ){ }θλπ
5sin24
sin2
)( 50
000det ⋅⋅⋅⎟⎟
⎠
⎞⎜⎜⎝
⎛⋅+= xJ
RBAty
( )xJRBAVtyofAmplitude rd 30
000
max3det
4sin)(__ ⋅⎟⎟
⎠
⎞⎜⎜⎝
⎛⋅+==
λπ
( )xJRBAVtyofAmplitude th 40
000
max4det
4cos)(__ ⋅⎟⎟
⎠
⎞⎜⎜⎝
⎛⋅−==
λπ
( )xJRBAVtyofAmplitude th 50
000
max5det
4sin)(__ ⋅⎟⎟
⎠
⎞⎜⎜⎝
⎛⋅+==
λπ
( ) ( ) ( ) ( )100[%]
1
25
24
23
22 ×
+++= RMS
st
RMSth
RMSth
RMSrd
RMSnd
VVVVV
THD
2
maxorderkthRMS
orderkthV
V −− =
-
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Fig.- 8 Vibration strength ΔR0 and Detected signal amplitude
DC Level=0 at Fig.- 3, Relative Distance R0=λ0/8
Fig.- 9 Total harmonic distortion ratio
DC Level=0 at Fig.- 3, Relative Distance R0=λ0/8
‐0.8
‐0.6
‐0.4
‐0.2
0
0.2
0.4
0.6
0.8
1
1.2
0 1 2 3 4 5
Detected Signal Amplitud
e [A.U.]
Vibration Amplitude ΔR0 [mm]
Detected Signal Amplitude of each harmonic order
1st order
2nd order
3rd order
4th order
5th orderRelative Distance R0 = λ0/8DC level = 0
1st
2nd
3rd
4th
5th
0
10
20
30
40
50
60
70
80
90
100
‐0.8
‐0.6
‐0.4
‐0.2
0
0.2
0.4
0.6
0.8
1
1.2
0 1 2 3 4 5
THD[%
]
Detected Signal Amplitud
e [A.U.]
Vibration Amplitude ΔR0 [mm]
Detected Signal Amplitude of each harmonic order
1st order
THD
Relative Distance R0 = λ0/8DC level=0
-
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Fig.- 10 Vibration strength ΔR0 and Detected signal amplitude
DC Level=0.16 at Fig.- 3, Relative Distance R0=(λ0/8)*1.1
Fig.- 11 Total harmonic distortion ratio
DC Level=0.16 at Fig.- 3, Relative Distance R0=(λ0/8)*1.1
‐0.8
‐0.6
‐0.4
‐0.2
0
0.2
0.4
0.6
0.8
1
1.2
0 1 2 3 4 5
Detected Signal Amplitud
e [A.U.]
Vibration Amplitude ΔR0 [mm]
Detected Signal Amplitude of each harmonic order
1st order
2nd order
3rd order
4th order
5th order
Relative Distance R0 = λ0/8*1.1DC level =+0.16
0
10
20
30
40
50
60
70
80
90
100
‐0.8
‐0.6
‐0.4
‐0.2
0
0.2
0.4
0.6
0.8
1
1.2
0 1 2 3 4 5
THD[%
]
Detected Signal Amplitud
e [A.U.]
Vibration Amplitude ΔR0 [mm]
Detected Signal Amplitude of each harmonic order
1st order
THD
Relative Distance R0 = λ0/8*1.1DC level=+0.16
1st 3rd
5th
2nd 4th
-
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Fig.- 12 Vibration strength ΔR0 and Detected signal amplitude
DC Level=0.45 at Fig.- 3, Relative Distance R0=(λ0/8)*1.3
Fig.- 13 Total harmonic distortion ratio
DC Level=0.45 at Fig.- 3, Relative Distance R0=(λ0/8)*1.3
‐0.8
‐0.6
‐0.4
‐0.2
0
0.2
0.4
0.6
0.8
1
1.2
0 1 2 3 4 5
Detected Signal Amplitud
e [A.U.]
Vibration Amplitude ΔR0 [mm]
Detected Signal Amplitude of each harmonic order
1st order
2nd order
3rd order
4th order
5th order
Relative Distance R0 = λ0/8*1.3DC level =+0.45
0
10
20
30
40
50
60
70
80
90
100
‐0.8
‐0.6
‐0.4
‐0.2
0
0.2
0.4
0.6
0.8
1
1.2
0 1 2 3 4 5
THD[%
]
Detected Signal Amplitud
e [A.U.]
