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TRANSCRIPT
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MERENCANAKAN JEMBATAN KAYU
A. DATA STRUKTUR JEMBATAN KAYU
Data Jembatan
- Panjang bentang (L) = 16 m- Lebar jalan (b) = 3.5 m
- Lebar trotoar = 0.75 m- Lebar jembatan = 3.5 + 2 (0.75)= 5 m
- Tinggi (H) = 5 m- Beban ter!"at = 5 ton- Beban merata = 2.5 ton#m$
- Te%anan angin (&) = 100
Data Kayu
- 'eni" %a! = a! %er!ing
- Berat jeni" %a! = 0.6- ela" %a! = ela" **
- o,!l!" ela"ti"ita" () = 100000
Konstruksi Tak Terlindun
- = 5#6
Muatan Teta!
- / = 1
Teanan "#inela" !at
* ** *** *
150 100 75 50
130 5 60 5
0 25 15 10 20 12 5
%g#m2
%g#4m2
'eni"Tegangan
lt
tr##
t%
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- = 5#6 (150) = 125
- = 5#6 (130) = 10.333
- = 5#6 (0) = 33.333
- = 5#6 (20) = 16.667
B. $EMBEBANAN
1 Trotoir
= 100 %g
= 1# (100) (75)= 175 %g.4m
'i%a lebar aan trotoir ,iambil = 20 4m
& =
= 3 1#3
lt %g#4m2
tr## %g#4m2
t% %g#4m2
%g#4m2
Porang
ma
1#6 b2
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MERENCANAKAN JEMBATAN KAYU
A. DATA STRUKTUR JEMBATAN KAYU
Data Jembatan
- 'embatan %ela" **- Panjang bentang (L) = 10.5 m
- Lebar jalan (b) = 3.5 m- Lebar trotoar = 0.75 m
- Lebar jembatan = 3.5 + 2 (0.75)= 5 m
- θ = 35
Data Kayu
- 'eni" %a! = a! jati
- Berat jeni" %a! = 0.8
- ela" %a! = ela" *- o,!l!" ela"ti"ita" () = 125000
Konstruksi Tak Terlindun
- = 5#6
Muatan Teta!
- / = 1
Teanan "#in
'eni" Tegangan ela" !at* ** *** *
150 100 75 50
130 5 60 5
0 25 15 10
20 12 5
o
t#m3
%g#4m2
lt
tr##
t%
E
35°
A CB
D
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Tegangan i9in !nt!% %a! %ela" *
- = 5#6 (150) = 125
- = 5#6 (130) = 10.333
- = 5#6 (0) = 33.333
- = 5#6 (20) = 16.667
B. $EMBEBANAN
% Trotoir
= 100 %g
= 0.1 ton:%!ran aan ; b = 20 4m
; = 5 4m
!atan berat "en,iri ; < = 0.2 (0.05) (0.80)= 0.008 t#m
omen ma%"im!m - >%ibat P = 1# Pl
= 1# (0.1) (0.75)= 0.01 t.m
- >%ibat berat "en,iri =
=
= 0.00063 t.m
a%a momen ma%"im!m = 0.01 + 0.00063= 0.018 t.m
& =
== 0.0000
= #?
= 0.01830.0000
= 232.58375
= 23.258375 @ 125
lt
tr##
t%
Porang
1#
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& 'antai Kendaraan
- Lebar jalan (b) = 3.5 m
'ara% gelagar memanjang ,an melintang"arat jara% gelagar memanjang
0. m A C 0.6 m
,iambil = 0.5 m
0.5 =3.5n-1
0.5 n - 0.5 = 3.50.5 n = 3.85
n = .77777 ≈ 8
- '!mla balo% gelagar = 8
Dierit!ng%an a"al + %eri%il "etebal 10 4m b, = 2. t#m
10 4m
Dierit!ng%an !nt!% ren4ana m!atan tr!4% ata! "emi trailer.
- 'embatan %ela" **P = 5000 %g= 5 ton
:%!ran lantai ; b = 20 4m; = 15 4m
!atan - < er%era"an = 0.20 (0.10) (2.0)
= 0.05 t#m$
=
=
= 0.0012 t.m
- < = 0.25 (0.1) (0.80)= 0.03 t#m$
berat "en,iri =
=
er%era"an
=
ma
1#
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= 0.0007 t.m
- !atan bergera% Te%anan gan,ar = 5 tonTe%anan 1 ro,a (P) = 1#2 te%anan gan,ar
= 2.5 ton= 2500 %g
>ng%a "ent!
E = 1 +0
100 + 0.5= 1.38201
P "ent! = 1.38 2500= 385.5 %g
=
= 1# 385.5 = 3832.6 %g.4m
er%era"an = 0.0012 t.m= 121.500 %g.4m
b" = 0.0007= 6.3 %g.4m
=
= 3832.6 + 121.50 += 3851. %g.4m
:%!ran lantai ; b = 25 4m; = 15 4m
& =
=
= 837.500
= #?
