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    Vibration in two lectures

    Sudipto Mukherjee, IIT Delhi

    This lecture is build upon a basic mechanics course. We assume

    that you understand basic concepts of degree of freedom as in the

    figures below having one, two, two and infinite degree of freedom.

    Morever that if the mass at the end in the figure below is

    significantly (factor of 10?) heavier than the beam, it can be

    approximated by a single degree of freedom. Otherwise, design

    using the lumped mass approach would be dicey.

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    In mechanics, we usually restrict ourselves to studying position (x),

    velocity (x ) and acceleration (x) dependent forces. While the

    acceleration dependent term is always linear and proportional tothe mass, that is not necessarily true of the position and velocity

    dependent terms, stiffness and damping. Luckily, for small

    velocities and displacement, linearity is observed in most

    mechanical systems.

    a) Free vibrations: system disturbed from an equilibrium

    position (pendulum)

    b) Forced vibration: external disturbance independent of the

    motion of the system (eccentric rotating mass)

    c) Self excited vibration: External disturbance is dependent onthe motion of the system (singing of wires)

    d) Parametrically excited vibration: system parameters changingwith time.

    e) Random vibration: Excitation is not deterministic but only

    probabilistically known.

    Undamped free vibration

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    0mx kx sin cos cosn n nx t A t B t X t

    With nk

    m being the natural frequency, which is a property of

    the system

    If the system is made vertical, how does gravity modify the

    system? Clearly, the mass will descend by an amount = mg/k.Writing the force balance equation in a coordinate system whose

    origin isshiftedto the new static equilibrium position: mx mg k x kx

    which is in the same form as earlier!

    Energy Conservation Approach

    21

    2T mx ,

    21

    2V mgx k x with the datum as the

    equilibrium position. Then using 0d

    T Vdt

    we get:

    0xmx kx and noting that is not equal to zero at alltimes,we get the same equation. This approach is sometime easier that

    the force balance approach, but works only for conservative

    systems.

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    There are several derivations of free vibration equations in Ghosh

    and Mallik that you can look into (especially the Trifilar

    suspension which is perhaps the only experimental method tomeasure moment of inertia). Books on vibration will have many

    more.

    One of special interest is the rod on the two roller system shown

    below:

    1 2,2 2

    a x a xN mg N mg

    a a

    and writing the equation of motion

    in thex direction:

    2 1( )mx N N or / 0x mg a x which is similar to that

    of a SDOF system with /n

    g a !

    There is no restoring element, and this is an example of a self

    excited system where the restoring force is generated by the

    motion of the rod! This system is actually used to measure friction

    coefficients, especially velocity dependent friction coefficients.

    Damping

    Energy of real life systems get dissipated and the rate of decay offree vibration is a measure of damping. This could be due to:

    a) Dry friction between surfaces (Coulumb)

    b) Drag between moving body and fluid environment (viscous)

    c) Internal friction within a material (hysteretic)

    d) Through radiation of energy into environment (wave)

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    Consider free vibration with viscous damping.

    0xmx c kx Assuming a solution of the form:x = e

    st, we get:

    2 0ms cs k which yields2

    1.2 22 4c c ksm m m

    a)2c km , over damped, in which case both roots are real

    and negative. 1 2s t s tx Ae Be and does not have periodic

    motion.

    b) 2cc km , critically damped, in which case both roots are

    identical and the solution is of the form 2ct

    mA Bt e

    (aperiodic) and the ratio, c/cc = , is called the damping

    ratio.

    c) 2c km , under-damped, in which case both roots are

    imaginary and the solution is periodic and with the usual n,

    1

    2 2cos 1nt nx Xe t

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    Rotating vector and phase-plane representation.

    Harmonic quantities are conveniently represented in this form withspeed of rotation , and length of the vector as the amplitude. The

    projection of the vector on the reference line represents the

    instantaneous value of the harmonic quantity.

    Differentiation multiplies the magnitude by and rotates thevector by 90

    o(leading) in the direction of rotation.

    The phase-plane has vertical axis asx and the horizontal axis is

    / nx . A point at the tip of the vector represents a particularphase

    of the motion. Note that the arrowhead is such that for a +ve

    velocity,x increases.

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    Undamped Vibration with Harmonic ExcitationThis solution of a SDF system subjected to a harmonic force

    Fcostis used to analyze general vibration problems by using

    Fourier transforms.

    cosmx kx F t And the solution is form:

    0

    2

    /

    sin cos cos1 /n n n

    F k

    x A t B t t

    for

    n and

    0sin cos sin2

    n n

    n

    F tx A t B t t

    m

    for=n

    For zero initial conditions we see, beats as there are two

    frequencies in the final solution for the first case. For the second

    case, the magnitude of the frequency at grows linearly with time

    and will finally go to infinity. This is called resonance.

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    Please see http://www.vibrationdata.com/Tacoma.htm

    http://www.youtube.com/watch?v=lXyG68_caV4&feature=related

    One needs to remember that all systems have some damping. So

    the initial free vibration will damp out and only the steady state

    solution will remain in the long run.

    0

    2

    /cos

    1

    F kx t

    r

    or

    0

    2

    /

    cos1

    F k

    x tr

    forr>1. Thus the response is in

    phase or out of phase in the

    two zones.

    Deflection is more than the

    static deflection till r> 2

    Viscously damped Vibration with Harmonic Excitation

    0 cosmx cx kx F t or

    2 02 / cosn nx x x F m t Which has a solution of the form:

    cos tx X with

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    0

    12 2

    22

    /

    1 2

    F kX

    r r

    and

    2

    2tan

    1

    r

    r

    Define

    1

    2 20 2 2

    1

    1 2

    XM

    F kr r

    as the magnification factorand the peak amplitude occurs at

    1

    2 21 2p n

    At resonance, the phase is /2, with the inertia force being

    neutralized by the spring force.

    The half power band width is usedto measure the damping for small

    damping : 2 1 / 2 n

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    Systems with base excitation

    0mx c x y k x y

    1

    22

    2 22

    1 2

    1 2

    r

    X Yr r

    and

    3

    22

    2

    tan 1 2

    r

    r r

    Transmissibility

    TR =X/Y in support motion

    =FTo/F0 in force excitation

    1

    22

    2 22

    1 2

    1 2

    rTRr r

    in force

    transmission as well as base motion.

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    Usually ris kept less than 5. Note that very low kvalues lead to

    large static deflections and large vibrations even if the force

    transmitted is reduced.

    Given one more lecture, it would have been interesting to study

    two body vibration problems, especially that of the vibration

    absorber.