Vibration Amplitude ΔR0 [mm]
Detected Signal Amplitude of each harmonic order
1st order
THD
Relative Distance R0 = λ0/8*1.3DC level=+0.45
1st 3rd
5th2nd
4th
-
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Fig.- 14 Vibration strength ΔR0 and Detected signal amplitude
DC Level=0.7 at Fig.- 3, Relative Distance R0=(λ0/8)*1.5
Fig.- 15 Total harmonic distortion ratio
DC Level=0.7 at Fig.- 3, Relative Distance R0=(λ0/8)*1.5
‐0.8
‐0.6
‐0.4
‐0.2
0
0.2
0.4
0.6
0.8
1
1.2
0 1 2 3 4 5
Detected Signal Amplitud
e [A.U.]
Vibration Amplitude ΔR0 [mm]
Detected Signal Amplitude of each harmonic order
1st order
2nd order
3rd order
4th order
5th order
Relative Distance R0 = λ0/8*1.5DC level =+0.7
0
10
20
30
40
50
60
70
80
90
100
‐0.8
‐0.6
‐0.4
‐0.2
0
0.2
0.4
0.6
0.8
1
1.2
0 1 2 3 4 5
THD[%
]
Detected Signal Amplitud
e [A.U.]
Vibration Amplitude ΔR0 [mm]
Detected Signal Amplitude of each harmonic order
1st order
THD
Relative Distance R0 = λ0/8*1.5DC level=+0.7
1st 3rd
5th
2nd
4th
-
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Fig.- 16 Vibration strength ΔR0 and Detected signal amplitude
DC Level=1.0 at Fig.- 3, Relative Distance R0=(λ0/8)*2.0 The total harmonic distortion ratio with condition of {DC Level=1.0, R0=(λ0/8)*2.0} is no point because of that no fundamental vib ration fv occurs.
Fig.- 17 Distance R0 and Detected signal amplitude (ΔR0=1.5mm)
‐0.8
‐0.6
‐0.4
‐0.2
0
0.2
0.4
0.6
0.8
1
1.2
0 1 2 3 4 5
Detected Signal Amplitud
e [A.U.]
Vibration Amplitude ΔR0 [mm]
Detected Signal Amplitude of each harmonic order
1st order
2nd oeder
3rd order
4th order
5th orderRelative Distance R0 = λ0/4DC level =+1.0
1st 3rd 5th
2nd 4th
‐1.5
‐1
‐0.5
0
0.5
1
1.5
0 1 2 3 4 5 6 7 8 9 10 11 12
Detected Signal Amplitud
e [A.U.]
Relative Distance R0[mm]
Detected Signal Amplitude of each harmonic order
1st order
2nd order
3rd order
4th order
5th order
Vibration Amplitude ΔR0 =1.5mm
1st
2nd
3rd
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Fig.- 18 Distance R0 and Detected signal amplitude (ΔR0=0.75mm)
Fig.- 19 Distance R0 and Detected signal amplitude (ΔR0=0.375mm)
‐1.5
‐1
‐0.5
0
0.5
1
1.5
0 1 2 3 4 5 6 7 8 9 10 11 12
Detected Signal Amplitud
e [A.U.]
Relative Distance R0[mm]
Detected Signal Amplitude of each harmonic order
1st order
2nd order
3rd order
4th order
5th order
Vibration Amplitude ΔR0 =0.75mm
‐1.5
‐1
‐0.5
0
0.5
1
1.5
0 1 2 3 4 5 6 7 8 9 10 11 12
Detected Signal Amplitud
e [A.U.]
Relative Distance R0[mm]
Detected Signal Amplitude of each harmonic order
1st order
2nd order
3rd order
4th order
5th order
Vibration Amplitude ΔR0 =0.375mm
1st
1st
2nd
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Fig.- 20 Total harmonic distortion ratio per Distance R0 (ΔR0=1.5mm)
Fig.- 21 Total harmonic distortion ratio per Distance R0 (ΔR0=0.75mm)
0
10
20
30
40
50
60
70
80
90
100
‐1.5
‐1
‐0.5
0
0.5
1
1.5
0 1 2 3 4 5 6 7 8 9 10 11 12
THD[%
]
Detected Signal Amplitud
e [A.U.]
Relative Distance R0[mm]
Total Harmonic Distortion Ratio
1st order
THD
Vibration Amplitude ΔR0 =1.5mm
0
10
20
30
40
50
60
70
80
90
100
‐1.5
‐1
‐0.5
0
0.5
1
1.5
0 1 2 3 4 5 6 7 8 9 10 11 12
THD[%
]
Detected Signal Amplitud
e [A.U.]
Relative Distance R0[mm]
Total Harmonic Distortion Ratio
1st order
THD
Vibration Amplitude ΔR0 =0.75mm
-
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Fig.- 22 Total harmonic distortion ratio per Distance R0 (ΔR0=0.375mm)
5. How to control the most proper position of distance R0
We can understand the fact that the most proper position of distance R0 exists at the peak of its 1st order fundamental detected signal strength which describes the true vibration signal, as will be noted from Fig.- 20, Fig.- 21, Fig.- 22.