3851. %g.4m
ma
1# P" l
ma
total ma
+ er%era"an + b"
1#6 b2
1#6 (25) (15)2
4m3
lantai
P = 2500 %g
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837.500 4m3
= 2.18
= 5#6 (1;1) (150)
= 137.5
( Balok )elaar ABC
'ara% gelagar = 0.5 m= 5 4m
Panjang bentangan = 1050 4m
- >%ibat beban "en,iriita a%ai balo% ,engan !%!ran
b = 20 4m
= 30 4m
= 0.20 (0.30) (0.80)
= 0.05 t#m$
- (b, = 2.
= F0.10 (0.80) + (0.1) (2.)G (0.5)
= (0.080+0.2) (0.5)= 0.168 t#m$
= 0.05 + 0.168
= 0.223 t#m$
=
=
= 3.068 t.m
- !atan tr!4%#trailer ----- te%anan 1 o, = 2.5 ton" = 1.38
= 5'ara% gelagar = 0.5 m
P$ =.85
2.5 0.55
= 1.11 ton
%g#4m2
IltJ
%g#4m2
,imana %on"tr!%"i terlin,!ngi; %arena lantai @ IltJ
< b"
arena aan lantai (20 15 4m2) + er%era"an 10 4m
<lantai
< b"
+ <lantai
ma 1#
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= 2;5 (P$) (;85)(")
10.5= 1.35
=
= 1;35(;85) - (1#2) (1;11) (3) (1;38)= 6.78 tm
-=
(1#2)P$(;25) + P$(5;25) + P$(2;25)
10.5
=11.625
P$10.5
= 1.107 1.11 = 1.72 ton
= 1;72(5;25) - (1#2) (1;11) (3) (1;38)
= 6.716 ton
:nt!% m!atan tr!4%#"emi trailer
6.78 tm ait! 0;3 m ,ari %iri#%anan tenga-tenga bentang >
- arena m!atan me"in elin,a"
'embatan %ela" ** P = 5 ton; ,itaan ole 3 gelagar
>
D
>(;85) - 1#2 P$ (5;25) (")
>
>
B
ma
P
2.2500
4.9500
P
2.2500
10.5000
12 P
2,5 t
P
212 P
112 P
10.5000
1.500 1.000
1
2 P
3 . 0 0 0
P
2 . 2 5 0 0
3 . 0 0 0
P
2 . 2 5 0 0
1 0 . 5 0 0 0
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P$ = 5 = 1.666666667 ton3
= 2;5 (P$) 3 =10.5
= 1.25 1.666666667= 2.033333333
= 2.033333333 5.25 =
10.83 tm ,i tenga-tenga bentang
omen a%ibat berat "en,iri + aan lantai + er%era"an
= 3.068 tm ,engan < = 0.223
= 3.068 + 10.8375= 1.0073 tm
'embatan %ela" ** P = 5 ton ,itaan ole 3 gelagar
P$ =5
=1.667 ton
3
= 2;5 P$ ;7510.5
= 1.131 1.667= 1.5 ton
= = .853373016
omen ma ang menent!%an (,iambil)
K
B
:nt!% me"in elin,a" ma
=
ma
total
K
K ;75
212 P
10.5000
P 112 P
212 P
10.5000
1.500 1.000
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= 3.068 + 10.8375 =
= 3.068 + .853373016 =
ang ,iambil = 1.0073 tm
ang menimb!l%an
=
=
1.0073 =
= 1.016007837 t#m
Dimen"i balo% gelagar >B ,an BK
l = 5.25 m< = 1.016 t#m
ma =
= 3.502 t#m
= (5#6) 150
= 125 %g#4m
?n =
= 3000
B
!atan berat "en,iri + aan lantai - er%era"an - me"in elin,!ng ,iganti ,engan m!atan terbagi
ma
tot
(1#) < l2
(1#) (
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?
=35011.3583 %g 4m
= 116.733000 4m3
:%!ran balo% ,aat ,ia%ai 20 30 4m
Tinja!an "tati" ti,a% tertent!
= 8 1.016
123= 0.380 tm @ 3.502
Perit!ngan "elanj!tna ,engan ma = 3.5011,imana %eamanan terjamin.
