two-port networks
DESCRIPTION
LEARNING GOALS. Study the basic types of two-port models. Admittance parameters Impedance parameters Hybrid parameters Transmission parameters. Understand how to convert one model into another. TWO-PORT NETWORKS. In many situations one is not interested in the internal organization of a - PowerPoint PPT PresentationTRANSCRIPT
TWO-PORT NETWORKS
In many situations one is not interested in the internal organization of anetwork. A description relating input and output variables may be sufficient
A two-port model is a description of a network that relates voltages and currentsat two pairs of terminals
Admittance parametersImpedance parametersHybrid parametersTransmission parameters
LEARNING GOALS
Study the basic types of two-port models
Understand how to convert one model into another
ADMITTANCE PARAMETERS
The admittance parameters describe the currents in terms of the voltages
2221212
2121111
VyVyIVyVyI
The first subindex identifies
the output port. The secondthe input port.
1 port to applied is voltage a and circuited-short is port
the when 2 port into flowingcurrent the determines 21y
The computation of the parameters follows directly from the definition
02
112
01
111
12
VV V
IyVIy
02
222
01
221
12
VV V
IyVIy
The network contains NO independent sources
LEARNING EXAMPLEFind the admittance parameters for the network
2221212
2121111
VyVyIVyVyI
][23)
211( 1111 SyVI
2111, yy determine to used Circuit
2I
1212 21
211 VIII ][
21
21 Sy
2212 , yy determine to used Circuit][
65
31
21
2222 SyVI
][21
6553
323
12221 SyVII
Next we show one use of this model
An application of the admittance parameters
2221212
2121111
VyVyIVyVyI
212
211
65
21
21
23
VVI
VVI
221 4,2 IVAI
The model plus the conditions at theports are sufficient to determine theother variables.
21
21
41
65
210
21
232
VV
VV
22 41VI
][112
][1186
13
2
2
21
AI
VV
VV
Determine the current through the4 Ohm resistor
IMPEDANCE PARAMETERS
The network contains NO independent sources
2221212
2121111
IzIzVIzIzV
The ‘z parameters’ can be derived in a manner similar to the Y parameters
01
221
01
111
22
II I
VzIVz
02
222
02
112
11
II I
VzIVz
LEARNING EXAMPLE Find the Z parameters
Write the loop equations
)(42)(42
1222
2111
IIjIjVIIjIV
24442
2221
1211
jzjzjzjz
212
211
244)42(
IjIjVIjIjV
rearranging
01
221
01
111
22
II I
VzIVz
02
222
02
112
11
II I
VzIVz
2221212
2121111
IzIzVIzIzV
LEARNING EXAMPLEUse the Z parameters to find the current through the 4 Ohmresistor
2221212
2121111
IzIzVIzIzV
Output port constraint
22 4IV
Input port constraint
11 )1(012 IV
212
211
244)42(
IjIjVIjIjV
21 )24(40 IjIj
21 4)43(12 IjIj
)43( j4j
2))43)(24(16(48 Ijjj 73.13761.12I
HYBRID PARAMETERS
The network contains NO independent sources
2221212
2121111
VhIhIVhIhV
admittance output circuit-opengain current forward circuit-short
gain voltage reverse circuit-openimpedance input circuit-short
22
21
12
11
hhhh
These parameters are very common in modeling transistors
01
221
01
111
22
VV I
IhIVh
02
222
02
112
11
II V
IhVVh
LEARNING EXAMPLE Find the hybrid parameters for the network
1I
1V
2I
2V2221212
2121111
VhIhIVhIhV
1I
1V
2I
02 V
14))3||6(12( 1111 hIV
32
636
2112
hII
1V
2I
2V01 I
32
636
1221
hVV
][91
9 222
2 ShVI
TRANSMISSION PARAMETERS
The network contains NO independent sources
221
221