So we are able to realize the best position adjustment of the distance R0 between the Antenna (ANT) of Radio Wave Module and the reflection surface of object by rotating slightly the angle of ANT with camera platform motor stage, or by displacing the distance R0 with linear guide stage in such a way as to get a peak of the 1st order fundamental detected signal like the following figure.
Actually, it is not so hard for us to get the best position of R0, because of that the ANT of Radio Wave Module has a broadening for its radiation characteristics, or of that the general objects have their gradual continuous perspective along the distance, and of that the strength of 1st order fundamental detected signal is most strong than the other harmonic order signals. So, in many general case, the condition for getting the 1st order fundamental detected signal, are coming into effect. Not so severe for us.
0
10
20
30
40
50
60
70
80
90
100
‐1.5
‐1
‐0.5
0
0.5
1
1.5
0 1 2 3 4 5 6 7 8 9 10 11 12
THD[%
]
Detected Signal Amplitud
e [A.U.]
Relative Distance R0[mm]
Total Harmonic Distortion Ratio
1st order
THD
Vibration Amplitude ΔR0 =0.375mm
-
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Fig.- 23 How to get the proper position of distance R0 with slightly adjusting the angle of ANT
6. Differences of the mechanism between radio wave vibration sensor and Doppler radar
When the reflection surface of object moves in a single direction with no restoring force in Fig.- 1 and in Fig.- 3, the Doppler phenomena occurs with going through the fringe of Fig.- 3 such as the following Fig.- 24. We can get the Doppler frequency by calculating the period time of going through one hill of its fringe such as below. eq.- 37
Also we are able to treat the Doppler effect term in eq.- 6 by replacing the parameter such as the following, eq.- 38
The eq.- 6 becomes the following in the case of Doppler phenomena, which is called Doppler Radar equation, Here fdoppler is same to eq.- 37. eq.- 39
0
10
20
30
40
50
60
70
80
90
100
‐1.5
‐1
‐0.5
0
0.5
1
1.5
0 1 2 3 4 5 6 7 8 9 10 11 12
THD[%
]
Detected Signal Amplitud
e [A.U.]
Relative Distance R0[mm]
Total Harmonic Distortion Ratio
1st order
THD
Vibration Amplitude ΔR0 =0.375mm
ANT
Adjusting the angle θ of ANT
Best position of R0
Adjusting the angle θ of ANT
[ ] [ ][ ] [ ]
[ ] [ ] [ ][ ]smcs
mHzfs
mm
sm
mTHzf
dopplerdoppler
υυ
λυ
λ⋅⋅
=⋅===0
00
22211
( ) ttfR v ⋅⋅⇒⋅⋅Δ⋅− υλππ
λπ
00
0
42sin4
( )
( ) ⎟⎟⎠
⎞⎜⎜⎝
⎛++⋅−⋅+⋅⋅=
⎟⎟⎠
⎞⎜⎜⎝
⎛++⋅−⋅−⋅⋅=
000
00
000
00
42cos
42cos)(
ϕϕλππ
ϕϕυλππ
rdoppler
rrx
RtffB
tRtfBty
-
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Fig.- 24 Process of Doppler phenomena
7. Our Radio Wave Vibration Sensor System
We can supply our Radio Wave Vibration Sensor System “OEL4232-02” which provides the powerful solutions for measuring the mechanical vibrations and for measuring the velocities of moving objects and for measuring the distances of various objects such as vehicles, buildings with an epoch-making non-contact remote sensing. Please contact our web site.
http://www.optoelec-engineering.com/products/products_en.html [email protected]
Functions 1)Monitoring a time-waveform of vibration with displaying on graph 2)Frequency Analysis of vibration by FFT(Fast Fourier Transform) 3)Automatic Area Scanning by camera motor platform with a color toned graph photo of objects per vibration strength shot by digital camera. 4)Measuring a distance to object and velocity of moving object.
‐1.5
‐1
‐0.5
0
0.5
1
1.5
‐10 ‐9 ‐8 ‐7 ‐6 ‐5 ‐4 ‐3 ‐2 ‐1 0 1 2 3 4 5 6 7 8 9 10
Normalized
Amplitud
e of detected signal [A.U.]
Relative displacement [mm]
Velocityυ[m/s]
⎟⎟⎠
⎞⎜⎜⎝
⎛+⋅−⋅⋅= rRBAty ϕλ
π0
000det
4cos21)(
20
0λ
−=R
-
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■Schematics of systems ■Photo
Fig.- 25 our Radio Wave Vibration Sensor System “OEL4232-02”
PlasticCaseBOX
RFantennaANT
RadioWaveModule
DSPControlBoard
miniComputer
(*)
AC PowerAdaptertripod stand
Application Software CD
PowerSupply
Power Supply;AC 100V Power Adapteror Pb‐Battery 12V*
CameraMotor Platform*
Digital Camera*
* ; paid‐for option