= 2 (1#2) < l + 2 (#l)
= 5.336 + 1.33
= 6.670 ton
* Balok Melintan Mena+an )elaar
lt
= 116;73 %g#4m2 @ I lt J = 125 %g#4m2
ma
B
B
5.255.25
> B K
0.45P = 6,670 t
0.450.75 0.45
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i"al%an !%!ran balo% = 20 304m< = 0;20 0;3 0;80
= 0.05 t#m
< =
= 1# 0;05 1= 0.00735
< = 1# P l= 1# 6;670 1= 1.66
tot = < + = 0.00735 + 1.66= 1.675 tm
= 0; (1#6) (20) (30)
= 200
=167.25520
= 68.77200
M = 20 20 = 00
= P = 6670.13020
M 00
= 16.675
= (5#6) 1;1 130
= 118.166666667
16.675 %g#4m2 = 118.167 %g#4m2
, Tian $enyokon
1# < l2
? N
lt
Tinja!an a,a lt O antara gelagar 20#30 ,engan balo% melintang 20#30
lt##
%g#4m2
Ilt##
J
t%##
= @ It%##
J
0.45P = 6,670 t
0.450.75 0.45
K2
C
0.90 0.90
K1
0.90 0.90
B
0.90 0.900.90 0.900.90
A
ED
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P = 6.670 ton
= 6;670 + (2 (6;670)#(2))
= 6;670 + 2 (0.07)= 13.30260167 + 0.1176= 13.5
=(1#2) (13;5)
=6.7280.57
= 11.732 ton
Diambil balo% !%!ran b = 20 4m = 20 4m
M = 20 20
= 00
= 0.28
= 0.28 (20)= 5.7 4m
l% =5.25
= 6.08 4m
=l%
=
6.08
5.7= 1.108
&0 1
---- %.%-
1 1.01 & %.-%%
? P
ton + berat"eanjang 2
1 =
2 "in 35o
4m2
imin
4o" 35o
imin
K2
C
0.90 0.90
K1
0.90 0.90
B
0.90 0.900.90 0.900.90
A
ED
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M
=1.011(6;670)
00
= 16.60
/ Sandaran
- Qelagar "an,aran'ara% tiang "an,aran = 1 mDia%ai !%!ran tiang "an,aran
b = 10 4m = 12 4m
!atan ori9ontal = 75 %g#m
=
=
= 8.375 %g.m = 837.5
=
=
= 182
=?
=837.5182
= .3
= 5#6 (1.1) (150)
= 137.5
t%##
%g#4m2
ma 1# (m!atan ori9ontal) (jara% tiang "an,aran)2
1# (75) (1)2
?n 0. (1#6) b 2
0. (1#6) (10) (12)2
4m2
lt
%g#4m2
IltJ
%g#4m2
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--------- >man
- Tiang "an,aranDiambil !%!ran balo%
b = 12 4m
= 12 4m!atan ori9ontal = 75
< = 12#12 (75)= 75 %g#m$
=
=
= 8.375 + .675= 1.0625
=
=
= 230.
=?
=1.0625
230.
= 0.061
= 5#6 (1.1) (150)
= 36.6666666667
---------- >man
- Bo!t-bo!t
=150 (1) (75)
25= 50 %g
= 2 (50)5
= 10 %g
Diambil ba!t ; R =
0 $er+itunan sambunan
t%##
= ;3 %g#4m2 @ It%##
J = 137;5 %g#4m2
%g#4m2
B$
"an,aran +
tiang
1# 75 12 + 1#2 1# 75 12
?n 0. (1#6) b 2
0. (1#6) (12) (12)2
4m2
lt
%g#4m2
IltJ
%g#4m2
t%##
@ It%##
J
P1
P2
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= ton
= ,an K
Eamb!ngan ,i,a"ar%an ata" be"arna momen ang ,aat ,itaan.Eamb!ngan ,engan ba!t ,an "amb!ngan "aming ,engan lat enamb!ng
= 2 10#25 ang ,itaan balo%.
= ==
= 1666.67
= 5#6 (1;1) (150)
= 137.5
=
?
= = 1666.66666667 137.5
= 228166.666667 %g 4m
Diambil ba!t R 2 4m
P = 0.65 30
= 0.65 30 = 111 %g
P = 0. 100 = 0. 100 = 1600 %g
P = 0. 200 = 0. 200 = 1600 %g
Diambil P = 111 %g; ,iambil 2 %elomo% ma"ing-ma"ing %elomo% b!a
B
>
>= >
?n . lt 0; (1#6) b 2
0; (1#6) 20 252
t%
t%
?n .
lt
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---------- on"tr!%"i ta% terlin,!ng
SSS 5#6 0.8 e l1 = 228167ll = 25
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E
C
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>man
%g#4m2
%g#4m2
%g#4m2
%g#4m2
%g#4m2
3.50 0.75
0.75
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5
6.3375
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t#m)
=3,28/..
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1.38
BK
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10.8375 tm
t#m (
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1.0073 tm
12.02316 tm
rata (=<e<
)
C
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5.25
%g#4m2
= 6,670 t
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aman
= 6,670 t
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alo% melintang00 m
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%g.4m
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m ,20 2
l ,10 2
,2
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