DICVIBIAVV
02
1
02
1
22
II V
ICVVA
02
1
02
1
22
VV I
IDIVB
ratio current circuit-short negative Dadmittance transfer circuit-open C
impedance transfer circuit-short negative Bratio voltage circuit openA
ABCD parameters
LEARNING EXAMPLEDetermine the transmission parameters
221
221
DICVIBIAVV
02
1
02
1
22
II V
ICVVA
02
1
02
1
22
VV I
IDIVB
jAV
j
jV
111
1
12
jVII
jV
2
112
1
02 I when02 V when
112 11
11
1
Ij
I
j
jI
jD 1
211 )1(12)1||1(1 IjjjI
jV
jB 2
PARAMETER CONVERSIONS
If all parameters exist, they can be related by conventional algebraic manipulations.As an example consider the relationship between Z and Y parameters
2
11
2221
1211
2
1
2
1
2221
1211
2
1
2221212
2121111
VV
zzzz
II
II
zzzz
VV
IzIzVIzIzV
2
1
2221
1211
VV
yyyy
1
2221
1211
2221
1211
zzzz
yyyy
1121
12221zzzz
Z
12212211 zzzzZ withIn the following conversion table, the symbol stands for the determinant of thecorresponding matrix
DCBA
hhhh
yyyy
zzzz
THYZ ,,,2221
1211
2221
1211
2221
1211
INTERCONNECTION OF TWO-PORTSInterconnections permit the description of complex systems in terms of simplercomponents or subsystems
The basic interconnections to be considered are: parallel, series and cascade
PARALLEL: Voltages are the same.Current of interconnectionis the sum of currents
The rules used to derive modelsfor interconnection assume thateach subsystem behaves in thesame manner before and afterthe interconnection
SERIES: Currents are the same.Voltage of interconnection is the sumof voltages
CASCADE:Output of first subsystemacts as input for thesecond
aaaba
aaa
a
aa
a
aa VYI
yyyy
YVV
VII
I
2221
1211
2
1
2
1 ,,bbb VYI manner similar a In
baba
baba
VVVVVVIIIIII
222111
222111
,,
:sconstraint ctionInterconne
ba
ba
VVVIII
ba YYY
VYYVYVYI babbaa )(
Parallel Interconnection: Description Using Y Parameters
YVIVV
yyyy
II
2
1
2221
1211
2
1
ndescriptioctionInterconne
Series interconnection using Z parameters
bbbaaa IZVIZV ,subsystem each of nDescriptio
Interconnection constraints
a b
a b
I I IV V V
IZZIZIZV baba )(
ba ZZZ
SERIES: Currents are the same.Voltage of interconnection is the sumof voltages
Cascade connection using transmission parameters
2 1 2 1
1 1 2 2
1 1 2 2
Interconnection constraints:
a b a b
a b
a b
I I V VV V V VI I I I
a
a
aa
aa
a
a
IV
DCBA
IV
2
2
1
1
b
b
bb
bb
b
b
IV
DCBA
IV
2
2
1
1
2
2
1
1
IV
DCBA
DCBA
IV
bb
bb
aa
aa
Matrix multiplication does not commute.Order of the interconnection is important
CASCADE:Output of first subsystemacts as input for thesecond
2
2
1
1
IV
DCBA
IV
221
221
DICVIBIAVV
LEARNING EXAMPLEFind the Y parameters for the network
11
2
2j1I
1V
2I
2V
1I
1V
2I
2V
12
121 2II
IjVV
11 121 1,2 2
a ay j y j
21 221 1,2 2
a ay j y j
212
211
32
IIVIIV
2113
51
3112 1
bY
][
21
52
21
51
21
51
21
53
Sjj
jjY
LEARNING EXAMPLEFind the Z parameters of the networkNetwork A
Network BUse direct method,or given the Y parameters transform to Z… or decompose the network in a seriesconnection of simpler networks
jj
j
jjj
Za
2342
232
232
2322
1111
bZ
jj
jj
jj
jj
ZZZ ba
2365
2325
2325
2345
LEARNING EXAMPLEFind the transmission parameters
By splitting the 2-Ohm resistor,the network can be viewed as thecascade connection of two identicalnetworks
jjjj
jjjj
DCBA
121
121
2
2
)1()2())(1()1()1)(2()2)(1()2()1(
jjjjjjjjjjjjjj
DCBA
22
22
24122264241
jjjj
DCBA
jjjj
DCBA
121
Two-Ports